Minimum Marks in JEE Main to qualify for JEE Advanced 2025: Candidates aspiring to clear the exam must know the minimum marks in JEE Main to qualify for JEE Advanced. To gain admission into IITs, students need to clear the JEE Advanced exam. Based on the previous year's general category cutoff, aspirants should gain 91 percentile and above in the JEE Main 2025 exam to be able to appear for JEE Adv. Also, candidates must be within the top 250000 ranks in the JEE Main 2025 exam. The eligibility to attempt the JEE Advanced 2025 is to qualify the JEE Main and be among the top 2,50,000 qualifying candidates. JEE Main exam aspirants can learn about the minimum marks in JEE Main to qualify for JEE Advanced on this page.
Can a candidate cancel the application form once submitted for JEE (Main) 2026?
According to the JEE Main 2026 FAQs, the online application form, once submitted successfully, cannot be cancelled or withdrawn
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Candidates should ensure they are thoroughly aware of the JEE Main scores that ensure eligibility of candidates to the JEE Advanced exam. Candidates can read the following article to know the minimum marks in JEE Main to qualify for JEE Advanced.
Qualifying exam | NTA JEE Main 2025 |
Total marks | 300 |
Frequency of exam | 2 times in a year |
Subjects covered | Maths, physics chemistry |
Marking scheme | Right answer +4 Wrong answer -1 |
Candidates must know the minimum marks in JEE Main 2025 to qualify for the JEE Advanced 2025 before attempting the exam. The minimum percentile for different categories is specified in the table below.
Category | JEE Main percentile |
|---|---|
General | 93.2362181 |
Gen-PwD | 0.0018700 |
EWS | 81.3266412 |
OBC-NCL | 79.6757881 |
SC | 60.0923182 |
ST | 46.6975840 |
While the most important eligibility to apply for the JEE Advanced 2025 exam is clearing the JEE Main 2025 cutoff, the ranks gained by the candidates also play a very important role in determining if the candidate can attempt the JEE Advanced exam. Only the top 2,50,000 candidates in the JEE Main exam will be eligible for the JEE Advanced exam. Hence, along with clearing the JEE Main 2025 cutoff, candidates also need to secure a rank in the top 2,50,000 JEE Main ranks.
NTA will release the JEE Main 2025 marks vs rank vs percentile on the official website. Candidates can check the JEE Main marks vs rank vs percentile from the table below. This will help them determine if they will qualify for the JEE Advanced exam or not. The scores mentioned in the table below are from the previous year data. The updated date will be mentioned once released.
Marks out of 300 | Rank | Percentile |
|---|---|---|
286- 292 | 19-12 | 99.99826992- 99.99890732 |
280-284 | 42-23 | 99.99617561 - 99.99790569 |
268- 279 | 106-64 | 99.99034797 - 99.99417236 |
250- 267 | 524-108 | 99.95228621- 99.99016586 |
231-249 | 1385-546 | 99.87388626-99.95028296 |
215-230 | 2798-1421 | 99.74522293-99.87060821 |
200-214 | 4667-2863 | 99.57503767- 99.73930423 |
189-199 | 6664- 4830 | 99.39319714- 99.56019541 |
175-188 | 10746-7152 | 99.02150308 - 99.3487614 |
160-174 | 16163-11018 | 98.52824811-98.99673561 |
149-159 | 21145-16495 | 98.07460288-98.49801724 |
102-109 | 65758-55269 | 94.01228357-94.96737888 |
95-101 | 76260-66999 | 93.05600452 -93.89928202 |
89-94 | 87219-78111 | 92.05811248 -92.88745828 |
Various factors are taken into consideration by NTA to calculate the minimum score for JEE Advanced eligibility. Candidates can use these factors to understand how to determine the JEE Main scores required to apply for the JEE Advanced 2025 exam. These factors include
Total number of candidates who appeared for JEE Main 2025
Level of difficulty of the exam
Total number of available seats in JEE Main participating institutes
Previous year cutoff trends
Frequently Asked Questions (FAQs)
Candidates should score above 91 marks out of 300 to be able to apply for the JEE Advanced 2025 exam.
NTA will release the JEE Main 2025 cutoff after the declaration of results on the official website.
Candidates with a score of 150 can expect to get a rank between 21145-16495. Hence the candidate will be eligible to apply for the JEE Advanced 2025 exam.
The top 250000 ranks will be allowed to apply for the JEE Advanced exam. The last rank will depend on the category of the candidate, JEE Main performance and difficulty level of the exam among other factors.
JEE Main 2025 cutoff will be released along with the exam result.
On Question asked by student community
Hello,
Here are the high weightage chapters in JEE Mains maths:
For more information access below mentioned link:
https://engineering.careers360.com/articles/jee-mains-maths-high-weightage-chapters-and-topics
Hope it helps.
Hello
The JEE syllabus mainly covers Physics, Chemistry, and Math from NCERT Class 11 and 12.
You should follow NCERT first because it builds the strongest foundation for all three subjects.
For a deeper understanding, use books like H.C. Verma (Physics), Cengage (Maths), and O.P. Tandon / M.S. Chouhan (Chemistry).
For practice, solve JEE Main PYQs to understand the exam pattern.
You can check the updated syllabus of JEE mains from here: SYLLABUS.
You can find books for all subjects from here: BOOKS
Hello,
You should select Jharkhand for the JEE Mains application form because you will be reappearing in the exam as a private candidate in Jharkhand. The state you will be appearing in and your passing year are what you should fill in your JEE Mains application form, but not your 12th class state.
Hope it helps!!!
It's a very good choice to aim for IIT, for getting admission in IIT you must take pure mathematics as it teach you more concept than applied which help to get more score in JEE Mains and Advanced.
You should practice more harder than yo0u do in your class 11.
To practice for JEE level questions --- Click Here . These questions help you in both your class 12th board exams and your upcoming JEE Mains Exam.
Click Here to get detailed solution for JEE questions
You can get the JEE MAIN chapterwise previous years question from careers360, you can get the PDFs from the article along with solutions in pdf. Follow the link given below-
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