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JEE Main Percentile Calculator 2025: How to Calculate Percentile using Answer Key
JEE Main Percentile Calculator 2025 - NTA uses a specific formula to calculate a candidate's JEE Mains percentile 2025. Those who took the JEE Mains 2025 exam must check the JEE Main 2025 percentile calculator details provided in this article. Using the JEE Mains percentile calculator, students can estimate their percentile as per their scores in the JEE Mains exam. The complete procedure for using the JEE Main percentile calculator 2025 is explained in this article in a simplified manner.
This Story also Contains
- JEE Main Result 2025 - Percentile Calculation
- JEE Main 2025 Percentile
- JEE Main Percentile vs Marks 2025
- JEE Main 2025 Tie-Breaking Rule
- JEE Main Tie-Breaking Rule for Paper 1 (B.Tech)
- JEE Main Tie-Breaking Rule for Paper 2 A (B.Arch)
- JEE Main Tie-Breaking Rule for Paper 2 B (B.Planning)
Using the JEE Main percentile calculator, candidates can assess their percentile and standing among all the other candidates who appeared for the JEE Main 2025 exam. Please note that the JEE Main rank list 2025 will be prepared based on a candidate's JEE Main percentile and not just raw scores.
Must Check: JEE Main Rank Predictor 2025 | JEE Main College Predictor 2025
JEE Main Result 2025 - Percentile Calculation
The National Testing Agency calculates the scores of JEE Main 2025 for percentile for individual subjects separately (Physics, Chemistry, and Mathematics) as well as in the combined format using the normalization formula as shown below.
Calculating JEE Main Percentile
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
JEE Main 2025 Percentile
NTA is expected to release a official notice consisting of a table to classify the range of percentages as secured by students who appeared in the JEE Main 2025 paper. Students will be able to check their official percentile as per their appeared shift from the NTA press release when uploaded. The same will be provided below.
JEE Main Percentile vs Marks 2025
NTA calculates the JEE Main 2025 percentile using the process of normalization of marks. There is a certain number of marks against which the percentile score is allotted, which in turn can be called the JEE Main 2025 marks vs percentile. Aspirants may refer to the table below to know the expected range of marks for which a certain percentile is allotted to the respective candidates.
JEE Main 2025 Expected Percentile vs Marks 2025
| Marks out of 300 | Percentile |
|---|---|
| 288- 294 | 99.99826992- 99.99890732 |
| 280-284 | 99.99617561 - 99.99790569 |
| 270-279 | 99.99034797 - 99.99417236 |
| 252- 268 | 99.95228621- 99.99016586 |
| 231-249 | 99.87388626-99.95028296 |
| 215-230 | 99.74522293-99.87060821 |
| 202-214 | 99.57503767- 99.73930423 |
| 190-200 | 99.39319714- 99.56019541 |
| 175-189 | 99.02150308 - 99.3487614 |
| 161-174 | 98.52824811-98.99673561 |
| 149-159 | 98.07460288-98.49801724 |
| 132-148 | 97.0109678-97.97507774 |
| 120-131 | 96.0687115-96.93721175 |
| 110-119 | 95.05625037-95.983027 |
| 102-109 | 94.01228357-94.96737888 |
| 95-101 | 93.05600452 -93.89928202 |
| 89-94 | 92.05811248 -92.88745828 |
| 79-88 | 90.0448455 -91.79177119 |
| 62-87 | 84.56203931-91.59517945 |
| 41-61 | 70.26839007-84.22540213 |
| 1-42 | 66.6590786-69.5797271 |
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JEE Main 2025 Tie-Breaking Rule
NTA has changed the JEE Main tie-breaking rule 2025. Candidates can check the updated JEE Main 2025 tie-breaking policy below. The tie-breaking rules apply when two candidates obtain the same JEE Main scores. However, to allot the JEE Main ranks, the authorities follow the tie-breaking policy JEE Main 2025. The tie-breaking for JEE Main 2025 will apply in the following order.
JEE Main Tie-Breaking Rule for Paper 1 (B.Tech)
- NTA score in Mathematics, followed by
- NTA score in Physics, followed by
- NTA score in Chemistry, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Physics in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Chemistry in the Test followed by
- If there is a tie even after this, candidates will be assigned the same rank.
JEE Main 2026: Preparation Tips & Study Plan
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
Download EBookJEE Main Tie-Breaking Rule for Paper 2 A (B.Arch)
The tie between candidates obtaining the same Total NTA scores will be resolved in the following manner:
- NTA score in Mathematics, followed by
- NTA score in Aptitude Test, followed by
- NTA score in Drawing Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics (Part-I) in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Aptitude Test (Part-II) in the Test followed by
- If there is a tie even after this, candidates will be assigned the same rank.
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JEE Main Tie-Breaking Rule for Paper 2 B (B.Planning)
In case two candidates obtain the same marks in the JEE Main 2025 B.Planning exam the tie-breaking will apply in the following order:
- NTA score in Mathematics, followed by
- NTA score in Aptitude Test, followed by
- NTA score in Planning Based Questions, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Mathematics (Part- I) in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Aptitude Test (Part- II) in the Test, followed by
- Candidate with less proportion of a number of attempted incorrect answers and correct answers in Planning Based Questions (Part-III) in the Test followed by
- If there is a tie even after this, candidates will be assigned the same rank.
Frequently Asked Questions (FAQs)
Q: What is the 99.5 percentile in JEE Mains?
A:
99.5 percentile in JEE Mains means the candidate has obtained approximately 200 marks.
Q: How much percentile is 70 marks in JEE Mains?
A:
70 marks in JEE Mains translates to a percentile of 90.
Q: How to calculate JEE Main percentile?
A:
To calculate the JEE Mains percentile 2025, candidates have to (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session.
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Have a question related to JEE Main ?
With your JEE Main CRL 476199 and OBC rank 173160, admission to Civil Engineering at Indira Gandhi Institute of Technology (IGIT), Sarang under JoSAA counseling is highly unlikely, since even civil branch closing ranks in IGIT usually remain within 50k–80k CRL (general) and much lower for OBC. However, you may try through state counseling (Odisha JEE) where cutoffs are sometimes more flexible, but chances are still very low. You should keep other private/state colleges as backup.
Hey! With a JEE Main rank of around 1 lakh, you still have a good chance to get admission in several engineering colleges that provide quality education at a reasonable fee. For government colleges, you can aim for NITs or GFTIs in branches like Civil, Mechanical, or Chemical Engineering, as these usually have slightly higher closing ranks. For example, colleges like NIT Goa, NIT Puducherry, and NIT Srinagar might have seats available in certain branches.
Apart from NITs, state government engineering colleges are also a good option, especially under home state quota. They often have lower tuition fees and good faculty, so you can get a solid education without spending much.
If you are open to private colleges, there are options like VIT Vellore, KIIT Bhubaneswar, or Amity University that provide decent infrastructure and placements. However, the fees may be higher than government colleges.
My advice is to focus on branches that are less competitive, check all counseling rounds, and make use of state quotas if applicable. With proper planning, a rank of 1 lakh can still help you get a good college and start your engineering career success
fully.
No, you can’t use a previous year’s JEE rank for the current year’s WBJEE counselling. Only the JEE Main rank of the same admission year is valid along with that year’s WBJEE rank.
Hello Aspirant,
Finding specific JEE exam centers for Whitefield is difficult as they vary each year. The list is released on the admit card . However, many centers are usually iON Digital Zones. For coaching, top centers near Whitefield include Aakash Institute , Narayana Institute , and Allen Career Institute . These centers have branches in and around the Whitefield area to help you prepare for the exam.
Its okay if you missed jee this year you can drop year for JEE to get into a government institute like IET Lucknow to get better placement here and fees is also less in comparison with SRMU but it also means delaying a year with no guarantee success.
Joining a private college like SRMU now avoids losing a year,but it comes with higher costs and generally lower placement statistics compared to top government institutions.
ultimately Your decision should be based on your skill whether you can significantly improve your JEE score versus accepting a faster, but potentially more expensive, path to your B.Tech.
Hope it helps..
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