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JEE Main 2026 Architecture College Predictor- Interested in taking admission into architecture programmes through JEE Main 2026? Would you like to know more about the colleges that will offer you admission as per your score? If yes, then this JEE Main 2026 Architecture college predictor tool by Careers360 can help you out.
To help students get detailed information on the colleges that offer admission on the basis of JEE Main 2026 scores, Careers360 team brings the JEE Main 2026 Architecture college predictor tool. Using this tool, students can identify the overall/ category of All India Rankings in the JEE Main exam and the colleges available at the rank. Moreover, students can get details on cutoff, fee structure, placement, and more.
The JEE Main 2026 college predictor tool is very simple to use.
NOTE: JEE Main 2026 Paper 2 Category Rank*:
The JEE Main Architecture college predictor tool is highly beneficial for students who wish to get admission into BArch courses. With the help of the JEE Main Architecture college predictor tool, students can get an idea about possibilities to get admission to the institution/college they want. This will help them to make informed career decisions.
Students will get an idea of colleges with the help of JEE Main Architecture college predictor, in which they can get admission. Students can get details about all the institutions/colleges they are getting and select the best one for them. The JEE Main BArch college predictor helps the students in making pre-decisions about selecting the perfect college.
JEE Mains 2026 result for session 1 will be declared by February 12. For more details check
https://engineering.careers360.com/articles/jee-main-result
Below are the day-wise JEE Main session 1 questions and answers
https://engineering.careers360.com/download/ebooks/jee-main-2026-analysis-january-session
The complete analysis for JEE Main Jan 29 shift 1 exam 2026 will be updated soon at https://engineering.careers360.com/articles/jee-main-2026-january-29-question-paper-with-solutions-pdf
JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-
https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-2-question-paper-with-solutions-pdf
The JEE Main Jan 28 paper for shift 1 was moderate. Although Chemistry was a bit tricky. As expected, Maths was time consuming. But Physics was on the easier side.
You can find the answers for Jan 28 shift 1 online. They are memory based. I found this article helpful
Hi Lucky, Please refer to this link and you can download the free pdf.
https://engineering.careers360.com/download/ebooks/jee-main-2026-memory-based-questions-and-analysis-of-21st-january-shift-1
625 = ms Δ T + mL 625 = m [ 125 × 300 + 2.5 × 10 4 ] 625 = m [ 37500 + 25000 ] 625 = m [ 62500 ] m = 1 100 kg M = 10 grams
HI Manisha Maharana
You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf. https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf Also, you can check ad attemp the online mock test on our platform. https://learn.careers360.com/test-series-jee-main-free-mock-test/
A general equation of a circle is
$ x^2+y^2+2 g x+2 f y+c=0 $
Since it passes through $(0,0)$,
$ c=0 $
So the equation becomes
$ x^2+y^2+2 g x+2 f y=0 $
It cuts the x -axis at ( $a, 0$ ).
Substituting:
$ a^2+2 g a=0 $
g=-a/2
Hi Ritesh Here is the article for your reference https://hospitality.careers360.com/articles/best-books-for-nchmct-jee-preparation
Feb. 1, 2026, 5:25 p.m. IST
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