JEE Advanced Cutoff for IIT Patna - The Joint Seat Allocation Authority (JoSAA) will release the cutoff of JEE Advanced 2020 for IIT Patna in online mode. The cutoff will be the minimum rank required by the candidates to get admission in various B.Tech courses offered by the institute. JEE Advanced 2020 cutoff for IIT Patna will act as a screening process at the institute. Therefore, the authorities consider various factors while determining the cutoff such as availability of seat, the total number of application, previous year’s cutoff trends, and more. Candidates who will score high marks in JEE Advanced will have increased chances of admission. Read the complete article to know more about JEE Advanced 2020 cutoff for IIT Patna.
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The concerned authorities will release the cutoff of JEE Advanced 2020 for IIT Patna in online mode after the declaration of result. The JEE Advanced 2020 result will be released tentatively on June 8. The cutoff will be updated in this article as soon as it will be released by the authorities.
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The following are the factors that will be considered while preparing the cutoff of JEE Advanced 2020 for IIT Patna:
Difficulty level of JEE Advanced 2020
Previous year’s cutoff trends
Availability of seats
Total number of applicants.
Candidates seeking admission to B.Tech programme must be looking for JEE Advanced 2020 cutoff for IIT Patna. Since the cutoff is not yet released by the authorities, the candidates can check previous year’s cutoff trends to have an idea regarding it.
Course Name
Category
Gender Neutral
Female
Chemical Engineering
OBC
3843
7197
EWS
1136
--
General
10497
17519
SC
2100
2949
ST
929
Civil Engineering
3450
6638
1023
10163
16636
1750
2890
585
893
Computer Science and Engineering
977
2475
196
547
2617
5912
612
1146
434
798
Mechanical Engineering
2783
6976
785
7872
15106
1700
3179
681
Metallurgical and Materials Engineering
4260
1290
12148
19843
2527
3254
1112
Electrical and Electronics Engineering
2194
5172
573
3995
11371
1335
2195
579
S.No
Programme
Opening Rank
Closing Rank
1.
6525
8746
OBC-NCL
2719
3432
1455
797
825
2.
6430
8674
2383
2993
1079
1511
419
3.
999
2731
729
1058
428
715
347
412
4.
Electrical Engineering
3127
5841
1617
2211
863
1393
482
564
5.
3019
7053
2077
2587
1055
1576
455
631
5479
8853
2467
2880
1407
1682
736
796
6090
8281
2024
2444
1015
1360
242
497
1849
3298
725
1122
259
664
356
498
3649
6151
1448
1995
1225
1299
450
614
4567
7237
1689
2234
858
1306
509
618
S.No.
Programme Name
1
Computer Science & Engineering
1541
2888
2
3895
5518
3
4359
6284
4
5776
7074
5
6560
7891
Computer Science and Engineering (4 Years, Bachelor of Technology)
719
1159
Electrical Engineering (4 Years, Bachelor of Technology)
1340
2101
Mechanical Engineering (4 Years, Bachelor of Technology)
1697
2225
Civil Engineering (4 Years, Bachelor of Technology)
1938
2391
Chemical Engineering (4 Years, Bachelor of Technology)
2555
2744
680
861
1130
1005
1211
1101
1312
1443
1605
376
447
475
576
438
586
516
613
597
939
Minimum Percentage of Marks in Each Subject
Minimum Percentage of Aggregate Marks
Common rank list (CRL)
10.0
35.0
GEN-EWS rank list
9.0
31.5
OBC-NCL rank list
SC rank list
5.0
17.5
Common-PwD rank list (CRL)
OBC-NCL-PwD rank list
SC-PwD rank list
ST-PwD rank list
Preparatory course rank lists
2.5
8.75
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Hello,
Considering 2019 cut off trends the cut was 89.75 percentile for General category.The cut off for 2020 is yet to be announced.Cut off changes every depending on number of seats available, number of candidates applied, difficulty of exam etc.So, there are less chances for you to qualify JEE main January session, if cut remain same or goes higher.You may qualify if cut off decrease.
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 58197. It’s difficult to tell exact qualifying marks for jee advanced eligibility but if you are getting more than 85 percentile score then you have decent chances to qualify for jee advanced. You can predict your colleges at: https://engineering.careers360.com/jee-main-college-predictor?
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