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JEE Main Cutoff for IIIT Srirangam- To participate in the admission process of IIIT Srirangam, candidates are required to meet the cutoff specified by the concerned authorities. The JEE Main 2020 cutoff for IIIT Srirangam will be the minimum rank required by the candidates to be eligible for admissions. The admission authorities will prepare the JEE Main cutoff for IIIT Srirangam depending upon various factors. The cutoff of JEE Main for IIIT Srirangam will be released category wise and course wise. The cutoff for each course and category will differ. Candidates who will be able to secure marks either equivalent to or more than the cutoff list will be offered admission to the institute. Read the complete article to know more about JEE Main cutoff for IIIT Srirangam.Latest: JEE Main 2020 result declared. NTA has also released the final answer key of JEE Main 2020.
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Indian Institute of Information Technology (IIIT), Srirangam offer admission to two B.Tech courses - Computer Science and Engineering (CSE) and Electronics and Communication Engineering (ECE). Separate cutoff for both the courses will be released by the authorities.
The cutoff of JEE Main for IIIT Srirangam will be the minimum rank required by the candidate to be eligible to participate in the admission process of the institute. Cutoff of JEE Main 2020 for IIIT Srirangam will be updated in this article as soon as it is released by the concerned authorities. It will be released after the declaration of JEE Main 2020 result.
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While preparing the cutoff of JEE Main 2020, the authorities consider the following factors.
Availability of seats
Total number of questions asked in JEE Main 2020.
Total number of applicants appeared for the exam.
Last year’s cut off trends
Difficulty level of the exam
Candidates can check the previous year’s cutoff of JEE Main for IIIT Srirangam in the tables below.
Computer Science and Engineering
Electronics and Communication Engineering
Name of the Course
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First of all for preparing organic chemistry, start with the NCERT. NCERT is very helpful in solving the doubts and clearing the basic concepts. At very starting, understand the basic concepts of organic chemistry. Then sincerely study and understand the mechanisms of reactions mentioned in the NCERT. Once you master the reactions, then refer the reference books of any renowned author. The reference books will help you to build your confidence and command over the reactions.
The Organic Chemistry requires frequent reading and revision. So, make sure that you revise the learned reactions at a specific intervals. You need to study daily in order to get your command over organic. About the theory portion, then just read the theory portion once and get it understood. Generally, 2-3 questions come directly from the theory.
I am mentioning some books that you can use as reference books :
well the syllabus will remain same even this year.the syllabus which was followed in 2019 will be followed and even the weightage of each subject i.e mathematics,physics ,chemistry will remain same .
It is a very tough to get admission in VIT Pune with 88 percentile in JEE Mains Examination.
You can try attempting some other engineering examinations. Also, you can attempt VITEEE Examination for admission into VIT campuses.
Hope this answer helps!
see there is no particular qualifying marks is applied for jee main exam, you need to score high to get tier 1 institute like nits, dtu, nsit, vit vellore etc. however at this score you have less chances for nits, and other state government colleges. so I suggest you to give your best for jee main april session. jee main score is calculated as 100 - (your total percentile) * 869010 /100 ., so if this time number of students is increase it will have effect on your current score.
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