120 marks in JEE Mains percentile - BTech aspirants must be curious to know what 120 marks in JEE Mains percentile are. Careers360 has provided the marks vs percentile JEE Mains 2026 comparison based on last year's data. Note that NTA releases the JEE Main 2026 result in the form of a percentile and ranks only. As per the previous years’ trends of the JEE Main exam, the 120 marks can translate to around 96 to 97 percentiles. A higher percentile indicates a better performance in the JEE Main 2026 exam. Hence, candidates must be aware of what 120 marks in the JEE Mains percentile means. The authority converts the raw scores of the candidates into the JEE Main percentile. Candidates can also utilise the JEE Main percentile calculator by Careers360 to determine their percentile based on the raw marks scored by the candidate.
Candidates can raise objections against the JEE Mains 2026 answer key by February 5, up to 11:50 pm.
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According to the previous year's trends, 120 marks can be expected to be converted into 96 percentile. NTA does not officially release the JEE Main marks vs percentile data. However, this information can be determined by analysing the previous year's trends.
JEE Main Marks | Expected Percentile Range |
115 – 116 | 96.10 – 96.30 |
117 – 118 | 96.30 – 96.55 |
119 – 120 | 96.70 – 97.40 |
121 – 122 | 97.55 – 97.80 |
123 – 124 | 97.80 – 98.05 |
125 - 126 | 98.05 – 98.15 |
JEE Main Percentile | Expected Rank (AIR) |
98.1 – 98.2 | 1,45,000 – 1,35,000 |
98.0 – 98.1 | 1,55,000 – 1,45,000 |
97.8 – 98.0 | 1,70,000 – 1,55,000 |
97.6 – 97.8 | 1,85,000 – 1,70,000 |
97.4 – 97.6 | 1,95,000 – 1,85,000 |
97.0 – 97.4 | 2,10,000 – 1,95,000 |
96.7 – 97.0 | 2,25,000 – 2,10,000 |
96.3 – 96.7 | 2,45,000 – 2,25,000 |
96.0 – 96.3 | 2,65,000 – 2,45,000 |
JEE Main 2026 percentile is the normalised score of the candidates in the JEE Main exam. NTA employs a formula to convert the raw scores of the candidates into the percentile scores. The JEE Main 2026 result will contain only the percentile scores of the candidates and not the raw scores.
The Normalised NTA scores indicate the performance of the candidate relative to the performances of the other candidates in a particular session of the NTA JEE Main exam. Hence, the higher the NTA Percentile, the higher the chance of the candidate clearing the JEE Main cutoff.
Candidates can refer to the formulas below to calculate the JEE Main 2026 percentile as well as the percentile scores of each subject.
Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) equal to or less than the candidate)/(Total number of candidates who appeared in that session)
JEE Main Percentile Scores for each subject and the total percentile score
Percentile score | Calculation |
Total Percentile (T1P): | (100 x No. of candidates from the session with a raw score equal to or less than the T1 score) / Total No. of candidates appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than the M1 score in Mathematics) / Total No. of candidates appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with raw score equal to or less than C1 score in Chemistry) / Total No. of candidates appeared in the session |
120 marks in the JEE Mains exam is a good score for candidates to choose more popular specialisations in lower-tier NITs. Candidates with 120 marks can expect to get ranks between 2,10,000 and 2,20,000. Some of the colleges available for candidates are mentioned below.
Institute | Course | Closing Rank |
B.Tech Chemical Engineering | 218902 | |
National Institute of Technology Srinagar | B.Tech Computer Science and Engineering | 220991 |
Puducherry Technological University, Puducherry | B.Tech Civil Engineering | 250437 |
B.Tech Mechanical Engineering | 220216 |
Yes. Candidates with 120 marks in the JEE Main exam can expect to get ranks between 2,10,000 and 2,20,000. The top 2,50,000 can apply for the JEE Advanced exam. Hence, candidates with 120 marks might be eligible to apply for the JEE Advanced 2026 exam. However, this depends on a variety of factors.
Apart from NITs, candidates can also apply for admission into various private institutions using their JEE Main 2026 scores. Candidates can also attempt the B.Tech. Entrance exams of the private universities and apply for admission using those scores. Some of the institutes that candidates can opt for include
Private Institute / University | Entrance Exam Accepted |
BITS Pilani (Pilani, Goa, Hyderabad Campuses) | |
Manipal Academy of Higher Education (MAHE) | MET (Manipal Entrance Test) |
AEEE (Amrita Entrance Examination – Engineering) |
Frequently Asked Questions (FAQs)
Candidates with 120 marks in the JEE Main exam can expect to get a percentile of 96 to 97.
Yes, it may be possible for candidates to apply for the JEE Advanced exam with 120 marks in the JEE Main exam.
NTA has announced the JEE Main 2026 exam date for session 1 as January 22 to 31, 2026, while session 2 will be held from April 2 to 9, 2026.
Candidates can expect to get around 2, 10,000 to 2,20,000 rank in the JEE Main exam with 120 marks.
No, candidates cannot apply for admission to Manipal University using their JEE Main scores. They have to attempt the MET exam for admission.
On Question asked by student community
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No, JEE Main Answer Key for 2026 session 1 is not out yet. NTA will release the JEE answer key 2026 on February 4.
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