JEE Main 2026 April 6 Shift 1 Question Paper with Solutions PDF (Out): Download Here

JEE Main 2026 April 6 Shift 1 Question Papers with Solutions PDF

Students can download the JEE Main 2026 April 6 Shift 1 Question Papers along with the solutions in the PDF format from the table given below. It will help students understand the exam pattern and type of questions asked in jee mains april 6 shift 1 paper.

JEE Main 2026 April 6 Shift 1 Exam Analysis

The detailed analysis of JEE Main 2026 April 6 Shift 1 Paper, including subject-wise difficulty level and important topics asked is provided in the table given below. It will help students understand the overall exam pattern and evaluate their performance more effectively.

JEE Main 2026 April 6 Shift 1 Question Papers with Solutions

Memory-based questions along with detailed solutions for JEE Main 2026 April 6 Shift 1 Paper are given below. Students can use these questions to verify their answers, estimate their scores, and gain a clear understanding of the paper pattern and important topics.

Physics

Question 1: In AC series circuit supply voltage $V_{(\mathrm{rms})}=100$ volts; $R=80 \Omega ; X_L=80 \Omega$ and source frequency is $f=50 \mathrm{~Hz}$. Find the power factor 1) $1 / \sqrt{2}$ 2) $1 / 2$ 3) $\frac{3}{4}$ 4) $\sqrt{3} / 2$

Question 2: an xpression of potential energy $=\frac{A \sqrt{x}}{B+x}$ is given. Then dimensions of $(A \cdot B)$ will be ( $x$ is positive here.)
1) $\mathrm{MLT}^{-1}$
2) $M^{1 / 2} L^{2 / 3} T^{-2}$
3) $\mathrm{ML}^{3.5} \mathrm{~T}^{-2}$
4) $\mathrm{ML}^{1 / 2} \mathrm{~T}^{-2}$

Question 3: In YDSE experiment a glass slab of thickness $8 \mu \mathrm{~m}$ is introduced in front of a slit. If the central maxima shifts to a position of $4^{\text {th }}$ minima, then find refractive index of glass slab (take $\lambda=500 \mathrm{~nm}$).

Question 4: Electric field at centre of semi-circular ring of radius 10 cm is $100 \mathrm{v} / \mathrm{m}$. Find charge on the ring if charge distribution is uniform.
1) $4 \varepsilon_0$
2) $20 \varepsilon_0$
3) $25 \varepsilon_0$
4) $30 \varepsilon_0$

Question 5: A point charge particle $Q=3 C$ is placed at point $A(0,-2,-5)$ and taken to point $B(2,1,3)$ in the electric field $\vec{E}=\left(2 x \hat{\imath}+3 y^2 \hat{\jmath}+4 \hat{k}\right)$. Find work done by electric field.
1) 75 Joule
2) 135 Joule
3) 89 Joule
4) 105 Joule

Chemistry

Question 1: Consider the reactions :

Find the no. of moles of benzene formed (if the efficiency of the reaction is 60%)
$1\quad0.05$
$2 \quad 0.06$
$3 \quad 0.03$
$4 \quad 0.04$

Question 2: Match column I & II

Question 3:

Match column I & II

Question 4: Match list I & II

Question 5: $\left(\mathrm{CH}_3\right)_3 \mathrm{C}-\mathrm{OH} \xrightarrow[\mathrm{H}^{+} / PhCOOH]{(Cu/573K)}$ major product

Question 6: An oxide of iron contains $69.9 \%$ iron. Find its empirical formula. (Given: Atomic masses $\mathrm{Fe}=56, \mathrm{O}=16$ )
a) $\mathrm{Fe}_3 \mathrm{O}_4$
b) $\mathrm{Fe}_2 \mathrm{O}_3$
c) $\mathrm{FeO}_3$
d) FeO

Question 7: Given below are two statements.

In light of above statements, choose correct option.

1 Both Statement I and Statement II are correct

2 Statement I is incorrect, Statement II is correct

3 Statement I is correct, Statement II is incorrect

4 Both Statement I and Statement II are incorrect

Question 8: 2,6-Diethylcyclohexanone and 2-propyl-6-methyl cyclohexanone are which type of isomers
(A) F.G.I
(B) Metamers
(C) Tautomers
(D) Position isomers

Maths

Question 1:

The value of $1^3-2^3+3^3-4^3+\ldots+15^3$ is equal to:

(1) 1856

(2) 1854

(3) 1786

(4) 1826

Question 2:

$\int_{-\pi / 4}^{\pi / 4} \frac{32 \cos ^4 \theta}{1+e^{\sin \theta}} d \theta$ is equal to
(1) $3 \pi+8$
$(2)3 \pi+4$
$(3)4 \pi+8$
(4) $4 \pi+4$

Question 3:

The value of $\lim _{x \rightarrow 0} \frac{x^2 \sin ^2 x}{x^2-\sin ^2 x}$ is equal to:

Question 4:

If $x_1, x_2, \ldots, x_{25}$ be 25 observations such that $\sum_{i=1}^{25}\left(x_i+5\right)^2=2500$ and $\sum_{i=1}^{25}\left(x_i-5\right)^2=1000$. Then, the ratio of Mean and Standard deviation of the given observations is
$(1) \frac{1}{4}$
$(2) \frac{1}{2}$
(3) $\frac{2}{3}$
(4) $\frac{1}{5}$

Question 5:

In the expansion of $(1+\alpha x)^{26}$ and $(1-\alpha x)^{28}$, the coefficient of the middle term is the same, then the value of $\alpha$ is:
$(1) \frac{7}{22}$
$(2) \frac{7}{27}$
$(3) \frac{5}{27}$
(4) $\frac{5}{22}$

Question 6:

$a_1, a_2, a_3, \ldots, a_n$ are in A.P., and the sum of the first 10 terms is $160. g_1, g_2, g_3, \ldots \ldots g_n$ are in G.P., were $g_1+g_2=8$. If the first term of A.P. is equal to the common ratio of G.P. and the first term of G.P. is equal to the common difference of A.P., then the sum of all possible values of $g_1$ is equal to
$(1 )\frac{34}{9}$
$(2)\frac{28}{9}$
$(3 )\frac{23}{3}$
$(4) \frac{28}{5}$

Question 7:

Consider $e_1$ and $e_2$ to be roots of the equation $x^2-a x+2=0$. Set of values of $a$ for which $e_1$ and $e_2$ are eccentricities of hyperbolas then $a \in[\alpha, \beta]$ and set of values of $a$ for which $e_1$ and $e_2$ are eccentricity of a (4) parabola and an ellipse is ( $\gamma, \infty$ ) then $\alpha^2+\beta^2+\gamma^2$ is equal to

(1) 26
(2) 24
(3) 18
(4) 32

JEE Mains 2026 YouTube Live Analysis

Refer to the Careers360 YouTube channel for detailed JEE Mains April 6 Shift 1 Paper analysis and live updates. Our experts go live after each shift to provide a complete breakdown and detailed explanations of JEE Mains 2026 question paper. Check out the link below to join the live update session.

How to Download JEE Main 2026 April 6 Shift 1 Question Paper – Free PDF

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Also Check: JEE Mains 2026 April 5 Shift 1 Paper | JEE Mains 2026 April 5 Shift 2 Paper

JEE Main 2026 April 6 Shift 1 Answer Key

Students can refer to JEE Main 2026 April 6 Answer key that will be available here soon. Using JEE Mains 6 April Shift 1 answer key students can cross check their answers and estimate their expected scores.

JEE Mains Previous Year Question Paper

Along with JEE Mains April 6 Shift 1 paper students can also refer to the previous year question papers that help students understand the exam pattern and important topics, and improve their preparation through consistent practice. Here, we are providing the previous years' question papers of JEE Main. You can check it from the table given below.

JEE Main January Session Exam Analysis

Candidates can check the day-wise NTA JEE Main analysis of January sessions JEE Mains 2026 as these analysis help students understand the expected JEE Mains 6 April Shift 1 exam level.

JEE Main Marks vs Percentile 2026 (Expected)

Check the given table for the JEE Mains marks vs percentile tentative value derived using an algorithm.

JEE Main 2026 Expected Cutoff

The JEE Main 2026 Expected Cutoff gives an estimate of the minimum marks required to qualify for the JEE Advanced It helps students understand their chances of selection and plan their preparation or counselling strategy accordingly. Refer to the table given below to get a rough idea about JEE Main 2026 April 6 Shift 1 Expected Cutoff:

JEE Main College Predictor

The JEE Main College Predictor tool enables you to predict your engineering college admission chances based on your projected rank and score results. JEE Main College Predictor tool helps you explore suitable colleges and courses according to your performance in JEE Mains April 6 Shift 1 Exam. This tool can guide you in making informed decisions during the counselling process.

JEE Main 2026 Rank predictor:

Students can use the JEE Main rank predictor to estimate their all india rank before the release of actual result of 6 April JEE Mains 2026 Shift 1 Exam. Using this JEE Main rank predictor students can get an idea about their score and decide on college and stream and stream they are going to get admission.

JEE Main 2026 Session 2 Result Date

The NTA will release the JEE Main 2026 Session 2 (April attempt) results for Paper 1 (B.E./B.Tech) by April 20, 2026, on the official website, jeemain.nta.nic.in. The Session 2 exam is scheduled from April 2 to 8, 2026, and the final scorecard, including All India Ranks, will be available until July 31.