JEE Main 2026 Exam Centres in Kerala : NTA has uploaded the list of JEE Main exam centres in Kerala on the official website, jeemain.nta.nic.in. Candidates can find the names of JEE Main exam centres in Kerala 2026 in this article. This year, Piyyanur has been removed, whereas Chengannur and Alappuzha, Ernakulam and Moovattupuzha have been clubbed together, respectively. It makes the total number of JEE Main Kerala exam cities 14 in number. The applicant can know the address of the exam centre allotted to them through the JEE Main admit card. NTA will conduct the Joint Entrance Examination Main in online mode. The session 1 JEE Mains 2026 exam will be held between January 21 to 30, 2026, while session 2 is scheduled from April 2 to 9, 2026.
Related-JEE Main 2026 exam centres
The National Testing Agency (NTA) has issued the JEE Mains 2026 January 29 admit card for BTech or BE candidates. The exam hall ticket can be accessed through the official website at jeemain.nta.nic.in using login details such as application number and password.
Those candidates residing in Kerala or otherwise preferring to appear for the upcoming session of the JEE Main exam from the city may check out the JEE Main 2026 exam centres in Kerala. The JEE Main entrance exam will be conducted in Kerala across 14 cities (some have been clubbed together). The following table provides the complete names of the districts and corresponding cities.
| JEE Main Test Cities | City Code |
|---|---|
| Idukki | KL05 |
| Kannur | KL07 |
| Kasaragod | KL08 |
| Kollam | KL09 |
| Kottayam | KL11 |
| Kozhikode/Calicut | KL12 |
| Malappuram | KL13 |
| Palakkad | KL15 |
| Pathanamthitta | KL16 |
| Thiruvananthapuram | KL17 |
| Thrissur | KL18 |
| Wayanad | KL19 |
| Alappuzha/Chengannur | KL01 |
| Ernakulam/Moovattupuzha | KL04 |
| JEE Main exam centre List : | |
|---|---|
On Question asked by student community
JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-
Math and Chemistry was difficult and Physics was moderate. The complete analysis is available here- https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-1-question-paper-with-solutions-pdf
You can also check the memory-based questions and detailed solutions for JEE Main Jan 28 shift 1 paper.
Hi Lucky,
Please refer to this link and you can download the free pdf.
HI Manisha Maharana
You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf
Also, you can check ad attemp the online mock test on our platform.
https://learn.careers360.com/test-series-jee-main-free-mock-test/
A general equation of a circle is
$
x^2+y^2+2 g x+2 f y+c=0
$
Since it passes through $(0,0)$,
$
c=0
$
So the equation becomes
$
x^2+y^2+2 g x+2 f y=0
$
It cuts the x -axis at ( $a, 0$ ).
Substituting:
$
a^2+2 g a=0
$
g=-a/2
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