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JEE Main Chemistry Formulas 2026 - The Joint entrance exam is one of the most competitive exam of engineering entrance exams. It is divided into three subsections (Physics, Chemistry, Maths). In which Chemistry is an important subject for JEE Main preparation. Hence, having a list of important formulas for JEE Main Chemistry 2025 is necessary. Every aspirant should have the short notes for JEE Mains that comprise the important formulas. These JEE important formulas for Chemistry help in solving the typical problems easily. Therefore, experts of Careers360 have issued a list of JEE Main 2026 Chemistry. Download the JEE Main Chemistry Formulas E-Book below:
Download JEE Main Chemistry Formulas pdf
There will be a total of 25 questions from Chemistry in JEE Main 2026, all of which have to be attempted. It is further segregated into Physical, Organic, and Inorganic sections. The maximum number of topics have been reduced from this section (chemistry) only. This makes Chemistry easier than before. However, the high-weightage topics for JEE Main remain the same.
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Below are important formulas for JEE Main 2026 Chemistry that are helpful for both sessions. Candidates should solve as many Chemistry questions as they can and implement these formulas to remember them quickly. To crack the JEE Main exam with good marks, paste these formulas near the study table and memorize them.
Atomic Structure
Redox Reaction and Electrochemistry
Chemical Thermodynamics
Coordination Compounds
d - and f - BLOCK ELEMENTS
GOC isomerism
Solutions
Alkyl halides and aryl halides
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Most Important Formulas for JEE Chemistry
$$
\begin{aligned}
& \mathrm{c}=\frac{\text { distance }}{\text { time }}=\frac{\text { Wavelength }}{\text { Time Period }}=\frac{\lambda}{\mathrm{T}} \\
& \because \nu=\frac{1}{\mathrm{~T}} \\
& \therefore \mathrm{c}=\nu \times \lambda
\end{aligned}
$$
(i) Work done in reversible isothermal process
$$
\begin{aligned}
& \mathrm{W}=-2.303 \mathrm{nRT} \log _{10} \frac{\mathrm{~V}_2}{\mathrm{~V}_1} \\
& \mathrm{~W}=-2.303 \mathrm{nRT} \log _{10} \frac{\mathrm{P}_1}{\mathrm{P}_2}
\end{aligned}
$$
(ii) Work done in irreversible isothermal process
Work $=-\mathrm{P}_{\text {ext. }}\left(\mathrm{V}_2-\mathrm{V}_1\right)$
That is, Work $=-\mathrm{P} \times \Delta \mathrm{V}$
At $\mathrm{T}=298 \mathrm{~K}$, Nernst equation is given as follows:
$$
\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^{\circ}-\frac{0.059}{\mathrm{n}} \log _{10} \mathrm{Q}
$$
Mass by Volume $\%$ of a component $=\frac{\text { Mass of the component }}{\text { Total volume of solution }} \times 100$
Frequently Asked Questions (FAQs)
JEE Main is an exam conducted for those aspirants who want to take admission in NIITs, IITs and other engineering colleges, and it is also an eligibility test for JEE advance.
Chemistry has three subparts (Physical, inorganic and organic). Physical chemistry has many numericals based on different formulas.
Yes, Class 12 syllabus carries more than 50% of weightage, so it is important for JEE Main Exam.
On Question asked by student community
Here’s a plan for JEE Mains 2026 in 4 months:
1. Divide time: 2 months for Class 12 syllabus, 1 month for Class 11, 1 month for full revision & mock tests.
2. Daily schedule: 6–7 hours study; 50% for theory & problem-solving, 50% for practice & revision.
3. Topic-wise focus: Prioritize high-weightage chapters and weak areas first.
4. Daily problem practice: Solve previous year questions and chapter-wise exercises.
5. Weekly tests: Take 1 full-length test weekly, analyze mistakes, and revise weak concepts.
6. Consistency: Avoid skipping days; maintain notes and formula sheets for quick revision.
If you want to crack JEE exam you read to dedicatedly prepared for that from the scratch to the advance focus on high weightage topic and prepare question in the time based and continuously practice the previous question this will help to know the pattern of JEE exam questions
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With your JEE Main CRL 476199 and OBC rank 173160, admission to Civil Engineering at Indira Gandhi Institute of Technology (IGIT), Sarang under JoSAA counseling is highly unlikely, since even civil branch closing ranks in IGIT usually remain within 50k–80k CRL (general) and much lower for OBC. However, you may try through state counseling (Odisha JEE) where cutoffs are sometimes more flexible, but chances are still very low. You should keep other private/state colleges as backup.
Hey! With a JEE Main rank of around 1 lakh, you still have a good chance to get admission in several engineering colleges that provide quality education at a reasonable fee. For government colleges, you can aim for NITs or GFTIs in branches like Civil, Mechanical, or Chemical Engineering, as these usually have slightly higher closing ranks. For example, colleges like NIT Goa, NIT Puducherry, and NIT Srinagar might have seats available in certain branches.
Apart from NITs, state government engineering colleges are also a good option, especially under home state quota. They often have lower tuition fees and good faculty, so you can get a solid education without spending much.
If you are open to private colleges, there are options like VIT Vellore, KIIT Bhubaneswar, or Amity University that provide decent infrastructure and placements. However, the fees may be higher than government colleges.
My advice is to focus on branches that are less competitive, check all counseling rounds, and make use of state quotas if applicable. With proper planning, a rank of 1 lakh can still help you get a good college and start your engineering career success
fully.
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