How Much Percentile Required for IITs? Candidates can check the percentile required for IITs on this page. The round 1 percentile required for IITs Bombay is opening ranking of 2666 and a closing ranking of 4095. A 75% score in your 12th grade (or be in the top 20 percentile of your board) for the general and OBC categories, and 65% for SC/ST/PwD candidates is recommended. The percentages of various categories of candidates to be shortlisted are: 10% for GEN-EWS, 27% for OBC-NCL, 15% for SC, 7.5% for ST, and the remaining 40.5% is OPEN for all. Within each of these five categories, 5% horizontal reservation is available for PwD candidates. The authority will conduct the JEE Advanced 2026 exam in April 2026. Read more about how much percentile required for IITs below.
Candidates must have passed class XII (or equivalent) Board examination with a minimum of five subjects and secured at least 75% aggregate marks. For SC, ST and PwD candidates, the aggregate marks should be at least 65%. Must have passed class XII (or equivalent) Board examination with a minimum of five subjects and be within the category-wise top 20 percentile of successful candidates in their respective Class XII (or equivalent) board examination.
Candidates who want to appear for IIT JEE exam must qualify their 12th with 75 per cent marks which is for the General and OBC category while 65 per cent cutoff is set for other reserved categories like SC, ST, PwD.
Institute | Opening Rank | Closing Rank |
10063 | 13957 | |
2666 | 4095 | |
10191 | 12346 | |
3030 | 4228 | |
8139 | 9821 | |
5615 | 7079 | |
5850 | 7945 | |
4280 | 5790 | |
4234 | 5629 | |
8115 | 9864 | |
11475 | 13158 | |
5247 | 6361 | |
10481 | 12350 | |
9142 | 10645 | |
7201 | 9145 | |
6867 | 7921 | |
12953 | 14852 | |
8956 | 14599 | |
10641 | 15217 |
Institute | Opening Rank | Closing Rank |
Indian Institute of Technology Bhubaneswar | 10922 | 16156 |
Indian Institute of Technology Bombay | 2666 | 4250 |
Indian Institute of Technology Mandi | 10954 | 14274 |
Indian Institute of Technology Delhi | 3244 | 4302 |
Indian Institute of Technology Delhi | 3660 | 9193 |
Indian Institute of Technology Kharagpur | 6188 | 7774 |
Indian Institute of Technology Hyderabad | 5850 | 8698 |
Indian Institute of Technology Kanpur | 4361 | 6161 |
Indian Institute of Technology Madras | 4356 | 6112 |
Indian Institute of Technology Gandhinagar | 9310 | 10796 |
Indian Institute of Technology Patna | 12605 | 15400 |
Indian Institute of Technology Roorkee | 5247 | 6870 |
Indian Institute of Technology (ISM) Dhanbad | 10753 | 13778 |
Indian Institute of Technology Ropar | 9142 | 12488 |
Indian Institute of Technology (BHU) Varanasi | 7606 | 10278 |
Indian Institute of Technology Guwahati | 7268 | 9021 |
Indian Institute of Technology Palakkad | 14109 | 16753 |
Indian Institute of Technology Tirupati | 8956 | 16548 |
Indian Institute of Technology Jammu | 15448 | 17263 |
Candidates can check the minimum percentage of marks required for IIT in the table below.
Minimum percentage of marks prescribed for inclusion in the rank list
Rank List | Minimum percentage of marks in each subject | Minimum percentage of aggregate marks |
Common rank list (CRL) | 5.83% | 20.56% |
GEN-EWS rank list | 5.25% | 18.50% |
OBC-NCL rank list | 5.25% | 18.50% |
SC rank list | 2.92% | 10.28% |
ST rank list | 2.92% | 10.28% |
Common-PwD rank list (CRL-PwD) | 2.92% | 10.28% |
GEN-EWS-PwD rank list | 2.92% | 10.28% |
OBC-NCL-PwD rank list | 2.92% | 10.28% |
SC-PwD rank list | 2.92% | 10.28% |
ST-PwD rank list | 2.92% | 10.28% |
Preparatory course rank lists | 1.46% | 5.14% |
Frequently Asked Questions (FAQs)
The minimum percentile for an IIT 12th-grade score of 75% (65% for SC/ST) or being in the top 20% of your class.
Yes, a minimum 75% marks required for the exam. A candidate should have appeared for the Class XII (or equivalent) examination for the first time in either 2024 or 2025 with Physics, Chemistry, and Mathematics as compulsory subjects.
There are a total seats are available 18160 in IIT
There is no age limit to attempt for the JEE Advanced exam.
On Question asked by student community
Hello,
You passed your Class 12 (Intermediate) from UP Board in
2024
.
As per
JEE Advanced rules
, a candidate can appear
only in the year of Class 12 passing and the next consecutive year
Eligible years for you were 2024 and 2025
You already appeared in 2025
2026 is not allowed
Your health issue does not change this rule.
You can still take JEE Main again in 2026 , but not JEE Advanced.
Hope it helps !
Hello,
Yes, many IITs now offer specialization BTech programs in AI and data science/engineering, separate from core CSE, while also providing AI/ML/robotics as electives or minors within CSE/other branches, with admission via JEE Advanced, but you'll find specific "robotics engineering" branches more at institutions like IITs/NITs, though IITs integrate robotics in AI/CSE.
I hope it will clear your query!!
Hello,
You can download the IIT JEE Last 5 Years Chapterwise PYQ's from the Careers360 website. Practising these papers will helps you to understand the exam pattern, to identify the important topics, to improve time management, and overall it enhances your exam preparation.
LINK: https://engineering.careers360.com/articles/jee-main-question-papers
Hope it helps!
Hello murali
No, your son is not eligible for OBC NCL for IIT JEE because you fall in the "creamy layer" occupational category, regardless of your current employment status or family income. Students whose family income is less than Rs. 8 lakhs annually and they are not belong to the "creamy layer".
Note -
Thank You
Hello,
In 2025, IIT Madras JEE Advanced, closing ranks are around 171 for CSE, 306 for AI & Data Analytics, 849 for Electrical, about 1300 for Computational Engineering, around 1440 for Engineering Physics, 2468 for Mechanical, and about 6112 for Civil.
To know more access below mentioned link:
https://engineering.careers360.com/articles/jee-advanced-cutoff-for-iit-madras
Hope it helps.
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