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MHT CET 2026 May 12 Question Paper with Solutions: The MHT CET May 12 was successfully conducted for both shifts at various exam centres across the state. The Maharashtra State CET Cell is conducting the MHT CET 2026 PCM exam from May 12 to May 21, 2026. The MHT CET 2026 May 12 question paper with solutions has been added on this page. Students can use it to match their answers and estimate their scores. This page also includes a detailed MHT CET 2026 May 12 paper analysis with difficulty level and student reactions. Stay tuned for the latest updates.
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Also Check: MHT CET 2026 Question Paper May 15
The link to download the MHT CET May 12 question paper with solutions is given in the table below. The question paper contains memory-based questions collected from students who appeared for the exam on that day.
Refer to the memory based questions given below from MHT CET 12 May Question Paper:
Chemistry
Question 1: Which of the following reagents is used to distinguish primary, secondary, and tertiary alcohols?
A) Lucas Test reagent
B) Hunsdiecker reagent
C) Grignard Reaction reagent
D) Benedict's reagent
Question 2: What is the oxidation state of $\mathrm{KO}_2, \mathrm{H}_2 \mathrm{O}_2, \mathrm{SO}_4{ }^{2-}$
Question 3: Which reagent helps to identify Primary, Secondary and Tertiary Alcohols
Question 4: Which of the following compounds is used for the preparation of methyl phenyl ether (anisole)?
A) Sodium phenoxide and methyl iodide
B) Phenol and chloroform
C) Benzene and methanol
D) Sodium acetate and methyl chloride
Question 5: What was molar mass of KMNO4
Mathematics Questions
Question 1: If $\sin x \cos x=\frac{1}{4}$, then the general solution is:
A) $\frac{n \pi}{2}+(-1)^n \frac{\pi}{12}$
B) $\frac{n \pi}{2}+\frac{\pi}{4}$
C) $n \pi \pm \frac{\pi}{6}$
D) $\frac{n \pi}{2}+(-1)^n \frac{\pi}{6}$
Question 2: If $n \in \mathbb{Z}$, then the expression $\frac{2^n}{(1-i)^{2 n}}+\frac{(1+i)^{2 n}}{2^n}$ is equal to:
A) $2(-1)^n$
B) 0
C) 2
D) $2^n$
Question 3: The value of $\int \frac{x^2-1}{\left(x^4+3 x^2+1\right) \tan ^{-1}\left(x+\frac{1}{x}\right)} d x$ is:
A) $\log \left|\tan ^{-1}\left(x+\frac{1}{x}\right)\right|+C$
B) $\tan ^{-1}\left(x+\frac{1}{x}\right)+C$
C) $-\log \left|\tan ^{-1}\left(x+\frac{1}{x}\right)\right|+C$
D) $\frac{1}{2} \log \left|x+\frac{1}{x}\right|+C$
Question 4: If $f(x)=\int \frac{x^2}{\left(1-x^2\right)\left(1+\sqrt{1-x^2}\right)} d x$ and $f(0)=2$, then $f\left(\frac{1}{2}\right)$ is:
Question 5: If $A=\left[\begin{array}{cc}\sin \alpha & -\cos \alpha \\ \cos \alpha & \sin \alpha\end{array}\right]$ and $\alpha \in\left(\frac{\pi}{2}, \frac{3 \pi}{2}\right)$. If $A+A^T=I$, then $\alpha=$
A) $\frac{2 \pi}{3}$
B) $\frac{5 \pi}{6}$
C) $\frac{\pi}{3}$
D) $\frac{4 \pi}{3}$
Question 6: The range of the function $y=\log (\sin x)$ where $\sin x>0$ is:
A) $[0, \infty)$
B) $(-\infty, 0]$
C) $(-\infty, \infty)$
D) $[-1,1]$
Question 7: If $x=a \sin t-b \cos t$ and $y=a \cos t+b \sin t$, and it is given that $\frac{d^2 y}{d x^2}=0$, then:
Question 8: If $n$ is an odd natural number and $I_n=\int_0^1 e^x(x-1)^n d x$, then $I_n+n I_{n-1}$ is equal to:
A) 1
B) -1
C) $e$
D) 0
Question 9: A line passes through the points $O(0,0)$ and $A(3,3)$. The polar coordinates of point $A$ are:
A) $(3 \sqrt{2}, \pi / 4)$
B) $(3, \pi / 4)$
C) $(6, \pi / 2)$
D) $(3 \sqrt{2}, \pi / 3)$
Question 10: In $\triangle A B C$, with usual notations, if $\sin B-\cos C=\cos A$, then $\triangle A B C$ is:
A) Equilateral
B) Isosceles
C) Right angled at $B$
D) Right angled at $A
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The official MHT CET 2026 answer key will be released after all exam shifts are completed. Until then, students can use the unofficial answer key provided in this section to match their responses and estimate their scores. The answer key will include detailed solutions to help students understand their mistakes and analyse their performance.
After you have access to the answer key, here’s how you can calculate your MHT CET 2026 score using the answer key.
Step 1: Download the Answer key: Download the answer key provided on our page.
Step 2: Follow the marking scheme: Before calculating the score, you must know about the marking scheme.
Correct answer: +1 for physics and chemistry, and +2 marks will be awarded for Maths.
Incorrect answer: There is no negative marking, so 0 marks will be deducted for an incorrect answer.
Unattempted answer: 0 marks will be awarded for an unattempted answer.
Step 3: Count and Calculate: Note the total correct and incorrect answers and apply the marking scheme, and then apply the following formula to calculate your total score:
Total Score = (No. of correct answers (mathematics) * 2) + (No. of correct answers (physics and chemistry) * 1)
The table below contains details of the MHT CET 2026 May 12 PCM paper based on student feedback collected from exam centres and expert reviews. The MHT CET 2026 analysis includes the overall difficulty level of Mathematics, Physics, and Chemistry. Students appearing in the upcoming shifts can use these details for better last-minute revision and preparation.
|
Section |
Analysis (Shift 1) |
Analysis (Shift 2) |
|
Easy to Moderate |
Moderate | |
| Easy to Moderate | Easy to Moderate | |
|
Moderate to Slight Lenghty |
Moderate |
These videos are prepared by experts based on live students' reactions
MHT CET May 12 Shift 1 Paper Analysis
MHT CET May 12 Shift 2 Paper Analysis
It is good to have knowledge of the exam pattern before we enter the exam hall. Below is a quick overview of the 12 May CET question paper.
|
Particulars |
Details |
|
Exam Name |
MHT CET 2026 |
|
Conducting Body |
Maharashtra State CET Cell |
|
Exam Date |
PCB Group: May 10 to 11, 2026 PCM Group: May 12 to 21, 2026 |
|
Mode |
Computer-Based Test (CBT) |
|
Shift 1 Timing |
9:00 AM to 12:00 PM |
|
Shift 2 Timing |
2:00 PM to 5:00 PM |
|
Total Marks |
200 |
|
Total Questions |
150 |
|
Duration |
3 hours (180 minutes) |
|
Negative Marking |
No |
|
Official Website |
cetcell.mahacet.org |
The MHT CET 2026 PCM exam has 150 questions for 200 marks. There is no negative marking. The full pattern is given in the table below.
|
Particulars |
Details |
|
Mode of Exam |
Computer-Based Test (CBT) |
|
Duration |
3 hours (180 minutes) |
|
Total Questions |
150 |
|
Total Marks |
200 |
|
Type of Questions |
Multiple Choice Questions |
|
Marking Scheme |
+1 for Physics and Chemistry, +2 for Maths |
|
Negative Marking |
No |
The subject-wise marks for the PCM paper are given below.
|
Subject |
Number of Questions |
Marks per Question |
Total Marks |
|
Mathematics |
50 |
2 |
100 |
|
Physics |
50 |
1 |
50 |
|
Chemistry |
50 |
1 |
50 |
|
Total |
150 |
200 | |
Students can use the MHT CET previous year question papers and MHT CET 2026 Session 1 papers for practice, revision, and understanding the exam pattern before the upcoming shifts.
Solving the May 12 paper is helpful in many ways. The main benefits are given below.
Students get a real idea of the 2026 paper difficulty
It helps to find the most important topics
Time management becomes better with real papers
Students having an exam on the next dates get a free practice
It builds confidence before the exam
Next year, aspirants will also get a clear idea of the pattern
Frequently Asked Questions (FAQs)
Scoring 70 marks in the MHT CET is considered average. Out of 200 total marks, a raw score of 70 generally translates to a percentile between 75 and 85.
No, there is no negative marking in MHT CET 2026. Students should attempt all questions to score well.
The total marks are 200. Maths carries 100 marks. Physics and Chemistry carry 50 marks each.
On Question asked by student community
Hello,
MHT-CET is a computer based test conducted only at allotted exam centers, not from home or personal PCs, Students from outside Maharashtra can appear for the exam at selected centres during application. Non-Maharashtra candidates usually can't claim state quota seats through CAP and often use JEE Main scores instead.
HEY THERE!!!
The official website for MHT CET (Maharashtra Common Entrance Test) is:
I GOT 72 persentile (GOBCH) in MHTCET and I want to pursue BTech CSE, AI, AI-DS,ai-ml,IT, (anyone) so which college can I get in Pune
Hey,
As per the MHT CET syllabus 2024 with weightage PCM and PCB prescribed by the Maharashtra CET Cell, 20 percent weightage is given to the Class 11 topics and the remaining 80 percent to the Class 12 topics of the Maharashtra board.
For detailed information about weightage chapter wise
Hello aspirant,
Certainly, admission to Bachelors in Physiotherapy (BPT) programs is possible through the MHT CET Exam by meeting the necessary cutoff. If you are a Maharashtra resident with a valid domicile, you are eligible to take the MHT CET exam for BPT admission. Alternatively, NEET and CET exams are
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