JEE Main Chemistry Formulas 2027 - Topic wise Important Formulas

JEE Main 2027 Chemistry Formula Overview

There will be a total of 25 questions from chemistry in JEE Main 2027, all of which have to be attempted. It is further segregated into Physical, Organic, and Inorganic sections. The maximum number of topics has been reduced from this section (chemistry) only. This makes Chemistry easier than before. However, the high-weightage topics for JEE Main remain the same.

Below are important formulas for JEE Main 2027 Chemistry that are helpful for both sessions. Candidates should solve as many chemistry questions as they can and implement these formulas to remember them quickly. To crack the JEE Main exam with good marks, paste these formulas near the study table and memorise them.

JEE Main Chemistry Important Formulas

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Candidates, while studying chemistry, need to revise and practice the chemical equations and symbols. To some, chemistry is a tough subject, but when candidates practice chemical equations and revise the properties, formulas and symbols, they will have command over the subject. Candidates can check the JEE Main Chemistry formulas below

JEE Main Important Formulas of Physical Chemistry

Some Basic Concepts in Chemistry Formulas

1. Boyle's Law: $P_1 V_1=P_2 V_2$ (at constant T and n)
2. Charles's Law: $\frac{V_1}{T_1}=\frac{V_2}{T_2}$ (at constant P and n)
3. Avogadro's Law: $\frac{v}{n}=$ constant
4. Average Atomic Mass

$=\frac{\Sigma(\text { Mass of Isotopes })_i \times(\% \text { abundance })_i}{100}$

5. Mole $=\frac{\mathrm{W}}{\mathrm{M}}=\frac{\text { (Wt. of substance in gm.) }{ }^{100}}{\text { (Molar mass of substance(G.m.m)) }}$
6. Mass $1 %$ of an element

$=\frac{\text { Mass of that element in one mole of the compound }}{\text { Molar mass of the compound }} \times 100$

7. Equivalent Weight $=\frac{\text { Molecular weight }}{n-\text { factor }(x)}$

Atomic Structure Formulas

1. Frequency $v=\frac{1}{T}$
2. Wave number $(\bar{v}) \bar{v}=\frac{1}{\lambda}$
3. $E=h v=\frac{h c}{\lambda}$
4. Line Spectrum of Hydrogen-like atoms

$\frac{1}{\lambda}=R Z^2\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)$

5. Bohr radius of nth orbit:

$\mathrm{r}_{\mathrm{n}}=0.529 \frac{\mathrm{n}^2}{\mathrm{z}} \mathrm{~A}^0$

6. Velocity of electron in nth orbit:

$V_n=\left(2.18 \times 10^6\right) \frac{\mathrm{Z}}{\mathrm{n}} \mathrm{~m} / \mathrm{s}$

where Z is atomic number
7. Total energy of electron in nth orbit:

$E_n=-13.6 \frac{Z^2}{n^2} \mathrm{eV}=-2.18 \times 10^{-18} \frac{Z^2}{n^2} \mathrm{~J}$

where Z is atomic number
8. Hisenberg Uncertainity Principle: $\Delta x \cdot \Delta P \geq \frac{h}{4 \pi}$
9. $\mathrm{E}_{\mathrm{n}}=-\frac{1312 \times \mathrm{Z}^2}{\mathrm{n}^2} \mathrm{~kJ} / \mathrm{mol}$

Chemical Thermodynamics Formulas

1. Expansion Work $=\mathrm{P} \times \Delta \mathrm{V}=-\mathrm{P}_{\text {ext. }}\left[\mathrm{V}_2-\mathrm{V}_1\right] \mathrm{P}=$ external pressure And $\Delta \mathrm{V}=$ increase or decrease in volume.
2. Work done in a reversible isothermal process

$\begin{aligned}
\mathrm{W} & =-2.303 \mathrm{nRT} \log _{10} \frac{\mathrm{~V}_2}{\mathrm{~V}_1} \\
\mathrm{~W} & =-2.303 \mathrm{nRTlog} \frac{\mathrm{P}_1}{\mathrm{P}_2}
\end{aligned}$

3. Work done in an irreversible isothermal process

$\text { Work }=-P_{\text {ext. }}\left(V_2-V_1\right)$

That is, Work $=-\mathrm{P} \times \Delta \mathrm{V}$
4. $W=\Delta E=n C_V \Delta T$
5. Enthalpy: $H=U+p V$
6. First Law of Thermodynamics: $\Delta U=q+W$
7. $\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta(\mathrm{S})$
8. $\Delta G=-n F E$

Equilibrium Formulas

1. For a reaction:

$\mathrm{mA}+\mathrm{nB} \rightleftharpoons \mathrm{pC}+\mathrm{qD} \frac{\mathrm{~K}_{\mathrm{f}}}{\mathrm{~K}_{\mathrm{b}}}=\frac{[\mathrm{C}]^{\mathrm{p}}[\mathrm{D}]^{\mathrm{q}}}{[\mathrm{~A}]^{\mathrm{m}}[\mathrm{~B}]^{\mathrm{n}}}=\mathrm{K}_{\mathrm{c}}$

2. $\mathrm{pH}=-\log _{10}\left[\mathrm{H}^{+}\right]$
3. $\mathrm{k}_{\mathrm{W}}=\left[\mathrm{H}^{+}\right]\left[\mathrm{OH}^{-}\right]=10^{-14}$
4. $\mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log _{10} \frac{\text { [Salt] }}{\text { Acid }}$
5. $\mathrm{pOH}=\mathrm{pK}_{\mathrm{b}}+\log _{10} \frac{[\text { Salt] }}{[\text { Base }]}$

Electrochemistry Formulas

1. $W=\frac{\text { Eit }}{96500}$

$\frac{E_1}{E_2}=\frac{M_1}{M_2} \text { or } \frac{W_1}{W_2}=\frac{Z_1}{Z_2}$

2. $E_1=$ equivalent weight
$E_2=$ equivalent weight
W or M = mass deposited
3.

$\begin{gathered}
E_{\text {cell }} \text { or } E M F=\left[E_{\text {red }}(\text { cathode })-E_{\text {red }}(\text { anode })\right. \\
E_{\text {eell }}^{\circ} \text { or } E M F^{\circ} \\
=\left[E_{\text {red }}^{\circ}(\text { cathode })-E_{\text {red }}^{\circ}(\text { anode })\right]
\end{gathered}$

$\begin{aligned}
& \text { 4. } \mathrm{E}=\mathrm{E}^{\circ}-\frac{\mathrm{RT}}{\mathrm{nF}} \ln Q \\
& \text { 5. } \mathrm{xA}+\mathrm{yB} \rightarrow \mathrm{mC}+\mathrm{nD}
\end{aligned}$

The emf can be calculated as

$\text { Ecell }=E^{\circ} \text { cell }-\frac{0.059}{n} \log \frac{[\mathrm{C}]^{\mathrm{m}}[\mathrm{D}]^{\mathrm{n}}}{[\mathrm{~A}]^{\mathrm{x}}[\mathrm{~B}]^{\mathrm{y}}}$

6. $\Lambda_{\mathrm{m}}=\kappa \times \frac{1000}{\mathrm{c}}$

7. $\Lambda_{\mathrm{eq}}=\frac{1000 \times \kappa}{\mathrm{N}}$

Solutions Formulas

1. Mass % of a component $=\frac{\text { Mass of the component in the solution }}{\text { Total mass of the solution }} \times 100$
2. Volume $\%$ of a component $=\frac{\text { Volume of the component }}{\text { Total volume of solution }} \times 100$
3. Mass by Volume $\%$ of a component $=\frac{\text { Total valume of solution }}{\text { Total volume of solution }} \times 100$
4. Parts per million

$=\frac{\text { Number of parts of the component }}{\text { Total number of parts of all components of the solution }} \times 10^6$

5. Mole fraction of a component

$=\frac{\text { Number of moles of the component }}{\text { Total number of moles of all the components }}$

6. Molarity: $(M)=\frac{\text { No. of Moles of Solutes }}{\text { Volume of Solution in Liters }}$
7. Molality: $(m)=\frac{\text { No. of Moles of Solutes }}{\text { Mass of solvent inkg }}$

$P_A=P_A^o X_A$

8. $\left(P_T\right)=P_A^o X_A+P_B^o X_B\left(P_B=P_B^o X_B\right)$
9. $\Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \times \frac{\mathrm{W}}{\mathrm{M}} \times \frac{1000}{\mathrm{~W}}$
10. $\Delta T_f=K_f \times \frac{w}{M} \times \frac{1000}{W}$
11. $\Pi=C R T$

$\mathrm{i}=\frac{\text { Observed number of solute particles }}{\text { Number of particles initially taken }}$

12.

$\mathrm{i}=\frac{\text { Observed value of colligative property }}{\text { Theoretical value of colligative property }}$

Chemical kinetics

1. Unit of average velocity $=\frac{\text { Unit of concentration }}{\text { Unit of time }}=\frac{\text { mole }}{\text { litre second }}=$ mole litre -1 second -1
2. $a A+b B \rightarrow c C+d D$

Rate w.r.t. $[\mathrm{A}]=-\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}} \times \frac{1}{\mathrm{a}}$
Rate w.r.t. $[B]=-\frac{d[B]}{d t} \times \frac{1}{b}$
Rate w.r.t. $[\mathrm{C}]=-\frac{\mathrm{d}[\mathrm{C}]}{\mathrm{dt}} \times \frac{1}{\mathrm{c}}$
Rate w.r.t. $[\mathrm{D}]=-\frac{\mathrm{d}[\mathrm{D}]}{\mathrm{dt}} \times \frac{\mathrm{c}}{\mathrm{d}}$
3. $\mathrm{R} \propto[\mathrm{A}]^{\mathrm{p}}[\mathrm{B}]^{\mathrm{q}}$

4. Unit of Rate Constant-

The differential rate expression forn th order reaction is as follows:

$\begin{gathered}
-\frac{d x}{d t}=k(a-x)^n \\
\text { k }=\frac{d x}{(a-x)^n d t}=\frac{(\text { concentration })}{(\text { concentration })^n \text { time }}=(\text { conc. })^{1-n} \text { time }^{-1}
\end{gathered}$

5. For the first-order reaction,

$\begin{aligned}
& k=\frac{2.303}{t} \log \frac{[\mathrm{R}]_0}{[\mathrm{R}]} \\
& \text { 6. } t_1 / 2=\frac{0.693}{k}
\end{aligned}$

7. For any general nth order reaction it is evident that,

$\mathrm{t}_{\frac{1}{2}} \propto[\mathrm{~A}]_0^{1-\mathrm{n}}$

It is to be noted that the above formula is applicable for any general nth-order reaction except $\mathrm{n}=1$.
8. Arrhenius Equation: $\mathrm{k}=\mathrm{Ae}^{-\mathrm{Ea} / \mathrm{RT}}$
9. $\log \frac{\mathrm{K}_2}{\mathrm{~K}_1}=\frac{\mathrm{Ea}}{2.303 \mathrm{R}}\left[\frac{1}{\mathrm{~T}_1}-\frac{1}{\mathrm{~T}_2}\right]$

JEE Main Important Formulas of Inorganic Chemistry

Coordination Compounds

1. $\mathrm{EAN}=Z-O+2 L$
Where:
$Z=$ Atomic number of the central metal atom/ion
0= Oxidation state of the metal atom/ion
$\mathrm{L}=$ Number of ligands (or donor atoms) × number of electrons donated per ligand

2. Crystal Field Stabilization Energy (CFSE):

Tetrahedral:

$\text { CFSE }=(-0.6 x+0.4 y) \Delta_t$

where $x=t_2 g$ electrons, $y=$ e g electrons

d- & f-Block Elements

1. Magnetic Moment:

$\mu=\sqrt{n(n+2)} \mathrm{BM}$

Chemical Bonding and Molecular Structure

1. Formal Charge:

$\text { F.C. }=V-N-\frac{B}{2}$

( $\mathrm{V}=$ valence electrons, $\mathrm{N}=$ non-bonding, $\mathrm{B}=$ bonding electrons)
2. Bond Order (Molecular Orbital Theory):

$\text { Bond Order }=\frac{\left(N_b-N_a\right)}{2}$

3. Dipole Moment:

$\begin{gathered}
\mu=q \times d \\
(q=\text { charge }, d=\text { distance between charges })
\end{gathered}$

JEE Main Important Formulas: Inorganic Chemistry

Some Basic Principles of Organic Chemistry

1. Degree of Unsaturation (DU or IHD):

$\mathrm{DU}=\frac{2 C+2-H+N-X}{2}$

( $\mathrm{C}=$ carbon, $\mathrm{H}=$ hydrogen, $\mathrm{N}=$ nitrogen, $\mathrm{X}=$ halogen )

Hydrocarbons

1. Alkanes: $\mathrm{C}_n \mathrm{H}_{2 n+2}$
2. Alkenes: $C_n H_{2 n}$
3. Alkynes: $\mathrm{C}_n \mathrm{H}_{2 n-2}$

Carboxylic Acids and Derivatives

Method of Preparation of Carboxylic Acids

JEE Main 2027 Chemistry High Weightage Formula Chapters

Not all Chemistry chapters are formula-heavy. Focus your JEE Main Chemistry Revision Notes on the chapters below—these have the most formulas to memorise and appear regularly in the exam pattern.

Preparation tips for JEE Mains

Given below are some tips to help you prepare for JEE Main and score good marks in the exam:

1. First, students need to understand the JEE Main syllabus and Exam Pattern so that they get familiar with the syllabus and the exam pattern.

2. Try to find out the important and high-scoring topics of JEE Main Chemistry and prepare accordingly.

3. Make a good JEE Main study plan as per your preparation level. Divide your preparation in monthly, weekly and daily targets and spend more time on tough subjects or topics.

4. Students need to focus on the clarity of concepts; they need to know the logic behind the derivation of each formula.

5. Try to solve questions on a regular basis. Solve JEE Main previous year question papers and attempt mock tests and sample papers regularly.

How to Memorize Chemistry Formulas Effectively

Students find it difficult to learn formulas for JEE Main, but with the right approach, they can remember them. Given below are some points to remember:

1. Students must try to understand why a formula works and how chemical reactions occur, and their mechanism.

2. Then break down formulas into chapters or topics.

3. To learn these formulas easily, try to make a formula notebook.

4. Sometimes students must try to make mnemonics and short tricks, as it helps in quick revision.

5. Try to solve as many questions and revise

6. Try to use diagrams and flowcharts.

Common Mistakes to Avoid While Memorising the JEE Main 2027 Chemistry Formulas

Small formula errors in Chemistry can cost easy marks in JEE Main 2027. Before your next JEE Main mock test, make sure you are not making these mistakes with your JEE Main Chemistry Revision Notes.

• Mixing sections—Keep Physical, Organic, and Inorganic Chemistry formulas in different sections of your Chemistry Formula Sheet PDF. Mixing them during the revision creates confusion in the exam.

• Memorising without units—Formulas like the Nernst equation and Arrhenius equation have specific units. Always note them alongside the formula.

• Ignoring NCERT derivations—Many Important Chemistry Formulas for JEE Main come directly from NCERT. If you only memorise the final expression, a slightly twisted question will trip you up.

• Revising all chapters equally—The JEE Main exam pattern shows some chapters appear far more than others. Revise based on weightage, not habit.