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JEE Main Percentile Calculator 2025: How to Calculate Percentile using Answer Key
JEE Main Percentile Calculator 2025 - NTA uses a specific formula to calculate a candidate's JEE Mains percentile 2025. Those who took the JEE Mains 2025 exam must check the JEE Main 2025 percentile calculator details provided in this article. Using the JEE Mains percentile calculator, students can estimate their percentile as per their scores in the JEE Mains exam. The complete procedure for using the JEE Main percentile calculator 2025 is explained in this article in a simplified manner.
This Story also Contains
- JEE Main Result 2025 - Percentile Calculation
- JEE Main 2025 Percentile
- JEE Main Percentile vs Marks 2025
- JEE Main 2025 Tie-Breaking Rule
- JEE Main Tie-Breaking Rule for Paper 1 (B.Tech)
- JEE Main Tie-Breaking Rule for Paper 2 A (B.Arch)
- JEE Main Tie-Breaking Rule for Paper 2 B (B.Planning)
Using the JEE Main percentile calculator, candidates can assess their percentile and standing among all the other candidates who appeared for the JEE Main 2025 exam. Please note that the JEE Main rank list 2025 will be prepared based on a candidate's JEE Main percentile and not just raw scores.
Must Check: JEE Main Rank Predictor 2025 | JEE Main College Predictor 2025
JEE Main Result 2025 - Percentile Calculation
The National Testing Agency calculates the scores of JEE Main 2025 for percentile for individual subjects separately (Physics, Chemistry, and Mathematics) as well as in the combined format using the normalization formula as shown below.
Calculating JEE Main Percentile
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
JEE Main 2025 Percentile
NTA is expected to release a official notice consisting of a table to classify the range of percentages as secured by students who appeared in the JEE Main 2025 paper. Students will be able to check their official percentile as per their appeared shift from the NTA press release when uploaded. The same will be provided below.
JEE Main Percentile vs Marks 2025
NTA calculates the JEE Main 2025 percentile using the process of normalization of marks. There is a certain number of marks against which the percentile score is allotted, which in turn can be called the JEE Main 2025 marks vs percentile. Aspirants may refer to the table below to know the expected range of marks for which a certain percentile is allotted to the respective candidates.
JEE Main 2025 Expected Percentile vs Marks 2025
| Marks out of 300 | Percentile |
|---|---|
| 288- 294 | 99.99826992- 99.99890732 |
| 280-284 | 99.99617561 - 99.99790569 |
| 270-279 | 99.99034797 - 99.99417236 |
| 252- 268 | 99.95228621- 99.99016586 |
| 231-249 | 99.87388626-99.95028296 |
| 215-230 | 99.74522293-99.87060821 |
| 202-214 | 99.57503767- 99.73930423 |
| 190-200 | 99.39319714- 99.56019541 |
| 175-189 | 99.02150308 - 99.3487614 |
| 161-174 | 98.52824811-98.99673561 |
| 149-159 | 98.07460288-98.49801724 |
| 132-148 | 97.0109678-97.97507774 |
| 120-131 | 96.0687115-96.93721175 |
| 110-119 | 95.05625037-95.983027 |
| 102-109 | 94.01228357-94.96737888 |
| 95-101 | 93.05600452 -93.89928202 |
| 89-94 | 92.05811248 -92.88745828 |
| 79-88 | 90.0448455 -91.79177119 |
| 62-87 | 84.56203931-91.59517945 |
| 41-61 | 70.26839007-84.22540213 |
| 1-42 | 66.6590786-69.5797271 |
JEE Main 2025 Tie-Breaking Rule
NTA has changed the JEE Main tie-breaking rule 2025. Candidates can check the updated JEE Main 2025 tie-breaking policy below. The tie-breaking rules apply when two candidates obtain the same JEE Main scores. However, to allot the JEE Main ranks, the authorities follow the tie-breaking policy JEE Main 2025. The tie-breaking for JEE Main 2025 will apply in the following order.
JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters
JEE Main Tie-Breaking Rule for Paper 1 (B.Tech)
- NTA score in Mathematics, followed by
- NTA score in Physics, followed by
- NTA score in Chemistry, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Physics in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Chemistry in the Test followed by
- If there is a tie even after this, candidates will be assigned the same rank.
JEE Main 2026: Preparation Tips & Study Plan
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
Download EBookJEE Main Tie-Breaking Rule for Paper 2 A (B.Arch)
The tie between candidates obtaining the same Total NTA scores will be resolved in the following manner:
- NTA score in Mathematics, followed by
- NTA score in Aptitude Test, followed by
- NTA score in Drawing Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics (Part-I) in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Aptitude Test (Part-II) in the Test followed by
- If there is a tie even after this, candidates will be assigned the same rank.
JEE Main Tie-Breaking Rule for Paper 2 B (B.Planning)
In case two candidates obtain the same marks in the JEE Main 2025 B.Planning exam the tie-breaking will apply in the following order:
- NTA score in Mathematics, followed by
- NTA score in Aptitude Test, followed by
- NTA score in Planning Based Questions, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics (Part- I) in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Aptitude Test (Part- II) in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Planning Based Questions (Part-III) in the Test followed by
- If there is a tie even after this, candidates will be assigned the same rank.
Frequently Asked Questions (FAQs)
Q: What is the 99.5 percentile in JEE Mains?
A:
99.5 percentile in JEE Mains means the candidate has obtained approximately 200 marks.
Q: How much percentile is 70 marks in JEE Mains?
A:
70 marks in JEE Mains translates to a percentile of 90.
Q: How to calculate JEE Main percentile?
A:
To calculate the JEE Mains percentile 2025, candidates have to (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session.
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Have a question related to JEE Main ?
Hello,
No, you don’t have to give JEE Main or Advanced to become an app developer .
Here’s what you can do:
-
Choose the right stream: After 10th, take the Science stream (PCM) or even Commerce/Arts if you’re confident. Science is preferred but not compulsory.
-
Learn programming: Start with languages like Java, Python, or Kotlin. You can learn online or join short courses.
-
After 12th: Do a degree like BCA , B.Sc. (Computer Science) , or B.Tech (CSE/IT) . For B.Tech, some colleges use JEE Main, but many private colleges don’t.
-
Build skills: Make small apps, do internships, and create a portfolio.
-
Keep learning: Explore Android, iOS, or cross-platform tools like Flutter or React Native.
In short, JEE is not mandatory . It’s only needed if you want to study B.Tech in top engineering colleges like IITs or NITs. You can become an app developer without JEE by taking other courses and practising on your own.
Hope it helps !
Hello
For JEE Main registration, your EWS certificate must be issued before the registration deadline.
Ideally, the certificate should be dated after April 1 of the current academic year .
NTA usually mentions the required issue date in the official JEE information bulletin. If your EWS certificate is delayed, you can upload an EWS undertaking temporarily. But you must produce a valid certificate during counseling (JoSAA), or your claim won’t be accepted.
Always get it made from your local Tehsildar/SDO office well in advance to avoid last-minute issues.
Since you passed Class 12 in 2025 with 70.2% and later improved English in the same year (July 2025) to make it 75% , you have to upload the latest marksheet that shows your improved marks . For JEE Main/Advanced and later JoSAA counselling , NTA and IITs always consider the final result after improvement . During application form filling, you can enter your updated percentage, and at the document upload stage, you should upload:
-
Your original Class 12 marksheet (March/April 2025)
-
Your improvement marksheet (July 2025) showing the revised score
Both documents are important because the improvement marksheet proves your eligibility (75% criteria) while the original shows you passed in the same year. During JoSAA document verification, candidates usually upload both marksheets together in one PDF so that authorities can clearly see the updated percentage.
In short: Use your improved percentage (75%) for eligibility and upload both old + improvement marksheets merged as a single file to avoid confusion.
In Malda district, West Bengal, the JEE Main 2025 exam centre code is WB20. Candidates from the district can choose Malda as their preferred exam centre during registration. The final allotment of centres depends on availability and preferences submitted by students. The exact number of exam halls may vary each year based on the number of applicants. Students should confirm their allotted centre through the official JEE Main admit card.
Hey
Yes, it is better to get your EWS certificate ready before filling the JEE Main 2026 application . The EWS (Economically Weaker Section) certificate is used to claim reservation benefits during counseling and seat allotment. If you don’t have it while applying, you may miss the reserved quota advantage and may not be able to update it later.
To get it, you need to apply at your local Tehsildar / Revenue office with required income and property documents. Once issued, keep a scanned copy ready because JEE Main application requires uploading it. Having it prepared in advance ensures that during application and JoSAA counseling , you can claim EWS reservation smoothly without delays.
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