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JEE Mains Marks vs Rank 2025: Candidates can check the JEE Mains 2025 marks vs rank in this article. To secure a rank between 1 to 2000, candidates need to score marks of 200+ in the JEE Mains 2025. Candidates who score a total of 300 marks in the exam will land a top rank from 1 to 5. Examinees can calculate their accurate marks and rank using careers360’s JEE Main 2025 rank predictor. Candidates can also check the JEE Main 2025 marks vs rank vs percentile online. The authority conducted the JEE Main entrance exam in online mode.
The last three years’ closing ranks of all NITs for CSE courses are given below.
NIT JEE Mains cut-off | 2025 | 2024 | 2023 | |||
Institute | Opening Rank | Closing Rank | Opening Rank | Closing Rank | Opening Rank | Closing Rank |
NIT Tiruchirappalli | 659 | 1449 | 299 | 1224 | 176 | 1509 |
NIT Karnataka, Surathkal | 1191 | 1827 | 14 | 1615 | 966 | 1984 |
NIT Warangal | 1521 | 2409 | 1043 | 2186 | 889 | 2413 |
NIT Rourkela | 2442 | 3431 | 591 | 2940 | 2529 | 3786 |
Motilal Nehru National Institute of Technology Allahabad | 2730 | 4594 | 2417 | 4191 | 2758 | 4777 |
NIT Calicut | 3651 | 5222 | 2614 | 4482 | 2483 | 5256 |
Malaviya National Institute of Technology Jaipur | 3027 | 5601 | 1501 | 4711 | 2684 | 4909 |
Visvesvaraya National Institute of Technology, Nagpur | 4442 | 6359 | 4555 | 5795 | 4920 | 7087 |
NIT Kurukshetra | 5180 | 7037 | 4472 | 6000 | – | – |
NIT Delhi | 2363 | 7651 | 2438 | 8018 | 4278 | 9930 |
Sardar Vallabhbhai National Institute of Technology, Surat | 6343 | 8130 | 5587 | 7113 | 5052 | 7741 |
NIT Jamshedpur | 6378 | 8902 | 4935 | 7944 | 3260 | 9204 |
Maulana Azad National Institute of Technology Bhopal | 5942 | 9249 | 6217 | 8830 | 6409 | 9370 |
NIT Durgapur | 6565 | 9836 | 5973 | 8765 | 6848 | 10070 |
Dr. B R Ambedkar National Institute of Technology, Jalandhar | 7991 | 11262 | 6330 | 10957 | 9028 | 11017 |
NIT Hamirpur | 9637 | 12586 | 8376 | 12236 | 9929 | 12426 |
NIT Silchar | 8010 | 12665 | 5736 | 11930 | 8606 | 12818 |
NIT Raipur | 8140 | 13559 | 10323 | 13177 | 10110 | 12773 |
NIT Goa | 10279 | 13640 | 7914 | 12511 | 8584 | 12604 |
NIT Patna | 10529 | 14996 | 9288 | 14442 | 8125 | 13964 |
Indian Institute of Engineering Science and Technology, Shibpur | 13917 | 16765 | 6068 | 14635 | 8043 | 13711 |
NIT Andhra Pradesh | 11739 | 18183 | 10309 | 18548 | 11839 | 17272 |
NIT Uttarakhand | 16359 | 18491 | 14598 | 18039 | 14432 | 18447 |
NIT Puducherry | 11429 | 19758 | 6318 | 18515 | 12546 | 17305 |
NIT Agartala | 13104 | 22013 | 8121 | 20298 | 14010 | 20102 |
NIT Meghalaya | 20712 | 24074 | 14656 | 20039 | 15911 | 19175 |
NIT Srinagar | 15080 | 26171 | 12751 | 21839 | 12931 | 22814 |
NIT Sikkim | 15389 | 26616 | 23245 | 28284 | 19566 | 24093 |
NIT Arunachal Pradesh | 27500 | 30607 | 22046 | 28514 | 25273 | 29087 |
NIT Manipur | 26617 | 33098 | 15616 | 30611 | 17658 | 29644 |
NIT Mizoram | 35504 | 37751 | 31598 | 33181 | 28938 | 31336 |
NIT Nagaland | 32717 | 39594 | 22429 | 31391 | 24324 | |
JEE Main 2026: NIT Tiruchirappalli, Surathkal, Warangal retain highest BTech cut-offs among NITs
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The formula to be used to calculate the Jee mains marks vs rank 2025 category wise is to divide the number of scores below your score by the total number of scores, and then multiply by 100. Normalization in JEE Main 2025 is a process used to ensure fairness and consistency in evaluating student performance across different exam shifts or sessions. Since the difficulty level may vary between sessions, the National Testing Agency (NTA) releases the JEE Main 2025 results as percentile scores instead of raw marks. Read more details in the article given below on Jee mains marks vs rank 2025.
Candidates can check the JEE Mains 2025 Marks vs Rank in the table below.
Marks | JEE Main Rank |
|---|---|
300 | 1-5 |
270-279 | 50-20 |
260-269 | 101-53 |
240-259 | 399-105 |
219-239 | 975-400 |
200 -217 | 2001 — 971 |
180-199 | 3909 - 2001 |
159-179 | 7001 - 3905 |
140-157 | 12190 - 7010 |
121-138 | 21010 -12205 |
101 -119 | 35010 - 21003 |
Candidates can calculate their JEE Main percentile rank using a simple formula: (Number of candidates with scores below yours ÷ Total number of candidates) × 100.
The authority has released the JEE Mains 2025 cutoff after the result. Candidates can check the JEE Mains 2025 marks vs rank cutoff in the table below.
Category/Year | General | OBC | SC | ST |
|---|---|---|---|---|
2025 | 93.1023262 | 79.4313582 | 61.1526933 | 47.9026465 |
2024 | 93.2362181 | 79.6757881 | 60.0923182 | 46.6975840 |
2023 | 90.7788642 | 73.6114227 | 51.9776027 | 37.2348772 |
2022 | 88.4121383 | 67.0090297 | 43.0820954 | 26.7771328 |
Difficulty level of the exam
Total number of registered candidates
Overall performance of the candidates
Number of questions in the paper
Previous years’ JEE Main Marks vs Rank data.
If two candidates have the same percentile score, the NTA will resolve the tie using the following criteria:
Applicants who attained a greater score in the Mathematics in the percentile will receive a better rank.
In case a tie still prevails, a candidate with higher Percentile Score in Physics will be ranked better.
In case there is a tie still, the candidate with a better score on Percentile in Chemistry will be ranked higher.
In case there is still a tie, then those who are older in age will be preferred over the rest.
On Question asked by student community
Hello,
Yes, attendance is compulsory in Class XI and XII.
As per school and board rules, students must maintain minimum attendance, usually around 75%. Schools can stop students from appearing in board exams if attendance is short.
Even if a student is preparing for JEE or any other competitive exam
Hello,
You can find here the direct links to download the JEE Main last 10 years PYQ PDFs from the Official Careers360 website.
Kindly visit this link to access the question papers : Last 10 Years JEE Main Question Papers with Solutions PDF
Hope it helps !
Hello Harika,
Firstly, you cannot prepare for JEE in 8 days if you havent studied before. But still, You can try solving the previous year question papers. Here's a Link for the same
HELLO,
If you are from General category with 57 percent in 12th then to appear for JEE Advanced you need to be in top percentile of your board as the eligibility for JEE advanced you need at least 75 percent in 12th or in the top 20 percentile of your
Hello aspirant,
The JEE Main 2026 admission card will include information about the exam location. On the other hand, students can use the JEE Main 2026 city notification slip, which was made available on January 8, 2026, to check the exam city beforehand. The second week of January 2026 is
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