JEE Main Result 2020
Satyendra Singh, 04 Nov 2019, #JEE Main
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JEE Main Result 2020 - NTA will declare the result of JEE Main 2020 in online mode on January 31 for January session. The JEE Main 2020 result for April attempt will be released on April 30. The JEE Main result will be declared in the form of score card containing four NTA scores, one each for Physics, Chemistry and Mathematics and one combined score. The JEE Main 2020 result will also mention the All India Rank and Category Rank of candidates. The final result of JEE Main 2020 is formulated after the April attempt on the basis of candidates performance in January and/ or April attempt. JEE Main result 2020 for candidates who appear in both January and April attempt will be formulated using the best of two scores. Students who qualify JEE Main 2020 will become eligible to appear in JEE Advanced 2020. The JEE Main score is used for admission in NITs, IIITs, GFTIs and many other institutes. Candidates can find below more details regarding the JEE Main result 2020 and the various process involved in admission.
Latest: Students of J&K can now fill the online JEE Main application form 2020 till November 8.

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JEE Main Result 2020 - Important Dates

Events

January Attempt Dates

April Attempt Dates

JEE Main 2020 Exam

January 6 to 11, 2020

April 3 to 9, 2020

Release of Provisional Answer Key

January second week

April second week

Release of Final Answer Key

January third week

April third week

Declaration of Result

January 31, 2020

April 30, 2020

Registration for JEE Advanced 2020

May first week, 2020

JEE Advanced 2020

May Second week, 2020

JEE Advanced 2020 Result

May last week, 2020

Registration for JoSAA 2020 Counselling

June 15, 2020

How to Check JEE Main Result 2020

NTA will declare the result of JEE Main 2020 in online mode separately for both the attempts. The direct link for checking JEE Main result 2020 will be provided below once it is declared. The January attempt result will be declared on January 31 and the April attempt result will be declared on April 30, 2020. Students can check the result by login either by using their Application Number and Password or with Application Number and Date of Birth. Following is the step by step guide to check JEE Main Result 2020

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  1. Open the JEE Main 2020 Portal : jeemain.nic.in

  2. Click on the result link

  3. Login using JEE Main 2020 Application Number and Password/ Date of Birth

  4. Result will be displayed on screen

  5. Download the result and take a print of it

  6. Keep the result copy safe till the complete admission process

Details included in JEE Main Result 2020

Students will find the following details in their result of JEE Main 2020

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  1. Name of the candidate

  2. Roll number

  3. Date of birth

  4. Name of the candidate’s parents

  5. State code of eligibility

  6. Category and Nationality

  7. Subject-wise NTA scores

  8. Total NTA scores obtained in first attempt and second attempt

  9. Best of the two scores

  10. All India Rank of Candidate

  11. Category Rank of Candidate (If applicable)

  12. Cutoff for JEE Advanced


JEE Main 2019 State-wise Toppers with NTA score

S.No.

State Code of Eligibility

Candidate Name

NTA Score

1

ANDAMAN AND NICOBAR ISLAND

SHUBHANSHU PRASAD

98.7250736

2

ANDHRA PRADESH

BOJJA CHETAN REDDY

100

3

ARUNACHAL PRADESH

PRINCE KUMAR GUPTA

98.8802243

4

ASSAM

PRADIPTA PARAG BORA

99.9963677

5

BIHAR

ABHISHEK KUMAR

99.9771914

6

CHANDIGARH

DISHANK JINDAL

99.997251

7

CHHATTISGARH

RISHABH BHATNAGAR

99.972758

8

DADRA AND NAGAR HAVELI

VISHWAJEET DESHMUKH

98.8751498

9

DAMAN & DIU

ASHMIT SINGH

99.3978968

10

DELHI

NAVNEET JINDAL

99.999083

11

FOREIGN/OCI/PIO/NEPAL/BHUTAN

ANANYA AMANCHERLA

99.8928714

12

GOA

JAIPRAKASH SURESH GURAV

99.9872898

13

GUJARAT

RAGHAV SOMANI

99.9907511

14

HARYANA

ASHUTOSH SINGLA

99.9981753

15

HIMACHAL PRADESH

SARTHAK GUPTA

99.8950807

16

JAMMU AND KASHMIR

AMAN YADAV

99.9789101

17

JHARKHAND

ANKIT KUMAR JAIN

99.9899608

18

KARNATAKA

KEVIN MARTIN

100

19

KERALA

VISHNU VINOD

99.9990801

20

LAKSHADWEEP

ABDUL JAVAD PA

88.3358227

21

MADHYA PRADESH

DHRUV ARORA

100

22

MAHARASHTRA

ANKIT KUMAR MISRA

100

23

MAHARASHTRA

GUPTA KARTIKEY CHANDRESH

100

24

MAHARASHTRA

RAJ ARYAN AGRAWAL

100

25

MANIPUR

LAISHRAM PRINCE SINGH

97.5009989

26

MEGHALAYA

GOURAV KUMAR

99.8872894

27

MIZORAM

AKASH JYOTI SAHOO

94.521163

28

NAGALAND

KARTIKEYA CHANDRA

96.7983937

29

ODISHA

SIBASIS NAYAK

99.9844902

30

PUDUCHERRY

CHIRANTANDIP MAHANTA

99.7827873

31

PUNJAB

JAYESH SINGLA

100

32

RAJASTHAN

SHUBHANKAR GAMBHIR

100

33

RAJASTHAN

SAMBIT BEHERA

100

35

SIKKIM

RAHUL GUPTA

99.1418764

36

TAMIL NADU

GAURAV P

99.993561

37

TELANGANA

ADELLY SAI KIRAN

100

38

TELANGANA

YINDUKURI JAYANTH PHANI SAI

100

39

TELANGANA

BATTEPATI KARTHIKEYA

100

40

TELANGANA

VISWANATH K

100

41

TRIPURA

SHAYANDEEP BHAUMIK

99.7457412

42

UTTAR PRADESH

HIMANSHU GAURAV SINGH

100

43

UTTAR PRADESH

NAMAN GUPTA

100

44

UTTARAKHAND

PALLAV SEMWAL

99.9556053

45

WEST BENGAL

SHASWATA DUTTA

99.9972491


Candidates who scored 100 Percentile in JEE Main 2019

SI No.

Candidate Name

State Code of Eligibility

1

Shubhan Srivastava

Delhi

2

Kevin Martin

Karnataka

3

Dhruv Arora

Madhya Pradesh

4

Jayesh Singla

Punjab

5

Battepati Karthikeya

Telangana

6

Nishant Abhangi

Rajasthan

7

Adelly Sai Kiran

Telangana

8

Viswanath K

Telangana

9

Konda Renu

Andhra Pradesh

10

Abhay Pratap Singh Rathore

Madhya Pradesh

11

Sambit Behera

Rajasthan

12

Shubhankar Gambhir

Rajasthan

13

Ankit Kumar Mishra

Maharashtra

14

Himanshu Gaurav Singh

Uttar Pradesh

15

Prakhar Jagwani

Madhya Pradesh

16

Dravya Marwaha

Haryana

17

Naman Gupta

Uttar Pradesh

18

Gupta Kartikey Chandresh

Maharashtra

19

Yindukuri Jayanth Phani Sai

Telangana

20

Samiksha Das

Rajasthan

21

Bojja Chetan Reddy

Andhra Pradesh

22

Gudipaty Aniket

Jharkhand

23

Jitender Kumar Yadav

Haryana

24

Raj Aryan Agrawal

Maharashtra


JEE Main 2019 Paper 2 Toppers who scored 100 Percentile

Application Number

Name of Student

NTA Score

190310031218

Gollapudi N Lakshman Narayana

Andhra Pradesh

190310155658

Gudla Raghunandan Reddy

Andhra Pradesh


Marking scheme of JEE Main 2020

NTA follows the predetermined marking scheme for calculating the marks obtained in each part of the question paper. The marking scheme is discussed below

For every correct answer

4 marks is awarded

For wrong answers

1 mark is deducted

For unanswered question

No mark is awarded or deducted


How is the JEE Main result 2020 calculated?

JEE Main result is calculated in the form of percentile NTA score each for Physics, Chemistry and Mathematics and one combined score. NTA scores are obtained by normalization using the raw score obtained by the candidates. The following formula is used for obtaining the NTA score



Total Percentile (T1P):



100 X

No. of candidates appeared from the session with raw score EQUAL TO OR LESS than T1 score

Total No. of candidates appeared in the session



Mathematics Percentile (M1P)




100 X

No. of candidates appeared from the session with raw score EQUAL TO OR LESS than M1 score in Mathematics

Total No. of candidates appeared in the session


Physics Percentile (P1P)


100 X

No. of candidates appeared from the session with raw score EQUAL TO OR LESS than P1 score in Physics

Total No. of candidates appeared in the session


Chemistry Percentile (C1P):


100x

No. of candidates appeared from the session with raw score EQUAL TO OR LESS than C1 score in Chemistry

Total No. of candidates appeared in the session


Declaration of the final result of JEE Main 2020 and All India Ranks
JEE Main 2020 will be conducted in two attempts in January and April. Since the exam will be held on multiple shifts each day across the two sessions, the calculation of score to a single percentile score is done through a normalization process. The normalization is done to reach a disambiguated score of candidates despite the variations in difficulty level of question papers held on multiple shifts and sessions. NTA adopts an established formula for the calculation of percentile score.

Compilation and display of Paper 1 Result for First January session:
JEE Main 2020 Paper-1 first attempt will be conducted in multi-shifts, NTA scores will be calculated corresponding to the raw marks obtained by a candidate. This shall comprise of the four NTA scores for each of the three subjects (Mathematics, Physics, Chemistry) and the total in Paper-1 of JEE Main 2020 for the first attempt.

Compilation and display of Paper 1 Result after April session:
Similarly, JEE Main 2020 Paper-1 second attempt will be conducted in multi-shifts, NTA scores will be calculated corresponding to the raw marks obtained by a candidate. The calculated NTA scores for the Raw Marks for all the shifts/sessions will be merged for further processing. The four NTA scores for each of the candidates in Paper-1 of JEE Main 2020 for the first attempt as well as for the second attempt will be merged for compilation of results and preparation of overall Merit List / Ranking. Those appeared in both the attempts; their best of the two NTA scores (total) will be considered for further processing.

Tie-Breaking
In case of a tie when two or more candidates obtain equal Total NTA Score in JEE Main 2020, inter-se merit of such candidates shall be determined in the following order:

  1. Rank list for admission to B.E. /B. Tech
  2. NTA score of raw mark in Mathematics
  3. NTA score of raw mark in Physics
  4. NTA score of raw mark in Chemistry
  5. Candidates older in age

If the resolution is not possible after this criterion, candidates will be given the same rank.
The NTA scores of both the attempts and rank of Paper 1 of JEE Main 2020 for all candidates who appeared in first attempt as well as in second will be declared by April, 2020. This shall comprise the four NTA scores obtained by the candidate in first attempt and four NTA scores obtained in second attempt along with the status of those who qualify for appearing in JEE Advanced 2020 provided and subject to other conditions of eligibility being met. The rank shall comprise All India rank and All India category rank

Compilation and display of Paper 2 Result for January session
JEE Main 2020 Paper-2 may be conducted in single-shift only, the raw marks obtained by all the candidates who appeared in first attempt will be declared by January, 2020. This shall comprise the actual marks obtained in Paper-2 of JEE Main 2020 for the first attempt.

Compilation and display of Paper 2 Result after April session
JEE Main 2020 Paper-2 second attempt also may be conducted in single-shift, the raw marks obtained by all the candidates who appeared in the second shift as well as for the first attempt will be merged for compilation of results and preparation of overall Merit List / Ranking. Those appeared in both the attempts; their best of the two raw marks will be considered for further processing.

In case of a tie when two or more candidates obtain equal Total Marks in JEE Main 2020, inter-se merit of such candidates shall be determined in the following order:

  1. Rank list for admission to B.Arch./B.Planning
  2. Candidates obtaining higher marks in Aptitude Test in Paper-2
  3. Candidates obtaining higher marks in Drawing Test in Paper-2
  4. Candidates older in age

If the resolution is not possible after this criterion, candidates will be given the same rank.
The Total raw marks of both the attempts and rank of Paper-2 of JEE Main 2020 for all candidates who appeared in first attempt as well as in second will be declared by April, 2020. This shall comprise the total raw marks obtained by the candidate in first attempt as well as in second attempt along with All India rank and All India category rank.

Difference between percentage and percentile score
Students must note that percentage and percentile are two different entities. Percentage is the absolute number while percentage is relative. If a student obtained 90 marks out of 100, his/her percentage will be 90 but percentile would be different. Percentile is calculated in relation to the total number of candidates appeared. The formula for calculating the percentage and percentile is given below

Percentage

Percentile

Percentage =

Marks obtained / Total marks (x) 100

Percentile =

100 (x) Number of candidates in the group with aggregate marks less than that obtained by the candidate / Total number of candidates in the group


JEE Main 2020 Cutoff

NTA will declare the JEE Main cutoff 2020 along with the declaration of result. JEE Main cutoff is the minimum marks a candidate need to secure in order to qualify the exam. Students who score marks more than or equal to JEE Main cutoff becomes eligible to appear for JEE Advanced and also for taking admission in NITs, IIITs, GFTIs and other institutes which take admission through the score. JEE Main cutoff is different for various categories and varies year over year. Students can find below JEE Main Cutoff for previous year.

JEE Main 2019 Cutoff

Category

Cutoff Score

Common Merit List

89.754849

General (EWS)

78.2174869

OBC

74.3166557

SC

54.0128155

ST

44.3345172

PWD

0.1137173


JEE Main Cutoff for previous years

Category

2018

2017

2016

2015

2014

2013

General

74

81

100

105

115

113

OBC-NCL

45

49

70

70

74

70

SC

29

32

52

50

53

50

ST

24

27

48

44

47

45

PwD

-35

1





JEE Main 2020 Rank List

NTA will release the JEE Main 2020 rank list along with the declaration of result. JEE Main rank list mentions the ranks obtained by students. NTA will release two types of rank, All India Rank and Category Rank. JEE Main 2020 Rank list will be prepared on the basis of candidates percentile score in the exam.

JEE Main Mark Vs Rank

Students who qualify JEE Main are provided percentile NTA score and its corresponding All India Rank and Category Rank. Joint Seat Allocation Authority (JoSAA) uses the All India Rank of Candidates for the allotment of seats in all the participating institutes. Students can find the reference JEE Main Mark vs Rank criteria in order to get an idea about their rank as per their score

JEE Main Scores

JEE Main Ranks (CRL)

336 - 360

1 - 20

310 to 335

21 - 225

251 to 300

226 - 1492

201 to 250

1493 - 5752

151 to 200

5753 - 18377

101 to 150

18378 - 57131

51 to 100

57132 - 240541

1 to 50

240542 - 984170

-40 to 0

984171 - 1074221

JEE Main Marks vs Percentile
The result of JEE Main 2020 will be released in the form of NTA score, which is a percentile score obtained by normalization process. Normalization is done on the basis of candidates raw score obtained in each subject. Normalization is done to eliminate any parity in difficulty level of exam held across multiple session and shifts. The JEE Main result enlists percentile NTA score each for Physics, Chemistry and Mathematics and one combined score. Students can find for reference the JEE Main marks vs Percentile scores

JEE Main Marks

Percentile

360 to 310

100 - 99.98724751

309 to 299

99.985572 - 99.9740296

298 to 288

99.97589128 - 99.96258028

287 to 278

99.96146328 - 99.94424276

277 to 268

99.94098483 - 99.91929629

267 to 258

99.91836545 - 99.89081262

257 to 248

99.88643768 - 99.84845946

247 to 238

99.84510844 - 99.79959043

237 to 228

99.79679791 - 99.73294238

227 to 218

99.73005678 - 99.65475193

217 to 208

99.64888765 - 99.55273201

207 to 198

99.54919482 - 99.43609792

197 to 188

99.4200875 - 99.28958392

187 to 178

99.26473052 - 99.07781811

177 to 168

99.06329703 - 98.85683701

167 to 158

98.82509541 - 98.55710695

157 to 148

98.53104347 - 98.20040957

147 to 138

98.14939961 - 97.75686494

137 to 128

97.69477799 - 97.17648701

127 to 118

97.13841571 - 96.41990133

117 to 108

96.35511496 - 95.49744019

107 to 98

95.42678954 - 94.40128456

97 to 88

94.19473145 - 92.74709113

87 to 78

92.61891464 - 90.64227869

77 to 68

90.42902355 - 87.34180397

67 to 58

87.34180397 - 82.68016383

57 to 48

81.92571907 - 75.39020758

47 to 38

74.13450619 - 64.11300382

37 to 28

62.88839244 - 49.28762915

27 to 18

49.01228707 - 33.08815042

17 to 1

31.32570046 - 9.077538863

JEE Main 2020 Seat Matrix

Students can find here the seat matrix of JEE Main

Institute Type

Seats

IIT

13,376

NITs

17,967

IIITs

4,023

GFTIs

4,683

JEE Main 2020 Reservation

All the participating institutes of JEE Main has reserved certain number of seats for candidates belonging to reserved categories. Admission to candidates belonging to reserved categories are done considering the reservation criteria mandated by the Government. Students can find below the percentage of seats reserved in the institutes.

Categories

Reservation Percentage

Scheduled Caste

15%

Scheduled Tribe

7.5%

OBC (NCL)

27%

Person with Disabilities

5%

Economically Weaker Section

10%

Eligibility Criteria for Appearing in JEE Advanced 2020

Students who will qualify JEE Main 2020 with the minimum cutoff mark as decided by the official authority becomes eligible to appear in JEE Advanced. Students can find below the previous year cutoff trends for appearing in JEE Advanced.

Category

2019 (NTA Score)

2018

2017

2016

2015

2014

2013

General

89.754849

74

81

100

105

115

113

OBC-NCL

78.2174869

45

49

70

70

74

70

SC

74.3166557

29

32

52

50

53

50

ST

54.0128155

24

27

48

44

47

45

PwD

44.3345172

-35

1






Frequently Asked Question (FAQs) - JEE Main Result 2020

Question: How to know if qualified for JEE Advanced 2019 exam?

Answer:

Candidates who score more than or equal to cut off (category wise) released by NTA will be qualified for the JEE Advanced exam 2020. Only the top 2,45,000 JEE Main 2020 qualified candidates will be eligible for JEE Advanced examination. You can check your cut off in your JEE Main 2020 score card.

Question: How to check eligibility for JEE Advanced 2020?

Answer:

The followings are the eligibility to appear for JEE Advanced examination,

  • Age limit – The Supreme Court of India has released an order declaring that candidates who are above the age of 25 years can apply for JEE Advanced 2020.

  • Qualifying examination – The candidates should have appeared and qualified 12th standard (or equivalent) examination in 2019 or 2020.

  • Number of attempts – JEE Advanced can be attempted by the candidates two times in two consecutive years.

  • JEE Main – All of the candidates have to qualify JEE Main exam and satisfy the specified cutoff for admissions into IITs through JEE Advanced exam.

  • IIT Admissions – Should not have been admitted in an IIT irrespective of whether or not he/she continued in the programme or accepted an IIT seat by reporting at a reporting centre in the past. Those candidates whose admission at IITs was cancelled after joining will also not be considered eligible for JEE Advanced.

Question: How many students appeared in JEE Mains 2019?

Answer:

There are 608440 candidates were appeared in the January session and similarly, there are totally 881096 candidates participated in the April session. 77% of students appeared in both the sessions of JEE Main 2019 examination i.e., 11,47,125 candidates.

Question: What will my JEE Main result in April contain?

Answer:

The JEE Main result 2020 to be declared in April will give the percentile scores and the ranks obtained by the students. The ranks will be used as the basis for admissions.

Question: How will I know my best score? Will the April and January scores be given separately?

Answer:

To allow candidates a clear idea, both the January and April scores will be mentioned and the rank will also be mentioned.

Question: How will the ranking be calculated for JEE Main 2020 considering both the attempts?

Answer:

JEE Main 2020 ranks will be calculated on the basis of the final percentile that will be mentioned for each candidate. The best of the two scores will be used for candidates who have appeared in both the sessions while the score of the session appeared will be used for all others.

Question: Since percentile can be the same in a session for two or more candidates, how will the ranks be awarded?

Answer:

Well, the ranking will be as per the inter-se-merit guidelines which are discussed in detail in the article above. The ranks will be awarded as per the same.

Question: How can I know for which percentile I will get a seat?

Answer:

This, unfortunately, is something that cannot be predicted just like that. Its better to use a rank predictor tool that uses past trends keeping your category in mind and then gives all those options.

Question: Will the JEE Advanced qualifying status be announced with the JEE Main 2020 result?

Answer:

Yes, the cutoff marks, as well as JEE Advanced qualifying status, will be announced by NTA with the JEE Main result 2020. It must be noted that this is the cutoff to appear for JEE Advanced and not for admission through JEE Main.

Question: Should I drop one year if I don't get the requisite percentile for admissions?

Answer:

This is not advisable as statistics show very few candidates succeeding in their second attempt. It is more prudent to take admissions in colleges /universities other than NITs, IIITs or GFTIs. That way you won't waste one whole year. However, if you are strong-minded about the reattempt and willing to work very hard, you may also choose to do so.

Question: Can I ask for revaluation of the result of JEE Main 2020?

Answer:

No, you cannot ask for revaluation. This is a computer-based test hence chances of malpractices are less and NTA does not entertain revaluation.

Question: I think I should have got more marks when I check the answer key but my result shows a lower percentile? Can I get clarity on this?

Answer:

Actually, NTA will release your marks and percentile. To know the calculation behind it, you will require statistics on how many students attempted the test along with you which NTA does not release. So chances of clarity on this is practically nil.

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7 Views

sir right now I am in 12th I want to do mining geology further will you tell me which College in Maharashtra in best for it ( government college )n shall I get a admission in government college in Maharashtra on the basis of mhcet score because Im not giving jee exam

Saurabh 23rd Nov, 2019
Yes, you can get admission in engineering college through MHT CET which is held technical department of Maharashtra government.
You can get the list of top mining college in
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Reasoning is also comes in JEE Mains With PCM or Only PCM comes??

Aditi Amrendra Student Expert 22nd Nov, 2019
Hello,



Jee mains is a computer based test with su jevt including Physics, Chemistry, and Mathematics.
75 (Each subject will have 25 questions) will be asked in the exam.20 Objective questions having 4 options each with only 1 correct option
5 Numerical questions with numerical value as answer.Although mathematical Reasoning is a topic covered under the syllabus of JEE-Mains only,

https://engineering.careers360.com/articles/jee-main-exam-pattern


I hope this helps.
6 Views

please Hindi note for jee main

sarthak goel 22nd Nov, 2019

Hello Rajesh,

JEE main is a national level exam for admission to IITs, NITs, CFTI, IIIT etc.

Therefore, it is available in several languages including hindi and english. For Hindi notes you may consider the coaching material of any reputed coaching centre, and ask them for JEE main notes in Hindi language. Top coaching centres have multilingual course materials.

As such I should not take name of any institute, but all top 5 JEE coaching institutes offer coaching course materials in Hindi as well as English.

You may also search on internet about JEE Coaching material in Hindi, or see hindi videos on YouTube regarding same.

Hope this helps.

Regards

22 Views

BEST COLLEGES OR INSTITUTES IN INDIA FOR AEROSPACE WHICH CAN BE GET BY JEE MAINS

Shagufa Zareen Student Expert 22nd Nov, 2019
Hello Aspirant,

I am providing you the link here you will find all the names of the college in which Btech in aerospace is there. You can choose according to your preference.

https://engineering.careers360.com/colleges/list-of-aerospace-engineering-colleges-in-india

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How much minimum marks I will have to score in jee main 2020 (obc candidate) (other state) to get admission in NIT srinagar Or any Nit college?

ÑÍthesh 22nd Nov, 2019
Hello Vishal!!
Jee mains cutoff 2020 to get admission in NITs for OBC category is expected to be around 75.
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-nit-srinagar/amp?espv=1
And.. Check the above link,to know about the cutoffs in NIT Srinagar.
Hope this would help you a little bit. Thank you!!
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