JEE Main 2025 April 3 Shift 1 Question Paper with Solutions - The JEE Main 2025 April 3 Shift 1 exam is conducted as part of the national-level engineering entrance test by NTA. Once the JEE Main examination is completed, candidates can access the JEE Main 2025 April 3 Shift 1 Question Paper with Solution to understand the correct approach for solving each question. Careers360 will assist students in evaluating their performance and refining their preparation for future attempts. Stay updated for the JEE Main 2025 April 3 Shift 1 Question Paper with Solutions and in-depth exam review. To see the correct answer, you can download JEE Main April 3 Answer Key 2025 Shift 1 on this page.
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Details | Information |
Total Time | 3 hours (180 minutes) |
Total Questions | 75 questions |
Maximum Marks | 300 marks |
Exam Medium | Available in 13 languages |
Exam Mode | Computer Based Test (CBT) |
Question Type | MCQs and Numerical Value-Based |
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The JEE Main 2025 April 3 Shift 1 Question Paper is now accessible to view as the examination is over. Candidates will have to demonstrate their ability in topics related to Physics, Chemistry and Mathematics while addressing both conceptual information and numerical problems. Test-takers of the JEE Main 2025 April 3 Shift 1 Question Paper with Solutions PDF can check their results now and students preparing for upcoming shifts should use it for planning purposes. Students can access the JEE Main 2025 April 3 Shift 1 Paper PDF Download to study all questions followed by solutions.
Watch Live Analysis of 3 April Shift 1
Maths Questions
Q 1. Let $A$ be $3 \times 3$ matrix such that $\operatorname{det}(A)=5$. If $\operatorname{det}(3 \operatorname{adj}(2 A \operatorname{adj}(2 A)))=2^{\alpha} \cdot 3^\beta \cdot 5^\gamma$, then $(\alpha+\beta+\gamma)$ is equal to
1. 25
2. 26
3. 27
4. 28
Q 2. The sum of all rational numbers in $(2+\sqrt{3})^8$ is
1. 18117
2. 18817
3. 17280
4. 1800
Q 3. If the sum $\sum_{r=1}^9\left(\frac{r+3}{r}\right) \cdot{ }^9 C_r=\alpha \cdot\left(\frac{3}{2}\right)^9-\beta$, then the value of $(\alpha+\beta)^2$ is equal to
1. 9
2. 81
3. 27
4. 36
3 april shift 1
Q.1 Which of the following ion shows spin only magnetic moment of 4.9 B.M.
1) $\mathrm{Mn}^{2+}$
2) $\mathrm{Cr}^{2+}$
3) $\mathrm{Fe}^{3+}$
4) $\mathrm{Co}^{2+}$
Q.2 Which of following has highest atomic number
1 Po
2 Pt
3 Pr
4 Pb
Q.3 An ideal gas with an adiabatic exponent 1.5 , initially at $27^{\circ} \mathrm{C}$ is compressed adiabatically from 800 cc to 200 C . The final temperature of the gas is
(A) 700 K
(B) 500 K
(C) 250 K
(D) 600 K
Q.4 2 moles each of ethylene glycol and glucose are mixed with 500 g of water. Find the boiling point of solution.
Given : $\mathrm{K}_{\mathrm{b}}=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$
$1 \quad 377.16 \mathrm{~K}$
$2 \quad 368.84 \mathrm{~K}$
$3 \quad 376.16 \mathrm{~K}$
$4 \quad 369.84 \mathrm{~K}$
Q.5 0.5 g of an organic compound gives $1.46 \mathrm{~g} \mathrm{CO}_2$ and $0.9 \mathrm{~g} \mathrm{H}_2 \mathrm{O}$. What is the % of carbon in organic sample.
Physics
Q 1) An ideal gas with an adiabatic exponent 1.5 , initially at $27^{\circ} \mathrm{C}$ is compressed adiabatically from 800 cc to 200 cc . The final temperature of the gas is
Q 2) In YDSE, light of intensity of $4I$ and $9I$ passes through two slits respectively. The difference of maximum and minimum intensity of the interference pattern is
The difficulty level of the JEE Main 2025 April 3 Shift 1 Question Paper is expected to be moderate to difficult. Below is a subject-wise breakdown of the expected difficulty and key topics covered:
Subject | Expected Difficulty Level | Key Topics Covered |
Physics | Moderate to Difficult | Optics, Thermodynamics, Electromagnetism |
Difficult | Differential Equations, Probability, Matrices | |
Chemistry | Easy to Moderate | Coordination Compounds, Organic Reactions, Chemical Kinetics |
Candidates can refer to the JEE Main 2025 Shift 1 Question Paper with Solutions PDF for a detailed step-by-step explanation of the questions and solutions. Understanding the JEE Main 2025 April 3 All Shifts Question Paper will help students in identifying important concepts and recurring question patterns.
Students can access the JEE Main 2025 April 3 Answer Key through PDF download after the exam date for checking responses against official solutions. The probable scores can be estimated through the JEE Main 2025 April 3 Answer Key Download after the exam. Candidates must frequently visit this page to access the most recent information about the JEE Main 2025 April 3 Shift 1 Paper PDF and the entire solution set.
Frequently Asked Questions (FAQs)
The answer key will become accessible through the official website of NTA after its official release. Users can access the link through this page.
Students will find the question paper and solutions available shortly after exams end for them to evaluate their responses and enhance their exam preparation.
On Question asked by student community
Hello there,
Understanding and solving different question papers is one of the best practices for preparation ,especially when it comes to JEE. It gives you a proper understanding of the exam pattern, important topics to cover, and the marking scheme.
Here is the link attached from the official website of Careers360 which will provide you with the question papers of JEE exam. Hope it helps!
https://engineering.careers360.com/articles/jee-main-question-papers
thank you!
Hello aspirant,
In order to prepare for the JEE Main 2026 exam, it is strongly advised that students complete the JEE Main 2025 Question Paper. This will help them comprehend the exam's difficulty level and question kinds. The JEE Main 2026 session 1 test will be administered by NTA from January 21 to 30, while the session 2 exam will take place from April 2 to 9.
To get the previous year question papers, you can visit our site through following link:
https://engineering.careers360.com/articles/jee-main-question-papers
Thank you
With a BC-E category certificate, EWS certificate, and Telangana home-state quota, your chances of getting admission to AIML or related CSE branches in CBIT, VNR VJIET, or similar top private colleges in Telangana depend mainly on your JEE Main percentile and the TS EAMCET counselling process, because these colleges fill seats through both TS EAMCET ranks and JEE Main scores (Category-B seats).
For Category-A seats (through TS EAMCET), JEE Main percentile is not considered. Admission is purely based on your TS EAMCET rank, reservation category, gender, and home-state status. CBIT and VNR are highly competitive, especially for AIML, CSE, and IT branches, so you generally need a very strong TS EAMCET rank (usually within a few thousand for BC-E candidates, sometimes slightly relaxed for girls).
For Category-B seats (JEE Main quota), JEE Main percentile matters. Based on recent trends, to have a realistic chance:
For CBIT (AIML / CSE / IT), a JEE Main percentile of around 95+ is usually expected, even for reserved categories, because Category-B seats are limited and competition is high.
For VNR VJIET (AIML / CSE / IT), candidates with 92–95 percentile sometimes have chances, depending on availability and the specific branch.
If your percentile is below 90, getting AIML or core CSE in CBIT or VNR becomes difficult, but you may still have chances in slightly lower-demand branches (like ECE, EEE, or emerging specialisations) or in other good private colleges affiliated with JNTU or autonomous institutions.
Your BC-E and EWS certificates do help mainly in TS EAMCET counselling (Category-A seats), not significantly in Category-B (JEE Main) admissions, where merit largely dominates. Home-state status is already assumed for these colleges, so there is no extra advantage beyond eligibility.
In summary, if your JEE Main percentile is 95 or above, you can reasonably target AIML/CSE in VNR and possibly CBIT through Category-B. If it is 90–94, VNR or related branches are more realistic than CBIT. Below that, it is better to focus on TS EAMCET performance or consider other reputed Telangana colleges offering AIML. If you want, you can share your exact JEE Main percentile and TS EAMCET rank, and I can give you a more precise college- and branch-wise estimate.
Hello,
JEE Mains is a national level entrance examination conducted for admission to UG engineering course in IITs, NITs, etc. This also is a qualifying test for JEE Advanced.
Practicing with previous year question paper will give you on overview of the entire exam pattern, marking scheme, types of questions asked, etc.
Check out the official website of Careers360 for the question papers, preparation tips, etc.
https://engineering.careers360.com/articles/jee-main-question-papers
Careers360 is also conducting a free JEE Mains mock test which you can attempt. The last date for registration is 8th January, 2026.
https://learn.careers360.com/test-series-jee-main-2026-free-mock-test/
Thank you.
Hello,
The link to the mock test series is attached here. The mock test of Careers360 is completely free, and the structure and questions were prepared keeping in mind the exam of JEE Mains. The registration is ongoing. the last date of registration on 8th January.
https://learn.careers360.com/test-series-jee-main-free-mock-test/
Thank you.
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