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JEE Main 2026 January 24 Shift 1 Answer Key: NTA has released the JEE Main final answer key for January 24 shift 1. The authority has uploaded the JEE Main 2026 final answer key in PDF format at jeemain.nta.nic.in. The final answers have been published after considering all the objections raised against the JEE Main 2026 answer key. The JEE Main 2026 provisional answer key for Jan 24 Shift 1 was uploaded on February 4, 2026. Along with the answer key, candidates can download the JEE Mains 2026 question paper and response sheet. Coaching institutes released JEE Mains 24 Jan shift 1 answer key 2026 immediately after the exam. The answer key of JEE Main 24 Jan 2026 shift 1 paper contains answers and solutions to the questions asked.
Check This- JEE Main 2026 score calculator
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NTA will release the JEE Main result 2026 by February 16, for session 1. The JEE Main 2026 exam was held fromJanusry 21 to 29. Once the session 2 result is released, candidates can check the JEE Main cutoff 2026 to analyse their scores. And they can use the JEE Main 2026 college predictor to find the best colleges based on JEE score.
The session 1 answer key for JEE Main 2026 is released by NTA online on February 4, 2026. Candidates can download the JEE Main 2026 session 1 answer key pdf link on this page. The JEE Main 2026 answer key download link will be updated here.
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Here are the Answer Key PDF links for JEE Mains 2026, 24th Jan shift 1 by Coaching Institutes.
Check the JEE Answer Key by Resonance for cross-verifying all the answers after the exam. The answer key s curated by the coaching centre's subject matter experts.
| Subjects | JEE Main 24 Jan Shift 1 Answer Key |
|---|---|
Mathematics | |
Physics | |
Chemistry |
The JEE Answer Key by Aakash has been released by the coaching institute after each shift of the exam. Candidates can refer to the answer key to verify their answer after the exam.
| Date | Answer Key PDF |
|---|---|
Jan 24 shift 1 |














The unofficial JEE Main answer key is released on the same day of the exam. The JEE Main 2026 24th Jan shift 1 answer key is prepared based on participants' memories. Candidates will be able to cross-check their answers with the answer key to evaluate their answer accuracy and probable score.
The JEE answer plays an important role when analysing their exam performance by analysing their score estimation and error identification. Further, the answer key helps candidates to calculate the topic weightage across Physics, Chemistry, and Maths. The National Testing Agency will release the official JEE Main answer key 2026 online. The answer key will be released a few days after the exam. However, candidates can always refer to the answer key by reliable coaching institutes, which are memory-based. Read on to find more information on the JEE answer key for the Jan 24 shift.
Today’s JEE Mains answer key is released after the conclusion of the exam. Candidates can download the answer key from unofficial sources by following the steps.
First of all, visit the website of the coaching institute, including Resonance, Sri Chaitanya, Aakash, Byju's, and Narayan.
On the website, candidates have direct access to the JEE Mains 2026 January 24 Shift 1 answer key PDF.
Just download the PDF and cross-check to verify your answer.
The National Testing Agency has released the JEE Main 2026 answer key on February 4, 2026. Follow the steps to download from the official answer key.
Visit the official website of NTA, jeemain.nta.nic.in.
Look for the link with the title ‘JEE Main 2026 Answer Key’.
Click on the link, and the JEE Main answer key page will be displayed.
Candidate must now log in with their JEE application number, password/ date of birth.
Download the answer key to match your answers.
Given below is the JEE Main 2026 marking scheme to calculate based on the answer keys. Candidates can score each answer as per the marking scheme to find out the probable JEE scores for the Jan 24th shift 1.
| Type of Response | Marking Scheme |
|---|---|
Correct Response | +4 marks awarded |
Incorrect Response | -1 marks deducted |
No answer | No marks |
Marked for review | No marks |
Based on the above marking scheme, candidates will be able to calculate their probable score with the given formula.
Probable Score = (No. of correct answers x 4) - (No. of incorrect answers)
Frequently Asked Questions (FAQs)
The JEE Main Jan 24th shift 1 2026 answer key provisional was released on February 4, 2026.
A -1 marks deduction for every incorrect answer at JEE Main 2026.
Yes, the unofficial JEE answer key is reliable, since it is a memory-based question set done by the participants.
On Question asked by student community
Hello Aspirant,
Based on your profile—108 marks in NATA, 96.52 percentile in JEE Main Paper 2 (B.Arch), 84% in Class 12 and Gujarat domicile—you have a competitive profile for Architecture admissions through ACPC counselling. Admission to CEPT University, Ahmedabad is highly competitive and depends on the final merit list, seat
Hello Aspirant,
If you were unable to download your JEE Advanced scorecard earlier, first visit the official JEE Advanced website and check whether the result portal is still accessible through your login credentials.
If the scorecard download option is no longer available, immediately contact the JEE Advanced helpdesk and explain
Hello Dear Student,
With a 12,360 rank in JEE Main, you are eligible for Electrical Engineering (and often Electrical and Electronics Engineering) at several top-tier NITs. Based on previous closing ranks, you have strong chances at NIT Calicut , NIT Rourkela , NIT Allahabad , NIT Patna , and NIT
Hello Dear Student,
With a 68 percentile in JEE Main (approx. rank 3.75–4.00 lakh ), admission to top-tier Pune colleges like COEP or PICT for Computer Science is not possible , as these typically require significantly higher scores (160+ in MHT-CET or very high JEE ranks).
However, you may secure
Hello Dear Student,
Yes, you can appear for JEE Main on the basis of your diploma qualification , but your eligibility for admission will depend on the specific rules applicable in that year.
In your case:
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