Most Repeated Questions in JEE Mains: Comprehensive Analysis

Most Repeated Questions in JEE Mains Physics

In JEE Mains, Physics questions often come from a few important topics that are repeated every year. Knowing these topics helps you focus your preparation and score better. Here the most repeated Physics questions that you should definitely practise before the exam and prepared according to JEE Main Latest Syllabus 2026 are given:

Some of the JEE Main most repeated questions of Physics are given below, students can also refer JEE Main 2026 Sample Paper:

Question: A plane electromagnetic wave propagates along the $+x$ direction in free space. The components of the electric field, $\vec{E}$ and magnetic field, $\vec{B}$ vectors associated with the wave in Cartesian frame are :

(1) $\mathrm{E}_y, \mathrm{~B}_{\mathrm{x}}$

(2) $\mathrm{E}_{\mathrm{y}}, \mathrm{B}_{\mathrm{z}}$

(3) $E_x, B_y$

(4) $\mathrm{E}_z, \mathrm{~B}_y$

Solution:

Direction of propagation $=\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}}$

$E \rightarrow y, B \rightarrow z, c \rightarrow x$

$\hat{\mathrm{E}} \times \hat{\mathrm{B}}=\hat{\mathrm{j}} \times \hat{\mathrm{k}}=\hat{\mathrm{i}}=\hat{\mathrm{c}}$

Hence, the answer is the option (2).

Question: Given below are two statements :

Statement I: For transmitting a signal, the size of the antenna (I) should be comparable to the wavelength of the signal (at least $l=\frac{\lambda}{4}$ in dimension)

Statement II: In amplitude modulation, the amplitude of the carrier wave remains constant (unchanged).

In the light of the above statements, choose the most appropriate answer from the options given below.

(1) Statement I is correct but Statement II is incorrect

(2) Both Statement I and Statement II are correct

(3) Statement I is incorrect but Statement II is correct

(4) Both Statement I and Statement II are incorrect

Solution:

Statement 1 is correct.
In Modulation Amplitude of the carrier wave is increased.
Statement 2 is incorrect, in amplitude modulation amplitude of the wave is varied.
Hence, the answer is the option (1).

Most Repeated Questions in JEE Mains Chemistry

Chemistry includes conceptual as well as numerical questions. Among the most repeated questions in JEE Mains Chemistry, Organic and Physical Chemistry dominate.The most repeated questions in JEE Mains chemistry help students to score good marks. Alsoo they can refer JEE Main 2026 - A complete preparation strategy

Question:

Some Questions from JEE Main Chemistry are given below:

Question: Concentrated nitric acid is labelled as $75 \%$ by mass. The volume in mL of the solution which contains 30 g of nitric acid is $\_\_\_\_$ . Given : Density of nitric acid solution is $1.25 \mathrm{~g} / \mathrm{mL}$

(1) 45

(2) 55

(3) 32

(4) 40

Solution :

$75 \%$ by mass means :
$\because \quad 75 \mathrm{gHNO}_3$ in 100 g solution.
$\therefore \quad 30 \mathrm{gHNO}_3$ in $\frac{100}{75} \times 30 \mathrm{~g}$ solution.
$\mathrm{m}_{\text {solution }}=\frac{100 \times 30}{75} \mathrm{~g}$

$$
\because \quad \mathrm{V}_{\text {sol }}=\frac{\mathrm{m}_{\text {sol }}}{\mathrm{d}_{\text {sol }}}=\frac{100 \times 30}{75 \times 1.25}=32 \mathrm{~mL}
$$

Hence, the correct answer is option (3).

Question:

Given below are two statements :
Statement I : $\mathrm{CrO}_3$ is a stronger oxidizing agent than $\mathrm{MoO}_3$
Statement II : $\mathrm{Cr}(\mathrm{VI})$ is more stable than $\mathrm{Mo}(\mathrm{VI})$
In the light of the above statements, choose the correct answer from the options given below

(1) Statement I is false but Statement II is true

(2) Statement I is true but Statement II is false

(3) Both Statement I and Statement II are true

(4) Both Statement I and Statement II are false

Solution:

Statement-I is true but statement II is false.

$\mathrm{Cr}(\mathrm{VI})$ is less stable than $\mathrm{Mo}(\mathrm{VI})$

Stability : $\mathrm{Cr}^{6+}<\mathrm{Mo}^{6+}$
Hence, $\mathrm{CrO}_3$ easily reduce into $\mathrm{Cr}^{-3}$ as compared to $\mathrm{MoO}_3$ and show stronger oxidizing nature.

Hence, the correct answer is option (2).

Most Repeated Questions in JEE Mains Mathematics

Mathematics questions often involve direct applications of formulas and standard problem-solving techniques. Here are the JEE Main most repeated questions of Maths. These most repeated questions in JEE Mains maths predominantly involve formulas and standard techniques, making them critical for scoring well.

Some Important Questions from JEE Main Mathematics are given below:

Question: If in the expansion of $(1+x)^p(1-x)^q$, the coefficients of $x$ and $x^2$ are 1 and -2 , respectively, then $\mathrm{p}^2+\mathrm{q}^2$ is equal to:

(1) 8

(2) 18

(3) 13

(4) 1

Solution:

$$
(1+x)^p(1-x)^q=\left({ }^p C_0+{ }^p C_1 x+{ }^p C_2 x^2+\ldots\right)\left({ }^q C_0-{ }^q C_1 x+{ }^q C_2 x^2-\ldots\right)
$$

To find the coefficient of $x$, we consider terms whose degrees add up to 1 :
Coefficient of $x={ }^p C_0 \cdot\left(-{ }^q C_1\right)+{ }^p C_1 \cdot{ }^q C_0=-{ }^q C_1+{ }^p C_1=1$
Given that $p-q=1$, so:

$$
p=q+1
$$

Now for the coefficient of $x^2$, the relevant terms are:
Coefficient of $x^2={ }^p C_0 \cdot{ }^q C_2-{ }^p C_1 \cdot{ }^q C_1+{ }^p C_2 \cdot{ }^q C_0=-2$
Now express binomial coefficients using formulas:

$$
{ }^q C_2=\frac{q(q-1)}{2}, \quad{ }^p C_2=\frac{p(p-1)}{2}, \quad{ }^p C_1=p, \quad{ }^q C_1=q
$$
Substitute these into the expression:

$$
\frac{q(q-1)}{2}-p q+\frac{p(p-1)}{2}=-2
$$
Multiply the entire equation by 2 to eliminate denominators:

$$
q(q-1)-2 p q+p(p-1)=-4
$$

$$
q^2-q-2 p q+p^2-p=-4
$$

Now substitute $p=q+1$ into the equation:

$$
q^2-q-2 q(q+1)+(q+1)^2-(q+1)=-4
$$
Expand:

$$
q^2-q-2 q^2-2 q+q^2+2 q+1-q-1=-4
$$
Simplify:

$$
\left(q^2-2 q^2+q^2\right)+(-q-2 q+2 q-q)+(1-1)=-4 \Rightarrow 0-2 q=-4 \Rightarrow q=2
$$
Now:

$$
p=q+1=3
$$
Therefore:

$$
p^2+q^2=3^2+2^2=9+4=13
$$

Hence, the correct answer is option (3).

Question: $\int_0^{\pi / 4} \frac{\cos ^2 x \sin ^2 x}{\left(\cos ^3 x+\sin ^3 x\right)^2} d x$ is equal to

(1) $1 / 12$

(2) $1 / 9$

(3) $1 / 6$

(4) $1 / 3$

Solution:

$\int_0^{\pi / 4} \frac{\tan ^2 x \sec ^2 x d x}{\left(1+\tan ^3 x\right)^2} d x$

$\begin{aligned} & \text { Let } 1+\tan ^3 \mathrm{x}=\mathrm{t} \\ & \tan ^2 x \sec ^2 x d x=\frac{d t}{3} \\ & \frac{1}{3} \int_1^2 \frac{d t}{t^2}=\frac{1}{6}\end{aligned}$

Hence, the correct answer is Option 3.

Why Focus on Repeated Questions?

By focusing on the most repeated questions in JEE Mains physics, chemistry, and maths, aspirants can significantly improve their chances of scoring well in the exam.

High Probability of Appearance:

Questions from certain chapters or concepts tend to appear consistently every year. For example, in Physics, topics like Electrostatics, Modern Physics, and Mechanics often have recurring questions. Similarly, in Chemistry, Chemical Bonding, Coordination Compounds, and Organic Reactions are frequently tested. By focusing on these repeated topics, candidates increase their chances of attempting questions they are already familiar with, reducing uncertainty during the exam.

Efficient Time Management:

When you practice repeated questions, you solve questions in less time. This improves speed and accuracy, which are critical in a time-bound exam like JEE Main. Attempting familiar questions first during the exam can help you secure easy marks quickly, allowing more time for tougher problems.

Better Understanding of Question Patterns:

Repeated questions help candidates recognize patterns of question and trends in the exam. Like, the way a particular concept is framed in multiple-choice questions, or the typical twists applied to numerical problems, becomes predictable with practice. This pattern recognition reduces the chances of errors and builds confidence during the exam.

Smart Revision Strategy:

Focusing on repeated questions allows for revision of selected section. Instead of attempting all topics equally, candidates can prioritize high-yield areas that historically appear in the exam. This strategy ensures that the limited revision time is used efficiently and helps in retaining important formulas, concepts, and shortcuts.

Boosts Confidence and Reduces Exam Stress:

Solving repeated questions from previous years provides a sense of confidence in our mind. Candidates feel more prepared and confident, knowing that they have already practiced questions that are likely to appear. This reduces exam anxiety and helps maintain a calm and focused mindset on the day of the exam.

Also read

• JEE Main 2026 Sample Paper

• How to Prepare for JEE Main 2026