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JEE Mains 2025 April 2 Shift 1 Question Paper with Solutions - Are you attempting the JEE Main exam this April? Then this is the right spot for you! The JEE Main 2025 April 2 Shift 1 exam is held by the National Testing Agency (NTA) just got over. As the exam is now over, the candidates will be able to access the JEE Main 2025 April 2 shift 1 question paper with solutions on this page. These solutions will help IIT JEE aspirants to judge how the JEE Main April 2 shift 1 difficulty level, topic-wise weightage and recurring question patterns are going to be like. Find updates on JEE Main 2025 April 2 shift 1 question papers PDF download link and a detailed exam analysis.
Also Check: JEE Main 2025 April 2 Answer key Shift 1
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Check the following table for the JEE Main 2025 exam pattern. The exam is held for a duration of 3 hours.
Details | Information |
Total Time | 3 hours (180 minutes) |
Total Questions | 75 questions |
Maximum Marks | 300 marks |
Exam Medium | Available in 13 languages |
Exam Mode | Computer-Based Test (CBT) |
Question Type | MCQs and Numerical Value-Based |
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The JEE Main 2025 April 2 Shift 1 Question Paper with Solutions PDF will provide a step-by-step explanation for each question, assisting students in analyzing their performance.
Subject | Difficulty Level | Key Topics Covered |
Physics | Moderate | Thermodynamics, Electromagnetic Induction |
Mathematics | Tough | Calculus, Probability, Algebra |
Easy to Moderate | Organic Chemistry, Chemical Bonding |
JEE Main 2025 April 2 Shift 1 Question Paper is definitely going to help in the preparation of the exam. Download JEE Main 2025 April 2 Shift 1 Paper PDF here to be well prepared for further exams or test how your exam went. Here we provide the live session for memory based question paper and analysis.
The JEE Main 2025 April 2 Answer Key PDF download link is now activated as the examination is over. Students can match their responses with the JEE Main 2025 April 2 Answer Key Download to estimate their scores. Once all shifts are completed the JEE Main 2025 April 2 All Shifts Question Paper will also be accessible for reference. The unofficial JEE Main 2025 April 2 Question Paper PDF Download link is available now.
Q 1. Find the maximum value of $n$ such that $50!$ is divisible by $3^n$.
Q 2. Let $P_n=\alpha^n+\beta^n, P_{10}=123, P_9=76, P_8=47$ and $P_1=1$, the quadratic equation whose roots are $\frac{1}{\alpha}$ and $\frac{1}{\beta}$.
1. $ x^2+x-1=0$
2. $x^2-2 x+1=0$
3. $x^2+x-2=0$
4. $x^2-x-2=0$
Q 3. Number of solutions in $[-2 \pi, 2 \pi]$ for equation $2 \sqrt{2} \cos ^2 \theta+(2-\sqrt{6}) \cos \theta-\sqrt{3}=0$.
Q 4. The total number of 10 digits sequences formed by only $\{0,1,2\}$ where 1 should be used at least 5 times and 2 should be used exactly three times, is
Q 5. Let $a_1, a_2, a_3, \ldots$. is an A.P. and $\sum_{k=1}^{12} a_{2 k-1}=-\frac{72}{5} a_1$ and $\sum_{k=1}^n a_{k=0}$. Then the value of $n$ is
Q 6. Given the equation of a hyperbola $H: \frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ and its directrix is $x=\sqrt{\frac{10}{81}}$ with a focus at $(\sqrt{10}, 0)$, then find the value of $9\left(e+l^2\right)$, where $I$ is length of latus rectum is
1. 2697
2. 2597
3. 2487
4. 2587
Q 7. If a twice differentiable function $f$ satisfies $f^{\prime}(x)=f(x)$ such that $f(0)=\frac{1}{2}=f^{\prime}(0)$. Then find $f^{\prime \prime}\left(\frac{\pi}{3}\right)$
Q.6 Which of the following statement(s) is correct is/are for the adiabatic process?
A. Molar heat capacity is zero.
B. Molar heat capacity is infinite.
C. Work done on gas is equal to increase in internal energy
D. The increase in temperature results in decrease in internal energy
1 A and C only
2 B and C only
3 A and D only
Q.7 What is the units of viscosity, intensity of wave and pressure gradient
Q.8 Which does not follow general trends among Halogens
(1) I. E
(2) Electro Affinity
(3) Ionic Radius
(4) Covalent Radius
Q.9 The figure shows an infinite plane having uniform charge density $\sigma$ and a small charged particle having charge $q$ and mass $m$ suspended by a light insulating thread. Find $\sigma$ if the charge is in equilibrium.
$1 \quad \frac{2 f_0 m g}{q}$
$2 \frac{\varepsilon_0 m g}{2 q}$
$3 \quad \frac{2 q}{\varepsilon_0 m g}$
$4 \frac{2 q \varepsilon_0}{m g}$
Q.10 Find the ratio of $\left(\gamma=\frac{C_p}{C_v}\right)$ for two gases having degree of freedoms $f=3$ and $f=5$.
Q.11 Relation between magnetic sucesptibility and magnetic permeability
Q.12 The ratio of magnetic field to center of circular coil to magnetic field at distance $x$ from the centre of circular coil
$
\left(\frac{x}{R}=3 / 4\right)
$
Q.13 The greatest value of $n, n \in N$. If $3^n$ divides 50 !
a) 20
b) 21
c) 22
d) 23
Q.14 Two point charges $q$ and $9 q$ are placed at distance of $l$ from each other. Then the electric field is zero at a
1 Distance $\frac{l}{4}$ from charge $9 q$
2 Distance $\frac{3 l}{4}$ from charge $q 3$ Distance $\frac{l}{3}$ from charge $9 q$
4 Distance $\frac{l}{4}$ from charge $q$
Q.15 Given the equation of a hyperbola $H: \frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ and its directrix is $x=\sqrt{\frac{10}{81}}$ with a focus at $(\sqrt{10}, 0)$, then find the value of $9\left(e+l^2\right)$, where $I$ is length of latus rectum is
1 2697
2 2597
$3 \quad 2487$
$4 \quad 2587$
Q.16 Which Amino acids is optically inactive
(1) Alanine
(2) Glycine
(3) Valine
(4) Aspartic Acid
Q. Two point charges $q$ and $9 q$ are placed at distance of $l$ from each other. Then the electric field is zero at a
1 Distance $\frac{l}{4}$ from charge $9 q$
2 Distance $\frac{3 l}{4}$ from charge $q$3 Distance $\frac{l}{3}$ from charge $9 q$
4 Distance $\frac{l}{4}$ from charge $q$
You can download detailed questions and analysis from here:
| JEE Main 2025 Memory Based Questions of 2nd April (Shift-1) |
JEE Main 2025 Memory Based Questions 2nd April (Shift-2) |
This round of applications closing on 15th July | Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Last Date to Apply: 15th July | Ranked #43 among Engineering colleges in India by NIRF | Get Upto 100% Scholarships | Spot Admissions via CUET
Students must learn all syllabus contents and test conditions so they can manage their time properly.
Design a scheduled timetable which equally covers every subject to establish balanced preparation.
Students should focus on studying NCERT textbooks for Physics Chemistry and Mathematics since these books provide foundation building material.
Consistent Practice will bring success Through Previous Year Question Paper Solutions and Practice of Mock Tests Which Build Speed Accurately.
Learning efficient time distribution for subjects along with question-solving speed practice during time-limited sessions is vital.
You should work on understanding basic concepts clearly instead of repeating information by memory during your studies. Standard reference materials should be consulted if required.
Regular revisions of important topics and concepts and formulas will help you retain information.
Do mock tests according to full-length formats to monitor your performance while locating your knowledge gaps.
A healthy balance of sleep with nutritious food alongside stress control measures helps both mental focus and work productivity.
Frequently Asked Questions (FAQs)
The JEE Main 2025 official answer key will be released on NTA website. The link to download the same will be made available here once it is released.
On Question asked by student community
Hello,
Based on your JEE Main Paper 2 percentile (96.3), CRL 2566, NATA percentile (88.69), and Class 12 score (88.8%), you have a good academic profile for B.Arch admissions.
Since COMEDK has its own merit preparation for B.Arch admissions, your exact rank cannot be predicted before the merit list is
Hello Student,
With your rank og 129537 as an OBC candidate, it is highly unlikely that you will get a seat in core branches. There is a possibility, though, that you might get a seat in lower-tier NITs or GFTIs, in branches such as Biotechnology , Mining, Metallurgy and Civil
Hello Dear Student,
Neither branch is universally "better"; it depends entirely on your interests.
Computer Science Engineering (CSE) focuses on software, coding, and algorithms, and generally yields higher immediate IT salaries. Electronics and Communication Engineering (ECE) focuses on hardware, microchips, and circuits, offering a dual-advantage of core hardware jobs +
Hey there,
With 94.95 percentile in JEE Main, Rajasthan home state, and REAP OBC-NCL merit rank 202, you have a very good chance of getting B.Tech CSE at MBM University, Jodhpur. While admission cannot be guaranteed until the official seat allotment is announced, your profile is competitive based on previous
Hello Dear Student,
You will not be able to secure a seat (CS or core branches) at the COEP Technological University with your current score. COEP is highly competitive, and closing ranks for the SC category normally range between \(\approx 10{,}000\) to (20,000), well below your (38,647) category rank.
Hope
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