जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 प्रश्न पत्र समाधान के साथ - पीडीएफ डाउनलोड करें
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क्या आप समाधान के साथ जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 प्रश्न पत्र की तलाश कर रहे हैं? तलाश करने के लिए यह सही जगह है! जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 प्रश्न पत्र समाधान के साथ जेईई मेन परीक्षा समाप्त होने के तुरंत बाद इस पृष्ठ पर डाउनलोड किया जा सकता है। अप्रैल में जेईई मेन परीक्षा का दूसरा चरण आयोजित किया जा रहा है और प्रत्येक छात्र और शिक्षक अब अपने आखिरी प्रयास के लिए तैयार हो रहे हैं! अधिक जानकारी के लिए जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 प्रश्न पत्र समाधान लेख के साथ पढ़ते रहें।
जेईई मेन 2025 पेपर: 2 अप्रैल (शिफ्ट-2) के मेमोरी बेस्ड प्रश्न और विश्लेषण
This Story also Contains
- जेईई मेन 2025 2 अप्रैल शिफ्ट 2 प्रश्न पत्र पैटर्न और संरचना
- कुछ स्मृति आधारित प्रश्न (Some Memory Based Questions)
- जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 प्रश्न पत्र समाधान और विश्लेषण के साथ - विषयवार अवलोकन (अपेक्षित)
- जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 उत्तर कुंजी और समाधान पीडीएफ डाउनलोड करें
जेईई मेन 2025 2 अप्रैल शिफ्ट 2 प्रश्न पत्र पैटर्न और संरचना
विषय | विवरण |
कुल समय | 3 घंटे (180 मिनट) |
कुल सवाल | 75 प्रश्न |
अधिकतम अंक | 300 अंक |
परीक्षा माध्यम | 13 भाषाओं में उपलब्ध है |
परीक्षा मोड | कंप्यूटर आधारित टेस्ट (सीबीटी) |
प्रश्न प्रकार | एमसीक्यू और संख्यात्मक मूल्य-आधारित |
यह भी पढ़ें: जेईई मेन्स 2025 2 अप्रैल शिफ्ट 1 प्रश्न पत्र समाधान के साथ
कुछ स्मृति आधारित प्रश्न (Some Memory Based Questions)
2 अप्रैल शिफ्ट 2 पेपर के स्मृति आधारित प्रश्न नीचे दिए गए हैं
2nd April Shift 2 Maths
Q 1. Total number of terms in an A.P are even. Sum of odd terms is 24 and sum of even terms is 30. Last term exceeds the first term by $\frac{21}{2}$. Find the total number of terms.
Q 2. If the domain of the function $f(x)=\frac{1}{\sqrt{3 x+10-x^2}}+\frac{1}{\sqrt{x+|x|}}$ is $(a, b)$ then $(1+a)^2+b^2$ is equal to
1. 25
2. 16
3. 24
4. 26
Q 3. If $\theta \in\left[-\frac{7 \pi}{6}, \frac{4 \pi}{3}\right]$, then number solutions of $\sqrt{3} \operatorname{cosec}^2 \theta-2(\sqrt{3}-1) \operatorname{cosec} \theta-4=0$, is
Q 4. Find the eccentricity of ellipse in which length of minor axis is equal to onefourth of the distance between foci
1. $\frac{4}{\sqrt{17}}$
2. $\frac{2}{\sqrt{17}}$
3. $\frac{7}{\sqrt{17}}$
4. $\frac{8}{\sqrt{17}}$
Chemistry
Q.1 Which of the following statement(s) is correct is/are for the adiabatic process?
A. Molar heat capacity is zero.
B. Molar heat capacity is infinite.
C. Work done on gas is equal to increase in internal energy
D. The increase in temperature results in decrease in internal energy
1 A and C only
2 B and C only
3 A and D only
Q.2 Which does not follow general trends among Halogens
(1) I. E
(2) Electro Affinity
(3) Ionic Radius
(4) Covalent Radius
Q.3 Relation between magnetic sucesptibility and magnetic permeability
Q.4 Which Amino acids is optically inactive
(1) Alanine
(2) Glycine
(3) Valine
(4) Aspartic Acid
Q.4 In the following graph between $\mathrm{t}_{1 / 2}$ and initial concentration [ $\mathrm{A}_0$ ]. If slope of the graph is $79.62 \mathrm{M}^{-1} \mathrm{~min}$. and initial concentration is 2.5 M . Find the concentration of A after 10 min .
Q.5 $100 \mathrm{~g} \mathrm{CaCO}_3$ when reacted with 0.19 mole of HCl then the moles of $\mathrm{CaCl}_2$ formed is $\mathrm{P} \times 10^{-3} \mathrm{~mol}$. Find P ?
Q.6 Vapour pressure of pure liquid A is 200 mm Hg . If 1 mol of A and 3 mol of B are mixed. Assuming solution to be ideal, find the vapour pressure of pure liquid ' B ', if total pressure of solution is 500 mm Hg
Q.7
$$
\begin{aligned}
& \mathrm{CaCO}_3+2 \mathrm{HCl} \rightleftharpoons \mathrm{CaCl}_2+\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2 \\
& 1000 \mathrm{~g} 2 \mathrm{l}, 2 \mathrm{M}
\end{aligned}
$$
Find moles of $\mathrm{CaCl}_2$ Produced.
(1) 10
(2) 2
(3) 6
(4) 8
Q.8 Which of the following property does not have the regular trend in group $17^{\text {th }}$ of the period table?
(1)XAtomic size
(2) I.E.
(3) Electronegativity
(4)Electron Affinity
Q.9 Statement-I: Ga has larger metallic radius than Al .
Statement-II: $\mathrm{Ga}^{+3}$ has larger ionic radius than $\mathrm{Al}^{+3}$.
In the light of the above statements, choose the most appropriate answer from the options given below:
(1) Both Statement-I and Statement-II are false
(2) Statement-I is false but Statement-II is true
(3) Both Statement I and Statement-II are true
(4) Statement-I is true but Statement-II is false
Q.10 In $A X_A Y, X$ and $Y$ are the top two electronegative atoms and A has the highest ionization enthalpy in its period. Predict the hybridization of $A X_A Y$.
(1) $\mathrm{sp}^3$
(2) $\mathrm{sp}^3 \mathrm{~d}$
(3) $\mathrm{sp}^3 \mathrm{~d}^2$
(4) $s p^2$
Physics
Q.1 What is the units of viscosity, intensity of wave, and pressure gradient
Q.2 The figure shows an infinite plane having uniform charge density $\sigma$ and a small charged particle having charge $q$ and mass $m$ suspended by a light insulating thread. Find $\sigma$ if the charge is in equilibrium.
$1 \quad \frac{2 f_0 m g}{q}$
$2 \frac{\varepsilon_0 m g}{2 q}$
$3 \quad \frac{2 q}{\varepsilon_0 m g}$
$4 \frac{2 q \varepsilon_0}{m g}$
Q.3 Find the ratio of $\left(\gamma=\frac{C_p}{C_v}\right)$ for two gases having degree of freedoms $f=3$ and $f=5$.
Q.4 The ratio of the magnetic field to the center of the circular coil to the magnetic field at a distance $x$ from the center of a circular coil
$
\left(\frac{x}{R}=3 / 4\right)
$
Q.5 Two point charges $q$ and $9 q$ are placed at a distance of $l$ from each other. Then the electric field is zero at a
1 Distance $\frac{l}{4}$ from charge $9 q$
2 Distance $\frac{3 l}{4}$ from charge $q 3$ Distance $\frac{l}{3}$ from charge $9 q$
4 Distance $\frac{l}{4}$ from charge $q$
Q.6 Given the equation of a hyperbola $H: \frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ and its directrix is $x=\sqrt{\frac{10}{81}}$ with a focus at $(\sqrt{10}, 0)$, then find the value of $9\left(e+l^2\right)$, where $I$ is length of latus rectum is
1 2697
2 2597
$3 \quad 2487$
$4 \quad 2587$
Q. Two point charges $q$ and $9 q$ are placed at distance of $l$ from each other. Then the electric field is zero at a
1 Distance $\frac{l}{4}$ from charge $9 q$
2 Distance $\frac{3 l}{4}$ from charge $q$3 Distance $\frac{l}{3}$ from charge $9 q$
4 Distance $\frac{l}{4}$ from charge $q$
जेईई मेन 2025 2 अप्रैल शिफ्ट 2 प्रश्न पत्र समाधान के साथ - हाइलाइट्स (JEE Main 2025 April 2 Shift 2 Question Paper with Solutions - Highlights)
परीक्षा तिथि: 2 अप्रैल, 2025 |
पाली का समय: दूसरी पाली (शाम) |
विषय: भौतिक विज्ञान, रसायन विज्ञान, गणित |
प्रश्न पत्र उपलब्धता: परीक्षा के बाद |
उत्तर कुंजी जारी: परीक्षा के बाद प्रकाशित की जाएगी |
जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 प्रश्न पत्र समाधान और विश्लेषण के साथ - विषयवार अवलोकन (अपेक्षित)
जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 प्रश्न पत्र मध्यम कठिनाई स्तर का पालन करने की उम्मीद है। उम्मीदवार समाधानों के विस्तृत चरण-दर-चरण विश्लेषण के लिए समाधान पीडीएफ के साथ जेईई मेन 2025 2 अप्रैल शिफ्ट 2 प्रश्न पत्र का उल्लेख कर सकते हैं। जेईई मेन 2025 2 अप्रैल 2 प्रश्न पत्र पीडीएफ डाउनलोड परीक्षा समाप्त होने के तुरंत बाद इस पृष्ठ पर उपलब्ध होगा!
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जेईई मेन 2025 अप्रैल 2 शिफ्ट 2 उत्तर कुंजी और समाधान पीडीएफ डाउनलोड करें
परीक्षा समाप्त होने के बाद छात्रों को अपने उत्तरों को सत्यापित करने के लिए जेईई मेन 2025 2 अप्रैल उत्तर कुंजी पीडीएफ डाउनलोड उपलब्ध होगा। जेईई मेन 2025 2 अप्रैल सभी शिफ्ट प्रश्न पत्र सभी सत्र समाप्त होने के बाद जारी किए जाएंगे। जेईई मेन 2025 2 अप्रैल उत्तर कुंजी डाउनलोड और संपूर्ण समाधान सेट पर अपडेट की जांच करते रहें।
Frequently Asked Questions (FAQs)
Q: समाधान के साथ जेईई मेन 2025 2 अप्रैल शिफ्ट 2 प्रश्न पत्र कब तक प्राप्त किया जा सकता है?
A:
परीक्षार्थी परीक्षण पूरा होने के तुरंत बाद जेईई मेन 2025 2 अप्रैल की पाली 2 के प्रश्न पत्र को समाधान के साथ देख सकते हैं।
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With your JEE Main CRL 476199 and OBC rank 173160, admission to Civil Engineering at Indira Gandhi Institute of Technology (IGIT), Sarang under JoSAA counseling is highly unlikely, since even civil branch closing ranks in IGIT usually remain within 50k–80k CRL (general) and much lower for OBC. However, you may try through state counseling (Odisha JEE) where cutoffs are sometimes more flexible, but chances are still very low. You should keep other private/state colleges as backup.
Hey! With a JEE Main rank of around 1 lakh, you still have a good chance to get admission in several engineering colleges that provide quality education at a reasonable fee. For government colleges, you can aim for NITs or GFTIs in branches like Civil, Mechanical, or Chemical Engineering, as these usually have slightly higher closing ranks. For example, colleges like NIT Goa, NIT Puducherry, and NIT Srinagar might have seats available in certain branches.
Apart from NITs, state government engineering colleges are also a good option, especially under home state quota. They often have lower tuition fees and good faculty, so you can get a solid education without spending much.
If you are open to private colleges, there are options like VIT Vellore, KIIT Bhubaneswar, or Amity University that provide decent infrastructure and placements. However, the fees may be higher than government colleges.
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No, you can’t use a previous year’s JEE rank for the current year’s WBJEE counselling. Only the JEE Main rank of the same admission year is valid along with that year’s WBJEE rank.
Hello Aspirant,
Finding specific JEE exam centers for Whitefield is difficult as they vary each year. The list is released on the admit card . However, many centers are usually iON Digital Zones. For coaching, top centers near Whitefield include Aakash Institute , Narayana Institute , and Allen Career Institute . These centers have branches in and around the Whitefield area to help you prepare for the exam.
Its okay if you missed jee this year you can drop year for JEE to get into a government institute like IET Lucknow to get better placement here and fees is also less in comparison with SRMU but it also means delaying a year with no guarantee success.
Joining a private college like SRMU now avoids losing a year,but it comes with higher costs and generally lower placement statistics compared to top government institutions.
ultimately Your decision should be based on your skill whether you can significantly improve your JEE score versus accepting a faster, but potentially more expensive, path to your B.Tech.
Hope it helps..
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