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JEE Main Response Sheet 2024 Session 2 for BTech (Out) - Download Link at jeemain.nta.ac.in

JEE Main Response Sheet 2024 Session 2 for BTech (Out) - Download Link at jeemain.nta.ac.in

Edited By Jalla Venkatesh | Updated on Jul 26, 2024 11:14 PM IST | #JEE Main

JEE Main Response Sheet 2025: NTA will release the JEE Main 2025 response sheet date on the official website. The authority will update the JEE Main Response Sheet 2025 in the first week of February 2025. Candidates who appeared for the NTA JEE Main exam can download the response sheet of JEE Main 2025 for B.Tech and B.Arch at, jeemain.nta.ac.in. To download the JEE Mains response sheet 2025, candidates must provide the application number and date of birth. The response sheet will consist of a question paper with recorded responses. Students can use the JEE Main 2025 answer key and response sheet to verify their answers and predict the probable scores. The authority will conduct the JEE Main 2025 exam in online mode.

The JEE Main response sheet 2025 can be used to analyze the understanding and clarity of certain topics and chapters. Candidates can then focus on improving those topics. The JEE Main 2025 response sheet is thus crucial for candidates aiming to improve their performance in future attempts or for those planning to appear in the JEE Main 2025. To know more about the JEE Main Response Sheet 2025 download and other aspects, refer to the article below.

JEE Main Response Sheet 2025 Date

NTA wiil announce the JEE Main response sheet 2025 release date at jeemain.nta.ac.in. Candidates can check the table for the schedule of the JEE Main 2025 response sheet.

JEE Main Response Sheet Date 2025

Particulars

Dates

JEE Main 2025 exams

  • Session 1 - last week of January 2025
  • Session 2 - first week of April 2025

Release of provisional answer key

Session 1: First week of February 2025

Session 2: Last week of April 2025

Release of JEE Main 2025 response sheet and question paper

Session 1: First week of February 2025

Session 2: Second week of April 2025

Objections against the provisional answer key (revised)

Second week of February 2025

Final answer key

Second week of February 2025

Result date

  • Session 1 -Second week of February 2025
  • Session 2 - Last week of April 2025

How to download the JEE Main 2025 Response Sheet?

The National Testing Agency will release the JEE Main response sheet link at jeemain.nta.ac.in 2025. Candidates will be able to download the JEE response sheet pdf in a few simple steps. Below are the steps to access the JEE Main 2025 response sheet link and question paper pdf:

Steps for JEE Main Response Sheet Download

  • Visit the official website at jeemain.nta.ac.in 2025.
  • Click on the link to JEE Main response sheet 2025.
  • Candidates will be required to log in using their JEE Main application number and password.
  • In the candidate login, there will be a link for JEE Main response sheet download, click on it.
  • Download the pdf and save it for reference.
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What will the JEE Main 2025 Response Sheet contain?

Most of the time students get confused over the contents provided by the authorities through the JEE main response sheet 2025. The response sheet of JEE Main 2025 will contain the questions asked through the JEE Main question paper and the responses made by them during the exam. There will be questions asked and corresponding to which the answers attempted by candidates will reflect.

JEE Main 2025 response sheet details

The candidate JEE Main response sheet 2025 shall contain the following:

  • Candidate application number and roll number
  • Date and time of JEE Main 2025
  • Type of Question
  • Option IDs (distinct for each one of the four options)
  • Status of Question (attempted or not, and if correctly attempted)
  • Correct Option
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How to use the NTA JEE Main Response Sheet?

The authorities will release the answer key along with JEE Main response sheet 2025 and question paper for candidates. With the help of these, candidates can compare their responses in JEE Main 2025 with the correct answers to the questions asked. Candidates have to verify their answers using the JEE Main answer key 2025 and responses.

This will help them calculate the score expected in JEE Main 2025 and also raise objections against the questions that seem erroneous and may result in an invalid deduction of marks for such candidates. Elaborate steps on using the NTA JEE Mains response sheet are below:

  • Open the response sheet and answer key of JEE Main
  • Note the question and correct option ID from JEE Main answer key 2025
  • Check if the JEE Main 2025 response sheet contains the same option ID against the same question ID
  • If the option ID is the same, then there will be an addition of 4 marks in the score calculation
  • If the option ID in the two is different, it means 1 mark will be deducted.
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JEE Main Answer Key

NTA will release the provisional JEE Main answer key on the official website. Candidates have to log in and download their answer key to calculate their score along with the JEE Main 2025 response sheet.

What after JEE Main Response Sheet Release?

NTA will announce the JEE Main result 2025 online on the official website jeemain.nta.ac.in. Candidates will need their application number and password/ date of birth to check the JEE Main exam result. With the help of results, candidates can check their total score and rank obtained in JEE Main 2025.

JEE Mains OMR sheet pdf download

Along with the response sheet, the authorities will release the JEE Mains OMR sheet pdf download link. For the JEE Main OMR sheet pdf download, candidates have to log in using their application number and password. The JEE Mains OMR sheet pdf download link will be updated at the official website - jeemain.nta.ac.in.

How to download JEE Main OMR Sheet PDF

  • Visit jeemain.nta.ac.in
  • Click on the JEE Mains omr sheet pdf download link
  • Login using the application number and password
  • Download the JEE Mains OMR sheet.

Frequently Asked Question (FAQs)

1. What is the JEE Main response sheet?

The authorities will release the JEE Main 2025 question paper containing the candidate responses attempted on the day of the exam.

2. When will the official JEE Main response sheet and answer key be released?

JEE Main 2025 respone sheet and answer key will be released in the first week of February 2025.

3. Will the JEE Main response sheet and answer key be released in OMR form?

No, as the JEE Main 2025 exam will be conducted online, the response sheet will be released in accordance.

4. How to download the JEE Main 2025 response sheet?

Candidates have to log in to the official website to download the response sheet of JEE Main 2025.

5. Can I challenge the recorded responses in the JEE Main Response Sheet?

Yes, candidates can challenge the recorded responses in the JEE Main Response Sheet during the specified challenge window. However, there may be a nominal fee for challenging the responses.

6. What is the purpose of the JEE Main Response Sheet?

The JEE Main Response Sheet helps candidates to review their attempted answers, compare them with the official answer key, and calculate their probable scores in the exam.

7. Can I download the JEE Main Response Sheet?

Yes, candidates can download their JEE Main Response Sheet from the NTA website. It is available in a PDF format for easy access.

8. Will the JEE Main Response Sheet be available for all shifts of the exam?

Yes, the JEE Main Response Sheet will be available for all shifts of the exam conducted during the JEE Main 2025 exam.

9. Is the JEE Main Response Sheet used for calculating the JEE Main result?

No, the JEE Main Response Sheet is not used for calculating the final result. It is solely for the candidates' reference to check their attempted responses.

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Questions related to JEE Main

Have a question related to JEE Main ?

Hello,


Yes, even after clearing JEE, you need to pay fees to study in a college. The fee structure varies depending on the college and course you choose. Here's a general idea:


1. Government Colleges: Fees are relatively low, around 5,000 to 50,000 per year.

2. Government-Aided Colleges: Fees are moderate, around 50,000 to 1,50,000 per year.

3. Private Colleges: Fees can be higher, ranging from 1,50,000 to 5,00,000 or more per year.

4. IITs (Indian Institutes of Technology): Fees are around 2,00,000 to 3,00,000 per year.

5. NITs (National Institutes of Technology): Fees are around 1,50,000 to 2,50,000 per year.


Additionally, you may need to pay for:


· Hostel fees (if you opt for on-campus accommodation)

· Mess fees (for food)

· Other expenses (books, materials, etc.)


Hope this helps,

Thank you

Hi there,

Congratulations on getting a percentile of 96.21 in the jee mains examination.

At this percentile you will be certainly in the top list of candidates participating in the exam and the counselling. You can also check about the previous year cutoffs and the opening and closing ranks by visiting the official website of the nta and then checking about the score required to get an admission in the nits.

Also, you can take the help of our college predictor which will definitely help you in finding the exact list of the colleges which are suitable for admission based upon your jee mains rank and score.

The link of the predictor is mentioned below. You can take  the help from there.

https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp

Hope this resolves your query.

Yes you can participate in Centralized Admission Process (CAP) conducted by the State Common Entrance Test Cell, Maharashtra with your JEE mains score under 15% jee quota.some private universities such as Pict ,Spit, vit ,rocem take admission under this quota but Vjti,Coep state government dont accept JEE marks.for counselling you need to report at the time of counselling and get your documents verified then the merit list will be displayed and admission process is done by the authority.for more refer link

https://engineering.careers360.com/articles/mht-cet-counselling-through-jee-main

Hello,


The syllabus for JEE Main 2026 is based on the Class 11 and 12 curriculum of CBSE. Here's a general overview of the syllabus and most concentrated parts:


Physics:


· Mechanics (30-35%): Kinematics, dynamics, work, energy, power, rotational motion, gravitation

· Thermodynamics (15-20%): Laws of thermodynamics, heat transfer, kinetic theory of gases

· Electromagnetism (20-25%): Electric charges, fields, potential, circuits, magnetism, electromagnetic induction

· Optics (10-15%): Reflection, refraction, lenses, wave optics

· Modern Physics (10-15%): Atomic structure, dual nature of matter, nuclear physics


Chemistry:


· Physical Chemistry (30-35%): Atomic structure, chemical bonding, thermodynamics, kinetics, equilibrium

· Inorganic Chemistry (25-30%): Periodic table, s-block, p-block, d-block, f-block elements

· Organic Chemistry (30-35%): Hydrocarbons, functional groups, reactions, stereochemistry


Mathematics:


· Algebra (30-35%): Sets, relations, functions, matrices, determinants, complex numbers

· Calculus (25-30%): Limits, derivatives, integrals, differential equations

· Coordinate Geometry (20-25%): Lines, circles, parabolas, ellipses, hyperbolas

· Trigonometry (10-15%): Triangles, trigonometric functions, identities


Most Concentrated Parts:


· Physics: Mechanics, Electromagnetism, and Thermodynamics

· Chemistry: Physical Chemistry, Inorganic Chemistry, and Organic Chemistry

· Mathematics: Algebra, Calculus, and Coordinate Geometry


Important Topics:


· Physics: Newton's laws, work-energy theorem, electric circuits, magnetic fields, optics

· Chemistry: Atomic structure, chemical bonding, acid-base equilibria, redox reactions, organic reactions

· Mathematics: Quadratic equations, functions, limits, derivatives, integrals, matrices


hope this helps,

Thank you

Hello,


Yes, admission to the Indian Statistical Institute (ISI) is possible through JEE Advanced score. ISI considers JEE Advanced scores for admission to its undergraduate programs, including:


1. Bachelor of Statistics (Honours) [B.Stat (Hons)]

2. Bachelor of Mathematics (Honours) [B.Math (Hons)]


To be eligible, you need to:


1. Appear for JEE Advanced and score a minimum qualifying mark.

2. Apply to ISI separately, mentioning your JEE Advanced roll number and score.

3. Meet the cutoff score set by ISI for admission.


hope this helps,

Thank you

View All

 5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C.  If Na2SO4 is 81.5% ionised, the value of x (Kf for water=1.860C kg mol−1) is approximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)
Option: 1  15 g
Option: 2  25 g
Option: 3  45 g
Option: 4  65 g  
 

 50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl.  If pKb of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75
Option: 3 8.25
Option: 4 9.25
 

CH_3-CH=CH-CH_3+Br_2\overset{CCl_4}{\rightarrow}A

What is A?

Option: 1

CH_3-CH(Br)-CH_2-CH_3


Option: 2

CH_3-CH(Br)-CH(Br)-CH_3


Option: 3

CH_3-CH_2-CH_2-CH_2Br


Option: 4

None


\mathrm{NaNO_{3}} when heated gives a white solid A and two gases B and C. B and C are two important atmospheric gases. What is A, B and C ?

Option: 1

\mathrm{A}: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 2

A: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 3

A: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


Option: 4

\mathrm{A}: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


C_1+2 C_2+3 C_3+\ldots .n C_n=

Option: 1

2^n


Option: 2

\text { n. } 2^n


Option: 3

\text { n. } 2^{n-1}


Option: 4

n \cdot 2^{n+1}


 

A capacitor is made of two square plates each of side 'a' making a very small angle \alpha between them, as shown in the figure. The capacitance will be close to : 
Option: 1 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{4 d } \right )

Option: 2 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 + \frac{\alpha a }{4 d } \right )

Option: 3 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{2 d } \right )

Option: 4 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{3 \alpha a }{2 d } \right )
 

 Among the following compounds, the increasing order of their basic strength is
Option: 1  (I) < (II) < (IV) < (III)
Option: 2  (I) < (II) < (III) < (IV)
Option: 3  (II) < (I) < (IV) < (III)
Option: 4  (II) < (I) < (III) < (IV)
 

 An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant.  If during  this process the relation of pressure P and volume V is given by PVn=constant,  then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
Option: 1  n=\frac{C_{p}}{C_{v}}


Option: 2  n=\frac{C-C_{p}}{C-C_{v}}


Option: 3 n=\frac{C_{p}-C}{C-C_{v}}

Option: 4  n=\frac{C-C_{v}}{C-C_{p}}
 

As shown in the figure, a battery of emf \epsilon is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit ) is : 


Option: 1 \frac{\epsilon L }{R^{2}} \left ( 1 - \frac{1}{e} \right )
Option: 2 \frac{\epsilon L }{R^{2}}


Option: 3 \frac{\epsilon R }{eL^{2}}

Option: 4 \frac{\epsilon L }{eR^{2}}
 

As shown in the figure, a particle of mass 10 kg is placed at a point A. When the particle is slightly displaced to its right, it starts moving and reaches the point B. The speed  of the particle at B is x m/s. (Take g = 10 m/s2 ) The value of 'x' to the nearest is ___________.
Option: 1 10
Option: 2 20
Option: 3 40
Option: 4 15

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