Most Repeated Questions in JEE Mains: Comprehensive Analysis

Most Repeated Questions in JEE Mains Physics

In JEE Mains, Physics questions often come from a few important topics that are repeated every year. Knowing these topics helps you focus your preparation and score better. Here, the most repeated Physics questions that you should definitely practise before the exam and prepare according to the JEE Main Latest Syllabus 2026 are given:

Some of the JEE Mains most repeated questions of Physics are given below. Students can also refer to the JEE Main 2026 Sample Paper:

Question: A plane electromagnetic wave propagates along the +x direction in free space. The components of the electric field, E→ and magnetic field, B→, vectors associated with the wave in the Cartesian frame are :

(1) Ey, Bx

(2) Ey, Bz

(3) Ex, By

(4) Ez, By

Solution:

Direction of propagation $= \vec{E} \times \vec{B}$

$\vec{E} \to y, \quad \vec{B} \to z, \quad \vec{c} \to x$

$\hat{E} \times \hat{B} = \hat{j} \times \hat{k} = \hat{i} = \hat{c}$

Hence, the answer is option (2).

Question: Given below are two statements :

Statement I: For transmitting a signal, the size of the antenna (I) should be comparable to the wavelength of the signal (at least l=λ⁴ in dimension)

Statement II: In amplitude modulation, the amplitude of the carrier wave remains constant (unchanged).

In light of the above statements, choose the most appropriate answer from the options given below.

(1) Statement I is correct, but Statement II is incorrect

(2) Both Statement I and Statement II are correct

(3) Statement I is incorrect,t but Statement II is correct

(4) Both Statement I and Statement II are incorrect

Solution:

Statement 1 is correct.
In modulation, the amplitude of the carrier wave is increased.
Statement 2 is incorrect; in amplitude modulation, the amplitude of the wave is varied.
Hence, the answer is option (1).

Most Repeated Questions in JEE Mains Chemistry

Chemistry includes conceptual as well as numerical questions. Among the most repeated questions in JEE Mains Chemistry, Organic and Physical Chemistry dominate. The most repeated questions in JEE Mains chemistry help students to score good marks.

Some of the most asked questions in JEE Mains Chemistry are given below:

Question: Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is ____ . Given: Density of nitric acid solution is 1.25 g/mL

(1) 45

(2) 55

(3) 32

(4) 40

Solution :

75% by mass means: $\because 75\ g\ HNO_3$ in $100\ g$ solution.

$\therefore 30\ g\ HNO_3$ in $\dfrac{100}{75} \times 30\ g$ solution.

$m_{solution} = \dfrac{100 \times 30}{75}\ g$

$\because V_{sol} = \dfrac{m_{sol}}{d_{sol}} = \dfrac{100 \times 30}{75 \times 1.25} = 32\ mL$

Hence, the correct answer is option (3).

Question:

Given below are two statements :
Statement I CrO₃ is a stronger oxoxidisinggent than MoO₃
Statement II : Cr(VI) is more stable than Mo(VI)
In light of the above statements, choose the correct answer from the options given below

(1) Statement I is false, but Statement II is true

(2) Statement I is tru,e but Statement II is false

(3) Both Statement I and Statement II are true

(4) Both Statement I and Statement II are false

Solution:

Statement I: $CrO_3$ is indeed a stronger oxidising agent than $MoO_3$.

This is because $Cr^{6+}$ is less stable than $Mo^{6+}$, so $CrO_3$ has a greater tendency to get reduced to $Cr^{3+}$, making it a stronger oxidising agent. Hence Statement I is TRUE.

Statement II: $Cr(VI)$ is more stable than $Mo(VI)$.

This is incorrect. The stability order is:

$Cr^{6+} < Mo^{6+}$

$Mo(VI)$ is more stable than $Cr(VI)$ because as we go down the group, higher oxidation states become more stable. Hence Statement II is FALSE.

Therefore, Statement I is true but Statement II is false.

Hence, the correct answer is Option (2).

Repeated Questions in JEE Mains Mathematics

Mathematics questions often involve direct applications of formulas and standard problem-solving techniques. Here are the JEE Mains most repeated questions of Maths. The most asked questions in JEE Mains of maths are predominantly involved in important formulas of maths and standard techniques, making them critical for scoring well.

Some Important Questions from JEE Main Mathematics are given below:

Question: If in the expansion of $(1+x)^p(1-x)^q$, the coefficients of $x$ and $x^2$ are $1$ and $-2$ respectively, then $p^2 + q^2$ is equal to:

(1) 8 $\quad$

(2) 18 $\quad$

(3) 13 $\quad$

(4) 1

Solution:

$(1+x)^p(1-x)^q = \left(^pC_0 + ^pC_1x + ^pC_2x^2 + \ldots\right)\left(^qC_0 - ^qC_1x + ^qC_2x^2 - \ldots\right)$

To find the coefficient of $x$, we consider terms whose degrees add up to 1:

$\text{Coefficient of } x = ^pC_0 \cdot (-^qC_1) + ^pC_1 \cdot ^qC_0 = -^qC_1 + ^pC_1 = 1$

Given that $p - q = 1$, so:

$p = q + 1$

Now for the coefficient of $x^2$, the relevant terms are:

$\text{Coefficient of } x^2 = ^pC_0 \cdot ^qC_2 - ^pC_1 \cdot ^qC_1 + ^pC_2 \cdot ^qC_0 = -2$

Now express binomial coefficients using formulas:

$^qC_2 = \dfrac{q(q-1)}{2}, \quad ^pC_2 = \dfrac{p(p-1)}{2}, \quad ^pC_1 = p, \quad ^qC_1 = q$

Substitute these into the expression:

$\dfrac{q(q-1)}{2} - pq + \dfrac{p(p-1)}{2} = -2$

Multiply the entire equation by 2 to eliminate denominators:

$q(q-1) - 2pq + p(p-1) = -4$

$q^2 - q - 2pq + p^2 - p = -4$

Now substitute $p = q+1$ into the equation:

$q^2 - q - 2q(q+1) + (q+1)^2 - (q+1) = -4$

Expand:

$q^2 - q - 2q^2 - 2q + q^2 + 2q + 1 - q - 1 = -4$

Simplify:

$(q^2 - 2q^2 + q^2) + (-q - 2q + 2q - q) + (1-1) = -4$

$\Rightarrow 0 - 2q = -4$

$\Rightarrow q = 2$

Now:

$p = q + 1 = 3$

Therefore:

$p^2 + q^2 = 3^2 + 2^2 = 9 + 4 = 13$

Hence, the correct answer is Option (3).

Question: $\displaystyle\int_0^{\pi/4} \dfrac{\cos^2 x \sin^2 x}{(\cos^3 x + \sin^3 x)^2}dx$ is equal to:

(1) $\dfrac{1}{12}$ $\quad$

(2) $\dfrac{1}{9}$ $\quad$

(3) $\dfrac{1}{6}$ $\quad$

(4) $\dfrac{1}{3}$

Solution:

$\displaystyle\int_0^{\pi/4} \dfrac{\tan^2 x \sec^2 x}{(1+\tan^3 x)^2}\ dx$

Let $1 + \tan^3 x = t$

$\Rightarrow \tan^2 x \sec^2 x\ dx = \dfrac{dt}{3}$

$\dfrac{1}{3}\displaystyle\int_1^{2} \dfrac{dt}{t^2} = \dfrac{1}{6}$

Hence, the correct answer is Option 3.

Why Focus on Repeated Questions?

By focusing on the most repeated questions in JEE Mains physics, chemistry, and maths, aspirants can significantly improve their chances of scoring well in the exam.

High Probability of Appearance:

Questions from certain chapters or concepts tend to appear consistently every year. For example, in Physics, topics like Electrostatics, Modern Physics, and Mechanics often have recurring questions. Similarly, in Chemistry, Chemical Bonding, Coordination Compounds, and Organic Reactions are frequently tested. By focusing on these repeated topics, candidates increase their chances of attempting questions they are already familiar with, reducing uncertainty during the exam.

Efficient Time Management:

When you practice repeated questions, you solve questions in less time. This improves speed and accuracy, which are critical in a time-bound exam like JEE Main. Attempting familiar questions first during the exam can help you secure easy marks quickly, allowing more time for tougher problems.

Better Understanding of Question Patterns:

Repeated questions help candidates recognise patterns of questions and trends in the exam. Likewise, the way a particular concept is framed in multiple-choice questions, or the typical twists applied to numerical problems, becomes predictable with practice. This pattern recognition reduces the chances of errors and builds confidence during the exam.

Smart Revision Strategy:

Focusing on repeated questions allows for revision of the selected section. Instead of attempting all topics equally, candidates can prioritise high-yield areas that historically appear in the exam. This strategy ensures that the limited revision time is used efficiently and helps in retaining important formulas, concepts, and shortcuts.

Boosts Confidence and Reduces Exam Stress:

Solving repeated questions from previous years provides a sense of confidence in our minds. Candidates feel more prepared and confident, knowing that they have already practised questions that are likely to appear. This reduces exam anxiety and helps maintain a calm and focused mindset on the day of the exam.