UPES B.Tech Admissions 2025
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JEE Main 2025 Marks vs Rank - Careers360 provides the JEE Main Marks vs Rank 2025 here on this page. The marks vs rank of JEE Main 2025 indicates the range of marks and their corresponding rank range. To secure a high rank in JEE Main exam, candidates need to obtain 270+ marks. Moreover, to secure a 98 percentile, candidates require 160+ marks. The final JEE marks vs rank has been released along with JEE Main scorecards of session 2. The JEE Main 2025 result for session 2 has beeb released on April 18, 2025. The authority has conducted the JEE Main 2025 exam for session 2 on April 2 to 9, 2025.
National Testing Agency held the JEE Main entrance exam from January 22 to 30, 2025 (session 1) and session 2 was held from April 2 to 9, 2025. Aspirants must note that JEE Main 2025 marks vs rank are indicative. The marks vs ranks of JEE Main 2025 have been compiled by taking students' data from multiple sources. The JEE Main Marks vs Rank will vary each year based on various factors. Hence, candidates should look at the marks vs rank data given below as an indicator of how their performance translates into ranks.
Also Check: JEE Main Percentile Predictor | JEE Main Rank Predictor
Candidates can check the JEE Main marks vs rank 2025 to know how many marks to obtain for good rank. Moreover, students can also check the JEE Main marks vs percentile vs rank 2025 to know what percentile they will get based on their score in JEE Main. The data given is indicative.
Marks Out of 300 | Overall Rank |
---|---|
290- 280 | 13 - 36 |
280 - 250 | 36 - 428 |
250 - 240 | 428 - 755 |
240 - 230 | 755 - 1189 |
230 - 220 | 1189 - 1893 |
220 - 210 | 1893 - 2720 |
210 - 200 | 2720 - 3803 |
200 - 190 | 3803 - 5320 |
190 - 180 | 5320 - 7354 |
180 - 170 | 7354 - 9968 |
170 - 160 | 9968 - 13163 |
160 - 150 | 13163 - 17290 |
150 - 140 | 17290 - 22533 |
140 - 130 | 22533 - 29145 |
130 - 120 | 29145 - 37440 |
120 - 110 | 37440 - 47979 |
110 - 100 | 47979 - 61651 |
100 - 90 | 61651 - 79298 |
90 - 80 | 79298 - 102421 |
80 - 70 | 102421 - 135695 |
70 - 60 | 135695 - 183105 |
60 - 50 | 183105 - 260722 |
50 - 40 | 260722 - 380928 |
40 - 30 | 380928 - 568308 |
30 - 20 | 568308 - 844157 |
20 - 10 | 844157 - 1118638 |
10 - 0 | 1118638 - 1321716 |
To calculate your percentile rank among your classmates' test scores, you can use the formula: divide the number of scores below your score by the total number of scores, and then multiply by 100. To illustrate, consider that Candidates scored an 88 on the test, and you want to determine your percentile rank among scores ranging from 67 to 95.
The factors typically considered when determining the relationship between JEE Main marks, rank, and percentile include:
Total number of registered candidates
Number of questions in the paper
Difficulty level of the exam
Candidates' overall performance
Trends in previous years' JEE Main marks versus ranks data
Institutes/Seats | NITS | IIITs | CFTIs |
---|---|---|---|
Number of Institutes | 31 | 25 | 28 |
Total Seats | 17967 | 4023 | 4683 |
Open + Open-PwD | 9264 | 2078 | 2878 |
OBC-NCL + OBC-NCL-PwD | 4858 | 1089 | 776 |
SC + SC-PwD | 2762 | 609 | 658 |
ST + ST-PwD | 1736 | 310 | 391 |
*Based on JoSAA Seat Matrix
The authority will activate the JEE Main rank card download link on the website, jeemain.nta.nic.in. Candidates can download the JEE Main rank card using the application number and date of birth. The rank card of JEE Main 2025 will comprise marks and rank secured in the entrance test. Candidates can check the actual rank obtained in the JEE Main exam. Below is the step to download the JEE Main rank card.
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The authorities has released the cutoff for JEE Main 2025 online. JEE Mains cutoff 2025 is the minimum mark required by the candidates to qualify for the exam. The cutoff of JEE Main 2025 will differ for all categories. JEE Main admission cutoff 2025 is the opening and closing ranks within which admission is offered in institutes. The cutoff of IIT JEE Mains for admission is released by JoSAA after each round of counselling. Candidates can check the opening and closing ranks for admissions into NITs, IIITs, and CFTIs through the JEE Main 2025 Cutoff. Those candidates who manage to secure within the cutoff marks will have a higher chance of admission into the institute. One important thing to note is that the cutoff will differ according to the course and institute selected by the candidates.
Category/Year | General | OBC | SC | ST |
---|---|---|---|---|
2025 | 93.1023262 | 79.4313582 | 61.1526933 | 47.9026465 |
2024 | 93.2362181 | 79.6757881 | 60.0923182 | 46.6975840 |
2023 | 90.7788642 | 73.6114227 | 51.9776027 | 37.2348772 |
2022 | 88.4121383 | 67.0090297 | 43.0820954 | 26.7771328 |
2021 | 87.8992241 | 68.0234447 | 46.8825338 | 34.6728999 |
2020 | 70.2435518 | 72.8887969 | 50.1760245 | 39.0696101 |
2019 | 78.2174869 | 74.3166557 | 54.0128155 | 44.3345172 |
2018 | 74 | 45 | 29 | 24 |
2017 | 81 | 49 | 32 | 27 |
2016 | 100 | 70 | 52 | 48 |
2015 | 105 | 70 | 50 | 44 |
2014 | 115 | 74 | 53 | 47 |
2013 | 113 | 70 | 50 | 45 |
At 96 JEE Main percentile, candidates' positions in CRL would be in the range of 65k. It can be considered a good JEE Main score.
Good JEE Main percentile can be said in the range of 99. At this JEE percentile, candidates belonging to any category can get admission of his desired NIT, IIITs or GFTI. However, JEE Main score in range of 99 to 95 is also good.
No, AIR and CR are different, AIR is the overall rank obtained by the candidate respective of their category and CR is the rank candidates got in their respective category.
Candidates having 99 percentile can be having marks between 175 to 292. Candidates having 98 percentile have marks in range of 149-174.
The formula to calculate JEE Main Rank from Percentile Score is ((100 – P)/100)*N + 1, where p denotes the NTA score, and N denotes the number of students.
JEE Main 2025 percentile of a candidate is prepared by NTA using a formula.
Yes! JEE Main percentile in range of 95 would position the candidate in range of 63K to 65K CRL. It can be considered good JEE Main percentile.
If we look in to JEE Main Marks vs Rank 2019, the marks of Rank 1 candidate was 331 out of 360, marks of candidate with rank 103 was 287, marks of candidate having rank 5365 was 171, candidate having 50,000 rank range had marks in range of 60.
The JEE Main rank is expected to be around 17K approximately for 150 marks.
Candidates can use JEE Main rank predictor to get idea about their rank on the basis of percentile they get in exam.
The formula to calculate JEE Main Rank from Percentile Score is ((100 – P)/100)*N + 1, where p denotes the NTA score, and N denotes the number of students.
In 2025, there will be two sessions for the upcoming JEE Main test. The first session ran from January 22 to January 30, 2025. Paper 1 (BE/BTech) was held on April 2, 3, 4, 7, and 8, while Paper 2 (BArch/BPlan) was held on April 9. Session 2 took place from April 2 to April 9, 2025. There won't be any more JEE Main examinations in 2025.
The next set of JEE exams you would be referring to would be JEE Advanced 2025 .
The important dates for JEE Advanced 2025 are as follows:
Therefore, the next major exam date for JEE aspirants is May 18, 2025, for JEE Advanced 2025. Keep in mind that the registration for this exam is closing today, May 2, 2025. If you are eligible and wish to appear for JEE Advanced, ensure you complete the registration process before the deadline.
To secure a seat in an Indian Institute of Technology (IIT) through JEE Advanced, you need to fulfill a set of conditions that cover your performance in JEE Main, your academic background, and other criteria. Here's a breakdown of the key conditions:
First and foremost, you must qualify in JEE Main and be among the top 250,000 candidates (including all categories) who clear Paper 1 of JEE Main. This is the primary filter to be eligible to appear for JEE Advanced.
Secondly, there are criteria related to your Class 12 (or equivalent) examination . You must have passed this examination with Physics, Chemistry, and Mathematics as compulsory subjects. Additionally, you need to either secure at least 75% aggregate marks in the qualifying examination (65% for SC, ST, and PwD candidates) or be within the top 20 percentile of successful candidates in your respective Class 12 board examination.
Regarding the number of attempts , a candidate can appear for JEE Advanced a maximum of two times in two consecutive years. For JEE Advanced 2025, candidates must have appeared for their Class 12 (or equivalent) examination for the first time in either 2024 or 2025. Those who appeared for the first time in 2023 or earlier are generally not eligible.
There is also an age limit . Candidates should have been born on or after October 1, 2000. However, there is a five-year age relaxation for SC, ST, and PwD candidates, meaning they should have been born on or after October 1, 1995.
Finally, candidates who have already been admitted to an IIT under any academic program in previous years (through JoSAA) are generally not eligible to appear for JEE Advanced again. However, there are some exceptions for those who were admitted to a preparatory course or whose admission was cancelled before the final round of seat allotment.
In simple terms, to get into an IIT through JEE Advanced, you need to perform well enough in JEE Main to be eligible, pass your Class 12 with good marks (or be a top performer in your board), be within the allowed number of attempts and age limit, and not have already taken admission in an IIT previously. Make sure to check the official JEE Advanced website for the most up-to-date and detailed eligibility criteria.
Hello,
With your CRL rank of 230,902 and OBC-NCL rank of 79,675, you might get admission to some colleges. Here are a few options:
NIT Andhra Pradesh : Biotechnology, Metallurgical Engineering.
IIIT Chittoor : Electrical Engineering, possibly some branches of Computer Science.
Government Engineering Colleges in Andhra Pradesh : Andhra University, JNTU Kakinada, JNTU Hyderabad.
Other GFTIs : Assam University, Tezpur University, Central University of Rajasthan.
Check JoSAA counselling and consider AP EAMCET for better chances of admission.
You can also use our JEE Main College Predictor tool to predict which college you can get based on your scores.
Hope it helps !
With a CRL rank of 49,000 and an EWS rank of 6,786, getting admission to DTU and NSUT through JAC Delhi is unlikely for top branches like CSE, IT, or ECE. You may have better chances in lower branches or other colleges under JAC Delhi. Consider exploring other options as well.
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