How to calculate JEE Main 2025 rank based on Percentile score? - Aspirants wondering how to calculate the JEE Main 2025 rank based on the percentile score will find important information in this article. Candidates will be able to predict their rank based on the JEE 2025 result. As we know, NTA has released the JEE Main score in the form of percentile. The JEE Main rank is based on the percentile score of NTA JEE Mains. The reason why students ask about JEE Main 2025 rank based on the NTA percentile score is know their chances of admission. Whether to appear JEE Main April session or not. Check out how to calculate the JEE Main 2025 rank using the percentile score below in this article.
Also Check: JEE Main marks vs percentile table
NTA will conduct the JEE Main normalisation process session-wise so the percentile score you got would be relative to the others in your session. This score denotes the percentage of candidates who have scored equal to or below (same or lower raw scores) that particular Percentile in that examination. So the 9 toppers are students who have got 100 NTA Scores and have got the highest scores which is 100 percentile after normalisation in their respective sessions. The marks obtained in between the highest and lowest scores will also been converted to appropriate Percentiles.
Note: It may be noted that the formula given for the calculation of percentile in JEE Main is indicative and should not be taken as accurate as the actual ranks will vary on account of many factors. For the actual rank, candiadtes should check the alloted rank on the JEE Main 2025 scorecard.
JEE Main 2025 exam dates will be announced on the official website. Candiadtes can follow the previous year statistics to get an idea of how to calculate the JEE Main rank from the percentile. Below is the process of calculating rank from percentile with last year's example.
As per the previous year NTAJEE Main statistics, 823967 students appeared for JEE Main in the January session. NTA announced that 20 students have scored 100 percentile in the previous year sessions and has declared them as JEE Main Toppers.
To calculate the JEE Main rank, you first need to know the percentage of candidates with higher percentile scores than you. To calculate that, the formula would be 100 (highest score) - your percentile score.
Since the percentile is calculated from 100 to 0 for each session of examinees, the formula applies the total number of students in the January session which is 8,22,000 /100 * percentage of people ahead of you to arrive at the rank.
Therefore, the formula to calculate the JEE Main rank through percentile for January is
JEE Main rank (probable) = (100- NTA percentile score ) X 823967 /100
If the NTA percentile score is 90.70, JEE Main rank will be (100-90.70 ) X 823967/100 = 76628
Consider the NTA score of 80.60 then JEE Main 2023 rank = (100-80.60) X 823967 /100. The rank will be 159849
** This formula would not be for a 100 percentile score as those are the top ranks.
Candidates can also use the JEE Main Rank Predictor to check their rank.
Candidates can take a probable calculation of percentile in JEE Main January 2025 session and check the rank. Based on your performance in the JEE Main January session, you can decide if you want to attempt the April session or not.
According to the previous year statistics, the total number of candidates that appeared for the JEE Main April session are 10,67,959. Using this as a basis, use the NTA score and see what is the JEE Main rank.
Why the January NTA score? The reason is that the authority will consider the better of the two session's scores. So if you perform badly in April, the January NTA score will be counted and if you perform better, then the rank will only be better.
So what will be the April JEE Main rank from the NTA Percentile Score of January?
Using the same formula,
If the NTA percentile score is 90.70, JEE Main rank will be (100-90.70) X 10,67,959/100 = 99320
In this case, you have a good chance of qualifying for JEE Advanced (as 2,50,000 students qualify for it) and can check the JEE Main cutoff from previous years to understand which institute you can apply for admissions.
Consider the NTA score of 80.60 then JEE Main rank = (100-80.60) X 10,67,959 /100. The rank will be 207184 which means may not have a chance of qualifying for JEE Advanced.
The NTA percentile score of 89.7548849 will stand a chance at JEE Advanced if one takes a look at the JEE Main cutoff from last year.
It is a fact that IITs are dream institutions for most engineering aspirants. So a student who has done exceptionally well in January session of JEE Main may wish to skip the JEE Main April session to concentrate on JEE Advanced preparation. Another student may have scored well enough and feels that another session is too strenuous so may wish to skip it if only he/she has a fair chance of a seat in one good NIT or IIIT. Others may wish to know if they have the chance for any admissions based on their January JEE Main percentile scores or if should they appear for the April exam to better this.
We hope that the decision to write or skip can be made a bit easier using the calculation methods mentioned in this article.
Frequently Asked Questions (FAQs)
JEE Main 2025 normalisation process is done by the authority to ensure all candidates scores are at an equal level regardless of the difficulty level of the session.
On Question asked by student community
In Malda district, West Bengal, the JEE Main 2025 exam centre code is WB20. Candidates from the district can choose Malda as their preferred exam centre during registration. The final allotment of centres depends on availability and preferences submitted by students. The exact number of exam halls may vary each year based on the number of applicants. Students should confirm their allotted centre through the official JEE Main admit card.
Yes, you should apply EWS in JEE Main form if you are eligible. For 2026 attempt, it’s better to make your EWS certificate in advance and keep it ready, because at the time of counseling they ask for a valid certificate.
You can find chapter-wise JEE Main previous year questions (PYQs) in Hindi through various resources. MTG publishes a popular book, “24 Years JEE Main Chapterwise Solutions,” covering Physics, Chemistry, and Mathematics with detailed solutions. Websites like SelfStudys, MathonGo, Mockers, and eSaral provide PDF downloads of chapter-wise PYQs with answers. Additionally, mobile apps on the Google Play Store offer Hindi versions of past JEE Main papers with solutions. These resources help students practice topic-wise questions efficiently and prepare thoroughly for exams.
The approximate annual cost for 11th/12th PCM and JEE coaching is around 1.5 to 3.5 lakhs for institutes, excluding hostel and mess fees. The total fees including hostel as well as mess fees can rise upto 4.5 to 6.5 lakhs and above, depending on location and institute quality.
Hi dear candidate,
You can anytime visit our official website to find the previous 10 years JEE Mains question papers with solutions. Kindly refer to the link attached below to download them in PDF format:
JEE Main Last 10 Years Question Papers with Solutions (2025 to 2015)
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