JEE Main Maths Formulas 2026 -Students preparing for JEE Main 2026 should keep the list of important formulas for JEE Main 2026. This list of JEE Main Maths formulas 2026 helps students to solve questions quickly. While creating short notes, it is a must to list down the important formulas for JEE Mains 2026. JEE Main Exam is conducted by NTA (National Testing Agency) in two sessions.
There will be 14 chapters in Mathematics, including the Class 11 and 12 topics, according to the new syllabus given by NTA. Hence, it is suggested to follow the NCERT books to prepare for JEE Mains. To help the aspirants, we have created an e-book on JEE Main Maths 2026 formulas, students can also download the same and study from it.
Probability Formula
- $P(A \cup B)=P(A)+P(B)-P(A \cap B)$
- $P(A \cap B)=P(A) \times P\left(\frac{B}{A}\right)$
- $P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}$
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Trigonometric Limits
Some important JEE formulas for trigonometric limit are
(i) $\lim _{x \rightarrow 0} \frac{\sin x}{x}=1$
(ii) $\lim _{\mathrm{x} \rightarrow 0} \frac{\tan \mathrm{x}}{\mathrm{x}}=1$
(iii) $\lim _{\mathbf{x} \rightarrow \mathrm{a}} \frac{\sin (\mathbf{x}-\mathrm{a})}{\mathbf{x}-\mathbf{a}}=\mathbf{1}$
As $\lim _{x \rightarrow 0} \frac{\tan x}{x}=\lim _{x \rightarrow 0} \frac{\sin x}{x} \times \frac{1}{\cos x}$
$=\lim _{x \rightarrow 0} \frac{\sin x}{x} \times \lim _{x \rightarrow 0} \frac{1}{\cos x}=1 \times 1$
As $\lim _{x \rightarrow a} \frac{\sin (x-a)}{x-a}=\lim _{h \rightarrow 0} \frac{\sin ((a+h)-a)}{(a+h)-a}$
$$
\begin{aligned}
& =\lim _{h \rightarrow 0} \frac{\sin h}{h} \\
& =1
\end{aligned}
$$
(iv) $\lim _{\mathbf{x} \rightarrow \mathbf{a}} \frac{\tan (\mathbf{x}-\mathbf{a})}{\mathbf{x}-\mathbf{a}}=\mathbf{1}$
(v) $\lim _{x \rightarrow a} \frac{\sin (f(x))}{f(x)}=1$, if $\lim _{x \rightarrow a} f(x)=0$
Similarly, $\lim _{x \rightarrow a} \frac{\tan (f(x))}{f(x)}=1$, if $\lim _{x \rightarrow a} f(x)=0$
(vi) $\lim _{x \rightarrow 0} \cos x=1$
(vii) $\lim _{x \rightarrow 0} \frac{\sin ^{-1} x}{x}=1$
As $\lim _{x \rightarrow 0} \frac{\sin ^{-1} x}{x}=\lim _{y \rightarrow 0} \frac{y}{\sin y} \quad\left[\because \sin ^{-1} x=y\right]$
$$
=1
$$
(viii) $\lim _{\mathbf{x} \rightarrow 0} \frac{\tan ^{-1} \mathrm{x}}{\mathbf{x}}=\mathbf{1}$
Exponential Limits
To solve the limit of the function involving the exponential function, we use the following standard results
(i) $\lim _{\mathrm{x} \rightarrow 0} \frac{\mathrm{a}^{\mathrm{x}}-1}{\mathrm{x}}=\log _{\mathrm{e}} \mathrm{a}$
Proof:
$$
\lim _{x \rightarrow 0} \frac{a^x-1}{x}=\lim _{x \rightarrow 0} \frac{\left(1+\frac{x(\log a)}{11}+\frac{x^2(\log a)^2}{2!}+\cdots\right)-1}{x}
$$
[using Taylor series expansion of $a^x$ ]
$$
\begin{aligned}
& =\lim _{x \rightarrow 0}\left(\frac{\log a}{1!}+\frac{x(\log a)^2}{2!}+\cdots\right) \\
& =\log _e a
\end{aligned}
$$
(ii) $\lim _{\mathrm{x} \rightarrow 0} \frac{\mathrm{e}^{\mathrm{x}}-1}{\mathrm{x}}=1$
In General, if $x \rightarrow a$, then we have
(a) $\lim _{x \rightarrow a} \frac{a^{f(x)}-1}{f(x)}=\log _e a$
(b) $\lim _{x \rightarrow a} \frac{e^{f(x)}-1}{f(x)}=\log _e e=1$
Remembering important formulas from Maths will be very useful for the students preparing for the JEE Main 2025 exam. Students should practice a few questions on each formula just to remember them easily.
Also, Read-
Frequently Asked Questions (FAQs)
JEE Main exam has 75 questions, 25 each from Physics, Chemistry and Mathematics. Out of 25 questions, 20 will be MCQ and 5 will be questions with numerical value answers.
Binomial theorem and its simple applications, coordinate geometry, Limit, continuity and Differentiability,3D geometry, sets, Relation and Functions, Integral calculus, complex numbers, and Quadratic equations.
Yes, Lots of important concepts, formulas, and theorems from maths are really helpful for understanding a few important chapters of physics from mechanics, electrostatics, thermodynamics, etc.
Mathematics Books by R.D. Sharma, IIT Mathematics by M.L. Khanna, and NCERT are a few important books for JEE Main Mathematics.
On Question asked by student community
The approximate annual cost for 11th/12th PCM and JEE coaching is around 1.5 to 3.5 lakhs for institutes, excluding hostel and mess fees. The total fees including hostel as well as mess fees can rise upto 4.5 to 6.5 lakhs and above, depending on location and institute quality.
Hi dear candidate,
You can anytime visit our official website to find the previous 10 years JEE Mains question papers with solutions. Kindly refer to the link attached below to download them in PDF format:
JEE Main Last 10 Years Question Papers with Solutions (2025 to 2015)
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Hello,
For JEE Main and JEE Advanced , the cut-offs are lower for ST category students. Here is a simple idea based on recent trends:
JEE Main qualification for ST : Around 50–60 marks is usually enough to qualify for JEE Advanced.
JEE Advanced qualification for ST : You just need to clear the JEE Main cut-off, then appear for Advanced.
To get good NITs or IITs , you will need higher marks.
For NITs (Hyderabad or good branches), try for 120+ marks in JEE Main .
For IITs , even with ST quota, you should aim for at least 80–100+ marks in JEE Advanced for decent branches.
Since you are from ST category and Hyderabad , you don’t need 300 marks in JEE Main. Try to score as high as possible to get better branches, but even moderate marks can qualify you.
Hope it helps !
Yes, you can. If you do 11th from CBSE in 2025 and 12th from NIOS in 2026, then you are allowed to attempt JEE. NIOS is a valid board, so you can give JEE in 2026 and again in 2027. Just take admission on time and pass your 12th exams.
For the JEE 2026, priority-wise, high weightage chapters include Integral
1. Calculus, Coordinate Geometry, Vectors, 3D Geometry, Complex Numbers, and Quadratic Equations in Maths
2. Semiconductors, Current Electricity, Work, Power and Energy, and Gravitation in Physics
3. Organic Chemistry Containing Oxygen, Hydrocarbons, and P-Block Elements in Chemistry.
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