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Top 10 Most Repeated Topics In Chemistry For JEE Mains - Chemistry is often seen as the most scoring section in JEE Main, as it requires less time to solve compared to Physics and Mathematics. With the right preparation, students can secure strong marks by focusing on the areas that carry the highest weightage. Over the years, certain chapters in Chemistry have been repeated more frequently in JEE Main, making them important for every aspirant to prioritize during their revision.
JEE Mains 2026 will be conducted by the National Testing Agency (NTA), while as per media reports, IIT Roorkee will likely conduct JEE Advanced for admission to IITs.
 IIT Roorkee to conduct JEE Advanced 2026. (Image source: Wikimedia Commons)
IIT Roorkee to conduct JEE Advanced 2026. (Image source: Wikimedia Commons)
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                The JEE Mains chemistry is known for being the most scoring subject so far. Hence, in this article we will help you prepare for chemistry by looking at the most repeated chemistry topics for JEE mains. Not only that, we will also be delving into top 10 most repeated topics in chemistry for JEE Mains to help you get exam ready. First, let's start with understanding the exam pattern and getting familiar with the details of JEE Mains 2026.
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Preparing for any exam requires research and specially for a competitive entrance exam like JEE Mains requires thorough preparation. So, our experts have collected and done the thorough research from JEE Main Latest Syllabus 2026. In the below table we have provided you with the top 10 most repeated topics in chemistry for JEE Mains 2026. This data comprises last 10 years JEE mains question papers of all slots.
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This table contains the most repeated chemistry topics for JEE Mains. For more details we have also provided you with a count of the total numbers of questions from these topics along with the chapters that they are from.
| Chapter | Topic | Number of Questions | 
| Some Basic Concepts of Chemistry | Concentration Terms | 48 | 
| Some Basic Concepts of Chemistry | Mole Concept and Molar Mass | 48 | 
| Some Basic Concepts of Chemistry | Stoichiometry, Stoichiometric Calculations and Limiting Reagent | 39 | 
| Organic Compounds containing Oxygen | Reduction and Oxidation Reaction | 37 | 
| Organic Chemistry – General Organic Chemistry + Hydrocarbons | Stereoisomerism | 34 | 
| Biomolecules | Disaccharides and Polysaccharides | 33 | 
| Chemical Kinetics | 33 | |
| Redox Reactions/d-Block Elements | Oxidation State | 32 | 
As seen, the topic Concentration Terms happen to be the most important with the highest weighted topic. The 10th most important topic is Oxidation State, a part of both the chapters : d-Block Element/Redox Reactions. Following this list, we have more high weighted topics which could be a game changer for the JEE mains chemistry exam.
Now, after seeing the topics, let’s dive into the most important chapters for JEE mains chemistry 2026. Understanding this aspect will give you an upper hand in the preparation for the exam!
We have already seen the most repeated chemistry topics for jee mains and the chapters that they are asked from. Now, let’s see which chapters have the highest number of questions from the past 10 years. Most important chapters for JEE mains Chemistry 2026 are curated by analyzing the frequency of the questions asked from the whole chapter in the last 10 years.
This table contains the chapter name on one side and the total number of questions asked from each chapter on the other side. These following listed chapters constitute the most important chapters for chemistry with organic compounds containing oxygen being the highest weighted chapter. This list has most important chapters ranked in order of most to least important.
| Chapter | No. of Questions (Last 10 Years) | 
| Organic Compounds containing Oxygen | 259 | 
| 216 | |
| Co-ordination Compounds | 185 | 
| 188 | |
| Redox Reaction and Electrochemistry | 173 | 
| Organic Compounds Containing Nitrogen | 172 | 
| Chemical Thermodynamics | 166 | 
| Atomic Structure | 155 | 
| Chemical Bonding and Molecular Structure | 151 | 
| 149 | |
| d - and f - BLOCK ELEMENTS | 148 | 
| Some basic concepts in chemistry | 142 | 
| 136 | |
| Some Basic Principles of Organic Chemistry | 136 | 
| 120 | 
Refer to JEE Main Chapter-Wise Weightage for for a better understanding of important topics and helps you to prepare accordingly.
In this section, we will be diving into each topic and looking at the set of most important questions from those particular topics listed above individually. Understanding the level of these questions and practicing them will help you increase your chances of scoring better and increasing your rank in JEE Mains exam 2026. Let’s dive in!
Question: Some amount of dichloromethane ( CH 2 Cl 2 ) is added to 671.141 mL of chloroform ( CHCl 3 ) to prepare 2.6 × 10 − 3 M solution of CH 2 Cl 2 ( DCM ) . The concentration of DCM is ppm (by mass).
Given : atomic mass : C = 12
H = 1 Cl = 35.5
density of CHCl 3 = 1.49   g   cm − 3
Solution:
Molar mass = 12 + 2 + 71
= 85mmoles of DCM = 671.141 × 2.6 × 10 − 3
mass of solution = 1.49 × 671.141
PPM = 671.141 × 2.6 × 10 − 3 × 85 × 10 − 3 1.49 × 671.141 × 10 6
= 148.322 ..
Hence, the answer is (148.322).
Question: The molarity of 0.006 moles of NaCl in 100 ml solutions in -
(1) 0.6
(2) 0.06
(3) 0.006
(4) 0.066
Solution:
As we learn
Molarity -
Molarity = Moles of solute Vol.of solution ( L ) Molarity = Moles of solute Vol.of solution ( L ) M = n V ( l ) = 0.006 0.1 = 0.06
Hence, the answer is the option (2).
Question: 1 gram of a carbonate ( M 2 CO 3 ) on treatment with excess HCl produces 0.01186 mole of CO 2 .. The molar mass of M 2 CO 3 in g mol − 1 is :
(1) 118.6
(2) 11.86
(3) 1186
(4) 84.3
Solution:
Given,
Mass of carbonate ( M 2 CO 3 ) = 1 gram
As we have learned,
Number of Moles -
No of moles = given mass of substance/ molar mass of a substance
Given the Chemical reaction,
M 2 CO 3 + 2 HCl → 2 MCl + 2 H 2 O + CO 2
From the balanced equation
1 M = 0.01186 ⇒ M = 1 0.01186 = 84.3
Hence, the answer is an option (4).
Magnetic moment explains the magnetic behavior of coordination compounds using Valence Bond Theory (VBT). Questions are mostly conceptual and numerical, moderate in difficulty.
Question: The calculated magnetic moments (spin only value) for species [ FeCl 4 ] 2 − , [ Co ( C 2 O 4 ) 3 ] 3 − and MnO 4 2 − respectively are :
(1) 5.82, 0 and 0 B M
(2) 5.92 , 4.90 and 0 B M
(3) 4.90 , 0 and 1.73 B M
(4) 4.90 , 0 and 2.83 B M
Solution:
[ FeCl 4 ] 2 − Fe 2 + 3 d 6 → 4 unpaired electron
as Cl– in a weak field liquid.
μ spin = 24 8 M = 4.9 BM
[ Co ( C 2 O 4 ) 3 ] 3 Co 3 + 3 d 6 → for Co 3 + with coodination no. 6
C 2 O 4 2 − is strong field ligand & causes pairing & hence no. unpaired electron.
μ spin = 0
[ MnO 4 ] 2 − Mn + 6 it has one unpaired electron.
μ spin = 3 BM = 1.73 BM
Hence,the answer is the option(3).
Question: A sample of NaClO 3 is converted by heat to NaCl with a loss of 0.16 g of oxygen. The residue is dissolved in water and precipitated as AgCl. The mass of AgCl (in g) obtained will be:
(1) 0.35
(2) 0.41
(3) 0.48
(4) 0.54
Solution:
As we learnt in
Stoichiometry -
Stoichiometry deals with measurements of reactants and products in a chemical reaction.
- wherein
aA ( g ) + bB ( g ) → cC ( g ) + dD ( g )
Here, ‘a’ moles of A(g) reacts with ‘b’ moles of B(g) to give ‘c’ mole of C(g) and ‘d’ moles of D(g)
2 NaClO 3 → Δ 2 NaCl + 3 O 2 0.16 g
n NaCl 2 = n O 2 3
n NaCl = 0.16 32 × 2 3 = 1 200 × 2 3 = 1 300
NaCl → AgCl
PoAC on Cl
1 × n NaCl = 1 × n AgCl
1 300 = n A g C l
the weight of A g C l = 1 300 × [ 108 + 35.5 ] = 1 300 × 143.5 = 0.48 g
Hence, the answer is an option (3).
CFT explains color, magnetism, and stability of coordination compounds. Questions are mostly conceptual and numerical, moderate in difficulty.
Question: Which of the following 3 d -metal ion will give the lowest enthalpy of hydration ( Δ hyd H ) when dissolved in water?
(1) Cr 2 +
(2) Mn 2 +
(3) Fe 2 +
(4) Co 2 +
Solution:
Water act as a weak ligand.C F S E of metal ions depend on strength of ligand.


Since the CFSE of Mn 2 + is the least, Δ H Hyd of it is also lowest.
Hence, the answer is the option (2).
Redox reactions are key in electrochemistry and organic transformations. Questions are mostly numerical and moderate in difficulty.
Question: Experimentally reducing a functional group cannot be done by which one of the following reagents?
(1) Zn / H 2 O
(2) Pt − C / H 2
(3) Pd − C / H 2
(4) Na / H 2
Solution:
Out of the given reagents, Na / H 2 is not used as a reducing agent.
Hence, the answer is the option (4).
Stereoisomerism explains spatial arrangement of atoms in molecules, important in organic chemistry. Questions are mostly conceptual and moderate in difficulty.
Question: The total number of possible isomers for square-planar [ Pt ( Cl ) ( NO 2 ) ( NO 3 ) ( SCN ) ] 2 − is :
(1) 8
(2) 12
(3) 16
(4) 24
Solution:
As we have learnt,
NO 2 − and S C N − are ambidentate ligands and each of them can attach through two different donor sites.
Now, the given square planar complex can show geometrical isomerism as well as linkage isomers.
The number of isomers possible is listed below:
| Compound | Number of Isomers | 
| [ Pt ( Cl ) ( NO 2 ) ( NO 3 ) ( SCN ) ] 2 − | 3 | 
| [ Pt ( Cl ) ( ONO ) ( NO 3 ) ( SCN ) ] 2 − | 3 | 
| [ Pt ( Cl ) ( ONO ) ( NO 3 ) ( NCS ) ] 2 − | 3 | 
| [ Pt ( Cl ) ( NO 2 ) ( NO 3 ) ( NCS ) ] 2 − | 3 | 
Thus, the total number of Isomers is 12.
Hence, the answer is an option (2).
This topic is important in biomolecules, especially for carbohydrates' structure and properties. Questions are mostly conceptual and numerical, moderate in difficulty.
Question: Compound A gives D-Galactose and D-Glucose on hydrolysis. The compound A is :
(1) Amylose
(2) Sucrose
(3) Maltose
(4) Lactose
Solution:
As we have learned,
The monosaccharides are involved in the formation of the given sugars.
Amylose: α − D Glucose
Sucrose : α − D-Glucose + β − D-Fructose
Maltose : α - D-Glucose
Lactose : β - D-Galactose + β - D-Glucose
Hence, the answer is the option (4).
First-order reactions are important in chemical kinetics. Questions are mostly numerical and moderate in difficulty.
Question: For a first-order reaction, A → P , t 1 2 , (half-life) is 10 days. The time required for 1 4 th conversion of A (in days) is :
(ln 2=0.693, ln 3=1.1)
(1) 4.1
(2) 3.2
(3) 5
(4) 2.5
Solution:
For the first-order reaction: -
K = 0.693 t 1 2 = 0.693 10 K = 2.303 t log  R o R t 0.693 10 = 2.303 t log  R o × 4 3 R 0 0.693 10 = 2.303 t [ log  4 − log  3 ] = 2.303 t [ 0.6020 − 0.4771 ] 0.693 10 = 2.303 t × 0.1249 t = 2.303 × 0.1249 × 10 0.603 = 4.15 days
Hence, the correct answer is option (1)
Question: The amphoteric oxide among V 2 O 3 , V 2 O 4 and V 2 O 5 upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is:
(1) +3
(2) +7
(3) +5
(4) +4
Solution:
V 2 O 3 - basic
V 2 O 4 - weakly acidic or amphoteric
V 2 O 5 - amphoteric
V 2 O 5 +  alkali  → VO 4 3 −
In VO 4 3 − ion, vanadium is in a +5 oxidation state.
Hence, the correct answer is option (3).
Students can follow JEE Main- Top 30 Most Repeated Questions & Topics for better practice and revision. Along with that try to solve JEE Main 2026 Sample Paper.
Chemistry is divided into three branches Physical, Organic, and Inorganic Chemistry. And it is one of the most important and scoring subject if you are preparing for JEE Mains 2026. To study chemistry in a better way students must study each branch separately, focusing on its core concepts, formulas, and reaction mechanisms.
It is important to learn important reactions, formulas, and periodic table trends.
Read the NCERT textbook and solve exercises
Revise key topics frequently and solve full-length mock tests
Solve previous year questions
For complete preparation strategy follow JEE Main 2026 complete preparation strategy
Frequently Asked Questions (FAQs)
Actually, no! JEE Mains is a national competitive exam and students should refer to a lot of other books as well for the in depth preparation of chemistry. So you must refer to 2-3 books outside NCERT as well!
Start with high-weightage and repeated topics like Mole Concept, Thermodynamics, Coordination Compounds, Redox Reactions, and Hydrocarbons. Once strong in these, cover remaining chapters systematically to ensure no topic is left uncovered.
Inorganic chemistry has the easiest syllabus and is the highest to score. It is advisable to not leave any topic of this part of chemistry if you’re planning to bag a good rank in the exam.
The most repeated topics include Concentration Terms (Solutions), Mole Concept, Redox Reactions, Stoichiometry, Coordination Compounds, Chemical Kinetics, Chemical Bonding, and Oxidation States. These topics consistently appear in JEE Mains over the years.
On Question asked by student community
Hello,
From the below website you can download the previous year question papers of JEE Mains Hindi medium.
https://engineering.careers360.com/hi/articles/jee-main-question-paper
It consists of last 10 years question paper, solving them all will surely help you in preparation.
All the best.
Hello,
Visit the below website to know the high weightage chapters for JEE 2026.
https://engineering.careers360.com/articles/jee-main-chapter-wise-weightage
You'll also get to know which books should be referred for your preparation.
 
 
Hello,
From the below website you can get to know which are the important topics, chapter wise weightage and also which books to refer to prepare for JEE Mains 2026.
https://engineering.careers360.com/articles/jee-main-chapter-wise-weightage
 
Hello,
Visit the below website to know the important chapters for JEE 2026.
https://engineering.careers360.com/articles/jee-main-chapter-wise-weightage
You'll also get to know the weightage of chapters and which books to refer for your preparation.
 
Hello,
Yes, knowing the chapter wise weightage plays an important role in preparation of JEE.
Visit the below website to know it.
https://engineering.careers360.com/articles/jee-main-chapter-wise-weightage
Also refer the books that are recommended there as they'll help you in preparing well for your examination.
All the best.

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