55 marks in JEE Mains Percentile - Candidates aiming to clear the exam must know the meaning of 55 marks in JEE Mains percentile 2026. The significance of 55 marks in JEE Main percentile will help to predict the chances of admission in good colleges. Based on previous year's exam trends and analysis, 55 marks in the JEE Main 2026 exam can be equal to around 81 to 82 percentile. NTA releases the JEE Main 2026 result in the form of a percentile, rather than in the form of scores. Hence, candidates must be aware of the JEE Main percentile that corresponds to 55 marks in the JEE Main 2026 exam. Candidates shoudl go through this page to know what are 55 marks in JEE Mains percentile 2026.
The NTA has not yet released the JEE Main 2026 admit card. Candidates will be able to download the JEE Main 2026 session 1 admit card from jeemain.nta.nic.in about three days before the exam. It is expected to be released in the third week of January 2026.
JEE Mains 2026 admit card soon. (Representational image: Freepik)
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The JEE Main 2026 exam dates have been announced as January 21 to 30, 2026, while the session 2 of the exam will be held from April 2 to 9, 2026. The JEE Mains percentile that is mentioned below is an approximate analysis based on the previous year's trends. However, the JEE Mains marks vs percentile will differ every year based on various factors such as the difficulty level of the JEE Main exam, category of the candidate, number of candidates who attempted the exam and more. Hence, candidates should refer to this as an approximate analysis of the JEE Main marks vs percentile 2026.
JEE Main Marks Range | Expected Percentile Range |
|---|---|
45 – 46 | 72.0 – 73.5 |
47 – 48 | 73.5 – 75.0 |
49 – 50 | 75.0 – 78.0 |
51 – 52 | 78.0 – 79.5 |
53 – 54 | 79.5 – 81.0 |
55 – 56 | 81.0 – 82.5 |
57 – 58 | 82.5 – 84.0 |
59 – 60 | 84.0 – 86.0 |
61 – 62 | 86.0 – 87.0 |
63 – 64 | 87.0 – 88.0 |
65 – 66 | 88.0 – 89.0 |
67 – 68 | 89.0 – 90.0 |
69 – 70 | 90.0 – 91.0 |
JEE Main Percentile Range | Expected All India Rank (AIR) |
|---|---|
72.0 – 73.0 | 3,90,000 – 3,60,000 |
73.0 – 74.0 | 3,60,000 – 3,30,000 |
74.0 – 75.0 | 3,30,000 – 3,00,000 |
75.0 – 76.0 | 3,00,000 – 2,70,000 |
76.0 – 77.0 | 2,70,000 – 2,40,000 |
77.0 – 78.0 | 2,40,000 – 2,10,000 |
78.0 – 79.0 | 2,10,000 – 1,90,000 |
79.0 – 80.0 | 1,90,000 – 1,75,000 |
80.0 – 81.0 | 1,75,000 – 1,65,000 |
81.0 – 82.0 | 1,65,000 – 1,55,000 |
82.0 – 83.0 | 1,55,000 – 1,45,000 |
83.0 – 84.0 | 1,45,000 – 1,35,000 |
84.0 – 85.0 | 1,35,000 – 1,26,000 |
85.0 – 86.0 | 1,26,000 – 1,17,000 |
86.0 – 87.0 | 1,17,000 – 1,08,000 |
87.0 – 88.0 | 1,08,000 – 98,000 |
88.0 – 89.0 | 98,000 – 88,000 |
89.0 – 90.0 | 88,000 – 78,000 |
90.0 – 91.0 | 78,000 – 68,000 |
NTA releases the JEE Main 2026 result in the form of a percentile. It is the normalised score of every candidate based on their performance relative to the performance of the other candidates in the same session. This is done to ensure fairness in the JEE Main result as the exam is conducted in various sessions.
Raw marks in the JEE Main 2026 exam are the marks that the candidate has scored based on the correct and incorrect responses given in the JEE Main exam. The JEE Main 2026 total marks are 300.
Raw marks are calculated using the formula:
Raw Marks =(4× Correct Answers) − (1× Incorrect Answers)
| Response Type | Marks Awarded |
|---|---|
Correct answer | +4 marks |
Incorrect answer | −1 mark |
Unattempted question | 0 marks |
Questions withdrawn by NTA | +4 marks to all candidates |
Candidates can refer to the formulas below to calculate the JEE Main 2026 percentile as well as the percentile scores of each subject.
Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) equal to or less than the candidate)/(Total number of candidates who appeared in that session)
Percentile score | Calculation |
|---|---|
Total Percentile (T1P): | (100 x No. of candidates from the session with a raw score equal to or less than the T1 score) / Total No. of candidates appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than the M1 score in Mathematics) / Total No. of candidates appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session |
With 55 marks or approximately 81 percentile in the JEE Main exam, it is difficult for candidates to apply for admission to top branches in institutes like IITs, NITs and others. However, they can still apply for regional engineering institutes. Some of the courses available to candidates with 55 marks in the JEE Main exam are given in the table below
Institute | Course | Closing Rank |
|---|---|---|
Chemical Engineering | 218902 | |
B.Tech Mechanical Engineering | 169546 | |
B.Tech Computer Science and Engineering | 170692 | |
B.Tech Electrical Engineering | 169235 | |
B.Tech Computer Science and Engineering | 166719 | |
B.Tech Electrical Engineering | 169235 |
Candidates can also apply for admission to various private institutes in India. These engineering institutes conduct their own entrance exams; hence, candidates can attempt the exams for admission. Some of the top private institute entrance exams are given below.
| Private Institute / University | Entrance Exam Accepted |
|---|---|
BITS Pilani (Pilani, Goa, Hyderabad Campuses) | |
Manipal Academy of Higher Education (MAHE) | MET (Manipal Entrance Test) |
AEEE (Amrita Entrance Examination – Engineering) |
55 marks in the JEE Main exam are a low score. If the candidate has attempted only session 1, they should also attempt the JEE Main 2026 session 2 exam, as NTA will consider the best score out of the two attempts. If the JEE Main score is low even after both sessions of the exam, candidates can use their JEE Main scores to apply for regional institutes. Alternatively, they can also attempt the entrance exams conducted by private universities so as not to waste a year of their education.
Frequently Asked Questions (FAQs)
As 55 marks is a low score in the JEE Main exam, candidates can opt for State government engineering colleges accepting JEE Main ranks or Private institutes conducting their own entrance exams, such as BITSAT, VITEEE, SRMJEEE, MET, and AEEE.
No, candidates need to be in the top 2,50,000 ranks to attempt the JEE Advanced 2026 exam.
Candidates can expect a percentile of 81 to 82 in the JEE Main exam with 55 marks.
On Question asked by student community
Hello,
Yes, attendance is compulsory in Class XI and XII.
As per school and board rules, students must maintain minimum attendance, usually around 75%. Schools can stop students from appearing in board exams if attendance is short.
Even if a student is preparing for JEE or any other competitive exam
Hello,
You can find here the direct links to download the JEE Main last 10 years PYQ PDFs from the Official Careers360 website.
Kindly visit this link to access the question papers : Last 10 Years JEE Main Question Papers with Solutions PDF
Hope it helps !
Hello Harika,
Firstly, you cannot prepare for JEE in 8 days if you havent studied before. But still, You can try solving the previous year question papers. Here's a Link for the same
HELLO,
If you are from General category with 57 percent in 12th then to appear for JEE Advanced you need to be in top percentile of your board as the eligibility for JEE advanced you need at least 75 percent in 12th or in the top 20 percentile of your
Hello aspirant,
The JEE Main 2026 admission card will include information about the exam location. On the other hand, students can use the JEE Main 2026 city notification slip, which was made available on January 8, 2026, to check the exam city beforehand. The second week of January 2026 is
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