JEE Main 2025 April 3 Shift 1 Question Paper with Solutions - The JEE Main 2025 April 3 Shift 1 exam is conducted as part of the national-level engineering entrance test by NTA. Once the JEE Main examination is completed, candidates can access the JEE Main 2025 April 3 Shift 1 Question Paper with Solution to understand the correct approach for solving each question. Careers360 will assist students in evaluating their performance and refining their preparation for future attempts. Stay updated for the JEE Main 2025 April 3 Shift 1 Question Paper with Solutions and in-depth exam review. To see the correct answer, you can download JEE Main April 3 Answer Key 2025 Shift 1 on this page.
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Details | Information |
Total Time | 3 hours (180 minutes) |
Total Questions | 75 questions |
Maximum Marks | 300 marks |
Exam Medium | Available in 13 languages |
Exam Mode | Computer Based Test (CBT) |
Question Type | MCQs and Numerical Value-Based |
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The JEE Main 2025 April 3 Shift 1 Question Paper is now accessible to view as the examination is over. Candidates will have to demonstrate their ability in topics related to Physics, Chemistry and Mathematics while addressing both conceptual information and numerical problems. Test-takers of the JEE Main 2025 April 3 Shift 1 Question Paper with Solutions PDF can check their results now and students preparing for upcoming shifts should use it for planning purposes. Students can access the JEE Main 2025 April 3 Shift 1 Paper PDF Download to study all questions followed by solutions.
Watch Live Analysis of 3 April Shift 1
Maths Questions
Q 1. Let $A$ be $3 \times 3$ matrix such that $\operatorname{det}(A)=5$. If $\operatorname{det}(3 \operatorname{adj}(2 A \operatorname{adj}(2 A)))=2^{\alpha} \cdot 3^\beta \cdot 5^\gamma$, then $(\alpha+\beta+\gamma)$ is equal to
1. 25
2. 26
3. 27
4. 28
Q 2. The sum of all rational numbers in $(2+\sqrt{3})^8$ is
1. 18117
2. 18817
3. 17280
4. 1800
Q 3. If the sum $\sum_{r=1}^9\left(\frac{r+3}{r}\right) \cdot{ }^9 C_r=\alpha \cdot\left(\frac{3}{2}\right)^9-\beta$, then the value of $(\alpha+\beta)^2$ is equal to
1. 9
2. 81
3. 27
4. 36
3 april shift 1
Q.1 Which of the following ion shows spin only magnetic moment of 4.9 B.M.
1) $\mathrm{Mn}^{2+}$
2) $\mathrm{Cr}^{2+}$
3) $\mathrm{Fe}^{3+}$
4) $\mathrm{Co}^{2+}$
Q.2 Which of following has highest atomic number
1 Po
2 Pt
3 Pr
4 Pb
Q.3 An ideal gas with an adiabatic exponent 1.5 , initially at $27^{\circ} \mathrm{C}$ is compressed adiabatically from 800 cc to 200 C . The final temperature of the gas is
(A) 700 K
(B) 500 K
(C) 250 K
(D) 600 K
Q.4 2 moles each of ethylene glycol and glucose are mixed with 500 g of water. Find the boiling point of solution.
Given : $\mathrm{K}_{\mathrm{b}}=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$
$1 \quad 377.16 \mathrm{~K}$
$2 \quad 368.84 \mathrm{~K}$
$3 \quad 376.16 \mathrm{~K}$
$4 \quad 369.84 \mathrm{~K}$
Q.5 0.5 g of an organic compound gives $1.46 \mathrm{~g} \mathrm{CO}_2$ and $0.9 \mathrm{~g} \mathrm{H}_2 \mathrm{O}$. What is the % of carbon in organic sample.
Physics
Q 1) An ideal gas with an adiabatic exponent 1.5 , initially at $27^{\circ} \mathrm{C}$ is compressed adiabatically from 800 cc to 200 cc . The final temperature of the gas is
Q 2) In YDSE, light of intensity of $4I$ and $9I$ passes through two slits respectively. The difference of maximum and minimum intensity of the interference pattern is
The difficulty level of the JEE Main 2025 April 3 Shift 1 Question Paper is expected to be moderate to difficult. Below is a subject-wise breakdown of the expected difficulty and key topics covered:
Subject | Expected Difficulty Level | Key Topics Covered |
Physics | Moderate to Difficult | Optics, Thermodynamics, Electromagnetism |
Difficult | Differential Equations, Probability, Matrices | |
Chemistry | Easy to Moderate | Coordination Compounds, Organic Reactions, Chemical Kinetics |
Candidates can refer to the JEE Main 2025 Shift 1 Question Paper with Solutions PDF for a detailed step-by-step explanation of the questions and solutions. Understanding the JEE Main 2025 April 3 All Shifts Question Paper will help students in identifying important concepts and recurring question patterns.
Students can access the JEE Main 2025 April 3 Answer Key through PDF download after the exam date for checking responses against official solutions. The probable scores can be estimated through the JEE Main 2025 April 3 Answer Key Download after the exam. Candidates must frequently visit this page to access the most recent information about the JEE Main 2025 April 3 Shift 1 Paper PDF and the entire solution set.
Frequently Asked Questions (FAQs)
Students will find the question paper and solutions available shortly after exams end for them to evaluate their responses and enhance their exam preparation.
The answer key will become accessible through the official website of NTA after its official release. Users can access the link through this page.
On Question asked by student community
Usha Mittal of Technology has no AI quota officially. please contact the college for any mangement quota seats.
Hello student,
Kindly go through the article to understand what a safe percentile is in JEE Main 2026 to qualify for JEE Advanced.
Link - JEE Main 2026 Advanced Qualifying Percentile
Hope this will be helpful!
To get admission, your JEE Main rank should be between 2 to 5 lakh.
For mode details visit- https://www.careers360.com/university/odisha-university-of-technology-and-research-bhubaneswar/cut-off
Hi !
I am sorry to hear that. I wish you the best this year.
Yes, you can apply for JEE Mains while you are in 12th class. While filling the application form, make sure you state clearly that you are 'Appearing' in 12th boards. You need to also make
decent chances actually as home state quota seats are 50%. allotments will depend on the JEE rank and not percentile though. in 2025, for female supernumerary it closed at 9286 rank while for open gen it closed at 5573.
So, would advise to use this tool to check the probable
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