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How to calculate JEE Main Marks from Answer Key: NTA has uploaded the final JEE Main answer key session 2 on the official website, jeemain.nta.nic.in. The authority has released the JEE Main 2026 final answer key on April 20, 2026. Applicants can now finally estimate their final scores with the answer key. The authority had released the JEE Main 2026 provisional answer key for session 2 online. Aspirants can calculate their JEE Main marks from the answer key. The process is very simple. First, they must download their recorded responses and the provisional JEE Main answer key from the official NTA website. Candidates should follow the official marking scheme to calculate the JEE Mains marks from the answer key. Later, match it with the JEE marks vs rank to determine the expected rank.
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Candidates can also use the third-party JEE Main score predictor tool to calculate scores with the JEE Mains answer key. However, candidates may note that the scores are tentative and must wait for the final answer key and results. Candidates can also check the JEE Main college predictor to find out the best colleges. Scroll down to check more details on how to calculate JEE Main Marks from the answer key.
To calculate JEE Mains marks from the answer key, candidates should follow the steps below.
Visit the official website- jeemain.nta.nic.in
Click on the JEE Main 2026 session 2 answer key link
Enter the application number and password along with the other details asked.
Now click on “View response sheet.”
The complete question paper, along with the provisional JEE Main answer key and the candidate’s response sheet will appear on the screen.
Candidates should download the same to calculate the JEE Mains marks from the answer key. To do the same, they first give each correct answer +4 and deduct the -1 mark for each wrong response.
Lastly, add all the positive marks and subtract the negative one to calculate the marks online.
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The process of calculating the JEE Main 2026 percentile is called the JEE Main normalisation process.
Below is the NTA's formula to calculate the JEE Main percentile:
Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) equal to or less than the candidate)/(Total number of candidates who appeared in that session)
| Percentile Score | Calculation | |
|---|---|---|
Total Percentile (T1P): | (100 x No. of candidates from the session with raw score equal to or less than T1 score) / Total No. of candidates appeared in the session | |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than the M1 score in Mathematics) / Total No. of candidates appeared in the session | |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session | |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session | |
The JEE Main 2026 marking scheme must be followed while calculating the JEE Main Marks from the Answer Key. There are total of 75 questions of 300 marks in JEE Main 2026. Each question will have +4 marks, and -1 mark will be deducted for an incorrect response.
| Types of Resonance | Marking Scheme |
|---|---|
Correct Response | +4 marks awarded |
Incorrect Response | -1 marks deducted |
No answer | No marks |
Marked for review | No marks |
Subject | Physics | Chemistry | Mathematics |
|---|---|---|---|
Section A (MCQs) : All Compulsory | 20 | 20 | 20 |
Section (Numerical) | 05 | 05 | 05 |
Total Number of Questions | 25 | 25 | 25 |
Marks Distribution | 25 x 4 = 100 | 25 x 4 = 100 | 25 x 4 = 100 |
Total Marks | 300 | ||
Candidates can check the expected JEE Main marks vs percentile as per the latest answer key.
| Marks | Percentile |
|---|---|
292- 275 | 99.99890732-99.99289757 |
273-250 | 99.9926244-99.95228621 |
249-228 | 99.95028296-99.85977245 |
227-200 | 99.84556758-99.57503767 |
199-170 | 99.56019541-98.87981861 |
169-145 | 98.85149993-97.83312011 |
144-123 | 97.79414778-96.25929349 |
122-100 | 96.2215049-93.8020333 |
99-81 | 93.67910655-90.4734501 |
80-68 | 90.27631202-86.72136148 |
67-54 | 86.43043484-80.96656848 |
53-41 | 80.05827638-70.26839007 |
40-27 | 69.5797271-50.20710881 |
26-16 | 48.72452115-28.31294419 |
15-7 | 27.10088644-12.93936069 |
6-0 | 12.15909453-5.71472799 |
The JEE Main percentile is calculated with the normalisation formula. First of all, the JEE Main April 5 shift 2 raw score is obtained by adding and subtracting marks for the correct and wrong answers in accordance with the JEE Main marking scheme 2026. Check the JEE Main normalisation formula for percentile score.

Frequently Asked Questions (FAQs)
Yes, the JEE Main session 2 provisional answer key is out.
The JEE Main 2026 session 2 final answer key is expecte to release in April 2026.
On Question asked by student community
Hello Student,
No, It is not mandatory for every B.tech Admission that a student must have appeared for JEE main or CUET. The admission process depends on the college or University you are applying to. Many Institute admit students through JEE main score while some University conduct there own entrance
Hello Student,
If you JEE mains 2026 category rank is around 60,000, your chance of getting admission to NITs or IIITs depend largely on your category, CRL Rank, Home state quota and preferred branch based on previous year closing ranks admission to top NIT and popular branches such as CSE,
Hi there,
Considering your JEE Advanced 2026 rank of 1510, it looks like both ECE at IIT Kharagpur and Mathematics & Computing (MnC) at IIT Roorkee are great options.
The choice is a matter of your career prospects, rather than Institute prestige, as both IITs are among the top engineering
Hello Student,
With a PES University JEE main merit rank of 7697, your chances of getting B.Tech CSE (AI) will depend on the number of seats available, category (if applicable), and the closing rank for the current admission cycle. Based on previous year trends, admission to highly sought after branches
Hello student,
If you are seeking admission to B tech programme through your JEE main score for the year 2026 - 2027 academic session, the registration and counselling process is expected to being after the declaration of JEE mains results. For admission to NITs, IIITs and GFTIs, candidate need to
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