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JEE Main 2025 Normalization: How scores are calculated? -With JEE Main being a computer-based test held in multiple sessions, candidates are often confused about the JEE Main 2025 normalization process and the process through which scores are calculated to arrive at the ranks. The National Testing Agency (NTA), under whose aegis the exam will be conducted, announces the relevant information regarding normalization of JEE Main and how the scores and ranks will be calculated. Other important factors like preparation of the rank list, inter-se-merit guidelines have also been announced. Given below is the JEE Main 2025 Normalization process; how scores are calculated to allot the ranks to candidates of various shifts.
Since JEE Main 2025 will be conducted in different sessions & different dates, the question of maintaining equivalence among the different sets of question papers comes. It is likely that some candidates got a tough paper while some may find theirs easy. To ensure that no candidate is at a loss, or even benefits from this, normalisation in JEE Mains will be done for the purpose of ranking. NTA will rank students on the basis of their percentile scores which will be calculated according to a pre-determined formula.
The JEE Main 2026 eligibility criteria are as follows.
Age limit | No age limit |
Academic eligibility | Class 12 or equivalent level |
Year of the qualifying exam | 2024/ 2025 / 2026 |
Limit of attempts | Three consecutive years |
Class 12th subjects |
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Required 12th class percentage |
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NTA JEE Main 2025 Percentile scores are based on the relative performance of all those candidates who appeared for the examination. It is obtained after transforming the scores into a scale ranging from 100 to 0 for each session of examinees. Percentile score shows the percentage of candidates who scored equal to or below a particular percentile in an exam. It is the normalized score and not the raw score. After normalization, each topper of a session will get the same percentile of 100 which is the desirable one. Also, the marks between the lowest and highest JEE Main scores are also converted to the respective percentiles.
The formula to be used for JEE Main normalisation procedure is:
Formula - (100 x number of candidates appeared in the session with raw score equal to or less than the candidate) / total number of candidates appeared in that session
Note: To avoid bunching effect and reduce tie breaking, the JEE Main percentile scores will be calculated up to 7 decimal places.
Normalisation in JEE Mains 2025 is a procedure implemented to ensure fairness and equity in evaluating the performance of students across different shifts or sessions of the exam. Since JEE Main is conducted over multiple shifts to accommodate a large number of candidates, the difficulty level of the question papers may vary slightly between different shifts. JEE Main normalisation procedure helps account for these variations and ensures that no candidate is unfairly advantaged or disadvantaged due to the difficulty level of their particular shift.
The JEE Main normalisation procedure takes into consideration the principle that the overall ability of a candidate remains constant, regardless of the shift's difficulty level. It aims to create a level playing field for all candidates, regardless of the specific set of questions they face.
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Since the calculation is session wise, all the highest raw scores will have a JEE Main normalisation procedure based on percentile score of 100 for their respective sessions.
How to calculate JEE Main Percentile Score?
Let's take a look at how the JEE Main percentile is calculated. The JEE Main percentile score will be calculated using the following percentile formula:
Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) equal or less than the candidate)/(Total number of candidates who appeared in that session)
Step 1: Raw Scores Preparation
The marks obtained by each candidate in JEE Main eac session 2025 for all correct answers in each subject (Maths, Physics and Chemistry) shall be summed up to arrive at the raw scores.
Step 2: Preparation of JEE Main Percentile Scores for each of the subject and total percentile score
Total Percentile (T1P): | (100 x No. of candidates from the session with raw score equal to or less than T1 score) / Total No. of candidates appeared in the session | |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates appeared in the session | |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session | |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session |
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Inter-se-merit to resolve tie:
When two or more candidates obtain equal percentile, then ranking will be as follows
Candidates who obtain Percentile Score in Mathematics will be ranked higher
Candidates who obtain Percentile Score in Physics will be ranked higher
Candidates who obtain Percentile Score in Chemistry will be ranked higher
Date of Birth – the older candidate will be ranked higher
JEE Main 2025 Rank list
The authorities shall release the final JEE Main rank list 2025 after conclusion of both the sessions of the exam. This JEE Main normalisation procedure is considered to create the final merit list. This shall be used for admissions into JEE Main participating institutes.
First attempt compilation of NTA Scores:
After the conclusion of JEE Main January 2025 session, JEE Mains results will be displayed with the four NTA scores – for each of the three subjects (Mathematics, Physics, and Chemistry) and the total NTA score for that attempt. JEE Main NTA scores will be the percentile scores calculated as mentioned above.
Second attempt compilation of NTA Scores:
Similar to the January attempt, the result of the JEE Main 2025 April session will be declared after that. The JEE Main 2025 scores will be calculated for the total and that of the three subjects individually as mentioned for the first attempt.
Compilation of NTA Score for JEE Main Result and Merit List/ Ranking for Paper 1
The ranking or merit list for JEE Main 2025 will be compiled as follows
In case of candidates who will appear for both the attempts the best of the two NTA JEE Main scores will be used. Here the total NTA score will be used for ranking purpose and not those of the subjects.
In case of candidates who will appear for only one exam, the four JEE Main 2025 NTA scores of that attempt will be used for the preparation of the merit list
The final NTA scores will be used to rank the candidates and for the declaration of the JEE Main 2025 result. In case of any tie, the inter-se-merit guidelines mentioned above in this article will be used to resolve it.
JEE Main 2025 Rank Declaration:
The ranks derived through the method explained above will be used for the purpose of admissions to NITs, IIITs and GFTIs.
The JEE Main 2025 All India rank and All India Category Rank will be declared once the NTA scores are compiled by the authorities for April session.
How will the JEE Main 2025 scores for Paper 2 be calculated?
Raw marks for the first attempt will be announced in February 2025 for students who appeared for the exam held in January.
The actual marks for the April exam will be announced soon after the conclusion of exam.
The JEE Main Paper 2 marks will not be normalized as the exam was held in a single shift so there will be no question of equivalence of the question papers and variation in difficulty levels
Rank List preparation for JEE Main 2025 Paper II
The raw marks for both attempts will be considered for candidates who will give both the attempts and the better of the marks considered.
For candidates who appeared for only one attempt, the raw marks obtained for the same will be used for preparing JEE Main rank list.
The NTA JEE Main 2025 Rank lists will be prepared as per the marks obtained as mentioned above
Inter-se-Merit will be resolved as follows:
On Question asked by student community
Hello,
You can get the JEE 2025 Syllabus from this link : JEE Main Class 12th Syllabus 2026
Hope it helps !
Hello,
You cannot "renew" your September 2025 certificate. You must apply for a completely new EWS certificate after April 1, 2026.
EWS certificates are linked to a specific financial year.
Your certificate issued in September 2025 is valid for the financial year 2025-26. It is based on your family's income from the previous financial year (i.e., 2024-25).
The certificate required for JEE counselling in mid-2026 must be valid for the financial year 2026-27. This certificate must be based on your family's income from the financial year 2025-26 and must be issued on or after April 1, 2026.
Since they are based on two different income periods, they are considered completely different documents.
Hope it's helpful to you.
Hi! Don’t worry, you can correct your category this year while filling out the JEE Main 2025 application form. If you belong to BC/OBC category and have the valid caste certificate, you can apply under OBC NCL now. It will not be a problem if last year you had applied as General/EWS, since each year’s application is considered separately.
OBC NCL is for candidates from socially and educationally backward communities (non creamy layer) with income below 8 lakh, while EWS is for students from the general category (not SC/ST/OBC) with family income below 8 lakh. Since your family income is less than 2 lakh and you are BC, applying under OBC NCL is the right choice and will give you reservation benefits.
Hello,
To get below AIR 100 in JEE Advanced 2027, you need a strong and focused plan. Here’s a simple guide:
Clear Concepts : Make sure all NCERT basics are strong. Focus on Physics, Chemistry, and Maths concepts deeply.
Advanced Practice : Solve previous years’ JEE Advanced papers and high-level questions from books like HC Verma, I.E. Irodov, OP Tandon, and Cengage.
Regular Mock Tests : Take full-length tests every week. Analyse mistakes and improve weak areas.
Time Management : Learn to solve questions quickly and accurately. Work on speed and accuracy together.
Short Notes : Make notes/formulas for quick revision.
Consistency : Study daily and avoid long breaks. Consistent practice is key.
Focus on Weak Areas : Identify topics you struggle with and spend extra time on them.
Stress Management : Stay healthy, sleep well, and avoid last-minute panic.
If you follow a structured plan and stay consistent, AIR below 100 is achievable.
Hope it helps !
Helloaspirant,
The JEE Main 2026 syllabus, which is broken down into Physics, Chemistry, and Mathematics, is based on the NCERT curriculum for Classes 11 and 12. Calculus, Algebra, and Coordinate Geometry in Mathematics; Organic, Inorganic, and Physical Chemistry; and Mechanics, Thermodynamics, and Optics in Physics are important subjects.
To know the syllabus, you can visit our site through following link:
https://engineering.careers360.com/articles/jee-main-syllabus
Thank you
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