JEE Mains 2026 January 23 Shift 2 Question Paper with Solutions
We provided questions below from JEE Main 2026 January 23 Question Paper shift 2 from all subjects - Physics, Chemistry, and Maths.
Chemistry
Question 1: How many of the following complex(es) have unpaired electrons
$\left[\mathrm{Ni}(\mathrm{CO})_4\right],\left[\mathrm{NiCl}_4\right]^{2-},\left[\mathrm{PtCl}_4\right]^{2-},\left[\mathrm{Pt}(\mathrm{CN})_4\right]^{2-}$
Question 2: The oxidation state of chromium in the final product of the reaction between KI and acidified $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ solution
1) +2
2) +6
3) +4
4) +3
Question 3: For $\mathrm{XeO}_2 \mathrm{~F}_2$, select the correct statement(s),
(A) It shows see-saw shape.
(B) Number of lone pair(s) of $\mathrm{e}^{-}$on Xe is 1.
(C) $\angle \mathrm{FXeF}=180^{\circ}$ (approx.)
(D) It has tetrahedral shape.
1 (A), (C), (D) Only
2 (A), (B) only
3 (A), (B), (C) only
4 (B), (C), (D) only
Question 4: Both human DNA and RNA are Chiral molecules. The Chirality in DNA and RNA arise due to the presence of
1) Chiral Phosphate unit
2) D-sugar component
3) L-sugar component
4) Base unit.
Maths
Question 5: The area (in square units) between the curves $x^2+y^2=4$ and $x^2+(y-2)^2=4$ is
$1 \quad \frac{48}{3}-2 \sqrt{3}$
$2 \quad\frac{45}{3}+\sqrt{3}$
$3 \quad \frac{45}{3}-2 \sqrt{3}$
$4 \quad \frac{45}{3}+2 \sqrt{3}$
Question 6: The number of ways to distribute 6 identical oranges among 4 persons such that each gets at least one orange is:
1.8
2. 10
3. 12
4. 13
Question 7: Let $A=\{1,2,3, \ldots, 9\} ; x R y$ iff $x-y$ is multiple of 3.
$S_1$ : Number of elements in $R$ is 36
$S_2: R$ is equivalence relation
1. $S_1 \& S_2$ both are correct
2. $S_1$ is correct but $S_2$ is not correct
3. $S_2$ is correct but $S_1$ is not correct
4. $S_1 \& S_2$ both are incorrect.
Physics
Question 8: When an object is kept at distance 8 cm and 24 cm from a convex lens magnitude of magnification is same in both cases. Find focal length of the lens.
1 $\quad 32 \mathrm{~cm}$
2 $\quad 8 \mathrm{~cm}$
$3 \quad 24 \mathrm{~cm}$
$4 \quad 16 \mathrm{~cm}$
Question 9: From a uniform disc of radius $R$ and mass $M$ two small discs of radius $R / 4$ is being cut as shown in figure. Find the moment of inertia of the system about axis $A A^{\prime}$.
$1 \quad \frac{79}{128} M R^2$
$2 \quad \frac{79}{256} M R^2$
$3 \quad \frac{109}{256} M R^2$
$4 \quad \frac{109}{128} M R^2$
Question 10: A parallel plate capacitor with plate separation 5 mm is Charged by a battery. On introducing a mica sheet of 2 mm and maintaining the connections of the plates with the terminals of the battery, it is found that it draws $25 \%$ more charge from the battery. The dielectric constant of mica is $\_\_\_\_$
How to Calculate JEE Mains 2026 Marks
Every aspirant tries to make an assumption of what marks they might be getting in their exam. Not only JEE Mains but this mindset is quite common for competitive students. In an exam like JEE Mains, students do not get a hard copy of their question paper unlike school exams so it is comparatively tougher to give a direct calculation of their marks. So, we will be giving you the formula to calculate the marks in a range - the lower range and upper range.
Assume all doubtful questions are wrong
Lower Score Range = 4 × (Number of Sure Correct Questions) − (Number of Doubtful Questions + Number of Sure Wrong Questions)
Assume all doubtful questions are correct
Upper Score Range = 4 × (Number of Sure Correct Questions + Number of Doubtful Questions) − (Number of Sure Wrong Questions)
The Average of the both above figures is your mark (assumed).