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JEE Main ECE Cutoff 2025 - This article will be updated with the JEE Main 2025 cutoff for ECE. JoSAA will release the ECE cutoff for JEE Main 2025 online at, josaa.admissions.nic.in. The cutoff of JEE Main ECE will be available as opening and closing rank. The cut-off of JEE Main will be released after each round of JoSAA counselling. JEE Main ECE cutoff will vary for each category. Applicants with a higher rank in JEE Main will be offered admission to the NITs, IIITs, and GFTIs. The admission process will done through JoSAA. 29 NITs offer an Electronic and Communication Engineering (ECE) program.
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The cutoff of JEE Main ECE will be updated on this page after the official release. The authority will consider various factors to determine the JEE Main cutoff for Electronic and Communication Engineering. Candidates can also check the previous year cutof for JEE Main ECE to know the closing rank for various institutes.
Until the JEE Main 2025 cutoff for ECE is released candidates can refer to the previous year cutoff. The mentioned below cutoff is based on JoSAA round 1 home state gender neutral.
Institute | Opening Rank | Closing Rank |
|---|---|---|
14933 | 24613 | |
6149 | 9910 | |
10994 | 15364 | |
5751 | 8428 | |
34203 | 89175 | |
4211 | 11991 | |
11775 | 13698 | |
10363 | 15814 | |
35548 | 40779 | |
34141 | 51355 | |
2763 | 4872 | |
55668 | 102988 | |
16778 | 23841 | |
50168 | 71116 | |
20194 | 34342 | |
83257 | 209475 | |
73439 | 73439 | |
14414 | 17899 | |
11097 | 14883 | |
106364 | 357302 | |
293110 | 589420 | |
8119 | 12873 | |
26540 | 41123 | |
2712 | 6799 | |
31008 | 39909 | |
3393 | 4979 | |
7702 | 12529 | |
7461 | 10369 | |
18177 | 22673 |
Institute | Opening Rank | Closing Rank |
|---|---|---|
11792 | 29951 | |
9259 | 24176 | |
26806 | 37376 | |
27452 | 32781 | |
25526 | 31312 | |
5249 | 7355 | |
16479 | 23546 | |
12242 | 17721 | |
32474 | 48388 | |
11247 | 28407 | |
11215 | 35822 | |
19045 | 34561 | |
29374 | 35387 | |
27028 | 33090 | |
16437 | 21401 | |
30833 | 38074 | |
20535 | 31496 | |
18512 | 29048 |
Institute | Opening Rank | Closing Rank |
|---|---|---|
81577 | 95469 | |
31805 | 44242 | |
16734 | 28220 | |
91456 | 172193 | |
73164 | 86890 | |
55109 | 69388 |
While preparing the JEE Main cutoff for ECE various factors are considered. Below are the factors.
Number of candidates who appeared for JEE Main
Number of JEE Main qualified candidates
Total number of seats available
Past year cutoff trends
Frequently Asked Questions (FAQs)
Candidates can check the NIT cutoff category wise online at, josaa.admissions.nic.in.
JEE Mains cutoff 2025 will be released after each round of JoSAA counselling.
The cutoff marks of ECE are the minimum rank in JEE Main for admission.
On Question asked by student community
Hello,
Since the NTA conducts exams in Tamil, these official papers will have a Tamil language option. Kindly check the following link to get the question papers.
https://engineering.careers360.com/articles/jee-main-question-papers
I hope this helps you.
Hello there,
Understanding and solving different question papers is one of the best practice for the preparation specially when it comes to JEE mains. It gives you proper understanding of the exam pattern, important topics to cover and marking scheme.
Here is the link attached from the official website of Careers360 which will provide you with the link of previous year question papers on chemistry in PDF format. Hope it helps!
https://engineering.careers360.com/articles/jee-mains-chemistry-questions-in-last-year-exam-premium
thank you!
Good Morning, Candidate,
The 30-day study plan for JEE is now available on the website of Careers360. The link is attached herewith.
https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days
There is an option for free download, which will help to proceed further.
Careers360 would like to inform you that you can have an opportunity to analyse your in-depth performance. Careers360 is conducting a free all-India online JEE mock test series on 11th January. It will provide you with a proper question pattern with chapter-wise questions and answers.
Registration is closed on 8th January. Registered and assessed your learning.
Thank You
Hello,
Yes, you can be eligible , but it depends on how you passed Mathematics.
JEE Main
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics was passed as a full subject from NIOS.
NIOS is a recognized board.
Having two marksheets is allowed.
You are not eligible if:
Mathematics was taken only as an improvement or additional without passing it as a full subject.
MHT-CET
You are eligible if:
You passed Class 12 with Physics and Mathematics.
Mathematics from NIOS is shown as a passed subject.
NIOS is recognized for Maharashtra admissions.
Mathematics was passed before the admission year.
You are not eligible if:
Mathematics is not shown as a passed subject.
Important
Mathematics must be a separate and passed subject.
Keep both marksheets during counselling.
Always check the current year information brochure before applying.
Hope it helps !
The marks needed for a 99+ percentile in the JEE Main January attempt depend on the difficulty of the paper and the total number of candidates. Generally, you need roughly *180–200* marks out of 300 to hit the 99+ percentile. The exact cutoff varies each session, so checking the official NTA percentile score calculator or previous year cutoffs gives a more precise idea.
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