Amrita University B.Tech 2026
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
JEE Main Application Date:31 Oct' 25 - 27 Nov' 25
JEE Main Percentile Calculator 2025 - NTA uses a specific formula to calculate a candidate's JEE Mains percentile 2025. Those who took the JEE Mains 2025 exam must check the JEE Main 2025 percentile calculator details provided in this article. Using the JEE Mains percentile calculator, students can estimate their percentile as per their scores in the JEE Mains exam. The complete procedure for using the JEE Main percentile calculator 2025 is explained in this article in a simplified manner.
JEE Mains 2026 | The last year's closing and opening ranks for various BTech courses at NIT Surathkal are as follows.
Academic Program Name | Opening Rank | Closing Rank |
Artificial Intelligence (4 Years, Bachelor of Technology) | 2060 | 2650 |
Chemical Engineering (4 Years, Bachelor of Technology) | 11287 | 13477 |
Civil Engineering (4 Years, Bachelor of Technology) | 10550 | 22901 |
Computational and Data Science (4 Years, Bachelor of Technology) | 3026 | 3471 |
Computer Science and Engineering (4 Years, Bachelor of Technology) | 1191 | 1827 |
Electrical and Electronics Engineering (4 Years, Bachelor of Technology) | 4787 | 6872 |
Electronics and Communication Engineering (4 Years, Bachelor of Technology) | 2019 | 4347 |
Information Technology (4 Years, Bachelor of Technology) | 2132 | 3160 |
Mechanical Engineering (4 Years, Bachelor of Technology) | 6485 | 11950 |
Metallurgical and Materials Engineering (4 Years, Bachelor of Technology) | 16213 | 22965 |
Mining Engineering (4 Years, Bachelor of Technology) | 23987 | 28750 |
JEE Main 2026: NIT Surathkal closing ranks. (Image: Wikimediacommons)
This Story also Contains
Using the JEE Main percentile calculator, candidates can assess their percentile and standing among all the other candidates who appeared for the JEE Main 2025 exam. Please note that the JEE Main rank list 2025 will be prepared based on a candidate's JEE Main percentile and not just raw scores.
Must Check: JEE Main Rank Predictor 2025 | JEE Main College Predictor 2025
The National Testing Agency calculates the scores of JEE Main 2025 for percentile for individual subjects separately (Physics, Chemistry, and Mathematics) as well as in the combined format using the normalization formula as shown below.
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |

NTA is expected to release a official notice consisting of a table to classify the range of percentages as secured by students who appeared in the JEE Main 2025 paper. Students will be able to check their official percentile as per their appeared shift from the NTA press release when uploaded. The same will be provided below.
NTA calculates the JEE Main 2025 percentile using the process of normalization of marks. There is a certain number of marks against which the percentile score is allotted, which in turn can be called the JEE Main 2025 marks vs percentile. Aspirants may refer to the table below to know the expected range of marks for which a certain percentile is allotted to the respective candidates.
| Marks out of 300 | Percentile |
|---|---|
| 288- 294 | 99.99826992- 99.99890732 |
| 280-284 | 99.99617561 - 99.99790569 |
| 270-279 | 99.99034797 - 99.99417236 |
| 252- 268 | 99.95228621- 99.99016586 |
| 231-249 | 99.87388626-99.95028296 |
| 215-230 | 99.74522293-99.87060821 |
| 202-214 | 99.57503767- 99.73930423 |
| 190-200 | 99.39319714- 99.56019541 |
| 175-189 | 99.02150308 - 99.3487614 |
| 161-174 | 98.52824811-98.99673561 |
| 149-159 | 98.07460288-98.49801724 |
| 132-148 | 97.0109678-97.97507774 |
| 120-131 | 96.0687115-96.93721175 |
| 110-119 | 95.05625037-95.983027 |
| 102-109 | 94.01228357-94.96737888 |
| 95-101 | 93.05600452 -93.89928202 |
| 89-94 | 92.05811248 -92.88745828 |
| 79-88 | 90.0448455 -91.79177119 |
| 62-87 | 84.56203931-91.59517945 |
| 41-61 | 70.26839007-84.22540213 |
| 1-42 | 66.6590786-69.5797271 |
NTA has changed the JEE Main tie-breaking rule 2025. Candidates can check the updated JEE Main 2025 tie-breaking policy below. The tie-breaking rules apply when two candidates obtain the same JEE Main scores. However, to allot the JEE Main ranks, the authorities follow the tie-breaking policy JEE Main 2025. The tie-breaking for JEE Main 2025 will apply in the following order.
The tie between candidates obtaining the same Total NTA scores will be resolved in the following manner:
100% Placement Record | Highest CTC 54 LPA | NAAC A++ Accredited | Ranked #62 in India by NIRF Ranking 2025 | JEE & JET Scores Accepted
India's Largest University | NAAC A++ | 100% Placements Record | Highest CTC 2.5 Cr PA | 150 + Programmes across Multiple Disciplines
In case two candidates obtain the same marks in the JEE Main 2025 B.Planning exam the tie-breaking will apply in the following order:
Frequently Asked Questions (FAQs)
99.5 percentile in JEE Mains means the candidate has obtained approximately 200 marks.
70 marks in JEE Mains translates to a percentile of 90.
To calculate the JEE Mains percentile 2025, candidates have to (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session.
On Question asked by student community
Hello Aspirant
As you are preparing for JEEMains and you want to practice the PYQs, it is a good choice as NTA mainly follows the same pattern, and some questions are repeatedly asked. To get the most repeated question, just visit the link I'm attaching below.
The form requires the candidates to upload the signature in JPEG format within 10-100KB format, if this condition is not fulfilled the photo will not get uploaded. Assistance from an e-mitra might be needed or you may choose to convert the sizes and the types of your documents from various converting applications available
to get details about registration and avoid getting confused follow the link below from careers360 How to fill JEE Main Application Form 2026? – Steps to Apply Online
You can look up to the syllabus released by the NTA for the 2026 examination available in pdf form at careers360 from the link given below, you will get all the deleted syllabus and the additional added syallabus in the pdf itself JEE Main 2026 Syllabus (Out): Download Paper 1, 2 PDF Here
Hello, You want to get 99 percentile in JEE Mains, for this you should prepare very well.
I am providing you the link of a book to help you in your preparation, you will get everything in it to score well in JEE Mains.
Here is your link: CLICK HERE
You can download the ebook directly by clicking on "CLICK HERE".
I hope you found this information helpful and for any study related problems you can ask in careers360 app, Have a great day!
Hello,
JEE Main ke 75% eligibility ke liye marks calculation board ke total marks (as printed on marksheet) par based hoti hai, best of 5 nahi.
Agar aapke marksheet me total 355/500 likha hai, to wahi valid mana jayega.
Isliye agar ye 75% se kam hai, to aap JEE Main de sakte ho, par NIT, IIIT, ya GFTI admission ke liye eligible nahi hoge, unless aap SC/ST category se ho (unke liye 65% required hai).
Hope you understand.
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
India's Largest University | NAAC A++ | 100% Placements Record | Highest CTC 2.5 Cr PA | 150 + Programmes across Multiple Disciplines
AICTE ‘Platinum’ institute | NIRF 2024 Rank Band 151-200 under the engineering category | Tier-1 accreditation by NBA | Merit & Sports Scholarships
Dive into everything you need to know about IITs—from eligibility and cutoffs to fees and placements.
Hands on Mentoring and Code Coaching | Cutting Edge Curriculum with Real World Application