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एलन कोटा द्वारा जेईई मेन 2021 आंसर की (JEE Main 2021 Answer Key by Allen Kota in Hindi)

एलन कोटा द्वारा जेईई मेन 2021 आंसर की (JEE Main 2021 Answer Key by Allen Kota in Hindi)

Edited By Shanta Upadhyay | Updated on Mar 04, 2021 06:03 PM IST | #JEE Main
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एलन कोटा द्वारा जेईई मेन 2021 आंसर की - उम्मीदवार इस पृष्ठ से फ़रवरी परीक्षा के लिए एलन कोटा द्वारा जारी जेईई मेन 2021 आंसर की और सोल्युशन की जांच कर सकेंगे। एलन कोटा द्वारा जेईई मेन 2021 आंसर की में परीक्षा में पूछे गए सभी प्रश्नों के सही उत्तर शामिल हैं। कोचिंग संस्थानों ने प्रत्येक पाली के लिए जेईई मेन आंसर की जारी कर दिया है। उम्मीदवार एलन कोटा द्वारा जेईई मेन 2021 आंसर की के साथ अपनी प्रतिक्रियाओं की तुलना करके अपने स्कोर की गणना करने में सक्षम होंगे। उम्मीदवार एलन द्वारा जेईई मेन 2021 आंसर की का उपयोग करके गणना किए गए अंकों के आधार पर अपनी संभावित रैंक का अनुमान लगाने में भी सक्षम होंगे। उम्मीदवारों को जेईई मेन प्रश्न पत्रों की जांच करने की भी सलाह दी जाती है। उम्मीदवार पृष्ठ से एलन कोटा द्वारा पिछले वर्षों की जेईई मेन आंसर की भी देख सकते हैं। एलन कोटा द्वारा जेईई मेन 2021 आंसर की के बारे में अधिक जानने के लिए पूरा लेख पढ़ें।जेईई मेन इस वर्ष 4 सत्र फ़रवरी, मार्च, अप्रैल और मई में आयोजित किया जाएगा। एलन कोटा द्वारा जेईई मेन आंसर की चारो सत्रों के लिए जारी की जाएगी।
Latest: जेईई मेन आंसर की 2021 की जांच करें।

एलन कोटा द्वारा जेईई मेन 2021 आंसर की (JEE Main 2021 Answer Key by Allen Kota in Hindi)
एलन कोटा द्वारा जेईई मेन 2021 आंसर की (JEE Main 2021 Answer Key by Allen Kota in Hindi)

एलन द्वारा जारी जेईई मेन 2021 उत्तर कुंजी और प्रश्न पत्र (फरवरी सत्र)

एलन कोटा द्वारा जेईई मेन आंसर की - फरवरी सत्र



जेईई मेन एग्जाम डेट 2021

जेईई मेन फरवरी 2021 सत्र के लिए एलन कोटा द्वारा आंसर की

विषय

शिफ्ट I

शिफ्ट II

फ़रवरी 26

भौतिकी

Click Here

Click Here

रसायन विज्ञान

Click Here

Click Here

गणित

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फ़रवरी 25

भौतिकी

Click Here

Click Here

रसायन विज्ञान

Click Here

Click Here

गणित

Click Here

Click Here

फ़रवरी 24

भौतिकी

Click Here

Click Here

रसायन विज्ञान

Click Here

Click Here

गणित

Click Here

Click Here

फ़रवरी 23

भौतिकी

जल्द जारी होगा

जल्द जारी होगा

रसायन विज्ञान

जल्द जारी होगा

जल्द जारी होगा

गणित

जल्द जारी होगा

जल्द जारी होगा

स्कोर की गणना के लिए एलन कोटा द्वारा जेईई मेन 2021 आंसर की का उपयोग कैसे करें?

उम्मीदवार एलन कोटा द्वारा जेईई मेन 2021 की आंसर की का उपयोग करके अपने संभावित अंकों की गणना करने के लिए दिए गए चरणों का पालन कर सकते हैं।

  • आधिकारिक वेबसाइट से एलन कोटा द्वारा जेईई मेन 2021 आंसर की डाउनलोड करें।

  • संस्थान की आंसर की के साथ प्रतिक्रिया की तुलना करें।

  • सही और गलत प्रतिक्रियाएँ निर्धारित करें।

  • ऑफिसियल जेईई मेन 2020 अंकन योजना के आधार पर संभावित अंकों की गणना करें।

  • जेईई मेन रैंक प्रिडिक्टर 2021 का उपयोग करके संभावित रैंक की गणना करें।

जेईई मेन 2021 मार्किंग स्कीम

उम्मीदवार नीचे उल्लेखित जेईई मेन 2021 की आधिकारिक अंकन योजना का उल्लेख कर सकते हैं-

MCQ के लिए अंकन योजना - उम्मीदवारों को प्रत्येक सही उत्तर के लिए 4 अंक आवंटित किए जाएंगे और प्रत्येक गलत उत्तर के लिए 1 अंक की कटौती होगी

न्यूमेरिकल मूल्य उत्तर के लिए अंकन योजना - उम्मीदवारों को प्रत्येक सही उत्तर के लिए 4 अंक आवंटित किए जाएंगे और ऐसे प्रश्नों के लिए कोई नकारात्मक अंकन नहीं होगा।

एलन कोटा द्वारा जेईई मेन 2021 आंसर की की मुख्य विशेषताएं

  • एलन कोटा जेईई मेन 2021 आंसर की ऑनलाइन मोड में जारी की जाएगी।

  • एलन कोटा द्वारा जेईई मेन 2021 आंसर की संस्थान के विशेषज्ञ संकायों द्वारा तैयार की जाएगी।

  • आंसर की का उपयोग करके अपने संभावित जेईई मेन स्कोर की गणना करने के लिए उम्मीदवारों को उनकी प्रतिक्रियाओं को याद रखना होगा।

  • उम्मीदवारों को अपने स्कोर की गणना के लिए जेईई मेन 2021 की आधिकारिक अंकन योजना का उल्लेख करना चाहिए।

  • यह ध्यान दिया जाना चाहिए कि एलन कोटा जेईई मेन 2021 की आंसर की के आधार पर गणना किए गए अंक प्रकृति में सांकेतिक होंगे और उम्मीदवारों द्वारा अंतिम स्कोर नहीं माना जाना चाहिए।

पिछले वर्षों के एलन कोटा जेईई मेन आंसर की

उम्मीदवार पिछले वर्षों - 2020, 2019, 2018, 2017 और 2016 के लिए एलन कोटा द्वारा जेईई मेन की आंसर की की जांच कर सकते हैं। जेईई मेन 2021 आंसर की को यहां अपडेट किया जाएगा जैसे ही यह संस्थान द्वारा जारी किया जाएगा।

एलन (अप्रैल सत्र) द्वारा जेईई मेन 2020 आंसर की और प्रश्न पत्र

जेईई मेन 2020 आंसर की एलन कोटा द्वारा - 2 सितंबर


जेईई मेन 2020 आंसर की एलन कोटा द्वारा - 3 सितंबर


जेईई मेन 2020 आंसर की और सोल्युशन एलन कोटा द्वारा - 4 सितंबर


जेईई मेन 2020 आंसर की और सोल्युशन एलन कोटा द्वारा - 5 सितंबर

जेईई मेन 2020 आंसर की और सोल्युशन एलन कोटा द्वारा - 6 सितंबर

जेईई मेन 2020 आंसर की एलन (जनवरी सत्र) द्वारा

जेईई मेन 2020 आंसर की और समाधान एलन कोटा द्वारा - 7 जनवरी

जेईई मेन 2020 आंसर की और सोल्युशन एलन कोटा द्वारा - 8 जनवरी

जेईई मेन 2020 आंसर की और सोल्युशन एलन कोटा द्वारा - 9 जनवरी

एलन कोटा द्वारा जारी जेईई मेन 2019 आंसर की और हल सहित प्रश्न पत्र - अप्रैल सत्र

जेईई मेन 2019 अप्रैल सत्र

पाली

मैथ्स

फिजिक्स

केमिस्ट्री

8 अप्रैल, 2019 (पेपर 1)

सुबह की पाली

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

शाम की पाली

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

9 अप्रैल, 2019 (पेपर 1)

शाम की पाली

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

10 अप्रैल, 2019 (पेपर 1)

सुबह की पाली

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

शाम की पाली

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

12 अप्रैल, 2019 (पेपर 1)

सुबह की पाली

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

शाम की पाली

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

एलन कोटा द्वारा जेईई मेन 2019 आंसर की और हल सहित प्रश्न पत्र - जनवरी सत्र

तारीख

पाली

उत्तर सहित प्रश्नपत्र

हल सहित प्रश्नपत्र

फिजिक्स

केमिस्ट्री

मैथ्स

फिजिक्स

केमिस्ट्री

मैथ्स

9 जनवरी

पाली 1 (सुबह 9:30 बजे से दोपहर 12:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

पाली 2 (दोपहर 2:30 बजे से शाम 5:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

10 जनवरी

पाली 1 (सुबह 9:30 बजे से दोपहर 12:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

पाली 2 (दोपहर 2:30 बजे से शाम 5:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

11 जनवरी

पाली 1 (सुबह 9:30 बजे से दोपहर 12:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

पाली 2 (दोपहर 2:30 बजे से शाम 5:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

12 जनवरी

पाली 1 (सुबह 9:30 बजे से दोपहर 12:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

पाली 2 (दोपहर 2:30 बजे से शाम 5:30 बजे तक)

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

यहाँ क्लिक करें

एलन कोटा द्वारा जारी जेईई मेन 2018 आंसर की

विषय

कोड C

सभी कोड्स

फिजिक्स

यहाँ क्लिक करें

डाउनलोड

केमिस्ट्री

डाउनलोड

डाउनलोड

मैथ्स

डाउनलोड

डाउनलोड


जेईई मेन 2017 आंसर की और प्रश्न पत्र (पेपर I)


एलन कोटा द्वारा जारी जेईई मेन 2016 आंसर की

Frequently Asked Question (FAQs)

1. फ़रवरी 2021 के सत्र के लिए कोचिंग क्लासेस कब जेईई मेन उत्तर कुंजी जारी करेंगे?

आकाश, रेजोनेंस, FIITJEE, एलन, करियर पॉइंट, जैसे पूरे भारत के शीर्ष कोचिंग क्लासेस कुछ ही घंटों के भीतर परीक्षा की प्रत्येक पारी के समापन के तुरंत बाद जेईई मेन उत्तर कुंजी फ़रवरी 2021 जारी कर दिया है।

2. क्या हम NTA द्वारा जारी जेईई मेन उत्तर कुंजी को चुनौती दे सकते हैं?

हां, एनटीए छात्रों को जेईई मेन ऑफिसियल उत्तर कुंजी के खिलाफ अपनी आपत्तियां उठाने की अनुमति देता है यदि वे इससे संतुष्ट नहीं हैं या उन्हें लगता है कि आंसर की में कोई गलती हैं।

3. जेईई मेन आंसर की 2021 कहाँ से डाउनलोड कर सकते हैं?

आंसर की जारी होते ही इस लेख में अपलोड किया जाएगा।

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Questions related to JEE Main

Have a question related to JEE Main ?

Hello,


Yes, even after clearing JEE, you need to pay fees to study in a college. The fee structure varies depending on the college and course you choose. Here's a general idea:


1. Government Colleges: Fees are relatively low, around 5,000 to 50,000 per year.

2. Government-Aided Colleges: Fees are moderate, around 50,000 to 1,50,000 per year.

3. Private Colleges: Fees can be higher, ranging from 1,50,000 to 5,00,000 or more per year.

4. IITs (Indian Institutes of Technology): Fees are around 2,00,000 to 3,00,000 per year.

5. NITs (National Institutes of Technology): Fees are around 1,50,000 to 2,50,000 per year.


Additionally, you may need to pay for:


· Hostel fees (if you opt for on-campus accommodation)

· Mess fees (for food)

· Other expenses (books, materials, etc.)


Hope this helps,

Thank you

Hi there,

Congratulations on getting a percentile of 96.21 in the jee mains examination.

At this percentile you will be certainly in the top list of candidates participating in the exam and the counselling. You can also check about the previous year cutoffs and the opening and closing ranks by visiting the official website of the nta and then checking about the score required to get an admission in the nits.

Also, you can take the help of our college predictor which will definitely help you in finding the exact list of the colleges which are suitable for admission based upon your jee mains rank and score.

The link of the predictor is mentioned below. You can take  the help from there.

https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp

Hope this resolves your query.

Yes you can participate in Centralized Admission Process (CAP) conducted by the State Common Entrance Test Cell, Maharashtra with your JEE mains score under 15% jee quota.some private universities such as Pict ,Spit, vit ,rocem take admission under this quota but Vjti,Coep state government dont accept JEE marks.for counselling you need to report at the time of counselling and get your documents verified then the merit list will be displayed and admission process is done by the authority.for more refer link

https://engineering.careers360.com/articles/mht-cet-counselling-through-jee-main

Hello,


The syllabus for JEE Main 2026 is based on the Class 11 and 12 curriculum of CBSE. Here's a general overview of the syllabus and most concentrated parts:


Physics:


· Mechanics (30-35%): Kinematics, dynamics, work, energy, power, rotational motion, gravitation

· Thermodynamics (15-20%): Laws of thermodynamics, heat transfer, kinetic theory of gases

· Electromagnetism (20-25%): Electric charges, fields, potential, circuits, magnetism, electromagnetic induction

· Optics (10-15%): Reflection, refraction, lenses, wave optics

· Modern Physics (10-15%): Atomic structure, dual nature of matter, nuclear physics


Chemistry:


· Physical Chemistry (30-35%): Atomic structure, chemical bonding, thermodynamics, kinetics, equilibrium

· Inorganic Chemistry (25-30%): Periodic table, s-block, p-block, d-block, f-block elements

· Organic Chemistry (30-35%): Hydrocarbons, functional groups, reactions, stereochemistry


Mathematics:


· Algebra (30-35%): Sets, relations, functions, matrices, determinants, complex numbers

· Calculus (25-30%): Limits, derivatives, integrals, differential equations

· Coordinate Geometry (20-25%): Lines, circles, parabolas, ellipses, hyperbolas

· Trigonometry (10-15%): Triangles, trigonometric functions, identities


Most Concentrated Parts:


· Physics: Mechanics, Electromagnetism, and Thermodynamics

· Chemistry: Physical Chemistry, Inorganic Chemistry, and Organic Chemistry

· Mathematics: Algebra, Calculus, and Coordinate Geometry


Important Topics:


· Physics: Newton's laws, work-energy theorem, electric circuits, magnetic fields, optics

· Chemistry: Atomic structure, chemical bonding, acid-base equilibria, redox reactions, organic reactions

· Mathematics: Quadratic equations, functions, limits, derivatives, integrals, matrices


hope this helps,

Thank you

Hello,


Yes, admission to the Indian Statistical Institute (ISI) is possible through JEE Advanced score. ISI considers JEE Advanced scores for admission to its undergraduate programs, including:


1. Bachelor of Statistics (Honours) [B.Stat (Hons)]

2. Bachelor of Mathematics (Honours) [B.Math (Hons)]


To be eligible, you need to:


1. Appear for JEE Advanced and score a minimum qualifying mark.

2. Apply to ISI separately, mentioning your JEE Advanced roll number and score.

3. Meet the cutoff score set by ISI for admission.


hope this helps,

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 5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C.  If Na2SO4 is 81.5% ionised, the value of x (Kf for water=1.860C kg mol−1) is approximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)
Option: 1  15 g
Option: 2  25 g
Option: 3  45 g
Option: 4  65 g  
 

 50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl.  If pKb of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75
Option: 3 8.25
Option: 4 9.25
 

CH_3-CH=CH-CH_3+Br_2\overset{CCl_4}{\rightarrow}A

What is A?

Option: 1

CH_3-CH(Br)-CH_2-CH_3


Option: 2

CH_3-CH(Br)-CH(Br)-CH_3


Option: 3

CH_3-CH_2-CH_2-CH_2Br


Option: 4

None


\mathrm{NaNO_{3}} when heated gives a white solid A and two gases B and C. B and C are two important atmospheric gases. What is A, B and C ?

Option: 1

\mathrm{A}: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 2

A: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 3

A: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


Option: 4

\mathrm{A}: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


C_1+2 C_2+3 C_3+\ldots .n C_n=

Option: 1

2^n


Option: 2

\text { n. } 2^n


Option: 3

\text { n. } 2^{n-1}


Option: 4

n \cdot 2^{n+1}


 

A capacitor is made of two square plates each of side 'a' making a very small angle \alpha between them, as shown in the figure. The capacitance will be close to : 
Option: 1 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{4 d } \right )

Option: 2 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 + \frac{\alpha a }{4 d } \right )

Option: 3 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{2 d } \right )

Option: 4 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{3 \alpha a }{2 d } \right )
 

 Among the following compounds, the increasing order of their basic strength is
Option: 1  (I) < (II) < (IV) < (III)
Option: 2  (I) < (II) < (III) < (IV)
Option: 3  (II) < (I) < (IV) < (III)
Option: 4  (II) < (I) < (III) < (IV)
 

 An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant.  If during  this process the relation of pressure P and volume V is given by PVn=constant,  then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
Option: 1  n=\frac{C_{p}}{C_{v}}


Option: 2  n=\frac{C-C_{p}}{C-C_{v}}


Option: 3 n=\frac{C_{p}-C}{C-C_{v}}

Option: 4  n=\frac{C-C_{v}}{C-C_{p}}
 

As shown in the figure, a battery of emf \epsilon is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit ) is : 


Option: 1 \frac{\epsilon L }{R^{2}} \left ( 1 - \frac{1}{e} \right )
Option: 2 \frac{\epsilon L }{R^{2}}


Option: 3 \frac{\epsilon R }{eL^{2}}

Option: 4 \frac{\epsilon L }{eR^{2}}
 

As shown in the figure, a particle of mass 10 kg is placed at a point A. When the particle is slightly displaced to its right, it starts moving and reaches the point B. The speed  of the particle at B is x m/s. (Take g = 10 m/s2 ) The value of 'x' to the nearest is ___________.
Option: 1 10
Option: 2 20
Option: 3 40
Option: 4 15

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