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JEE Main Mock Test 2025 Free - Online and PDF

JEE Main Mock Test 2025 Free - Online and PDF

Edited By Team Careers360 | Updated on Jul 20, 2024 11:44 AM IST | #JEE Main
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JEE Main Mock Test 2025: Candidates can take a mock test on the NTA JEE Main website at nta.ac.in. The authorities will update the mobile application ‘National Test Abhyas’ to provide aspirants with multiple test options. Candidates must download the National Test Abhyas mobile application for subject-wise and full free JEE Main mock tests. Additional JEE Main free mock test by Careers360 is also available to help boost preparation. Practicing the JEE Main mock test is crucial for JEE Main exam aspirants. The authority will conduct the JEE Main 2025.

The questions in the JEE Mains mock test are based on the JEE syllabus and paper pattern. Candidates preparing for the JEE Main exam must attempt the free JEE Mains mock test to check their level of preparation and improve their time management skills.

JEE Main Mock Test 2025 - Free Download PDF

Attempting the mock test of JEE Mains 2025 is an effective way to boost preparation for students studying for the upcoming NTA engineering entrance exam. With the help of the JEE Mains 2025 mock test, aspirants can not only understand the exam pattern but also know the important and high-weightage topics.

JEE Mains Mock Test PDF

  • JEE Main mock test is also available on the mobile app ‘National Test Abhyas to practice the questions.

  • Mock tests help to increase the efficiency of solving questions.

  • Mock tests make students familiar with the style and scope of the question paper.

  • Here some free mock test links are provided.

  • To start the mock test first you have to register yourself.

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JEE Main Mock Test E-Book

We provided the e-book for the JEE Main mock test. In which a pattern of question papers is given and 10 mock tests are provided with solutions to practice the questions.

JEE Main 2025 ebook-pdf

How to access the JEE Main mock test 2025?

Aspirants can access the NTA Mock Test 2025 online at the official website, nta.ac.in. To access the JEE Main mock test 2025 free no login credentials are required. The mock test of JEE Main 2025 can also be solved through the “National Test Abhyas App”. Attempting the JEE Mains mock test free online will help in self-assessment and identifying the sections that require more attention. Candidates can follow the steps mentioned below to access the free mock test for JEE Mains 2025. To access the JEE Main exam mock test 2025, candidates will have to follow the below-given steps:

Steps to access JEE Main 2025 mock test

Step 1: Visit nta.ac.in and click on the “Mock Test’ link.

JEE Main Mock test

Step 2: After clicking on Mock Test, a new window will appear on the screen as shown below-

Mock Test new window

Candidates will have to “Select the exam they would like to appear in” i.e. JEE Main and “Paper” from the drop-down list. After this, candidates will have to click on the “Start JEE Mock Test’ Link.

Step 3: Next, a login window having the default Username and password will appear on the screen. Candidates will just have to click on the “Login” button to start the test.

mock test login

Step 4: After login, general instructions for attempting the JEE Main mock test will appear on the screen. Candidates will have to read all the instructions carefully, check the declaration box, and click on the “Proceed” button.

mock test instructions

Step 5: Next, the JEE Main mock test will start and candidates can attempt the test. The JEE Main 2025 mock test screen is shown below-

mock test start

Step 6: Submit the test by clicking on the “Submit” button. Check the exam summary .mock test submit

Click on the “Yes” button to finally submit the test and click on the “View Result” button to check the detailed result.

mock test result

Online Test Series of JEE Mains 2025

Solving the online JEE Main online test series 2025 can help students understand the syllabus and exam pattern in a better way. Students appearing for the exam are advised to visit jeemain.nta.nic.in 2025 to practice the JEE Main mock test series. Candidates will find a number of questions to solve in the JEE Main mock test series. A direct link to download the JEE Main sample paper is also available on this page. Candidates can get direct access to a free mock test for JEE Mains link on this page.

To help students, Careers360 presents the JEE Main online test series which is a personalized course designed to help you get accustomed to the online JEE Main exam pattern. It helps students get hands-on experience with the chapter-wise test series for JEE 2025.

JEE Main Question Paper 2024 with Solution

NTA released the JEE Main question paper with solutions at jeemain.nta.nic.in 2024 Candidates can also able to download the JEE Mains 2024 question paper Along with the question paper, the NTA JEE Main 2024 response sheet is also available to students.Careers360 also provided the direct link to download the 2024 question paper pdf.

JEE Main 2024 Question Paper April session pdf:

JEE Main 2024 January Session Pdf

JEE Mains Previous Year Question Paper with Solution

Apart from the JEE Mains mock test 2025, candidates can also attempt IIT JEE previous year question papers. Previous year papers can also be referred to as the JEE Main 2025 mock test as it consists of all questions asked in previous years.

JEE Mains Mock Test Pattern 2025

The mock test for JEE Mains 2025 is designed in an actual exam pattern. Aspirants are advised to check the detailed exam patterns to get an understanding of how the paper is designed.

JEE Main 2025 Test Pattern

Subject-wise distribution of questions, total number of questions, and marks

Subject

Section A

Section B

Marks

Physics

20

10*

100

Chemistry

20

10*

100

Mathematics

20

10*

100

Total

90

300 (100 marks for each section)

* Section B consists of 10 questions out of which any five questions have to be attempted.*

Benefits of Solving JEE Main Mock Test Papers

Candidates appearing for the entrance test must solve the JEE Mains mock test as they have many benefits. Below are the benefits of solving mock tests.

  • The mock test is like a replica of the actual exam so the candidates get prepared for the actual Computer-based test.

  • The mock test will be based on the actual pattern of the exam.

  • Attempting more and more mock tests will help in increasing the speed and time management skills of the candidates.

  • The mock test also helps to retain consistency and accuracy during the examination.

  • Candidates will be able to know about their weak and strong areas through the exam summary and results available after the JEE Mains mock test NTA.

  • After knowing the mistakes, students can work on the areas to improve their performance in the exam.

  • Solving the mock test for JEE Main will help in covering more questions and understanding the paper pattern and difficulty level.

JEE Main Exam's High Scoring Chapters and Topics
This free eBook covers JEE Main important chapters & topics to study just 40% of the syllabus and score up to 100% marks in the examination.
Download EBook

Important Instructions for attempting the JEE Main mock test 2025

While attempting the JEE Main mock test candidates will find the question palette on their screen having instructions. Students can below check the important instructions to attempt the mock test such as the status of answers on the question palette, navigating to a question, answering a question, and navigating through sections. To solve the JEE mock test 2025 online candidates should have good network connectivity to avoid any kind of interruptions.

JEE Main Mock Test 2025- Status of Answers on the Question Palette

The status of questions and answers in the mock test can be understood through colour codes-

Button Colour

Details

Red

Question not answered by the candidate

Gray

The candidate has not visited the question yet

Green

The candidate has answered the question

Purple with a green circle

The candidate has answered the question but marked it for review.

Purple

The candidate has not answered the question but has marked it for review

Navigating to a question in JEE Main 2025 Mock Test

To answer a question in a mock test, candidates have to follow the given instructions-

  • Click on the question number in the Question Palette at the right of the screen to go to that numbered question directly. Note that using this option does not save the answer to the current question.

  • Click on Save & Next to save the answer for the current question and then go to the next question.

  • Click on Mark for Review & Next to save the answer for the current question, mark it for review, and then go to the next question.

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mock test instructions

Answering a Question in JEE Main Mock Test 2025

The procedure for answering a multiple choice type question in the mock test is-

  • To select an answer in the mock test, click on the button of one of the options.

  • To deselect the chosen answer, click on the button of the chosen option again or click on the “Clear” button

  • To change the chosen answer, click on the button of another option

  • To save an answer, candidates must click on the “Save & Next” button.

  • To mark the question for review, click on the “Mark for Review & Next” button.

  • To change the answer to a question that has already been answered, first select that question for answering and then follow the procedure for answering that type of question.

Navigating through sections in JEE Main Mock Test 2025

  • Sections in the mock test are displayed on the top bar of the screen. Questions in a section can be viewed by clicking on the section name. The section candidates are currently viewing is highlighted.

  • After clicking on the Save & Next button on the last question for a section, candidates will automatically be taken to the first question of the next section.

  • Candidates can shuffle between sections and questions during the mock test at their convenience only during the time stipulated.

  • Candidates can view the corresponding section summary as part of the legend that appears in every section above the question palette.

How to register for the JEE Main 2025 Mock Test at the Practice Centre?

Candidates willing to appear for the JEE Main Mock Test 2025 at the designated Test Practice Centres (TPCs) will have to register for the test and book their slots. Check the detailed process of JEE Main mock test registration 2025 here -

Step-1: Firstly the candidates will have to visit the official website (nta.ac.in). Click on the "Registration (Mock Test)” button.

Step 2: Next, candidates will have to register using their email or mobile number and password. Click on "Log In".

mock test registration

Step 3: Candidates will have to select their preferred date for the JEE Main mock test.

mock test date

Step-4: The pin code/center where the candidates want to attempt the JEE Main mock test has to be entered.

mock test pin code

Step 5: Candidates will have to select their preferred mock test centers from the list of options and click on the “Confirm Booking” button.

mock test center

NOTE: The candidates will be able to book another slot only after their previously booked slot is complete.

When to take the JEE Main Mock Test 2025?

Many candidates get confused with what is the ideal time to take the JEE Main mock test. Some of them prefer to solve the NTA mock test while preparing for the JEE Main exam. However, the ideal time for taking the mock test is after the completion of the entire syllabus of JEE Main. Moreover, candidates should attempt several mock tests.

Frequently Asked Question (FAQs)

1. Where can I attempt the JEE Main mock test 2025?

Candidates can practice free JEE Mains 2025 mock test at nta.ac.in.

2. What are the login credentials required to attempt the JEE Main 2025 mock test?

No login credentials are required to attempt the mock test. Candidates will simply have to login; default credentials will be already entered in the login window.

3. What is the importance of the JEE Main mock test 2025?

JEE Main mock tests are based on the actual exam pattern of the exam thus giving an overview of the actual to the candidates. Attempting more and more JEE Main mock tests also increases the speed of the candidates.

4. Can I check the result of my JEE Main mock test?

Yes, candidates can check the exam summary and result of the JEE Main mock test 2025 after submitting it.

5. Is the JEE Main mock test helpful?

Yes, the JEE Main mock test is very important to understand the paper pattern of Joint Entrance Examination Mains.

6. What should be the ideal time to take JEE Main mock tests?

Candidates start solving the JEE Main mock test after completion of the entire syllabus. 

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Questions related to JEE Main

Have a question related to JEE Main ?

Hello Harshita,

Congratulations for your impressive 12th-grade score of 90.4%, you can explore several good engineering colleges in Madhya Pradesh that accept admissions based on 12th-grade marks or through other entrance exams apart from JEE Mains. Here are some of the top engineering colleges in MP where you might be able to secure admission for a B.Tech in CSE:

  1. Shri Govindram Seksaria Institute of Technology and Science (SGSITS), Indore :

    • Admission can be based on the JEE Main score or through the institute's own entrance criteria for vacant seats.
    • Known for its quality education and good placement records.
  2. Medi-Caps University, Indore :

    • Offers admission based on 12th-grade marks and conducts its own entrance exam for certain seats.
    • Good infrastructure and placement opportunities.
  3. Institute of Engineering and Technology (IET), DAVV, Indore :

    • Admissions are primarily through JEE Main, but they may have provisions for direct admissions based on merit.
    • Reputed for its CSE program and industry connections.
  4. LNCT Group of Colleges, Bhopal :

    • Offers admissions based on JEE Main scores, but they also have a management quota where 12th-grade marks can be considered.
    • Strong placement records, particularly in CSE.
  5. SAGE University, Indore :

    • Provides admissions based on 12th-grade marks and their own entrance test (SAGE Entrance Exam).
    • Offers good faculty and modern infrastructure.
  6. Oriental Institute of Science and Technology, Bhopal :

    • Admissions through JEE Main and direct admission based on 12th-grade performance.
    • Known for its robust placement cell and quality education.
  7. Acropolis Institute of Technology and Research, Indore :

    • Offers admission based on JEE Main and may consider 12th-grade marks for direct admission.
    • Good reputation for CSE and strong placement support.

Depends on the college..According to my experience you will get bcak atleast 30K..Check whether they told u it is refundable or not at the time of paying fee also..

Naming any one physical chemistry teacher for JEE preparation is challenging. Here are some highly recommended educators known for their expertise and teaching methods in physical chemistry for JEE.

1. Nitin jain ( Unacademy) : he is known for his clear explanations and has helped many students excel in their JEE exams.

2. MS chouhan ( FIIT JEE) : he is the author of several popular chemistry books for JEE

3. RK gupta ( bansal classes) : An experienced teacher with a deep understanding of physical chemistry concepts, popular among JEE aspirants.

4. P bahadur ( author ans teacher) : he is known for his comprehensive book on physical chemistry and detailed teaching style.

There are many online platforms like vedantu, Byju's,  Unacademy where you can find lectures from these and other top teachers.


Hello,

Based on your JEE Main rank (724408) and SC category rank (57744), it's important to consider that admission criteria can vary from year to year and depend on factors such as the number of seats available, the category-wise cutoffs, and the overall competition.

DCRUST (Deenbandhu Chhotu Ram University of Science and Technology) typically has its own cutoffs for admissions through JEE Main. However, with your rank of 724408 in the general category and 57744 in SC category, it might be challenging to secure admission, especially if the competition is high or if the seats are limited.

Hope it helps you!

Hello apspirant,

As you have not specified the subject your are keen to know its best books. I am providing you with the best books of all three core subjects.

FOR PHYSICS

  • Concepts of physics (Vol. 1 and 2)  by H.C Verma
  • Fundamental of physics by Halliday, Resnick & Walker
  • Understanding Physics: Set of books for
    • Electricity & Magnetism

    • Mechanics (Vol. 1 & 2)

    • Optics & Modern Physics

    • Waves & Thermodynamics by DC Pandey

  • Problems in General Physics  by I.E Irodov

    FOR CHEMISTRY

  • Modern Approach to Chemical Calculations  BY R.C Mukherjee

  • Organic Chemistry by O P Tandon

  • Concept of Physical Chemistry by P Bahadur

  • Concise Inorganic Chemistry  by J D Lee


    FOR MATHEMATICS

  • Objective Mathematics  by R D Sharma

  • The Elements Of Coordinate Geometry  by S N Loney

  • Plane Trigonometry  by S N Loney

  • Differential Calculus  by Amit M Aggrawal

Algebra  by Dr. SK Goyal

Apart from these practice books, a student should first focus on the NCERT Books before jumping to these practice books. Clearing basic is the key to crack any exam.

Good Luck.











View All

 5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C.  If Na2SO4 is 81.5% ionised, the value of x (Kf for water=1.860C kg mol−1) is approximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)
Option: 1  15 g
Option: 2  25 g
Option: 3  45 g
Option: 4  65 g  
 

 50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl.  If pKb of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75
Option: 3 8.25
Option: 4 9.25
 

CH_3-CH=CH-CH_3+Br_2\overset{CCl_4}{\rightarrow}A

What is A?

Option: 1

CH_3-CH(Br)-CH_2-CH_3


Option: 2

CH_3-CH(Br)-CH(Br)-CH_3


Option: 3

CH_3-CH_2-CH_2-CH_2Br


Option: 4

None


\mathrm{NaNO_{3}} when heated gives a white solid A and two gases B and C. B and C are two important atmospheric gases. What is A, B and C ?

Option: 1

\mathrm{A}: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 2

A: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 3

A: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


Option: 4

\mathrm{A}: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


C_1+2 C_2+3 C_3+\ldots .n C_n=

Option: 1

2^n


Option: 2

\text { n. } 2^n


Option: 3

\text { n. } 2^{n-1}


Option: 4

n \cdot 2^{n+1}


 

A capacitor is made of two square plates each of side 'a' making a very small angle \alpha between them, as shown in the figure. The capacitance will be close to : 
Option: 1 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{4 d } \right )

Option: 2 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 + \frac{\alpha a }{4 d } \right )

Option: 3 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{2 d } \right )

Option: 4 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{3 \alpha a }{2 d } \right )
 

 Among the following compounds, the increasing order of their basic strength is
Option: 1  (I) < (II) < (IV) < (III)
Option: 2  (I) < (II) < (III) < (IV)
Option: 3  (II) < (I) < (IV) < (III)
Option: 4  (II) < (I) < (III) < (IV)
 

 An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant.  If during  this process the relation of pressure P and volume V is given by PVn=constant,  then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
Option: 1  n=\frac{C_{p}}{C_{v}}


Option: 2  n=\frac{C-C_{p}}{C-C_{v}}


Option: 3 n=\frac{C_{p}-C}{C-C_{v}}

Option: 4  n=\frac{C-C_{v}}{C-C_{p}}
 

As shown in the figure, a battery of emf \epsilon is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit ) is : 


Option: 1 \frac{\epsilon L }{R^{2}} \left ( 1 - \frac{1}{e} \right )
Option: 2 \frac{\epsilon L }{R^{2}}


Option: 3 \frac{\epsilon R }{eL^{2}}

Option: 4 \frac{\epsilon L }{eR^{2}}
 

As shown in the figure, a particle of mass 10 kg is placed at a point A. When the particle is slightly displaced to its right, it starts moving and reaches the point B. The speed  of the particle at B is x m/s. (Take g = 10 m/s2 ) The value of 'x' to the nearest is ___________.
Option: 1 10
Option: 2 20
Option: 3 40
Option: 4 15

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