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JEE Main 2025 Marks vs Rank - Candidates can check the JEE Main Marks vs Rank data in this article. The JEE Main 2025 marks vs rank indicates the range of marks and their corresponding rank range. Candidates must obtain 270+ marks to secure a high rank in the JEE Main exam. For a 90+ percentile in JEE Main, candidates require 160+ marks. The JEE marks vs rank have been released along with JEE Main scorecards on the official website. The JEE Main 2025 exam for session 2 was held on April 2 to 9, 2025. The National Testing Agency held the JEE Main entrance exam from January 22 to 30, 2025 (session 1). Candidates attempting the JEE Main 2026 exam must be aware of the JEE Main 2025 marks vs rank to be aware of how many marks they should score.
Also Check: JEE Main Percentile Predictor | JEE Main Rank Predictor
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Applicants must note that JEE Main 2025 marks vs rank are indicative. The marks vs ranks of JEE Main 2025 have been compiled by taking students' data from multiple sources. The JEE Main Marks vs Rank will vary each year based on various factors. Hence, candidates should look at the marks vs rank data given below as an indicator of how their performance translates into ranks.
Candidates can check the JEE Main marks vs rank 2025 to know how many marks to obtain for good rank. Moreover, students can also check the JEE Main marks vs percentile vs rank 2025 to know what percentile they will get based on their score in JEE Main. The data given is indicative.
Score out of 300 | Rank |
|---|---|
286- 292 | 19-12 |
280-284 | 42-23 |
268- 279 | 106-64 |
250- 267 | 524-108 |
231-249 | 1385-546 |
215-230 | 2798-1421 |
200-214 | 4667-2863 |
189-199 | 6664- 4830 |
175-188 | 10746-7152 |
160-174 | 16163-11018 |
149-159 | 21145-16495 |
132-148 | 32826-22238 |
120-131 | 43174-33636 |
110-119 | 54293-44115 |
102-109 | 65758-55269 |
95-101 | 76260-66999 |
89-94 | 87219-78111 |
79-88 | 109329-90144 |
62-87 | 169542-92303 |
41-61 | 326517-173239 |
1-40 | 1025009-334080 |
To calculate your percentile rank among your classmates' test scores, you can use the formula: divide the number of scores below your score by the total number of scores, and then multiply by 100. To illustrate, consider that the candidate scored an 88 on the test, and you want to determine your percentile rank among scores ranging from 67 to 95.
The factors typically considered when determining the relationship between JEE Main marks, rank, and percentile include:
Total number of registered candidates
Number of questions in the paper
Difficulty level of the exam
Candidates' overall performance
Trends in previous years' JEE Main marks versus ranks data



Institutes/Seats | NITS | IIITs | GFTIs |
|---|---|---|---|
Number of Institutes | 31 | 25 | 28 |
Total Seats | 24525 | 9940 | 10228 |
Open + Open-PwD | 9876 | 4143 | 4634 |
OBC-NCL + OBC-NCL-PwD | 6381 | 2637 | 2183 |
SC + SC-PwD | 3628 | 1470 | 1504 |
ST + ST-PwD | 2295 | 737 | 874 |
*Based on JoSAA Seat Matrix
The authority will activate the JEE Main rank card download link on the website, jeemain.nta.nic.in. Candidates can download the JEE Main rank card using the application number and date of birth. The rank card of JEE Main 2025 will comprise the marks and the rank secured in the entrance test. Candidates can check the actual rank obtained in the JEE Main exam. Below are the steps to download the JEE Main rank card.
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The authorities released the cutoff for JEE Main 2025 online. JEE Mains cutoff 2025 is the minimum mark required by the candidates to qualify for the exam. The cutoff of JEE Main 2025 will differ for all categories. JEE Main admission cutoff 2025 is the opening and closing ranks within which admission is offered in institutes. The cutoff of IIT JEE Mains for admission is released by JoSAA after each round of counselling.
Candidates can check the opening and closing ranks for admissions into NITs, IIITs, and CFTIs through the JEE Main 2025 Cutoff. Those candidates who manage to secure within the cutoff marks will have a higher chance of admission into the institute. One important thing to note is that the cutoff will differ according to the course and institute selected by the candidates.
Category/Year | General | OBC | SC | ST |
|---|---|---|---|---|
| 2025 | 93.1023262 | 79.4313582 | 61.1526933 | 47.9026465 |
| 2024 | 93.2362181 | 79.6757881 | 60.0923182 | 46.6975840 |
| 2023 | 90.7788642 | 73.6114227 | 51.9776027 | 37.2348772 |
| 2022 | 88.4121383 | 67.0090297 | 43.0820954 | 26.7771328 |
| 2021 | 87.8992241 | 68.0234447 | 46.8825338 | 34.6728999 |
| 2020 | 70.2435518 | 72.8887969 | 50.1760245 | 39.0696101 |
| 2019 | 78.2174869 | 74.3166557 | 54.0128155 | 44.3345172 |
| 2018 | 74 | 45 | 29 | 24 |
| 2017 | 81 | 49 | 32 | 27 |
| 2016 | 100 | 70 | 52 | 48 |
| 2015 | 105 | 70 | 50 | 44 |
| 2014 | 115 | 74 | 53 | 47 |
| 2013 | 113 | 70 | 50 | 45 |
NTA doesn't release any specific JEE Main OBC ranks. The ranks are available as the All India Rank that a candidate achieves after taking the JEE Main exam. Candidates can check the JEE Main AIR ranks to find out which NITs, IIITs, and CFTIs they are eligible for.
Frequently Asked Questions (FAQs)
The formula to calculate JEE Main Rank from Percentile Score is ((100 – P)/100)*N + 1, where p denotes the NTA score, and N denotes the number of students.
JEE Main 2025 percentile of a candidate is prepared by NTA using a formula.
No, AIR and CR are different, AIR is the overall rank obtained by the candidate respective of their category and CR is the rank candidates got in their respective category.
On Question asked by student community
Hello aspirant,
If your syllabus is completed with theory , use the next 30 days only for smart revision . Make short notes and revise formulas daily for Physics , Chemistry and Maths . Solve previous year JEE Main questions topic-wise and then full mock tests every 3-4 days. Analyse mistakes properly and revise weak areas again . Avoid new topics and focus on accuracy , speed and confidence building during revision.
FOR REFERENCE : https://engineering.careers360.com/articles/jee-main-revision-strategy
Hope the details will help you.
THANK YOU
Preparing for the JEE Main in just 30 days is a challenging but achievable task if you follow a highly disciplined and strategic approach. According to the Careers360 30-day study plan , the key is to shift your focus from learning everything to mastering high-weightage topics and practicing rigorously.
During the first 15 days, prioritize topics that frequently appear in the exam.
Physics: Modern Physics, Heat & Thermodynamics, Optics, and Current Electricity.
Chemistry: GOC (General Organic Chemistry), Chemical Bonding, p-Block elements, and Solutions.
Maths: Matrices & Determinants, Sequences & Series, Coordinate Geometry, and Vector & 3D Geometry.
Study Strategy: Use NCERT for Chemistry and simplified notes for Physics/Maths. Spend 3-4 hours on each subject daily.
Short Notes: Go through the short notes you made during the first two weeks.
Flashcards: Use flashcards for inorganic chemistry reactions and physics formulas.
Mock Tests: Start giving one full-length mock test every alternate day. Analyze your mistakes immediately to avoid repeating them.
Previous Year Papers (PYQs): Solve the last 3-5 years of JEE Main papers in the actual exam time slot (9 AM–12 PM or 3 PM–6 PM) to sync your body clock.
No New Topics: Stop picking up new chapters. Focus solely on what you already know to build confidence.
Accuracy over Speed: Focus on getting the questions right rather than attempting all of them, as negative marking can significantly lower your percentile.
You can download the comprehensive day-by-day schedule, which includes specific topics to cover each morning and evening, by visiting the link : https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days
Hello
I think your question sounds like this: "Can a candidate who passed Class 12 in 2025 and filled JEE Main Session 1 apply for Session 2 as 'Appearing' in 2026 as a fresh board candidate, and will both sessions have the same details? "
So yes, you can fill the JEE Main Session 2 as "Appearing". The information filled in Session 1 will remain exactly as it was and will not change.
Session 1 and Session 2 are treated as separate applications. There is no issue if the qualifying status is different in both sessions. During counselling, the board marks that meet the 75 rule will be considered.
Hello,
If you filled the JEE Main January form with Class 12 passed in 2025 and are planning to appear again for the Class 12 exam through HOS, there is usually no serious issue. You were eligible to apply since you had already passed Class 12. Reappearing through HOS for improvement or requalification is allowed, provided HOS is a recognized board. During counselling, your latest valid Class 12 result will be considered. Make sure you meet the 75% marks or top 20 percentile requirement where applicable. If a correction window opens, update details if needed.
Hope this has solved your query. Thank You.
Good Evening,
Yes, you are eligible for both JEE Mains and Advanced, as you completed your 12th with physics, chemistry and biology. Moreover, you passed mathematics in 2025, which makes you fit the eligibility criteria of both exams.
Aspirant, I would like to inform you that Careers360 recently launched a free mock test series for JEE students. The last date of registration is 8th January, 2026. Enroll and solve chapter wise question papers and improve you concept and assess your learning. The link to the mock test series is attached herewith. https://learn.careers360.com/test-series-jee-main-free-mock-test/
Best regards.
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