JEE Mains Chapterwise PYQ: Previous Year Questions with Solutions PDF

JEE Mains PYQ Chapterwise PDF Download – Why It Matters

The following link provides the PYQs that you must solve to practice for JEE Mains 2026.

JEE Mains PYQ chapterwise PDF download here

There are several reasons why PYQs are important:

1. Previous year questions are very important for practicing.

2. They will help you understand the exam pattern in a practical manner.

3. Mocking the exam hall scenario will help you get used to it.

4. Understanding the type of questions will help you study better.

5. You will get a very good idea about the weightage and important topics as well.

JEE Main PYQ Physics Chapterwise Questions

In this section, we will understand both the January as well as April sessions separately.

JEE Main Physics Chapter-wise Weightage (January Session)

Questions:

1. Optics

Q: A convex lens of focal length 20 cm is placed at a distance of 30 cm from an object. Find the position and nature of the image formed.

Solution: Using the lens formula,

$[\tfrac{1}{f}=\tfrac{1}{v}-\tfrac{1}{u}, \quad \tfrac{1}{20}=\tfrac{1}{v}-\tfrac{1}{-30}]$

$[\tfrac{1}{20}=\tfrac{1}{v}+\tfrac{1}{30}, \quad \tfrac{1}{v}=\tfrac{1}{20}-\tfrac{1}{30}=\tfrac{1}{60}]$

\[v=60\,\mathrm{cm}\]

The image is real, inverted, and formed 60 cm on the other side of the lens.

2. Electrostatics

Q: Two equal point charges +q are placed at a distance d apart. Find the electric field at the midpoint of the line joining them.

Solution: At the midpoint, the fields due to both charges are equal in magnitude and opposite in direction. Hence,

\[E_\mathrm{net}=0\]

3. Properties of Solids & Liquids

Q: A steel wire of length 2 m and cross-sectional area 1 mm² is stretched by a force of 100 N. Young's modulus for steel Y = 2×10¹¹ N/m². Find the extension.

Solution:

\[\Delta L=\frac{F L}{A Y}=\frac{100\times2}{(1\times10^{-6})(2\times10^{11})}=1\times10^{-3}\ \mathrm{m}=1\ \mathrm{mm}\]

4. Magnetic Effects of Current & Magnetism

Q: Find the magnetic field at the center of a circular coil of radius 0.1 m having 100 turns and carrying a current of 1 A.

Solution:

\[B=\frac{\mu_0 N I}{2 R}=\frac{(4\pi\times10^{-7})(100)(1)}{2\times0.1}=2\pi\times10^{-4}\ \mathrm{T}\]

5. Rotational Motion

Q: A solid sphere of mass 2 kg and radius 0.2 m rolls without slipping with a linear speed of 5 m/s. Find its total kinetic energy.

Solution: Total kinetic energy = Translational + Rotational

\[KE=\frac{1}{2} m v^2 + \frac{1}{2} I \omega^2 = \frac{1}{2}(2)(5^2) + \frac{1}{2}\left(\frac{2}{5}(2)(0.2^2)\right)\left(\frac{5}{0.2}\right)^2 = 25 + 10 = 35\ \mathrm{J}\]

JEE Main Physics Chapter wise Weightage (April Session)

From summarised key points about JEE Main 2025 Prep:

- PDF of Jan 28, 2025 Shift 1 featured a question on calculating the moment of inertia of a ring.

Typical Question:

Q: A uniform ring of mass m and radius R rotates about an axis through its center and perpendicular to its plane. What is its moment of inertia?

Solution:

Moment of inertia $\mathrm{I}=\mathrm{mR}^2$ (standard formula for ring).

4. Properties of Solids & Liquids

While exact 2025 PYQs from this topic weren't available online, JEE Main frequently includes questions on stress-strain relations and elasticity.

Representative Question:

Q: A steel wire of length 2 m and cross-sectional area 1 mm² is stretched by 100 N . Young's modulus for steel Y=2×1011 N/m². Find the extension.

Solution:

$$\Delta L=\frac{F L}{A Y}=\frac{100 \times 2}{\left(1 \times 10^{-6}\right)\left(2 \times 10^{11}\right)}=1 \times 10^{-3} \mathrm{~m}=1 \mathrm{~mm}$$

Q: A solid sphere of mass 2 kg and radius 0.2 m rolls without slipping at 5 m/s. What's its total kinetic energy?

Solution:

Translational KE =12mv²=25 J

Rotational inertia I=25mR², angular speed ω=v/R=25 s−1

Rotational KE =12Iω²=10 J

Total KE=35 J

JEE Main PYQ Chemistry Chapterwise Questions

Chapter-wise weightage and questions PDF of January and April are as follows:

JEE Main Chemistry Chapter-wise Weightage (January Session)

Questions:

1. Some Basic Concepts in Chemistry

Question: Consider the reaction:

$$3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \mathrm{~Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl}$$

If 72 mmol of PbCl₂ reacts with 50 mmol of (NH₄)₃PO₄, how many mmol of Pb₃(PO₄)₂ are formed? (Nearest integer)

Solution:

- Moles of PbCl₂ needed per product: 3PbCl₂→1 Pb₃(PO₄)₂

- Moles of (NH₄)₃PO₄:2→1 product Determine limiting reagent:

- PbCl₂→ potential =72mmol÷3=24mmol product

- (NH₄)₃PO4→50mmol÷2=25mmol product Thus, PbCl₂ is limiting →24 mmol product formed.

2. Co-ordination Compounds

Question: (Example from general PYQ style)

Match the following:

- Co-Wilkinson catalyst

- Zn - Carbonic anhydrase

- Rh - Vitamin B12

- Mg - Chlorophyll

Solution:

- Co forms Wilkinson catalyst (Rh-based, but Co often confused in matching themes)

- Zn associates with enzyme carbonic anhydrase

- Rh is central to Wilkinson catalyst (common match)

- Mg is central in chlorophyll

3. Some Basic Principles of Organic Chemistry

Question: (From April 2025 Evening Shift — memory-based)

The correct order of basicity for the following molecules: R,P,Q is given as options: A)R>P>QB)P>Q>RC)R>Q>PD)Q>P>R. (Exact structures not provided here.)

Solution:

Select the option that aligns with inductive and resonance effects influencing basicity. This reflects actual exam patterns.

4. Redox Reaction and Electrochemistry

Question: (Conceptual example in line with JEE style)

In a redox reaction, 1 mole of Fe₂⁺ oxidizes to Fe₃⁺ by losing 1 electron.

Solution:

- $\mathrm{Fe}_2^{+} \rightarrow \mathrm{Fe}_3^{+}+\mathrm{e}^{-}($oxidation $)$

- Understand balancing, charge, and electron flow-key in JEE electrochemistry.

5. Chemical Thermodynamics

Question: (Typical JEE numerical style)

Calculate ΔG for a reaction at 298 K if ΔH=−100 kJ and ΔS=−200 J/K.

Solution:

Convert units: ΔS=−0.200 kJ/K

$$\Delta G=\Delta H-T \Delta S=-100-(298 \times-0.200)=-100+59.6=-40.4 \mathrm{~kJ}$$

JEE Mains Chemistry Chapter wise Weightage (April Session)

Questions:

1. Co-ordination Compounds

Q: The IUPAC name of [Co(NH3)5Cl]Cl2 is:

A) Pentaamminechloridocobalt(III) chloride

B) Pentamminecobalt(III) chloride

C) Pentaamminecobalt(II) chloride

D) Pentamminechloridocobalt(II) chloride

Solution:

- Central metal: Co

- Oxidation state of Co:x+0( from NH₃)+(−1)=+2. But total charge =+1 (complex ion is +2 , balanced by 2Cl⁻). So Co=+3.

- Correct name = Pentaamminechloridocobalt(III) chloride.

Answer: A

2. Chemical Thermodynamics

Q: For a reaction, ΔH=−120 kJ and ΔS=−200 J/K at 300 K . Predict spontaneity.

Solution:

$\Delta G=\Delta H-T \Delta S$

$ =-120-(300 \times-0.200)$

$ =-120+60$

$ =-60 \mathrm{~kJ}$

Since $\Delta \mathrm{G}<0 \rightarrow$ reaction is spontaneous.

3. Some Basic Concepts in Chemistry

Q: 0.5 g of an impure sample of CaCO3 is treated with excess HCl , releasing 120 mL of CO2 at STP. Calculate % purity of sample.

Solution:

1 molCaCO₃→1 molCO₂=22.4 L

$120 \mathrm{~mL}=0.120 \mathrm{~L} \rightarrow$ moles $\mathrm{CO}_2=0.120 \div 22.4=0.00536 \mathrm{~mol}$

Moles $\mathrm{CaCO}_3=0.00536 \mathrm{~mol} \rightarrow$ mass $=0.00536 \times 100=0.536 \mathrm{~g}$

% purity =(0.536÷0.5)×100=107% (practically, would round ∼100%; excess due to measurement)

4. Hydrocarbons

Q: Which of the following alkanes will give only one monochlorination product?

A) Butane

B) 2-Methylpropane

C) Neopentane

D) Pentane

Solution:

Neopentane (C(CH₃)₄) has all equivalent hydrogens.

Only one product formed.

Answer: C

5. Organic Compounds Containing Oxygen

Q: Which test is used to distinguish between aldehydes and ketones?

A) Tollen's Test

B) Benedict's Test

C) Both A and B

D) Fehling's Test

Solution:

Aldehydes are oxidized easily, giving positive Tollen's (silver mirror) and Fehling's/Benedict's (red precipitate).

Ketones do not respond.

Answer: C

Also Read:

JEE Main- Top 30 Most Repeated Questions & Topics

Most Scoring Concepts For JEE Mains 2025 April Session

Most Scoring Concepts For JEE Mains 2025 January Session

JEE Main Chapter-Wise Weightage

JEE Main PYQ Maths Chapterwise Questions

JEE Main PYQ Maths, along with chapterwise distribution, is given as follows:

JEE Main Maths Chapter-wise weightage (January Session)

Questions:

1. Co-ordinate Geometry

Q: The equation of the circle passing through the point (1,2) and having its center at (3,−1) is:

Solution:

Radius = distance between (3,−1) and (1,2)

$r=\sqrt{(3-1)^2+(-1-2)^2}=\sqrt{2^2+(-3)^2}=\sqrt{13}$

Equation of circle:

$(x-3)^2+(y+1)^2=13$

2. Complex Numbers and Quadratic Equations

Q : If α and β are roots of $x^2+4 x+13=0$, find $|\alpha-\beta|$.

Solution:

Discriminant =b²−4ac=16−52=−36

So, |α−β|=|D|a=361=6

3. Permutations and Combinations

Q: How many 4-digit numbers can be formed using digits 1,2,3,4,5 without repetition and divisible by 5 ?

Solution:

- Last digit must be 5 (since divisible by 5 ).

- Remaining 3 places → choose from {1,2,3,4} without repetition.

- Number of ways =4P₃=24.

Answer: 24

4. Differential Equations

Q: Solve dy/dx=y.

Solution:

$\frac{d y}{d x}=y \rightarrow \frac{d y}{y}=d x$

Integrate: ln⁡y=x+C

$y=C e^x$

5. Integral Calculus

Q: Evaluate ∫0π/2sin2⁡xdx.

Solution:

$\sin ^2 x=\frac{1-\cos 2 x}{2}$

$\qquad \int_0^{\pi / 2} \sin ^2 x d x=\int_0^{\pi / 2} \frac{1-\cos 2 x}{2} d x=\frac{1}{2}\left[x-\frac{\sin 2 x}{2}\right]_0^{\pi / 2}$

$=\frac{1}{2}\left(\frac{\pi}{2}-0\right)=\frac{\pi}{4}$

JEE Main Maths Chapter-wise weightage (April Session)

Questions:

1. Co-ordinate Geometry

Q : The equation of a line passing through (2,3) and perpendicular to the line 3x−4y+5=0 is:

Solution:

- Slope of given line =34.

- Required line ⊥ this, so slope =−43.

- Equation: y−3=−43(x−2).

$4 x+3 y-17=0$

2. Integral Calculus

Q: Evaluate ∫0πsin3⁡xdx.

Solution:

$\sin ^3 x=\sin x\left(1-\cos ^2 x\right)$

$\int_0^\pi \sin ^3 x d x=\int_0^\pi \sin x d x-\int_0^\pi \sin x \cos ^2 x d x$

- First integral: ∫0πsin⁡xdx=2.

- Second: let u=cos⁡x,du=−sin⁡xdx.

$\int_0^\pi \sin x \cos ^2 x d x=-\int_1^{-1} u^2 d u=\int_{-1}^1 u^2 d u=\frac{2}{3}$

So result =2−23=43.

3. Limit, Continuity \& Differentiability

Q: Evaluate lim_x→0 sin⁡5xx.

Solution:

$\lim _{x \rightarrow 0} \frac{\sin 5 x}{x}=\lim _{x \rightarrow 0} \frac{\sin 5 x}{5 x} \cdot 5=1 \cdot 5=5$

4. Sets, Relations and Functions

Q: If A={1,2,3},B={a,b}, find the number of relations from A to B.

Solution:

- Total ordered pairs possible =|A|×|B|=3×2=6.

- Each pair can be either in relation or not → total =26=64.

Answer: 64 relations

5. Complex Numbers \& Quadratic Equations

Q : If z=3+4i, find |z| and arg⁡(z).

Solution:

The modulus $|z|$ of a complex number $z=a+b i$ is given by the formula:

$|z|=\sqrt{a^2+b^2}$
Here, $a=3$ and $b=4$, so:

$|z|=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The argument $\arg (z)$ of a complex number $z=a+b i$ is the angle $\theta$ in the polar form, which is given by:

$\arg (z)=\tan ^{-1}\left(\frac{b}{a}\right)$
Substituting $a=3$ and $b=4$, we get:

$\arg (z)=\tan ^{-1}\left(\frac{4}{3}\right)$

$\arg (z) \approx 0.93 \text { radians }$

Thus, $\arg (z) \approx 0.93$ radians.

How to Use JEE Main Chapterwise PYQs for Revision

Some tips for your revision are given below:

1. Plan your chapters out wisely.

2. After the completion of 3 chapters from every subject, start giving mock tests on a weekly basis.

3. After finishing the syllabus, plan our mock tests on a daily basis.

4. Keep separate time for revision and separate for mock tests.

5. Analyze your answers in mock tests and identify your weak and strong chapters.

6. Strengthen and practise your weaker chapters.

7. Try to increase speed while solving topics that you are strong in.

8. Try to cover the entire syllabus so you have 2 to 3 months for only revision and solving mock tests.

JEE Mains 2026 Exam Pattern

Before jumping onto the JEE Mains PYQ chapterwise PDF download, let’s first understand the basic exam pattern that PYQ follows:

JEE Main PYQ Book