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JEE Main Physics Formulas 2025 - Topic wise Important Formulas
Edited By Team Careers360 | Updated on Dec 15, 2024 10:33 PM IST | #JEE Main
JEE Main Physics Formulas 2025 - JEE Main is one of the top Exams for engineering. Having a consolidated formula sheet makes your preparation for the JEE Main exam more manageable and efficient. Candidates should manage all three subjects properly, when candidates have a compiled list of important physics formulas candidates can revise the concepts faster and solve numerous problems easily. Knowing when and which formula to apply is crucial for aspirants. Here are some important JEE Main Physics formulas 2025 based on the JEE syllabus. Candidates can follow the Physics formulas to prepare for the IIT JEE exam:
Download JEE Main Physics Formulas PDF
Few Important JEE Main Physics Formulas 2025
Chapter - Kinematics
Speed and Velocity
I. Speed Formula-
Speed $=\frac{\text { Change in distance }}{\text { change in time }}$
$v=\frac{\text { distance }}{\text { time }}$
- Tips of Speed-
1. S.I. unit $\longrightarrow \mathrm{ms}^{-1}$ or meters per second.
2. Dimensions $=L T^{-1}$
3. Speed is a scalar quantity.
- E.g: A body covers a distance of 18 m in 1 sec
Using the formula of speed. $v=\frac{\text { distance }}{\text { time }}=\frac{18 \mathrm{~m}}{1 \mathrm{~s}} \Rightarrow 18 \mathrm{~m} / \mathrm{s}$
II. Average Speed and Instantaneous Speed
Average Speed Formula-
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Use NowAverage speed $=\frac{\text { total distance covered }}{\text { total time taken }} v_{a v}=\frac{s}{t}$
E.g. A body covers a total distance of 50 m with variable speed in 5 sec.
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$$
\begin{aligned}
& v_{a v}=\frac{s}{t} \\
& \Rightarrow \frac{50 \mathrm{~m}}{5 \mathrm{~s}}=10 \mathrm{~m} / \mathrm{s}
\end{aligned}
$$
Average Speed $=10 \mathrm{~m} / \mathrm{s}$
- Tips for average speed-
If an object or body covers s1 distance in $\mathrm{t1}$ time and s2 distance in 12 time then average speed is calculated by the Formula- $V_{\alpha v}=\frac{s_1+s_2}{t_1+t_2}$
2. Instantaneous Speed-
- It is the speed at that particular instant or small interval of time.
- Formula-
$$
v_{\text {inst }}=\lim _{\Delta t \rightarrow 0} \frac{\Delta x}{\Delta t}
$$
III. Velocity
Rate of change of displacement with time.
Formula-
$$
V=\frac{\text { displacement }}{\text { time }}
$$
- Tips For Velocity-
1. S.I. unit $\rightarrow \mathrm{m} / \mathrm{s}$
2. Dimensions- $L T^{-1}$
3. Velocity is a vector quantity.
4. Velocity is also called speed in a definite (particular) direction.
IV. Average Velocity and Instantaneous Velocity
1. Average Velocity-Formula-
Average Velocity $=\frac{\text { Total Displacement }}{\text { Total time taken }} \vec{V}_{\text {avg }}=\frac{\vec{S}_{\text {net }}}{t}$
2. Instantaneous Velocity Formula-
$$
\vec{V}_{\text {inst }}=\lim _{\Delta t \rightarrow 0} \frac{\overrightarrow{\Delta x}}{\Delta t}
$$
Chapter - Work Energy and Power
- Work done by a constant force-
1. The scalar product of the force vector $(\vec{F})$ and the displacement vector $(\vec{S})$
$$
W=\vec{F} \cdot \vec{S}
$$
2. The product of the magnitude of force $(F)$ magnitude of displacement $(S)$ and cosine of the angle between them $(\Theta)$
$$
W=F S \cos \theta
$$
3. If the number of forces $\vec{F}_1, \vec{F}_2, \vec{F}_3 \ldots \ldots, \vec{F}_{\mathrm{n} \text {, are acting on a body and it shifts from position vector }} \vec{r}_1$ to position vector $\vec{r}_2$
Then
$$
W=\left(\vec{F}_1+\vec{F}_2+\vec{F}_3 \ldots \ldots \ldots+\vec{F}_n\right) \cdot\left(\vec{r}_2-\vec{r}_1\right)=\vec{F}_{n e t} \cdot \vec{r}_{n e t}
$$- Work done by a variable force
Force is a vector quantity. So it has a magnitude as well as direction. A variable force means when its magnitude its direction or both varies with position.
And work done by the variable force is given by -$$
W=\int \vec{F} \cdot \overrightarrow{d s}
$$
Where $\vec{F}$ is a variable force and $\vec{d}$ is a small displacement
- Kinetic energy$$
K . E .=\frac{1}{2} m v^2
$$
Where $m \rightarrow$ mass$$
v \rightarrow \text { velocity }
$$- Work-energy theorem-
Net work done by all the forces acting on a particle is equal to the change in its kinetic energy.
$$
\begin{aligned}
W & =\frac{1}{2} m v^2-\frac{1}{2} m v_0^2 \\
W & =k_f-k_i
\end{aligned}
$$
Where $m=$ mass of the body
$v_0=$ initial velocity
$v=$ final velocity
- Relation of kinetic energy with linear momentum
$$
k=\frac{p^2}{2 m}
$$
Where $p \rightarrow$ momentum
$$
m \rightarrow \text { mass }
$$
- Change in potential energy -
The change in potential energy between any two points is defined as the work done by the associated conservative force in displacing the particle between these two points without any change in kinetic energy.
$$
U_i-U_f=\int_{r_i}^{r_f} \vec{f} \cdot \overrightarrow{d s}
$$
Where, $U_f$ - final potential energy
$U_i$ - initial potential energy
$f$-force
ds - small displacement
$r_i$ - initial position
$r_f-f i n a l$ position
We can define a unique value of potential energy only by assigning some arbitrary value to a fixed point called the reference point.
- Power
Average power-
$$
P_{a v}=\frac{\Delta w}{\Delta t}=\frac{\int_0^t p \cdot d t}{\int_0^t d t}
$$
Instantaneous power-
$$
P=\frac{d w}{d t}=P=\vec{F} \cdot \vec{v}
$$
Where, $\vec{F} \rightarrow$ force
$$
\vec{v} \rightarrow \text { velocity }
$$
i.e. power is equal to the scalar product of force with velocity
Experts of Careers 360 have compiled a list of important formulas for JEE Mains Physics to make the preparation easy for aspirants. Candidates preparing for the JEE Main exam should remember all the major formulas.
Frequently Asked Questions (FAQs)
1. Which chapter has more weightage in Physics in the JEE Main Exam?
Current electricity, optics, and Properties of solids have more weightage in Physics JEE Main.
2. How many questions of Physics are in the JEE Main Exam?
In the JEE Main Exam, there are 25 questions of physics out of which 20 questions in section A will be MCQ and 5 questions in section B will be questions with numerical value answers.
3. What is the formula in physics which relates speed, distance traveled and time taken by the body to travel that distance?
Speed= (distance) / (time)
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Questions related to JEE Main
Have a question related to JEE Main ?
With 64 percentile and a CRL rank around 5.4 lakh in JEE Mains 2025, getting admission in any NIT or IIIT is very unlikely, especially in the general category. Most NITs close their admissions below a rank of 1.5 lakh, and even the newer NITs usually fill seats by around 3 to 3.5 lakh rank. IIITs generally have closing ranks below 3 lakh.
Instead, you can try for state government engineering colleges through your state counselling or look for private engineering colleges that have lower cutoff ranks. Another option is to explore management quota or direct admission routes if available.
harsh singh 05 June,2025
With a JEE B.Arch rank of 30,000, getting admission in DCRUST is not possible because their cutoff ranks are much lower and they mainly consider NATA scores, not JEE Paper 2.
You can try these options instead:
Apply to other colleges accepting NATA scores.
Consider management quota seats in private colleges.
Prepare and appear for NATA exam for better chances.
harsh singh 05 June,2025
With a JEE Advanced rank of 20,340, your son can likely get admission in newer IITs like IIT Bhubaneswar, Gandhinagar, Ropar, Mandi, Indore, Patna, or Jodhpur, mostly in less competitive branches.
Top IITs and popular branches like CS or ECE are unlikely.
harsh singh 05 June,2025
Hello Hemalakshmi,
No, JEE Mains is not mandatory just because you are a resident of Pondicherry. Nevertheless, if you intend to gain admission into most engineering colleges/ Institutions across India including those in Pondicherry, you will most likely have to take and qualify in JEE Mains or any entrance tests which may be approved by the institution or college as the case may be. Certain colleges might also have their specified entrance criteria or admission by way of state-level entrance exams or management quota, but JEE Mains is the extremely primary national level engineering entrance and is thus widely used.
gopi 05 June,2025
Hello Aspirant,
Yes, to be under Foreign Nationals DASA Counselling 2025, you must have done atleast 2 years of education abroad (outside India) within 8 years to the time of admission. This is a pre-requisite eligibility for acceptance under Foreign Nationals category.
gopi 05 June,2025
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