JEE Main 2027 Chemistry Sample Paper with Answer Key - Download PDF & Solutions

JEE Main 2027 Chemistry Sample Paper with Answer Key

The JEE Main 2027 Chemistry Sample Paper with Answer Key is created to help students practice exam-oriented questions and improve their understanding of Physical, Organic, and Inorganic Chemistry. We are also giving the direct link so you can access, download, and solve the sample paper with ease.

For additional JEE Main Chemistry Sample Papers with Solutions 2027, students can use the free Careers360 resource. It provides mock tests, sample papers, chapter-wise and subject-wise tests, plus JEE Main Free Study Material.

Tips to Practice JEE Main Chemistry Sample Papers

1. Simulating Actual Examination Conditions

Simulating actual Examination Conditions by solving the JEE Main 2027 Chemistry sample paper with answer key using a timer similar to the one used in the actual JEE Main Examination helps to develop speed, accuracy, and examination temperament.

2. Identifying Your Weak Chapters

After attempting the Sample Papers, look at the topics that you performed poorly on, such as Chemical Bonding, Thermodynamics, Organic Reaction Mechanisms, etc., and revise those specific chapters before proceeding to the next set of Sample Papers.

3. Understanding Why Your Answers Were Correct or Incorrect

Go through the JEE Main Chemistry Sample Paper with Solutions 2027 to fully understand the rationale behind each answer, whether it was correct or incorrect. Understanding why you answered questions incorrectly will help you avoid making the same mistakes again.

4. Creating Notes of Formulas & Reactions

While going through the JEE Main Chemistry sample paper with answer key 2027, make sure to go through the important formulas of chemistry, patterns in reactions, exceptions, and shortcut techniques in your notes.

5. Monitoring Your Improvement

While practising with the JEE Main Chemistry sample paper with answer key 2027, continue to take at least one or two Sample Papers each week and compare your scores to determine your continued improvement and develop self-confidence.

JEE Main 2027 Chemistry Sample Questions

We have given some questions from the chemistry sample paper for reference.

Question 1: Identify the correct statement among the following:

1) All naturally occurring amino acids except glycine contain one chiral centre.

2) All naturally occurring amino acids are optically active.

3) Glutamic acid is the only amino acid that contains a –COOH group at the side chain.

4) The amino acid cysteine easily undergoes dimerisation due to the presence of the free SH group.

Correct Answer: The amino acid, cysteine, easily undergoes dimerisation due to the presence of a free SH group.

Solution:

* Isoleucine has 2 chiral centres

* Glycine is optically inactive

* Aspartic acid also contains COOH groups on the side chain.

* Cysteine easily dimmerise due to the free SH group

Question 2:Arrange the following metal complex/compounds in the increasing order of spin only magnetic moment. Presume all the three, high spins system.
(Atomic numbers $\mathrm{Ce}=58, \mathrm{Gd}=64$ and $\mathrm{Eu}=63$ )
$(a)\left(\mathrm{NH}_4\right)_2\left[\mathrm{Ce}\left(\mathrm{NO}_3\right)\right]_6$
(b) $G d\left(\mathrm{NO}_3\right)_3$
(c) $\mathrm{Eu}\left(\mathrm{NO}_3\right)_3$

answer is :

1) c < a< b

2) a < b < c

3) a < c < b

4) b < a < c

Answer: (3) a < c < b

Solution:

(a) ${ }_{58} \mathrm{Ce} \rightarrow[\mathrm{Xe}] 4 \mathrm{f}^2 5 \mathrm{~d}^0 6 \mathrm{~s}^2$

In complex $\mathrm{Ce}^{4+} \rightarrow[\mathrm{Xe}] 4 \mathrm{f}^0 5 \mathrm{~d}^0 6 \mathrm{~s}^0$ there is no unpaired electron so $\mu_{\mathrm{m}}=0$
(b) ${ }_{64} \mathrm{Gd}^{3+} \rightarrow[\mathrm{Xe}] 4 \mathrm{f}^7 5 \mathrm{~d}^0 6 \mathrm{~s}^0$
contain seven unpaired electrons so

$\mu_{\mathrm{m}}=\sqrt{7(7+2)}=\sqrt{63} \text { B.M. }$

(c) $\left.{ }_{63} \mathrm{Eu}^{3+} \rightarrow{ }_{54} \mathrm{Xe}\right] 4 \mathrm{f}^6 5 \mathrm{~d}^0 6 \mathrm{~s}^0$
contain six unpaired electrons
so, $\mu_{\mathrm{m}}=\sqrt{6(6+2)}=\sqrt{48}$ B.M.
Hence, the order of spin only magnetic movement

$\mathrm{b}>\mathrm{c}>\mathrm{a}$

Question 3: A solution is made by mixing one mole of volatile liquid A with 3 moles of volatile liquid B. The vapour pressure of pure A is 200 mm Hg and that of the solution is 500 mm Hg. The vapour pressure of pure B and the least volatile component of the solution, respectively, are :

1) 1400 mm Hg, A

2) 1400 mm Hg, B

3) 600 mm Hg, B

4) 600 mm Hg, A

Correct Answer: 600 mm Hg, A

Solution:

$P_S=P_A^{\circ} \cdot X_A+P_B^{\circ} \cdot X_B$

$500=200 \times \frac{1}{4}+P_B^{\circ} \cdot \frac{3}{4}$

$P_B^{\circ}=600 \text{ mmHg}$

$\text{As } P_A^{\circ} < P_B^{\circ} \Rightarrow \text{A is least volatile.}$

Hence, the correct answer is option (4).

Question 4: The property/properties that show irregularity in the first four elements of group-17 is/are :

(A) Covalent radius

(B) Electron affinity

(C) Ionic radius

(D) First ionisation energy

Choose the correct answer from the options given below:

1) B and D only

2) A and C only

3) B only

4) A, B, C and D

Correct Answer: B only

Solution:

The order of the first four elements of group 17 is as follows

F< Cl< Br< I (Covalent radius)

Cl > F>Br>I (Electron affinity)

$\mathrm{F}^{-}<\mathrm{Cl}^{-}<\mathrm{Br}^{-}<\mathrm{I}^{-}$

F >Cl>Br>I ( Ist ionization energy)

The electron affinity order is irregular.

Hence, the correct answer is option (3).

Question 5: In the sixth period, the orbitals that are filled are :

1) 6s, 4f, 5d, 6p

2) 6s, 5d, 5f, 6p

3) 6s, 5f, 6d, 6p

4) 6s, 6p, 6d, 6f

Correct answer: (1) 6s, 4f, 5d, 6p

Solution:

Energy order of orbital’s according to Aufbau principle

The order of orbitals filling is 6s, 4f, 5d, 6p.