JEE Main Chemistry Formulas 2026 - The Joint Entrance Exam is one of the most competitive exam of engineering entrance exams. It is divided into three subsections (Physics, Chemistry, Maths). Chemistry is an important subject for JEE Main preparation. Hence, having a list of important formulas for JEE Main Chemistry 2025 is necessary. Every aspirant should have the short notes for JEE Mains that comprise the important formulas. These JEE important formulas for Chemistry help in solving the typical problems easily. Therefore, experts of Careers360 have issued a list of JEE Main 2026 Chemistry. The registration process for JEE Main 2026 is now open, and students can apply from 31 October 2025 to 27 November 2025. Session 1 of the exam will be conducted from 21 to 30 January 2026.
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There will be a total of 25 questions from Chemistry in JEE Main 2026, all of which have to be attempted. It is further segregated into Physical, Organic, and Inorganic sections. The maximum number of topics has been reduced from this section (chemistry) only. This makes Chemistry easier than before. However, the high-weightage topics for JEE Main remain the same.
Below are important formulas for JEE Main 2026 Chemistry that are helpful for both sessions. Candidates should solve as many Chemistry questions as they can and implement these formulas to remember them quickly. To crack the JEE Main exam with good marks, paste these formulas near the study table and memorise them.
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Candidates while studying chemistry, they need to revise and practice the chemical equations and symbols. To some, chemistry is a tough subject, but when candidates practice chemical equations, revise the properties, formulas and symbols, they will have command over the subject. Candidates can check the JEE Main Chemistry formulas below
JEE Main Important Formulas of Physical Chemistry
Some Basic Concepts in chemistry
Boyle's Law: $P_1 V_1=P_2 V_2$ (at constant T and n )
Charles's Law: $\frac{V_1}{T_1}=\frac{V_2}{T_2}($ at constant P and n$)$
Avogadro's Law: $\frac{V}{n}=$ constant
Average Atomic Mass $=\frac{\Sigma(\text { Mass of Isotopes })_i \times(\% \text { abundance })_i}{100}$
Mole $=\frac{\mathrm{W}}{\mathrm{M}}=\frac{(\mathrm{Wt} . \text { of substance in gm. })}{(\text { Molar mass of substance }(\mathrm{G} . \mathrm{m} . \mathrm{m}))}$
Mass $\%$ of an element $=\frac{\text { Mass of that element in one mole of the compound }}{\text { Molar mass of the compound }} \times 100$
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
Expansion Work $=\mathrm{P} \times \Delta \mathrm{V}=-\mathrm{P}_{\text {ext. }}\left[\mathrm{V}_2-\mathrm{V}_1\right]$
$\mathrm{P}=$ external pressure And $\Delta \mathrm{V}=$ increase or decrease in volume.
Work done in an irreversible isothermal process
Work $=-\mathrm{P}_{\text {ext. }}\left(\mathrm{V}_2-\mathrm{V}_1\right)$
That is, Work $=-\mathrm{P} \times \Delta \mathrm{V}$
$\begin{aligned} & \mathrm{i}=\frac{\text { Observed number of solute particles }}{\text { Number of particles initially taken }} \\ & \mathrm{i}=\frac{\text { Observed value of colligative property }}{\text { Theoretical value of colligative property }}\end{aligned}$
Chemical kinetics
Unit of average velocity $=\frac{\text { Unit of concentration }}{\text { Unit of time }}=\frac{\text { mole }}{\text { litre second }}=$ mole litre $^{-1}$ second $^{-1}$
For any general nth order reaction it is evident that,
$\mathrm{t}_{\frac{1}{2}} \propto[\mathrm{~A}]_0^{1-\mathrm{n}}$
It is to be noted that the above formula is applicable for any general nth-order reaction except $\mathrm{n}=1$.
JEE Main Important Formulas of Inorganic Chemistry
Coordination Compounds
$\mathrm{EAN}=Z-O+2 L$
Where:
$\mathbf{Z}=$ Atomic number of the central metal atom/ion
$\mathbf{O}=$ Oxidation state of the metal atom/ion
L = Number of ligands (or donor atoms) $\times$ number of electrons donated per ligand
Crystal Field Stabilization Energy (CFSE):
Octahedral:
Given below are some tips to help you prepare for JEE Main and score good marks in the exam:
1. First, students need to understand the Syllabus and Exam Pattern so that they can refer to the JEE Main syllabus from the official website.
2. Try to identify the important and high-weightage topics and prepare according to that.
3. Create an effective study plan according to your preparation level. Divide your preparation into monthly, weekly, and daily targets and allocate more time to difficult subjects or topics.
4. Students must focus on conceptual clarity; they must understand the logic and derivations behind every formula.
5. Try to solve questions regularly. Solve previous years' JEE Main question papers and attempt mock tests and sample papers regularly.
Students find it difficult to learn formulas for JEE Main, but with the right approach, they can remember them. Given below are some points to remember:
1. Students must try to understand why a formula works and how chemical reactions occur, and their mechanism.
2. Then break down formulas into chapters or topics.
3. To learn these formulas easily, try to make a formula notebook.
4. Sometimes students must try to make Mnemonics and short tricks, as it helps in quick revision.
5. Try to solve as many questions and revise
6. Try to use diagrams and flowcharts.
JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters
JEE Main is an exam conducted for those aspirants who want to take admission in NIITs, IITs and other engineering colleges, and it is also an eligibility test for JEE advance.
Q: Which part of chemistry has many formulas ?
A:
Chemistry has three subparts (Physical, inorganic and organic). Physical chemistry has many numericals based on different formulas.
Q: Is the class 12 syllabus important for the JEE Main Exam ?
A:
Yes, Class 12 syllabus carries more than 50% of weightage, so it is important for JEE Main Exam.
Yes, during JEE Main registration, you can choose up to four preferred exam cities in order of priority. Since you are staying in Kota but belong to Bihar, you can select both locations. For example, Kota as your first choice and your hometown city in Bihar as another option.
When the admit card is released (usually a week before the exam), the final center will be allotted from your chosen options.
To know the Cutoff of the JEE Mains exam paper for the year 2025, and for previous year, you can visit the link I am attaching below. The link will provide you with the data and help you to improve your performance.
Here is the link of NIPER JEE previous year questions along with their solutions, it has question papers with solutions for year 2019-2025, including your requirement of 2021 :-
You can fill your JEE main and advance forms 2026 normally
. No, your 11th registration number will not cause any problem.
You will be treated as 12th appearing student in 2026, not as a dropper
. You just need to make sure that your CBSE 12th result comes out in 2026 before counselling.
To be eligible for Himachal Pradesh state quota you must have passed atleast two examinations from Himachal pradesh including the 10th and 12th grades. The other criteria are for government employee wards, if the parents have worked there for atleast two years and completed their 10th and 12th from HP.
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