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Are you looking to Download the JEE Main 2025 April 3 Shift 2 question paper with solutions? The Joint Entrance Examination Main 2025 is a crucial assessment for aspiring engineers seeking admission to top-tier institutions like NITs and IIITs. The April 3 Shift 2 paper is being conducted by the National Testing Agency as part of the second session of JEE Main exam 2025. Candidates can now access the question paper along with JEE Main April 3 Answer Key 2025 Shift 2 to evaluate their performance and gain insights into the exam pattern, difficulty level, and key topics covered.
The following documents are required for JEE Main 2026 registration:
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Also check: JEE Main 2025 April 3 Shift 1 question paper with solutions
This article provides a comprehensive analysis of the JEE Main 2025 April 3 Shift 2 question paper including subject-wise difficulty levels, weightage distribution, and expert solutions. JEE Main 2025 Shift 2 Question Paper with Solutions PDF will help in preparing for the exam for students of later shifts and days. Once the exam is over, JEE Main 2025 April 3 Question paper with solutions is updated for you to view and practice.
Details | Information |
Total Time | 3 hours (180 minutes) |
Total Questions | 75 questions |
Maximum Marks | 300 marks |
Exam Medium | Available in 13 languages |
Exam Mode | Computer Based Test (CBT) |
Question Type | MCQs and Numerical Value-Based |
Also Check:
Q.1 Find out the magnitude of work done in the process ABCD (in kJ) (1 atm. Lit = 101.3 J)
Q.2 Amount of magnesium (Mg) (in mg ) required to liberate 224 mL of $\mathrm{H}_2$ gas at STP, when reacted with HCl
Q.3 Among Sc, Ti, Mn and Co, Calculate the spin only magnetic moment in +2 oxidation state of metal having highest heat of atomisation.
Q.4 Statement-1: Wet cotton cloths made up of cellulose based carbo hydrate Takes comparatively longer time to get dried than wet nylon based clothes
Statement - 2: Intermolecular hydrogen bonding with water molecule is more In nylon based clothes than in cotton clothes.
1. Statement - 1 and Statement - 2 are correct
2. Statement - 1 and Statement - $\mathbf{2}$ are incorrect
3. Statement - 1 is true and Statement - 2 is false
4. Statement - $\mathbf{1}$ is false and Statement - $\mathbf{2}$ is true
Q.5 . At 715 mm pressure, 300 K , volume of $\mathrm{N}_2(\mathrm{~g})$ evolved was 80 mL by a 0.4 g sample of organic compound. Find \% of N in organic compound Aq. tension at $300 \mathrm{~K}=15 \mathrm{~mm}$
$1 \quad20.95$
$2 \quad 25.85$
$\begin{array}{ll}3 & 30.25\end{array}$
$\begin{array}{lr}4 & 15.83\end{array}$
Q 1)An equilateral prism is made of a material of refractive index $\sqrt{2}$. Find the angle of incidence for minimum deviation of the light ray.
Q 2) The moment of inertia of a ring of mass $M$ and radius $R$ about an axis passing through the tangential point in the plane of the ring is
Q 3) What is the dimensional formula of $\frac{1}{\mu_0 \varepsilon_0}$ (where $\mu_0$ is permeability and $\varepsilon_0$ is permittivity of free space)
Q 4) Two water drops each of radius of r coalesce to form a bigger drop. If T is the surface tension, surface energy released in this process is
Q 5) A particle moves on a circular path of radius 1 m. Find its displacement when it moves from $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{A} \rightarrow \mathrm{B}$. Also its distance are it moves from $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{A}$ $\rightarrow \mathrm{B} \rightarrow \mathrm{A}$.

Q 6) A disc of mass $M$ and radius 2 m is hinged, keeping the axis horizontal. If angular acceleration of the disc is $2 \mathrm{rad} / \mathrm{s}^2$. Find moment of inertia
Q 7) Binding energy per nucleon in ${ }_1^2 \mathrm{H}$ is x and for ${ }_2^4 \mathrm{He}$ is y . Find energy released in the given reaction ${ }_1^2 \mathrm{H}+{ }_2^4 \mathrm{He} \rightarrow{ }_2^4 \mathrm{He}$
Q 1. If $\lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)^{\frac{1}{x^2}}=p$, then $96 \ln p$ is
Q 2. Let $A=\{-3,-2,-1,0,1,2,3\}$. A relation $R$ is defined such that $x R y$ iff $y=\max \{x, 1\}$. Number of elements required to make it reflexive is $l$, number of elements required to make it symmetric as $m$ and number of elements in the relation $R$ is $n$. Then value of $l+m+n$ is equal to
Q 3. Let a circle $C$ with radius $r$ passes through four distinct points $(0,0),(k, 3 k)$, $(2,3)$ and $(-1,5)$, such that $k \neq 0$, then $\left(10 k+2 r^2\right)$ is equal to
Q 4. The distance of the point $(7,10,11)$ from the line $\frac{x-4}{1}=\frac{y-4}{0}=\frac{z-2}{3}$ along the line $\frac{x-9}{2}=\frac{y-13}{3}=\frac{z-17}{6}$ is
Q 5. $I=\int_0^\pi \frac{8 x}{4 \cos ^2 x+\sin ^2 x} d x$ equals to
1. $\pi^2$
2. $4 \pi^2$
3. $2 \pi^2$
4. $\frac{3}{2} \pi^2$
Q 6. $S=1+\frac{1+3}{1!}+\frac{1+3+5}{2!}+\ldots \infty$. The value of $S$ is equal to
1. $4 e-2$
2. $4 e$
3. $5 e$
4. $7 e$
Post the exam, JEE Main 2025 April 3 Shift 2 Question Paper and answer keys will be released. This change will test students on Physics, Chemistry and Mathematics on an application level with questions focused on conceptual understanding and problem-solving skills. Candidates who have appeared for the examination or are preparing for upcoming shifts may refer to the JEE Main 2025 April 3 Question Paper PDF Download to analyze question types and difficulty levels.
Watch Live Analysis of 3 April Shift 2
For preparation, you can also refer to the previous years question paper from the following:
After the answer key is officially released, candidates will be able to check their answers and evaluate their performance using the direct link to the JEE Main 2025 April 3 Answer Key PDF Download. Once all the shifts are conducted, the question paper of JEE Main 2025 April 3 All Shifts will be published here. The JEE Main 2025 April 3 Answer Key Download and solutions from every expert will be updated on this page.
Practicing Previous years papers are very important to help you get an idea of how the exam paper is going to be like. You can also refer to the previous years question paper from the following:
Frequently Asked Questions (FAQs)
Students can pay attention to question pattern, difficulty level, and crucial topics addressed in the paper by analyzing it, which will help them in optimizing their preparation plan for the next attempt
The official answer key will be released on NTA website and The link to download the same will be made available here once it is released.
On Question asked by student community
HELLO,
The JEE Main application verification system uses the name you enter in the application form at the time of Aadhar Card verification so if you your Aadhaar was updated but still it is showing name not verifies then it means the new details have not been reflected in the online system use by NTA
Now what you can do is :-
1. First check the status of your Aadhaar card updates on the official UIDAI website by using your Update request Number.
2. Verify the details you have entered in application form like ensure that the name that you have entered in the JEE main application form exactly matches your newly updated Aadhaar card
3. You can use the NTA Mismatch Advisory like if a name mismatch pop up appears during the application process so for this NTA has provided the solution first close the pop up then a new window will appear that will allow you to enter the name exactly as it is on your Aadhaar card
4. If still the problem does not solve then you can contact the NTA Helpdesk
Visit the link to know more :- https://engineering.careers360.com/articles/how-correct-aadhaar-name-mismatch-in-jee-mains
Hope this Helps!
While filling the form of JEE Mains 2026 January session, upload the improvement marksheet, as your improvement marksheet is your final marksheet of class 12th AISSCE exams. The one that you got before the improvement doesn't matter now as you appeared for the compartment exam to increase your overall score. So, use the marksheet given to you after appearing for your improvement exam everywhere as that is your finalized class 12th marksheet.
Hello, Yes, this mismatch will absolutely cause a problem during your JEE Mains 2026 registration, but there is a clear solution.
You must enter your father's name "Girisharadya" (without the 'a') in the main application form, as it appears on your 10th-grade marksheet. The 10th marksheet is the primary, non-changeable document for all NTA applications.
When the system tries to verify this with your Aadhaar, it will detect a mismatch ("Girisharadya" vs. "Girisharadhya") and will show a pop-up warning. NTA has created a process for this: you will be given an option to enter your father's name as per your Aadhaar in a separate field. The system will then capture both spellings, allowing you to complete the registration.
However, since you have time before 2026, the safest and most highly recommended solution is to get your Aadhaar card (and your father's) corrected to match the spelling on your 10th marksheet ("Girisharadya"). This will prevent any confusion or problems later during JoSAA counselling and final document verification.
I hope you found this information helpful and for any study related queries you can ask in careers360 app, Have a great day!
Hello Aspirant,
Jee main's high scoring chapters:
For mathematics : Coordinate Geometry, Calculus (especially Integral Calculus), and Algebra (Complex Numbers, Quadratic Equations, Matrices, Determinants) .
For physics: Thermodynamics, Current Electricity, Electrostatics, and Optics.
For Chemistry: Periodic Table, Chemical Bonding, Hydrocarbons, and Chemical Kinetics.
This chapters are the highest scoring in jee main. Hope this will help u. Wish u good luck.
Hello,
If you are currently studying in Class 12 and haven’t yet received your registration number or roll number from your board, you can leave that field blank or enter “NA” (Not Applicable) in the JEE Main application form.
Once your board issues the official registration or roll number, you don’t need to worry, NTA verifies your board details later during counselling or admission, not during registration.
So, do not enter random numbers, use “NA” or skip if optional.
Hope you understand.
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