Amity University-Noida B.Tech Admissions 2026
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
JEE Mains Marks vs Rank 2025: Candidates can check the JEE Mains 2025 marks vs rank in this article. To secure a rank between 1 to 2000, candidates need to score marks of 200+ in the JEE Mains 2025. Candidates who score a total of 300 marks in the exam will land a top rank from 1 to 5. Examinees can calculate their accurate marks and rank using careers360’s JEE Main 2025 rank predictor. Candidates can also check the JEE Main 2025 marks vs rank vs percentile online. The authority conducted the JEE Main entrance exam in online mode.
This Story also Contains
The formula to be used to calculate the Jee mains marks vs rank 2025 category wise is to divide the number of scores below your score by the total number of scores, and then multiply by 100. Normalization in JEE Main 2025 is a process used to ensure fairness and consistency in evaluating student performance across different exam shifts or sessions. Since the difficulty level may vary between sessions, the National Testing Agency (NTA) releases the JEE Main 2025 results as percentile scores instead of raw marks. Read more details in the article given below on Jee mains marks vs rank 2025.
Candidates can check the JEE Mains 2025 Marks vs Rank in the table below.
Marks | JEE Main Rank |
|---|---|
300 | 1-5 |
270-279 | 50-20 |
260-269 | 101-53 |
240-259 | 399-105 |
219-239 | 975-400 |
200 -217 | 2001 — 971 |
180-199 | 3909 - 2001 |
159-179 | 7001 - 3905 |
140-157 | 12190 - 7010 |
121-138 | 21010 -12205 |
101 -119 | 35010 - 21003 |
Candidates can calculate their JEE Main percentile rank using a simple formula: (Number of candidates with scores below yours ÷ Total number of candidates) × 100.
The authority has released the JEE Mains 2025 cutoff after the result. Candidates can check the JEE Mains 2025 marks vs rank cutoff in the table below.
Category/Year | General | OBC | SC | ST |
|---|---|---|---|---|
2025 | 93.1023262 | 79.4313582 | 61.1526933 | 47.9026465 |
2024 | 93.2362181 | 79.6757881 | 60.0923182 | 46.6975840 |
2023 | 90.7788642 | 73.6114227 | 51.9776027 | 37.2348772 |
2022 | 88.4121383 | 67.0090297 | 43.0820954 | 26.7771328 |
Difficulty level of the exam
Total number of registered candidates
Overall performance of the candidates
Number of questions in the paper
Previous years’ JEE Main Marks vs Rank data.
If two candidates have the same percentile score, the NTA will resolve the tie using the following criteria:
Applicants who attained a greater score in the Mathematics in the percentile will receive a better rank.
In case a tie still prevails, a candidate with higher Percentile Score in Physics will be ranked better.
In case there is a tie still, the candidate with a better score on Percentile in Chemistry will be ranked higher.
In case there is still a tie, then those who are older in age will be preferred over the rest.
On Question asked by student community
Hello,
Yes, you can be eligible , but it depends on how you passed Mathematics.
JEE Main
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics was passed as a full subject from NIOS.
NIOS is a recognized board.
Having two marksheets is allowed.
You are not eligible if:
Mathematics was taken only as an improvement or additional without passing it as a full subject.
MHT-CET
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics from NIOS is shown as a passed subject.
NIOS is recognized for Maharashtra admissions.
Mathematics was passed before the admission year.
You are not eligible if:
Mathematics is not shown as a passed subject.
Important
Mathematics must be a separate and passed subject.
Keep both marksheets during counselling.
Always check the current year information brochure before applying.
Hope it helps !
The marks needed for a 99+ percentile in the JEE Main January attempt depend on the difficulty of the paper and the total number of candidates. Generally, you need roughly *180–200* marks out of 300 to hit the 99+ percentile. The exact cutoff varies each session, so checking the official NTA percentile score calculator or previous year cutoffs gives a more precise idea.
Hello aspirant
JEE Main accepts NIOS, so you can appear if you meet the basic eligibility.
BITS does not accept marks from two different boards, so this option won’t work for BITS.
VIT and SRM generally accept NIOS, but having two separate mark sheets can be an issue. You should check their official eligibility rules before applying.
Thankyou I hope this help
Hello,
The
NCHM JEE 2026 registration
is expected to
start in the second week of December 2025
.
The application form will be available online.
The last date to apply will likely be
February or March 2026
.
The exact dates will be announced in the official notification.
Hope it helps !
Hello,
Here are some Government colleges that generally do not require 75% CBSE board criteria for admission through JEE mains based or university counselling.
I hope it will help you. Kindly check the latest eligibility rules for the specific year.
Thank you.
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
100% Placement Record | Highest CTC 54 LPA | NAAC A++ Accredited | Ranked #62 in India by NIRF Ranking 2025 | JEE & JET Scores Accepted
National level exam conducted by VIT University, Vellore | Ranked #16 by NIRF for Engg. | NAAC A++ Accredited
NAAC A+ & NBA Accredited | QS I-Gauge Gold rated University | Highest CTC 52 LPA | 300+ Companies | Avail Scholarships Application Deadline: 28th Feb’26
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships