JEE Main 2025 April 3 Shift 1 Question Paper with Solutions - The JEE Main 2025 April 3 Shift 1 exam is conducted as part of the national-level engineering entrance test by NTA. Once the JEE Main examination is completed, candidates can access the JEE Main 2025 April 3 Shift 1 Question Paper with Solution to understand the correct approach for solving each question. Careers360 will assist students in evaluating their performance and refining their preparation for future attempts. Stay updated for the JEE Main 2025 April 3 Shift 1 Question Paper with Solutions and in-depth exam review. To see the correct answer, you can download JEE Main April 3 Answer Key 2025 Shift 1 on this page.
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Details | Information |
Total Time | 3 hours (180 minutes) |
Total Questions | 75 questions |
Maximum Marks | 300 marks |
Exam Medium | Available in 13 languages |
Exam Mode | Computer Based Test (CBT) |
Question Type | MCQs and Numerical Value-Based |
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The JEE Main 2025 April 3 Shift 1 Question Paper is now accessible to view as the examination is over. Candidates will have to demonstrate their ability in topics related to Physics, Chemistry and Mathematics while addressing both conceptual information and numerical problems. Test-takers of the JEE Main 2025 April 3 Shift 1 Question Paper with Solutions PDF can check their results now and students preparing for upcoming shifts should use it for planning purposes. Students can access the JEE Main 2025 April 3 Shift 1 Paper PDF Download to study all questions followed by solutions.
Watch Live Analysis of 3 April Shift 1
Maths Questions
Q 1. Let $A$ be $3 \times 3$ matrix such that $\operatorname{det}(A)=5$. If $\operatorname{det}(3 \operatorname{adj}(2 A \operatorname{adj}(2 A)))=2^{\alpha} \cdot 3^\beta \cdot 5^\gamma$, then $(\alpha+\beta+\gamma)$ is equal to
1. 25
2. 26
3. 27
4. 28
Q 2. The sum of all rational numbers in $(2+\sqrt{3})^8$ is
1. 18117
2. 18817
3. 17280
4. 1800
Q 3. If the sum $\sum_{r=1}^9\left(\frac{r+3}{r}\right) \cdot{ }^9 C_r=\alpha \cdot\left(\frac{3}{2}\right)^9-\beta$, then the value of $(\alpha+\beta)^2$ is equal to
1. 9
2. 81
3. 27
4. 36
3 april shift 1
Q.1 Which of the following ion shows spin only magnetic moment of 4.9 B.M.
1) $\mathrm{Mn}^{2+}$
2) $\mathrm{Cr}^{2+}$
3) $\mathrm{Fe}^{3+}$
4) $\mathrm{Co}^{2+}$
Q.2 Which of following has highest atomic number
1 Po
2 Pt
3 Pr
4 Pb
Q.3 An ideal gas with an adiabatic exponent 1.5 , initially at $27^{\circ} \mathrm{C}$ is compressed adiabatically from 800 cc to 200 C . The final temperature of the gas is
(A) 700 K
(B) 500 K
(C) 250 K
(D) 600 K
Q.4 2 moles each of ethylene glycol and glucose are mixed with 500 g of water. Find the boiling point of solution.
Given : $\mathrm{K}_{\mathrm{b}}=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$
$1 \quad 377.16 \mathrm{~K}$
$2 \quad 368.84 \mathrm{~K}$
$3 \quad 376.16 \mathrm{~K}$
$4 \quad 369.84 \mathrm{~K}$
Q.5 0.5 g of an organic compound gives $1.46 \mathrm{~g} \mathrm{CO}_2$ and $0.9 \mathrm{~g} \mathrm{H}_2 \mathrm{O}$. What is the % of carbon in organic sample.
Physics
Q 1) An ideal gas with an adiabatic exponent 1.5 , initially at $27^{\circ} \mathrm{C}$ is compressed adiabatically from 800 cc to 200 cc . The final temperature of the gas is
Q 2) In YDSE, light of intensity of $4I$ and $9I$ passes through two slits respectively. The difference of maximum and minimum intensity of the interference pattern is
The difficulty level of the JEE Main 2025 April 3 Shift 1 Question Paper is expected to be moderate to difficult. Below is a subject-wise breakdown of the expected difficulty and key topics covered:
Subject | Expected Difficulty Level | Key Topics Covered |
Physics | Moderate to Difficult | Optics, Thermodynamics, Electromagnetism |
Difficult | Differential Equations, Probability, Matrices | |
Chemistry | Easy to Moderate | Coordination Compounds, Organic Reactions, Chemical Kinetics |
Candidates can refer to the JEE Main 2025 Shift 1 Question Paper with Solutions PDF for a detailed step-by-step explanation of the questions and solutions. Understanding the JEE Main 2025 April 3 All Shifts Question Paper will help students in identifying important concepts and recurring question patterns.
Students can access the JEE Main 2025 April 3 Answer Key through PDF download after the exam date for checking responses against official solutions. The probable scores can be estimated through the JEE Main 2025 April 3 Answer Key Download after the exam. Candidates must frequently visit this page to access the most recent information about the JEE Main 2025 April 3 Shift 1 Paper PDF and the entire solution set.
Frequently Asked Questions (FAQs)
Students will find the question paper and solutions available shortly after exams end for them to evaluate their responses and enhance their exam preparation.
The answer key will become accessible through the official website of NTA after its official release. Users can access the link through this page.
On Question asked by student community
Hello,
Based on your JEE Main Paper 2 percentile (96.3), CRL 2566, NATA percentile (88.69), and Class 12 score (88.8%), you have a good academic profile for B.Arch admissions.
Since COMEDK has its own merit preparation for B.Arch admissions, your exact rank cannot be predicted before the merit list is
Hello Student,
With your rank og 129537 as an OBC candidate, it is highly unlikely that you will get a seat in core branches. There is a possibility, though, that you might get a seat in lower-tier NITs or GFTIs, in branches such as Biotechnology , Mining, Metallurgy and Civil
Hello Dear Student,
Neither branch is universally "better"; it depends entirely on your interests.
Computer Science Engineering (CSE) focuses on software, coding, and algorithms, and generally yields higher immediate IT salaries. Electronics and Communication Engineering (ECE) focuses on hardware, microchips, and circuits, offering a dual-advantage of core hardware jobs +
Hey there,
With 94.95 percentile in JEE Main, Rajasthan home state, and REAP OBC-NCL merit rank 202, you have a very good chance of getting B.Tech CSE at MBM University, Jodhpur. While admission cannot be guaranteed until the official seat allotment is announced, your profile is competitive based on previous
Hello Dear Student,
You will not be able to secure a seat (CS or core branches) at the COEP Technological University with your current score. COEP is highly competitive, and closing ranks for the SC category normally range between \(\approx 10{,}000\) to (20,000), well below your (38,647) category rank.
Hope
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