JEE Main 2025 Normalization: How scores are calculated?

JEE Main 2025 Normalization: How scores are calculated?

Edited By Gandubilli Unnati | Updated on Sep 02, 2024 04:01 PM IST | #JEE Main

JEE Main 2025 Normalization: How scores are calculated? -With JEE Main being a computer-based test held in multiple sessions, candidates are often confused about the JEE Main 2025 normalization process and the process through which scores are calculated to arrive at the ranks. The National Testing Agency (NTA), under whose aegis the exam will be conducted, announces the relevant information regarding normalization of JEE Main and how the scores and ranks will be calculated. Other important factors like preparation of the rank list, inter-se-merit guidelines have also been announced. Given below is the JEE Main 2025 Normalization process; how scores are calculated to allot the ranks to candidates of various shifts.
Since JEE Main 2025 will be conducted in different sessions & different dates, the question of maintaining equivalence among the different sets of question papers comes. It is likely that some candidates got a tough paper while some may find theirs easy. To ensure that no candidate is at a loss, or even benefits from this, normalisation in JEE Mains will be done for the purpose of ranking. NTA will rank students on the basis of their percentile scores which will be calculated according to a pre-determined formula.

JEE Main 2025 Normalization: How scores are calculated?
JEE Main 2025 Normalization: How scores are calculated?

What is JEE Main Percentile Score?

NTA JEE Main 2025 Percentile scores are based on the relative performance of all those candidates who appeared for the examination. It is obtained after transforming the scores into a scale ranging from 100 to 0 for each session of examinees. Percentile score shows the percentage of candidates who scored equal to or below a particular percentile in an exam. It is the normalized score and not the raw score. After normalization, each topper of a session will get the same percentile of 100 which is the desirable one. Also, the marks between the lowest and highest JEE Main scores are also converted to the respective percentiles.

How will the JEE Main 2025 scores for Paper 1 be calculated?

The formula to be used for JEE Main normalisation procedure is:

Formula - (100 x number of candidates appeared in the session with raw score equal to or less than the candidate) / total number of candidates appeared in that session

Note: To avoid bunching effect and reduce tie breaking, the JEE Main percentile scores will be calculated up to 7 decimal places.

What is normalisation in JEE Mains 2025?

Normalisation in JEE Mains 2025 is a procedure implemented to ensure fairness and equity in evaluating the performance of students across different shifts or sessions of the exam. Since JEE Main is conducted over multiple shifts to accommodate a large number of candidates, the difficulty level of the question papers may vary slightly between different shifts. JEE Main normalisation procedure helps account for these variations and ensures that no candidate is unfairly advantaged or disadvantaged due to the difficulty level of their particular shift.

The JEE Main normalisation procedure takes into consideration the principle that the overall ability of a candidate remains constant, regardless of the shift's difficulty level. It aims to create a level playing field for all candidates, regardless of the specific set of questions they face.

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What will be the Highest Raw Score and Percentile Score in JEE Main 2025?

Since the calculation is session wise, all the highest raw scores will have a JEE Main normalisation procedure based on percentile score of 100 for their respective sessions.

How to calculate JEE Main Percentile Score?

Let's take a look at how the JEE Main percentile is calculated. The JEE Main percentile score will be calculated using the following percentile formula:

Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) equal or less than the candidate)/(Total number of candidates who appeared in that session)

Preparation of JEE Main 2025 Result for each session

Step 1: Raw Scores Preparation

The marks obtained by each candidate in JEE Main eac session 2025 for all correct answers in each subject (Maths, Physics and Chemistry) shall be summed up to arrive at the raw scores.

Step 2: Preparation of JEE Main Percentile Scores for each of the subject and total percentile score

Total Percentile (T1P):

(100 x No. of candidates from the session with raw score equal to or less than T1 score) / Total No. of candidates appeared in the session

Mathematics Percentile (M1P)

(100 x No. of candidates appeared from the session with raw score equal to or less than than M1 score in Mathematics)

/ Total No. of candidates appeared in the session

Physics Percentile (P1P)

(100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session

Chemistry Percentile (C1P):

(100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session

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Inter-se-merit to resolve tie:

When two or more candidates obtain equal percentile, then ranking will be as follows

  • Candidates who obtain Percentile Score in Mathematics will be ranked higher

  • Candidates who obtain Percentile Score in Physics will be ranked higher

  • Candidates who obtain Percentile Score in Chemistry will be ranked higher

  • Date of Birth – the older candidate will be ranked higher

  • In case the tie is still unresolved, the same rank will be given to the candidates

JEE Main 2025 Rank list

The authorities shall release the final JEE Main rank list 2025 after conclusion of both the sessions of the exam. This JEE Main normalisation procedure is considered to create the final merit list. This shall be used for admissions into JEE Main participating institutes.

First attempt compilation of NTA Scores:

After the conclusion of JEE Main January 2025 session, JEE Mains results will be displayed with the four NTA scores – for each of the three subjects (Mathematics, Physics, and Chemistry) and the total NTA score for that attempt. JEE Main NTA scores will be the percentile scores calculated as mentioned above.

Second attempt compilation of NTA Scores:

Similar to the January attempt, the result of the JEE Main 2025 April session will be declared after that. The JEE Main 2025 scores will be calculated for the total and that of the three subjects individually as mentioned for the first attempt.

Compilation of NTA Score for JEE Main Result and Merit List/ Ranking for Paper 1

The ranking or merit list for JEE Main 2025 will be compiled as follows

  • In case of candidates who will appear for both the attempts the best of the two NTA JEE Main scores will be used. Here the total NTA score will be used for ranking purpose and not those of the subjects.

  • In case of candidates who will appear for only one exam, the four JEE Main 2025 NTA scores of that attempt will be used for the preparation of the merit list

The final NTA scores will be used to rank the candidates and for the declaration of the JEE Main 2025 result. In case of any tie, the inter-se-merit guidelines mentioned above in this article will be used to resolve it.

JEE Main 2025 Rank Declaration:

  • The ranks derived through the method explained above will be used for the purpose of admissions to NITs, IIITs and GFTIs.

  • The JEE Main 2025 All India rank and All India Category Rank will be declared once the NTA scores are compiled by the authorities for April session.

How will the JEE Main 2025 scores for Paper 2 be calculated?

  • Raw marks for the first attempt will be announced in February 2025 for students who appeared for the exam held in January.

  • The actual marks for the April exam will be announced soon after the conclusion of exam.

  • The JEE Main Paper 2 marks will not be normalized as the exam was held in a single shift so there will be no question of equivalence of the question papers and variation in difficulty levels

Rank List preparation for JEE Main 2025 Paper II

  • The raw marks for both attempts will be considered for candidates who will give both the attempts and the better of the marks considered.

  • For candidates who appeared for only one attempt, the raw marks obtained for the same will be used for preparing JEE Main rank list.

  • The NTA JEE Main 2025 Rank lists will be prepared as per the marks obtained as mentioned above

Inter-se-Merit will be resolved as follows:

  • Candidates who scores more marks in Aptitude Test will be ranked higher
  • In case the tie is unresolved, Candidates who scores more marks in Drawing Test will be given the higher rank
  • Lastly the age of the candidates i.e. the older candidate will be awarded the higher rank
  • If the tie is still unresolved, the candidates will be given the same rank

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Questions related to JEE Main

Have a question related to JEE Main ?


As an outstate candidate from West Bengal with a JEE Main rank of 530000, your chances of getting admission to PMEC, Berhampur under the All India Quota are low for core branches like CSE or ECE, but you may still be considered for lower-demand branches in later rounds or spot counselling. It’s advisable to apply and keep checking for seat availability during the counselling rounds.


Hello

  • Not eligible for the general quota at VIT Pune with 62 percentile.

  • You could explore management quota (but fees will be steep).

  • Consider improving your score and reattempting JEE, or apply to other colleges with lower cutoffs.

Hello ,

As per your mentioned query , yes you can get admission without giving MHT CET and jee mains exam. There are numerous colleges that provides you direct admission on the basis of your class 12th marks. And also some colleges have their own entrance exams for the admission. Colleges like SRM University , VIT Vellore , MIT Manipal , KIIT University , Shiv Nadar University have their own entrance exams they can give admission without jee mains score.

You can also refer this for more details

https://engineering.careers360.com/articles/best-engineering-colleges-in-india-without-jee-main

Revert for further query!

With a JEE Main rank of 145213 under the general category your chances of getting admission at College of Technology Pantnagar are very slim compared to required cutoffs In 2024 for Outside Home State general category the closing rank for Computer Engineering at Pantnagar was 74526 and for Information Technology it was 70441 This means your rank is almost double the closing cutoffs for these branches As pantnagar follows JEE Main counselling through UTU your rank will likely not fetch a seat in top branches like CSE IT or ECE You could consider looking at less preferred branches or applying under Home State quota if you are domiciled in Uttarakhand but if you are from another state your chances remain low To improve your admission prospects you may explore other colleges with higher closing ranks or consider retaking JEE Main for a better rank

With 86 percentile in JEE Mains, you can get AI branch in these Pune colleges:

1. Ajeenkya DY Patil University – High chance

2. MMCOE (Marathwada Mitra Mandal COE) – Moderate chance

3. PES Modern COE (MCOE) – Borderline chance

4. PVGCOET – Moderate chance

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