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JEE Mains Marks vs Rank 2025: Candidates can check the JEE Mains 2025 marks vs rank in this article. To secure a rank between 1 to 2000, candidates need to score marks of 200+ in the JEE Mains 2025. Candidates who score a total of 300 marks in the exam will land a top rank from 1 to 5. Examinees can calculate their accurate marks and rank using careers360’s JEE Main 2025 rank predictor. Candidates can also check the JEE Main 2025 marks vs rank vs percentile online. The authority conducted the JEE Main entrance exam in online mode.
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The formula to be used to calculate the Jee mains marks vs rank 2025 category wise is to divide the number of scores below your score by the total number of scores, and then multiply by 100. Normalization in JEE Main 2025 is a process used to ensure fairness and consistency in evaluating student performance across different exam shifts or sessions. Since the difficulty level may vary between sessions, the National Testing Agency (NTA) releases the JEE Main 2025 results as percentile scores instead of raw marks. Read more details in the article given below on Jee mains marks vs rank 2025.
Candidates can check the JEE Mains 2025 Marks vs Rank in the table below.
Marks | JEE Main Rank |
|---|---|
300 | 1-5 |
270-279 | 50-20 |
260-269 | 101-53 |
240-259 | 399-105 |
219-239 | 975-400 |
200 -217 | 2001 — 971 |
180-199 | 3909 - 2001 |
159-179 | 7001 - 3905 |
140-157 | 12190 - 7010 |
121-138 | 21010 -12205 |
101 -119 | 35010 - 21003 |
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Candidates can calculate their JEE Main percentile rank using a simple formula: (Number of candidates with scores below yours ÷ Total number of candidates) × 100.
The authority has released the JEE Mains 2025 cutoff after the result. Candidates can check the JEE Mains 2025 marks vs rank cutoff in the table below.
Category/Year | General | OBC | SC | ST |
|---|---|---|---|---|
2025 | 93.1023262 | 79.4313582 | 61.1526933 | 47.9026465 |
2024 | 93.2362181 | 79.6757881 | 60.0923182 | 46.6975840 |
2023 | 90.7788642 | 73.6114227 | 51.9776027 | 37.2348772 |
2022 | 88.4121383 | 67.0090297 | 43.0820954 | 26.7771328 |
Difficulty level of the exam
Total number of registered candidates
Overall performance of the candidates
Number of questions in the paper
Previous years’ JEE Main Marks vs Rank data.
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If two candidates have the same percentile score, the NTA will resolve the tie using the following criteria:
Applicants who attained a greater score in the Mathematics in the percentile will receive a better rank.
In case a tie still prevails, a candidate with higher Percentile Score in Physics will be ranked better.
In case there is a tie still, the candidate with a better score on Percentile in Chemistry will be ranked higher.
In case there is still a tie, then those who are older in age will be preferred over the rest.
On Question asked by student community
Hello Dear Student,
With an 81.69 percentile in Joint Entrance Examination Main, your expected CRL rank may go above 2,00,000 . Because of this, getting a seat in top NITs, IIITs, or GFTIs through JoSAA/CSAB counselling can be quite difficult, especially for popular branches.
However, you still have good options
Hi,
With 72 percentile and ST category, you are eligible for JoSAA counselling and may still have chances in some newer NITs, IIITs, and GFTIs, especially for branches other than highly competitive ones like CSE or AI/ML.
Getting top NITs or CSE-related branches can be difficult at this percentile, but
Hi,
With a Telangana Board normalized score around 982, you may still have a decent chance through Stream 2 admissions, especially if admissions are mainly board-merit based. However, for ECE (CPS), chances will depend on the competition, cutoff trends, and the number of applicants for that branch.
Since your JEE
Hello Dear Student,
You have a good to moderate chance of getting ECE (Cyber Physical Systems) at SASTRA Deemed University.
Since your Telangana Board marks are strong , they will help you a lot in the admission process. Even if your Joint Entrance Examination Main score is low, you can
Hi,
Yes, you can get admission in BTech Fire and Safety even without JEE through direct merit-based admissions or university-level entrance exams. Most colleges usually require PCM in Class 12 with around 50% marks.
Some universities like UPES, GD Goenka University, and GSFC University offer Fire and Safety-related engineering courses
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