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JEE Main 2024 Cutoff for IIIT Pune - Check Opening and Closing Ranks here

JEE Main 2024 Cutoff for IIIT Pune - Check Opening and Closing Ranks here

Edited By Apeinuo Ziephru | Updated on May 19, 2024 02:23 PM IST | #JEE Main

IIIT Pune JEE Main Cutoff 2024 - The minimum rank required by the candidates to be eligible for getting admission to the B.Tech programme at IIIT Pune is the IIIT Pune 2024 JEE Main cutoff. Candidates have to meet the JEE Main 2024 cutoff of IIIT Pune to participate in the B.Tech admission process. IIIT Pune cutoff percentile 2024 will hold the opening and closing ranks within which the admissions will be offered at the institute.

JEE Main 2024 Cutoff for IIIT Pune - Check Opening and Closing Ranks here
JEE Main 2024 Cutoff for IIIT Pune - Check Opening and Closing Ranks here

Since the JEE Main cutoff for IIIT Pune will act as a screening process, the authorities will need to consider many factors while preparing it such as the availability of seats, the total number of applicants, the difficulty level of JEE Main 2024, and many more. The IIIT Pune 2024 JEE Main cutoff has been released in the form of opening and closing ranks. NTA has concluded the JEE Main exam for the January and April sessions. Read the complete article to know more about IIIT Pune JEE Main 2024 cutoff.

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Previous Years' IIIT Pune JEE Main Cutoff

Candidates can check the previous year’s cutoff of JEE Main for IIIT Pune in the tables given below. IIIT Pune cutoff OBC, general, ST, SC is available below.

JEE Main Cutoff for IIIT Pune 2023

Academic Program NameSeat TypeGenderOpening RankClosing Rank
Computer Science and Engineering (4 Years, Bachelor of Technology)OPENGender-Neutral420214966
Female-only (including Supernumerary)829021049
OPEN (PwD)Gender-Neutral328512
Female-only (including Supernumerary)11171117
EWSGender-Neutral21952499
Female-only (including Supernumerary)34624084
EWS (PwD)Gender-Neutral172172
OBC-NCLGender-Neutral36576174
Female-only (including Supernumerary)568010195
OBC-NCL (PwD)Gender-Neutral239257
Female-only (including Supernumerary)548548
SCGender-Neutral8353570
Female-only (including Supernumerary)33885179
SC (PwD)Gender-Neutral103103
STGender-Neutral4971995
Female-only (including Supernumerary)27803021
Electronics and Communication Engineering (4 Years, Bachelor of Technology)OPENGender-Neutral1518818945
Female-only (including Supernumerary)2169624607
OPEN (PwD)Gender-Neutral630630
EWSGender-Neutral28143358
Female-only (including Supernumerary)47834783
OBC-NCLGender-Neutral61998119
Female-only (including Supernumerary)1137011645
OBC-NCL (PwD)Gender-Neutral395395
SCGender-Neutral34205021
Female-only (including Supernumerary)57416480
STGender-Neutral23262699
Female-only (including Supernumerary)34933493

JEE Main Cutoff for IIIT Pune 2022

Course NameCategoryMale
Female
All IndiaClosing RankOpening RankClosing Rank
Computer Science and EngineeringOPEN533615894533621392
EWS2232257922324001
OBC NCL40866001408610230
SC2031370420315505
ST69318576932498
Electronics and Communication EngineeringOPEN16450215461645027728
EWS3393346633934607
OBC NCL60338244603313166
SC4140536741406451
ST2142291321422913


JEE Main Cutoff for IIIT Pune 2021

Course Name

Category

Male

Female

Computer Science and Engineering

OBC

6495

6495

EWS

2826

2826

General

15263

15263

SC

4477

4477

ST

2179

2179

Electronics and Communication Engineering

OBC

8364

8364

EWS

3570

3570

General

20386

20386

SC

6077

6077

ST

3432

3432

JEE Main Cutoff for IIIT Pune 2020

Course Name

Category

Male

Female

Computer Science and Engineering

OBC

89368936

EWS

42754275

General

2099920999

SC

62976297

ST

35203520

Electronics and Communication Engineering

OBC

1194211942

EWS

55085508

General

2589725897

SC

91179117

ST

44134413

JEE Main Cutoff 2019 for IIIT Pune

Course Name

Category

Gender Neutral

Female

Computer Science and Engineering

OBC

9799

--

EWS

3613

--

General

23600

--

SC

5791

--

ST

2810

--

Electronics and Communication Engineering

OBC

12453

--

EWS

4591

--

General

29345

--

SC

7684

--

ST

3650

--

JEE Main Cutoff 2018 for IIIT Pune

Course Name

Categories

Opening Rank

Closing Rank

Computer Science and Engineering

General

140

22427

OBC-NCL

246

10020

SC

132

5119

ST

1097

3517

Electronics and Communication Engineering

General

937

32589

OBC-NCL

477

12799

SC

2133

6789

ST

1926

4421

JEE Main Cutoff 2017 for IIIT Pune

Course Name

Category

Opening Rank

Closing Rank

Computer Science Engineering

General

5092

24754

OBC-NCL

4162

9835

SC

2041

4966

ST

1048

3473

PwD ST

-

673

PWD SC

-

-

PWD OBC

-

-

PWD GEN

-

927

Electronics and Communication Engineering

General

14867

30704

OBC-NCL

5133

11528

SC

3267

7339

ST

1671

4682

PwD ST

-

-

PWD SC

-

-

PWD OBC

-

-

PWD GEN

-

1144

JEE Main Cutoff 2016 for IIIT Pune


Course Name

Category

Opening Rank

Closing Rank

Computer Science and Engineering

General

1706

23670

OBC-NCL

2111

9966

SC

1573

5257

ST

931

3089

PwD ST

-

-

PWD SC

-

-

PWD OBC

317

519

PWD GEN

429

749

Electronics and Communication Engineering

General

9632

28620

OBC-NCL

3913

11118

SC

2411

6471

ST

1435

3275

PwD ST

-

-

PWD SC

-

-

PWD OBC

310

907

PWD GEN

393

412

IIIT Pune JEE Main Cutoff 2024

Candidates seeking admission to IIT Pune can check the JEE Main 2024 cutoff in this article. Using IIIT Pune JEE Mains cutoff 2024, candidates will be able to know their chances of getting admission to the institute. It should be noted that meeting cutoff does not guarantee admission. There will be more rounds such as counselling and document verification.

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Factors determining the IIIT Pune JEE Main 2024 Cutoff

The following are the factors that are considered while preparing the cutoff marks of JEE Main for IIIT Pune.

  • Difficulty level of questions asked in JEE Main 2024

  • Previous years’ cutoff trends

  • Availability of seats

  • Total number of applicants appeared for JEE Main 2024

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Questions related to JEE Main

Have a question related to JEE Main ?

Hello,


Yes, even after clearing JEE, you need to pay fees to study in a college. The fee structure varies depending on the college and course you choose. Here's a general idea:


1. Government Colleges: Fees are relatively low, around 5,000 to 50,000 per year.

2. Government-Aided Colleges: Fees are moderate, around 50,000 to 1,50,000 per year.

3. Private Colleges: Fees can be higher, ranging from 1,50,000 to 5,00,000 or more per year.

4. IITs (Indian Institutes of Technology): Fees are around 2,00,000 to 3,00,000 per year.

5. NITs (National Institutes of Technology): Fees are around 1,50,000 to 2,50,000 per year.


Additionally, you may need to pay for:


· Hostel fees (if you opt for on-campus accommodation)

· Mess fees (for food)

· Other expenses (books, materials, etc.)


Hope this helps,

Thank you

Hi there,

Congratulations on getting a percentile of 96.21 in the jee mains examination.

At this percentile you will be certainly in the top list of candidates participating in the exam and the counselling. You can also check about the previous year cutoffs and the opening and closing ranks by visiting the official website of the nta and then checking about the score required to get an admission in the nits.

Also, you can take the help of our college predictor which will definitely help you in finding the exact list of the colleges which are suitable for admission based upon your jee mains rank and score.

The link of the predictor is mentioned below. You can take  the help from there.

https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp

Hope this resolves your query.

Yes you can participate in Centralized Admission Process (CAP) conducted by the State Common Entrance Test Cell, Maharashtra with your JEE mains score under 15% jee quota.some private universities such as Pict ,Spit, vit ,rocem take admission under this quota but Vjti,Coep state government dont accept JEE marks.for counselling you need to report at the time of counselling and get your documents verified then the merit list will be displayed and admission process is done by the authority.for more refer link

https://engineering.careers360.com/articles/mht-cet-counselling-through-jee-main

Hello,


The syllabus for JEE Main 2026 is based on the Class 11 and 12 curriculum of CBSE. Here's a general overview of the syllabus and most concentrated parts:


Physics:


· Mechanics (30-35%): Kinematics, dynamics, work, energy, power, rotational motion, gravitation

· Thermodynamics (15-20%): Laws of thermodynamics, heat transfer, kinetic theory of gases

· Electromagnetism (20-25%): Electric charges, fields, potential, circuits, magnetism, electromagnetic induction

· Optics (10-15%): Reflection, refraction, lenses, wave optics

· Modern Physics (10-15%): Atomic structure, dual nature of matter, nuclear physics


Chemistry:


· Physical Chemistry (30-35%): Atomic structure, chemical bonding, thermodynamics, kinetics, equilibrium

· Inorganic Chemistry (25-30%): Periodic table, s-block, p-block, d-block, f-block elements

· Organic Chemistry (30-35%): Hydrocarbons, functional groups, reactions, stereochemistry


Mathematics:


· Algebra (30-35%): Sets, relations, functions, matrices, determinants, complex numbers

· Calculus (25-30%): Limits, derivatives, integrals, differential equations

· Coordinate Geometry (20-25%): Lines, circles, parabolas, ellipses, hyperbolas

· Trigonometry (10-15%): Triangles, trigonometric functions, identities


Most Concentrated Parts:


· Physics: Mechanics, Electromagnetism, and Thermodynamics

· Chemistry: Physical Chemistry, Inorganic Chemistry, and Organic Chemistry

· Mathematics: Algebra, Calculus, and Coordinate Geometry


Important Topics:


· Physics: Newton's laws, work-energy theorem, electric circuits, magnetic fields, optics

· Chemistry: Atomic structure, chemical bonding, acid-base equilibria, redox reactions, organic reactions

· Mathematics: Quadratic equations, functions, limits, derivatives, integrals, matrices


hope this helps,

Thank you

Hello,


Yes, admission to the Indian Statistical Institute (ISI) is possible through JEE Advanced score. ISI considers JEE Advanced scores for admission to its undergraduate programs, including:


1. Bachelor of Statistics (Honours) [B.Stat (Hons)]

2. Bachelor of Mathematics (Honours) [B.Math (Hons)]


To be eligible, you need to:


1. Appear for JEE Advanced and score a minimum qualifying mark.

2. Apply to ISI separately, mentioning your JEE Advanced roll number and score.

3. Meet the cutoff score set by ISI for admission.


hope this helps,

Thank you

View All

 5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C.  If Na2SO4 is 81.5% ionised, the value of x (Kf for water=1.860C kg mol−1) is approximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)
Option: 1  15 g
Option: 2  25 g
Option: 3  45 g
Option: 4  65 g  
 

 50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl.  If pKb of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75
Option: 3 8.25
Option: 4 9.25
 

CH_3-CH=CH-CH_3+Br_2\overset{CCl_4}{\rightarrow}A

What is A?

Option: 1

CH_3-CH(Br)-CH_2-CH_3


Option: 2

CH_3-CH(Br)-CH(Br)-CH_3


Option: 3

CH_3-CH_2-CH_2-CH_2Br


Option: 4

None


\mathrm{NaNO_{3}} when heated gives a white solid A and two gases B and C. B and C are two important atmospheric gases. What is A, B and C ?

Option: 1

\mathrm{A}: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 2

A: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 3

A: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


Option: 4

\mathrm{A}: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


C_1+2 C_2+3 C_3+\ldots .n C_n=

Option: 1

2^n


Option: 2

\text { n. } 2^n


Option: 3

\text { n. } 2^{n-1}


Option: 4

n \cdot 2^{n+1}


 

A capacitor is made of two square plates each of side 'a' making a very small angle \alpha between them, as shown in the figure. The capacitance will be close to : 
Option: 1 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{4 d } \right )

Option: 2 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 + \frac{\alpha a }{4 d } \right )

Option: 3 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{2 d } \right )

Option: 4 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{3 \alpha a }{2 d } \right )
 

 Among the following compounds, the increasing order of their basic strength is
Option: 1  (I) < (II) < (IV) < (III)
Option: 2  (I) < (II) < (III) < (IV)
Option: 3  (II) < (I) < (IV) < (III)
Option: 4  (II) < (I) < (III) < (IV)
 

 An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant.  If during  this process the relation of pressure P and volume V is given by PVn=constant,  then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
Option: 1  n=\frac{C_{p}}{C_{v}}


Option: 2  n=\frac{C-C_{p}}{C-C_{v}}


Option: 3 n=\frac{C_{p}-C}{C-C_{v}}

Option: 4  n=\frac{C-C_{v}}{C-C_{p}}
 

As shown in the figure, a battery of emf \epsilon is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit ) is : 


Option: 1 \frac{\epsilon L }{R^{2}} \left ( 1 - \frac{1}{e} \right )
Option: 2 \frac{\epsilon L }{R^{2}}


Option: 3 \frac{\epsilon R }{eL^{2}}

Option: 4 \frac{\epsilon L }{eR^{2}}
 

As shown in the figure, a particle of mass 10 kg is placed at a point A. When the particle is slightly displaced to its right, it starts moving and reaches the point B. The speed  of the particle at B is x m/s. (Take g = 10 m/s2 ) The value of 'x' to the nearest is ___________.
Option: 1 10
Option: 2 20
Option: 3 40
Option: 4 15

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