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JEE Mains Marks vs Rank 2025: Candidates can check the JEE Mains 2025 marks vs rank in this article. To secure a rank between 1 to 2000, candidates need to score marks of 200+ in the JEE Mains 2025. Candidates who score a total of 300 marks in the exam will land a top rank from 1 to 5. Examinees can calculate their accurate marks and rank using careers360’s JEE Main 2025 rank predictor. Candidates can also check the JEE Main 2025 marks vs rank vs percentile online. The authority conducted the JEE Main entrance exam in online mode.
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The formula to be used to calculate the Jee mains marks vs rank 2025 category wise is to divide the number of scores below your score by the total number of scores, and then multiply by 100. Normalization in JEE Main 2025 is a process used to ensure fairness and consistency in evaluating student performance across different exam shifts or sessions. Since the difficulty level may vary between sessions, the National Testing Agency (NTA) releases the JEE Main 2025 results as percentile scores instead of raw marks. Read more details in the article given below on Jee mains marks vs rank 2025.
Candidates can check the JEE Mains 2025 Marks vs Rank in the table below.
Marks | JEE Main Rank |
|---|---|
300 | 1-5 |
270-279 | 50-20 |
260-269 | 101-53 |
240-259 | 399-105 |
219-239 | 975-400 |
200 -217 | 2001 — 971 |
180-199 | 3909 - 2001 |
159-179 | 7001 - 3905 |
140-157 | 12190 - 7010 |
121-138 | 21010 -12205 |
101 -119 | 35010 - 21003 |
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Candidates can calculate their JEE Main percentile rank using a simple formula: (Number of candidates with scores below yours ÷ Total number of candidates) × 100.
The authority has released the JEE Mains 2025 cutoff after the result. Candidates can check the JEE Mains 2025 marks vs rank cutoff in the table below.
Category/Year | General | OBC | SC | ST |
|---|---|---|---|---|
2025 | 93.1023262 | 79.4313582 | 61.1526933 | 47.9026465 |
2024 | 93.2362181 | 79.6757881 | 60.0923182 | 46.6975840 |
2023 | 90.7788642 | 73.6114227 | 51.9776027 | 37.2348772 |
2022 | 88.4121383 | 67.0090297 | 43.0820954 | 26.7771328 |
Difficulty level of the exam
Total number of registered candidates
Overall performance of the candidates
Number of questions in the paper
Previous years’ JEE Main Marks vs Rank data.
If two candidates have the same percentile score, the NTA will resolve the tie using the following criteria:
Applicants who attained a greater score in the Mathematics in the percentile will receive a better rank.
In case a tie still prevails, a candidate with higher Percentile Score in Physics will be ranked better.
In case there is a tie still, the candidate with a better score on Percentile in Chemistry will be ranked higher.
In case there is still a tie, then those who are older in age will be preferred over the rest.
On Question asked by student community
Hello Aspirant,
With 79% in JEE main getting CSE in top Pune college through MHT CET CAP rounds maybe difficult specially in Institute like COEP Pune, VIT Pune, PCCOE, and PICT, where CSC cut off are usually much higher.
However, you may have a chance in some private colleges during
you have a good chance of securing admission in many private institutions through the regular admission process. You do not need to pay any donation if you meet the eligibility criteria and seats are available.
Cutoffs vary from one institution to another and depend
Hey there,
While JEE Mains score definitely provides the knowledge-base and skills to secure a government job, the minimum educational qualification still remains as a degree. Therefore, after completing your BTech or other degree, please look into PSU recruitments such as ISRO, DRDO, BARC, Indian Railways. There are also GATE-entry
Based on the information you provided, y our chances are good , but CSE at MBM University is not guaranteed .
Here's why:
MBM University is the most sought-after government engineering college in Rajasthan through REAP, and CSE is its most competitive branch.
A 94.4 percentile is within the range
Hello Student,
Can you please specify your exact or percentile for us to help you out with the answer?
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