JEE Main Exam Centres in Jharkhand 2026 - Centers in Dhanbad, Jamshedpur, Ranchi

JEE Main Exam Centres in Jharkhand 2026 - Centers in Dhanbad, Jamshedpur, Ranchi

K Guna SahitiUpdated on 18 Jan 2026, 05:00 PM IST

JEE Main Exam Centres in Jharkhand 2026- NTA has uploaded the list of JEE Main 2026 exam centres in Jharkhand on the official website, jeemain.nta.ac.in. The information brochure mentions the complete JEE Main 2026 exam centres in Jharkhand. There are 6 exam centres for JEE Main 2026 in the state of Jharkhand. The actual address of the exam centre allotted to the applicant is available on the JEE Main admit card. JEE Main will be a computer-based exam (except for Drawing) that will be conducted at a test centre. Further, the JEE Mains 2026 exam will be conducted as a computer-based test on January 21, 22, 23, 24, 28 and 29. Go through the complete article for the JEE Main exam centres in Jharkhand 2026.

LiveJEE Mains 2026 Jan 29 LIVE: BArch, BPlanning memory-based questions with solutions, answer key soonJan 29, 2026 | 4:30 PM IST

The JEE Main 2026 percentile predictor is available on Careers360 and helps students easily estimate their expected percentile based on their exam performance, so they can understand their chances and plan what to do next.

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JEE Main Exam Centres in Jharkhand 2026 - Centers in Dhanbad, Jamshedpur, Ranchi
JEE Main Exam Centres in Jharkhand 2026

The JEE Main exam locator is provided on the official website, and candidates can check all the JEE Main 2026 exam centres in Jharkhand using their locator. Moreover, JEE Main 2026 aspirants can know about the exact Google map location of the exam centre allotted to them.

JEE Main Exam Centres in Jharkhand 2026

National Testing Agency (NTA) has released the JEE Main 2026 exam centre at jeemain.nta.nic.in. Applicants can refer to the following table to learn about the exam centres in Jharkhand. Note that candidates have to choose the JEE Main exam centre while filling out the application form.

JEE Main 2025 Exam Centres in Jharkhand

CityCity Code
BokaroJH01
DhanbadJH02
JamshedpurJH03
RanchiJH04
HazaribaghJH05
RamgarhJH15

Related links:

Frequently Asked Questions (FAQs)

Q: How to check JEE Main exam centre?
A:
  • Visit the official NTA JEE website: jeemain.nta.ac.in.
  • Click on "JEE(Main) 2026: Download Advance City Intimation for B.E./B.Tech".
  • A login window will open.
  • Log in using your application number, date of birth, and course.
  • Access the JEE Main exam city intimation slip.
Q: How many students will appear for the JEE Mains 2026?
A:

Approximately 13 to 14 lakhs candidates are expected to appear for JEE Main 2026. Last year a total of 13.8 lakh students appeared for JEE Main 2025.

Q: How to change JEE Main exam centre in 2026?
A:

To change the JEE Main exam center, the NTA provided a correction window. However, they may be able to change the exam centre only under certain conditions. 

Q: How to check city allotment for JEE Mains?
A:
  • Go to the official website (jeemain.nta.ac.in)
  • Click on the application form correction link.
  • Candidates will have to enter their JEE Main application form number and password.
  • Click on 'Sign In'
  • Go to 'Correction in Application Form'
Q: What is the dress code for JEE?
A:

There is no formal dress code for the JEE exam, but it is advisable to wear simple and comfortable clothing, such as a T-shirt and jeans, or a top/kurta with leggings.

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Questions related to JEE Main

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Have a question related to JEE Main ?

JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-

https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-2-question-paper-with-solutions-pdf

Math and Chemistry was difficult and Physics was moderate. The complete analysis is available here- https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-1-question-paper-with-solutions-pdf

You can also check the memory-based questions and detailed solutions for JEE Main Jan 28 shift 1 paper.

HI Manisha Maharana

You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf

Also, you can check ad attemp the online mock test on our platform.
https://learn.careers360.com/test-series-jee-main-free-mock-test/



A general equation of a circle is

$
x^2+y^2+2 g x+2 f y+c=0
$

Since it passes through $(0,0)$,

$
c=0
$

So the equation becomes

$
x^2+y^2+2 g x+2 f y=0
$

It cuts the x -axis at ( $a, 0$ ).

Substituting:

$
a^2+2 g a=0
$

g=-a/2