55 marks in JEE Mains Percentile - Candidates attempting the JEE Main exam will be curious about what is 55 marks in the JEE Mains percentile means. According to the previous year trends, 55 marks in the JEE Main 2026 exam can translate to around 81 to 82 percentile. NTA releases the JEE Main 2026 result in the form of a percentile. Hence, candidates must be aware of the JEE Main percentile that corresponds to 55 marks in the JEE Main 2026 exam. Candidates can find complete information about 55 marks in the JEE Mains percentile from this article.
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The JEE Mains percentile that is mentioned below is an approximate analysis based on the previous year's trends. However, the JEE Mains marks vs percentile will differ every year based on various factors such as the difficulty level of the JEE Main exam, category of the candidate, number of candidates who attempted the exam and more. Hence, candidates should refer to this as an approximate analysis of the JEE Main marks vs percentile 2026.
JEE Main Marks Range | Expected Percentile Range |
45 – 46 | 72.0 – 73.5 |
47 – 48 | 73.5 – 75.0 |
49 – 50 | 75.0 – 78.0 |
51 – 52 | 78.0 – 79.5 |
53 – 54 | 79.5 – 81.0 |
55 – 56 | 81.0 – 82.5 |
57 – 58 | 82.5 – 84.0 |
59 – 60 | 84.0 – 86.0 |
61 – 62 | 86.0 – 87.0 |
63 – 64 | 87.0 – 88.0 |
65 – 66 | 88.0 – 89.0 |
67 – 68 | 89.0 – 90.0 |
69 – 70 | 90.0 – 91.0 |
JEE Main Percentile Range | Expected All India Rank (AIR) |
72.0 – 73.0 | 3,90,000 – 3,60,000 |
73.0 – 74.0 | 3,60,000 – 3,30,000 |
74.0 – 75.0 | 3,30,000 – 3,00,000 |
75.0 – 76.0 | 3,00,000 – 2,70,000 |
76.0 – 77.0 | 2,70,000 – 2,40,000 |
77.0 – 78.0 | 2,40,000 – 2,10,000 |
78.0 – 79.0 | 2,10,000 – 1,90,000 |
79.0 – 80.0 | 1,90,000 – 1,75,000 |
80.0 – 81.0 | 1,75,000 – 1,65,000 |
81.0 – 82.0 | 1,65,000 – 1,55,000 |
82.0 – 83.0 | 1,55,000 – 1,45,000 |
83.0 – 84.0 | 1,45,000 – 1,35,000 |
84.0 – 85.0 | 1,35,000 – 1,26,000 |
85.0 – 86.0 | 1,26,000 – 1,17,000 |
86.0 – 87.0 | 1,17,000 – 1,08,000 |
87.0 – 88.0 | 1,08,000 – 98,000 |
88.0 – 89.0 | 98,000 – 88,000 |
89.0 – 90.0 | 88,000 – 78,000 |
90.0 – 91.0 | 78,000 – 68,000 |
NTA releases the JEE Main 2026 result in the form of a percentile. It is the normalised score of every candidate based on their performance relative to the performance of the other candidates in the same session. This is done to ensure fairness in the JEE Main result as the exam is conducted in various sessions.
Raw marks in the JEE Main 2026 exam are the marks that the candidate has scored based on the correct and incorrect responses given in the JEE Main exam. The JEE Main 2026 total marks are 300.
Raw marks are calculated using the formula:
Raw Marks =(4× Correct Answers) − (1× Incorrect Answers)
Response Type | Marks Awarded |
Correct answer | +4 marks |
Incorrect answer | −1 mark |
Unattempted question | 0 marks |
Questions withdrawn by NTA | +4 marks to all candidates |
Candidates can refer to the formulas below to calculate the JEE Main 2026 percentile as well as the percentile scores of each subject.
Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) equal to or less than the candidate)/(Total number of candidates who appeared in that session)
Percentile score | Calculation |
Total Percentile (T1P): | (100 x No. of candidates from the session with a raw score equal to or less than the T1 score) / Total No. of candidates appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than the M1 score in Mathematics) / Total No. of candidates appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session |
With 55 marks or approximately 81 percentile in the JEE Main exam, it is difficult for candidates to apply for admission to top branches in institutes like IITs, NITs and others. However, they can still apply for regional engineering institutes. Some of the courses available to candidates with 55 marks in the JEE Main exam are given in the table below
Institute | Course | Closing Rank |
Chemical Engineering | 218902 | |
B.Tech Mechanical Engineering | 169546 | |
B.Tech Computer Science and Engineering | 170692 | |
B.Tech Electrical Engineering | 169235 | |
B.Tech Computer Science and Engineering | 166719 | |
B.Tech Electrical Engineering | 169235 |
Candidates can also apply for admission to various private institutes in India. These engineering institutes conduct their own entrance exams; hence, candidates can attempt the exams for admission. Some of the top private institute entrance exams are given below.
Private Institute / University | Entrance Exam Accepted |
BITS Pilani (Pilani, Goa, Hyderabad Campuses) | |
Manipal Academy of Higher Education (MAHE) | MET (Manipal Entrance Test) |
AEEE (Amrita Entrance Examination – Engineering) |
55 marks in the JEE Main exam are a low score. If the candidate has attempted only session 1, they should also attempt the JEE Main 2026 session 2 exam, as NTA will consider the best score out of the two attempts. If the JEE Main score is low even after both sessions of the exam, candidates can use their JEE Main scores to apply for regional institutes. Alternatively, they can also attempt the entrance exams conducted by private universities so as not to waste a year of their education.
Frequently Asked Questions (FAQs)
As 55 marks is a low score in the JEE Main exam, candidates can opt for State government engineering colleges accepting JEE Main ranks or Private institutes conducting their own entrance exams, such as BITSAT, VITEEE, SRMJEEE, MET, and AEEE.
No, candidates need to be in the top 2,50,000 ranks to attempt the JEE Advanced 2026 exam.
Candidates can expect a percentile of 81 to 82 in the JEE Main exam with 55 marks.
On Question asked by student community
Preparing for the JEE Main in just 30 days is a challenging but achievable task if you follow a highly disciplined and strategic approach. According to the Careers360 30-day study plan , the key is to shift your focus from learning everything to mastering high-weightage topics and practicing rigorously.
During the first 15 days, prioritize topics that frequently appear in the exam.
Physics: Modern Physics, Heat & Thermodynamics, Optics, and Current Electricity.
Chemistry: GOC (General Organic Chemistry), Chemical Bonding, p-Block elements, and Solutions.
Maths: Matrices & Determinants, Sequences & Series, Coordinate Geometry, and Vector & 3D Geometry.
Study Strategy: Use NCERT for Chemistry and simplified notes for Physics/Maths. Spend 3-4 hours on each subject daily.
Short Notes: Go through the short notes you made during the first two weeks.
Flashcards: Use flashcards for inorganic chemistry reactions and physics formulas.
Mock Tests: Start giving one full-length mock test every alternate day. Analyze your mistakes immediately to avoid repeating them.
Previous Year Papers (PYQs): Solve the last 3-5 years of JEE Main papers in the actual exam time slot (9 AM–12 PM or 3 PM–6 PM) to sync your body clock.
No New Topics: Stop picking up new chapters. Focus solely on what you already know to build confidence.
Accuracy over Speed: Focus on getting the questions right rather than attempting all of them, as negative marking can significantly lower your percentile.
You can download the comprehensive day-by-day schedule, which includes specific topics to cover each morning and evening, by visiting the link : https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days
Hello,
If you filled the JEE Main January form with Class 12 passed in 2025 and are planning to appear again for the Class 12 exam through HOS, there is usually no serious issue. You were eligible to apply since you had already passed Class 12. Reappearing through HOS for improvement or requalification is allowed, provided HOS is a recognized board. During counselling, your latest valid Class 12 result will be considered. Make sure you meet the 75% marks or top 20 percentile requirement where applicable. If a correction window opens, update details if needed.
Hope this has solved your query. Thank You.
Good Evening,
Yes, you are eligible for both JEE Mains and Advanced, as you completed your 12th with physics, chemistry and biology. Moreover, you passed mathematics in 2025, which makes you fit the eligibility criteria of both exams.
Aspirant, I would like to inform you that Careers360 recently launched a free mock test series for JEE students. The last date of registration is 8th January, 2026. Enroll and solve chapter wise question papers and improve you concept and assess your learning. The link to the mock test series is attached herewith. https://learn.careers360.com/test-series-jee-main-free-mock-test/
Best regards.
Hello,
Since the NTA conducts exams in Tamil, these official papers will have a Tamil language option. Kindly check the following link to get the question papers.
https://engineering.careers360.com/articles/jee-main-question-papers
I hope this helps you.
Hello there,
Understanding and solving different question papers is one of the best practice for the preparation specially when it comes to JEE mains. It gives you proper understanding of the exam pattern, important topics to cover and marking scheme.
Here is the link attached from the official website of Careers360 which will provide you with the link of previous year question papers on chemistry in PDF format. Hope it helps!
https://engineering.careers360.com/articles/jee-mains-chemistry-questions-in-last-year-exam-premium
thank you!
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