JEE Main 2026 January 23 Shift 2 Question Paper with Solutions: JEE Main 2026 January 23 Shift 2 official question paper pdf with the complete paper analysis is now available here. NTA has released the official question paper with answer key helps in evaluating the performance of candidates in the exam. Candidates can now cross-check their answers with the JEE Main Jan 23 shift 2 answer key. It helps to calculate their probable marks in JEE Main 2026. It will also include a comparative analysis of JEE Main Jan 23 shift 1 and shift 2. Read the article detailed updates and shift-wise comparisons.
Also Check- JEE Main 2026 Jan 23 Shift 1 Question Paper | JEE Main 2026 Jan 23 Shift 1 Answer Key
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Aspirants can use the JEE Main 2026 January 23 Shift 2 official question paper with answers to practice. Candidates can also use the JEE Main College Predictor 2026 to estimate the possibilities of their admission in an engineering college based on their score. A detailed exam analysis is now updated . Students can also get the JEE Main 2026 answer key.
From the table, you will be able to download JEE Main 2026 January 23 shift 2 Paper PDF. Aspirants can analyze the exam difficulty using the JEE Mains 2026 question paper.
Get expert advice on college selection, admission chances, and career path in a personalized counselling session.
We provided questions below from JEE Main 2026 January 23 Question Paper shift 2 from all subjects - Physics, Chemistry, and Maths.
Chemistry
Question 1: How many of the following complex(es) have unpaired electrons
$\left[\mathrm{Ni}(\mathrm{CO})_4\right],\left[\mathrm{NiCl}_4\right]^{2-},\left[\mathrm{PtCl}_4\right]^{2-},\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$
Question 2: The oxidation state of chromium in the final product of the reaction between KI and acidified $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ solution
1) +2
2) +6
3) +4
4) +3
Question 3: For $\mathrm{XeO}_2 \mathrm{~F}_2$, select the correct statement(s),
(A) It shows see-saw shape.
(B) Number of lone pair(s) of $\mathrm{e}^{-}$on Xe is 1.
(C) $\angle \mathrm{FXeF}=180^{\circ}$ (approx.)
(D) It has tetrahedral shape.
1 (A), (C), (D) Only
2 (A), (B) only
3 (A), (B), (C) only
4 (B), (C), (D) only
Question 4: Both human DNA and RNA are Chiral molecules. The Chirality in DNA and RNA arise due to the presence of
1) Chiral Phosphate unit
2) D-sugar component
3) L-sugar component
4) Base unit.
Maths
Question 5: The area (in square units) between the curves $x^2+y^2=4$ and $x^2+(y-2)^2=4$ is
$1 \quad \frac{48}{3}-2 \sqrt{3}$
$2 \quad\frac{45}{3}+\sqrt{3}$
$3 \quad \frac{45}{3}-2 \sqrt{3}$
$4 \quad \frac{45}{3}+2 \sqrt{3}$
Question 6: The number of ways to distribute 6 identical oranges among 4 persons such that each gets at least one orange is:
1.8
2. 10
3. 12
4. 13
Question 7: Let $A=\{1,2,3, \ldots, 9\} ; x R y$ iff $x-y$ is multiple of 3.
$S_1$ : Number of elements in $R$ is 36
$S_2: R$ is equivalence relation
1. $S_1 \& S_2$ both are correct
2. $S_1$ is correct but $S_2$ is not correct
3. $S_2$ is correct but $S_1$ is not correct
4. $S_1 \& S_2$ both are incorrect.
Physics
Question 8: When an object is kept at distance 8 cm and 24 cm from a convex lens magnitude of magnification is same in both cases. Find focal length of the lens.
1 $\quad 32 \mathrm{~cm}$
2 $\quad 8 \mathrm{~cm}$
$3 \quad 24 \mathrm{~cm}$
$4 \quad 16 \mathrm{~cm}$
Question 9: From a uniform disc of radius $R$ and mass $M$ two small discs of radius $R / 4$ is being cut as shown in figure. Find the moment of inertia of the system about axis $A A^{\prime}$.
$1 \quad \frac{79}{128} M R^2$
$2 \quad \frac{79}{256} M R^2$
$3 \quad \frac{109}{256} M R^2$
$4 \quad \frac{109}{128} M R^2$
Question 10: A parallel plate capacitor with plate separation 5 mm is Charged by a battery. On introducing a mica sheet of 2 mm and maintaining the connections of the plates with the terminals of the battery, it is found that it draws $25 \%$ more charge from the battery. The dielectric constant of mica is $\_\_\_\_$
Meanwhile, you can see the analysis below:
| Parameter | Key Observation |
|---|---|
| Overall Difficulty | Moderate |
| Toughest Section | Physics |
| Easiest Section | Chemistry |
| Difficulty Order | Physics > Chemistry > Mathematics |
| Physics Attempt (Avg.) | 10–11 questions |
| Maths Attempt (Avg.) | 8–12 questions |
| Chemistry Nature | Easy to Moderate, Inorganic-heavy |
| Class-wise Weightage | Class 11 > Class 12 |
| Statement-based Questions | Present in Physics & Chemistry |
| Expected Percentile Trend | Higher percentile at slightly lower marks |
For exam analysis and more details, Careers360 hosts daily live analysis sessions on its YouTube channel covering the JEE Mains 2026 question paper. Expert faculty members discuss each shift. The live session link will be provided here.
It is also important to get a detailed shift-wise analysis. Careers360 will also provide the JEE Main 2026 January 23 All Shifts Question Paper and will help you get an in detailed comparison between both shift 1 and shift 2. For more details, check the table below right after the exam is over.
| Parameter | Shift 1 (Morning) | Shift 2 (Evening) |
|---|---|---|
| Overall Difficulty Level | Moderate to Difficult | Moderate |
| Physics Difficulty | Moderate | Tough |
| Chemistry Difficulty | Moderate | Easy to Moderate |
| Mathematics Difficulty | Difficult (lengthy & calculation-heavy) | Moderate (lengthy but relatively easier) |
| Numerical-Based Questions | Moderate to High | Moderate |
| Conceptual Questions | Moderate | Moderate to High (notably in Physics & Chemistry) |
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The table shows the relationship between score, normalized percentile, and estimated All India Rank (AIR) in JEE Main 2026. It helps candidates understand how small differences in marks at higher score ranges significantly influence percentile and rank.
| score | overall_percentile | overall_rank |
| 292 | 99.99890732 | 16 |
| 290 | 99.9987252 | 19 |
| 288 | 99.99863415 | 20 |
| 286 | 99.99826992 | 26 |
| 284 | 99.99790569 | 31 |
| 283 | 99.99745041 | 38 |
| 282 | 99.99726829 | 40 |
| 281 | 99.99635773 | 54 |
| 280 | 99.99617561 | 56 |
| 279 | 99.99417236 | 86 |
| 277 | 99.99317074 | 101 |
| 275 | 99.99289757 | 105 |
| 273 | 99.9926244 | 109 |
| 272 | 99.991987 | 118 |
| 271 | 99.99153171 | 125 |
| 268 | 99.99034797 | 142 |
| 267 | 99.99016586 | 145 |
| 265 | 99.98907318 | 161 |
| 263 | 99.9854309 | 215 |
| 261 | 99.98087806 | 282 |
| 259 | 99.97687156 | 341 |
| 258 | 99.97413985 | 381 |
| 257 | 99.97168132 | 418 |
| 256 | 99.96967807 | 447 |
| 255 | 99.96740165 | 481 |
| 254 | 99.96339515 | 540 |
| 253 | 99.96039027 | 584 |
| 252 | 99.95574637 | 653 |
| 251 | 99.9554732 | 657 |
| 250 | 99.95228621 | 704 |
| 249 | 99.95028296 | 733 |
| 248 | 99.94573012 | 801 |
| 247 | 99.94254313 | 848 |
| 246 | 99.94172362 | 860 |
| 245 | 99.93862768 | 905 |
| 244 | 99.93498541 | 959 |
The JEE Main 2026 expected cutoff helps candidates understand the minimum score or percentile required to qualify for JEE Advanced and for admission to top engineering colleges. You can check the JEE Mains 2026 expected cut-off for each category below:
|
Category |
Expected Percentile |
|
General |
93 - 95 |
|
OBC-NCL |
79 - 80.5 |
|
EWS |
80 - 82 |
|
SC |
60 - 62 |
|
ST |
48 - 51 |
|
UR - PwD |
0.001 - 0.02 |
Use the JEE Mains 2026 rank predictor tool to understand your rank based on how your exam went. This tool can be very useful to calculate and presume an idea about your competitive standing in the JEE competition. This will also help you understand how well you have to prepare for your April shift to get your desired college and stream.
Every aspirant tries to make an assumption of what marks they might be getting in their exam. Not only JEE Mains but this mindset is quite common for competitive students. In an exam like JEE Mains, students do not get a hard copy of their question paper unlike school exams so it is comparatively tougher to give a direct calculation of their marks. So, we will be giving you the formula to calculate the marks in a range - the lower range and upper range.
Assume all doubtful questions are wrong
Lower Score Range = 4 × (Number of Sure Correct Questions) − (Number of Doubtful Questions + Number of Sure Wrong Questions)
Assume all doubtful questions are correct
Upper Score Range = 4 × (Number of Sure Correct Questions + Number of Doubtful Questions) − (Number of Sure Wrong Questions)
Using the previous years question paper, you will be able to see the difficulty level and the type of questions that have been asked in past years. Using the link below, you can download the JEE Mains previous 10 year question papers with solutions PDF.
| Year-Wise JEE Mains Question Paper |
|---|
|
JEE Main 2025 Question Paper with Solution (January Session) |
Here, we have compiled the JEE Mains exam analysis of previous years. Candidates can check the day-wise NTA JEE Main analysis of both sessions of the exam for 2025.
Some last-minute preparation tips for JEE Mains 2026 are added below:
1. Make your revision routine for the last days of JEE Mains if you are planning to give your exam in the January Shift.
2. For practice, refer to the above given previous year questions.
3. If you are weak in some chapters, check the analysis for the type of questions asked from that topic and practice those questions.
4. It is not advisable to start studying a new topic/chapter. Only focus on revision.
NTA uses the JEE Main normalisation formula to calculat theJEE Main Percentile. The formula converts the canddidates raw marks to a percentile by applying the formula shift-wise. Find below the formula.
| Particulars | Details |
|---|---|
|
Total Percentile (T1P) |
(100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
|
Mathematics Percentile (M1P) |
(100 x No. of candidates appeared from the session with a raw score equal to or less than the M1 score in Mathematics. / Total No. of candidates who appeared in the session |
|
Chemistry Percentile (C1P): |
(100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
|
Physics Percentile (P1P) |
(100 x No. of candidates appeared from the session with a raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
Candidates can check the expected JEE Main 2026 January 23 Marks vs Percentile by checking the below expected trends for 2026. Using the marks vs percentile data, candidates can estimate their raw marks and scores for the exam. Candidates can refer to the table below to check the expected JEE Main 2026 Jan 23.
| JEE Main Marks | JEE Main Percentile |
|---|---|
|
292-250 |
99.99890732 -99.9554732 |
|
249-200 |
99.95028296-99.57503767 |
|
199-150 |
99.56019541-98.09290531 |
|
149-100 |
98.07460288-93.8020333 |
|
99-50 |
93.67910655-78.35114254 |
|
49-1 |
77.81927947-6.66590786 |
The NTA had release the JEE Main 2026 cutoff on the official website. The minimum qualifying JEE Main cutoff is required for the candidates to get eligible for admission into NITs, IIITs, and GFTIs through JoSAA counselling. The JEE Main minimum qualifying cutoff below
| Category | Cutoff Percentile |
|---|---|
| General (UR) | 93.4123549 |
| EWS | 82.4164528 |
| OBC-NCL | 80.9232583 |
| SC | 63.9172792 |
| ST | 52.0174712 |
| PwD (UR) | 0.0023186 |
National Testing Agency has announced the JEE Main 2026 session 1 result on February 16, 2026.
Frequently Asked Questions (FAQs)
The JEE Main 2026 January 23 Shift 2 question paper with solutions is available in the article above.
Memorize formulas, do mock tests under a time constraint and understand how to take shortcuts such as dimensional analysis and methods of approximation.
No, the shift 2 was comparatively easier than the morning shift.
On Question asked by student community
Hello Student,
If we compare the two colleges, UEC Ujjain, being a government college, is a better option, simply because of the ROI factor. Because it is a government college, the fee is less, and the placement numbers for both colleges are similar, if not the same.
I am also
Hello Student,
With your rank of 6,29.374 and 12th percentage of 71.28 you are not eligible for CSAB special round, because you are from the general category and also you do not meet the 75% aggregate criteria. If you belonged to the reserved category, you could have had a chance
You have a good chance of getting NITs, IIITs, or GFTIs in CSAB special rounds, especially in:
Civil Engineering
Mechanical Engineering
Metallurgical Engineering
Production Engineering
Biotechnology
Chemical Engineering
CSE or AI in top NITs is unlikely, but lower-demand branches in some institutes are possible. Your exact options depend on your
Please specify:
Which entrance exam? (e.g., AP POLYCET, TS ECET, KEAM, etc.)
Is 160.5 your marks, score, or rank?
Without the exam name, it isn't possible to suggest colleges accurately.
Hello Dear Student,
With a JEE Main rank of 181,383, top-tier NITs and IIITs are generally out of reach for general engineering branches, but you can explore lower branches in some newer NITs, state government universities, GFTIs, or private engineering colleges.
You can check, find and access more information here:
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