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The JEE Main 2026 Jan 29 marks vs percentile will be published by coaching centres and institutes after the commencement of exams. The JEE Main 29 Jan shift 1 exam is being conducting now. Students who appeared for the same will be bale to check JEE Mains 29th Jan marks vs percentile. The marks vs percentile of Jan 29 will helps candidates to estimate their chances of qualifying the JEE Mains 2026 exam. The expected JEE Main Jan 29 marks vs percentile will be update for the paper 2(B.Arch and B.Plan) students. NTA do not release the official JEE Mains Jan 29 marks vs percentile.
As per the JEE Main 2026 schedule, the session 2 exam will be held from April 2 to April 9, 2026. The registration process is expected to begin soon.
The JEE Main answer key is expected to release in first week of February, 2026. The authority will publish the JEE Main results session 1 by February 12, 2026. The given details are provided by various coaching classes and experts. The data given here will help candidates know their Jan 29 Marks vs Percentile for the JEE Main 2026 exam.
Candidates can get the expected JEE Main 2026 Jan 29 Marks vs Percentile details from the table below. The given information has been taken from the previous year's official data. Aspirants can get their probable percentile and chances of admission into NITs, IIITs, or make them eligible for JEE Advanced 2026.
JEE Main Marks | JEE Main Percentile |
292-250 | 99.99890732 -99.9554732 |
249-200 | 99.95028296-99.57503767 |
199-150 | 99.56019541-98.09290531 |
149-100 | 98.07460288-93.8020333 |
99-50 | 93.67910655-78.35114254 |
49-1 | 77.81927947-6.66590786 |
The authority calculates the percentile of the JEE Mains 2026 exam with the help of a normalisation formula. The percentile score is different for each shift of the JEE Main exam. Many factors influence the percentile score, like the number of candidates appearing for the shift, the highest marks scored by the candidates, the difficulty level of the exam, etc. Candidates percentile score is calculated upto seven decimal for every shift. Below is the percentile formula that is used to get a candidate's percentile score.
Percentile Score = 100 x Total number of candidates appeared in shift with raw score eual to or less than the candidate / The total number of students in that session.
Raw score refers to the score achieved by the candidate by out 300 by adding 4 marks to the correct answer and minus 1 to the incorrect answer.
The JEE Mains 2026 Jan 29 Marks vs Rank data has been given below in table format. The information here has been taken from the previous year's official JEE Mains 2026 marks vs rank details.
JEE Main Marks | JEE Main Ranks |
300-250 | 1-704 |
249-200 | 733-6269 |
199-150 | 6488-28132 |
149-100 | 28402-91426 |
99-50 | 93240-319343 |
49-0 | 327188-1390805 |
Frequently Asked Questions (FAQs)
The JEE Main 2026 Jan 29 exam is tough, moderate or easy will be updated here soon.
The details of how was the JEE Main 2026 Jan 29 shift 1 exam will be updated here soon.
After all the shifts in JEE Main 2026 exam, the details of the toughest shift will be updated here.
Candidates need to score 230 marks in the JEE Mains 2026 exam to get 99 percentile.
On Question asked by student community
JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-
Math and Chemistry was difficult and Physics was moderate. The complete analysis is available here- https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-1-question-paper-with-solutions-pdf
You can also check the memory-based questions and detailed solutions for JEE Main Jan 28 shift 1 paper.
Hi Lucky,
Please refer to this link and you can download the free pdf.
HI Manisha Maharana
You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf
Also, you can check ad attemp the online mock test on our platform.
https://learn.careers360.com/test-series-jee-main-free-mock-test/
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$
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It cuts the x -axis at ( $a, 0$ ).
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g=-a/2
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