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JEE Main 2021 Question Paper PDF with Solutions

JEE Main 2021 Question Paper PDF with Solutions

#JEE Main
Avinash DongreUpdated on 30 Oct 2024, 01:15 PM IST

JEE Main 2021 Question Paper: Candidates preparing for the Joint Entrance Examination 2025 can practise the JEE Main 2021 question paper with solution pdf download. The JEE Main question papers and solutions are available for various sessions, including JEE Main previous question papers covering both shift 1 and shift 2. JEE Main 2021 question papers serve as the best material for candidates who have taken the exam, allowing them to assess their performance, estimate their scores, and tentatively gauge their ranks. The authority conducted the JEE Main exam in two sessions. The link for JEE Main question paper 2021 pdf download is provided on this page. The JEE Main 2021 paper was conducted in four sessions (i.e. February, March, July, and August) while The JEE Main 2019,2020,2022,2023,2024 papers were conducted in 2 sessions.

This Story also Contains

  1. JEE Main 2021 Question Paper with Solutions PDF
  2. JEE Main Sample Paper PDF
  3. Benefits of Solving JEE Main Question Papers 2021
  4. Few Solved Questions from JEE Main 2021 Paper
JEE Main 2021 Question Paper PDF with Solutions
JEE Main 2021 Question Paper PDF with Solutions

JEE Main 2021 Question Paper with Solutions PDF

Aspirants can find the link for the JEE Mains Question Paper 2021 pdf download for all shift question paper pdf with solutions pdf below.

As you can see a total number of 2340 questions are there for practice for candidates which will ultimately be very helpful to understand the JEE main 2025 exam pattern, question types, questions difficulty level etc. Also since the number of questions are very large here so candidates will have access to questions from nearly all the chapters from Physics, Maths and Chemistry subjects.

JEE Main 2021 Question Paper PDF With Solutions July Session

JEE Main 2021 Question Paper PDF by Resonance

JEE Main 2021 Question Paper PDF by Reliable Kota

JEE Main Question Paper 2021

The IIT Question Paper 2021, accessible on this page, is designed for both sessions. Additionally, candidates can access the JEE Main answer key for the question papers provided here. Utilising the JEE Main question paper with solutions, candidates can cross-check their responses following their attempts.

For aspirants gearing up for future exams, the JEE Mains 2021 question paper with solutions pdf offers a valuable window into the exam's format, level of difficulty, and the types of questions typically encountered. Subject matter experts have meticulously provided detailed explanations for each JEE Main 2021 question paper, enhancing their educational value.

The accessibility of JEE Main 2021 Question Paper Solutions in PDF format ensures that these materials are readily available and free to JEE Main 2021 all paper downloads, making them a potent resource for the efficient exam readiness. In essence, JEE Main 2021 Question Paper pdf downloads are indispensable assets for both current and future JEE aspirants, providing them with the necessary tools to excel in this fiercely competitive examination.

For effective preparation for the JEE Main examination, it's imperative for aspirants to thoroughly acquaint themselves with the JEE Main syllabus and exam structure. In addition to studying previous years' JEE Main question papers, candidates are encouraged to seek out the wisdom shared by successful JEE Main toppers and experienced educators. These sources can provide invaluable preparation tips and recommendations on essential reference books. Detailed information about JEE Main 2021 question papers is available in the provided article.

JEE Main Sample Paper PDF

Aspirants preparing for the IIT JEE Main examination are encouraged to practise with sample papers. Engaging with JEE Main sample papers enables candidates to gain insights into the question formats commonly featured in the exam. These sample questions are meticulously crafted to align with the official exam syllabus. You can access the JEE Main sample paper in PDF format via the provided link.

JEE Main Sample Paper

Benefits of Solving JEE Main Question Papers 2021

There are some significant benefits of solving JEE Main 2021 question papers. Here we have mentioned a few of them.

  • Clarity on Question Types: Solving JEE Main 2021 question papers helps students understand the variety and difficulty of questions in the exam.

  • Exam Pattern Familiarity: Going through JEE 2021 papers makes students acquainted with the JEE Main exam pattern and marking scheme.

  • Knowledge Assessment: It serves as a tool to assess their knowledge and readiness for the exam.

  • Skill Enhancement: Practice enhances problem-solving abilities and time management skills.

  • Real-time Experience: provides a real-time feel of the exam environment.

  • Effective Preparation Strategy: Helps in devising an efficient and result-oriented preparation plan.

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Few Solved Questions from JEE Main 2021 Paper

1. (Subject - Physics, Chapter - Current Electricity, Shift - 20 July shift 1)

Question:-

1719990199500

The value of current in the 6\; \Omega resistance is :

  1. 4A

  2. 8A

  3. 10A

  4. 6A

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Answer- 3) 10A

Solution:-

1719990199548

Applying KCL at the junction with voltage x (assigned)

1719990199447

By KCL,

\text{I}_{1}+\text{I}_{2}+\text{I}_{3}= 0

\left(\frac{x-90}{5}\right)+\left(\frac{x-140}{20}\right)+\left(\frac{x-0}{6}\right)=0

\begin{aligned} 24 x-24 \times 90+6 x-6 \times 140+20 x=0 \\ \end{aligned}

\begin{aligned} 50 x &=24 \times 90+6 \times 140 \\ \end{aligned}

\begin{aligned} &=6[4 \times 90+140] \\ \end{aligned}

\begin{aligned} 50 x &=3000 \\ \end{aligned}

\begin{aligned} x &=60 \mathrm{~V} \end{aligned}

Current through 6\; \Omega resistor is

I_{3}=\left(\frac{x-0}{6}\right)=\left(\frac{60-0}{6}\right)=10 \mathrm{~A}

The correct option is (3)

2. (Subject - Maths, Chapter - Integral Calculus, Shift - 27 August Shift 1)

Question:- \int_{6}^{16} \frac{\log _{\mathrm{e}} x^{2}}{\log _{\mathrm{e}} x^{2}+\log _{\mathrm{e}}\left(x^{2}-44 x+484\right)} \mathrm{d} x is equal to:

  1. 5

  2. 10

  3. 8

  4. 6

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Answer- 1) 5

Solution:-

Let\, I= \int_{6}^{16}\frac{\log_{e} x^{2} }{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx ---\left ( 1 \right )

Using properties of Integral

I= \int_{6}^{16}\frac{\log_{e} \left ( 6+16-x \right )^{2}}{\log_{e}\left ( 6+16-x \right )^{2}+\log_{e}\left ( 22-\left ( 6+16-x \right ) \right )^{2}}dx

\Rightarrow I= \int_{6}^{16}\frac{\log_{e} \left ( 22-x \right )^{2}}{\log_{e}\left ( 22-x \right )^{2}+\log_{e}x^{2}}dx---\left ( 2 \right )

Adding (1) and (2)

2I= \int_{6}^{16}\frac{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx

\Rightarrow 2I= \int_{6}^{16}dx= 10

\Rightarrow I= 5

Hence, the answer is the option 1.

3. (Subject - Chemistry, Chapter - Equilibrium, Shift - 31 August Shift 1)

Question:-

\mathrm{A}_{3} \mathrm{~B}_{2} is a sparingly soluble salt of molar mass \mathrm{M (g\ mol^{-1})} and solubility x \mathrm{~g} \mathrm{}^{-1}. The solubility product satisfies \mathrm{K}_{\mathrm{sp}}=a\left(\frac{x}{\mathrm{M}}\right)^{5}. The value of a is __________. (Integer answer)

Answer- (108)

Solution:-

Given,

\mathrm{solubility\, of\, A_{3}B_{2}}= x\ \mathrm{gL^{-1}}

\mathrm{\therefore solubility\, in\,\frac{moles}{lit}= \left ( \frac{x}{M} \right )\, mol\, L^{-1}}

{\therefore \mathrm{s}= \left ( \frac{x}{\mathrm{M}} \right )}

Now, \mathrm{ A_{3}B_{2}} dissolves as

\mathrm{A_{3}B_{2}\rightleftharpoons 3A^{2+}+2B^{3-}}

\quad - \quad\quad\quad 3s\quad\quad\quad2s

Expression for solubility product gives us

\mathrm{\therefore K_{sp}= \left ( 3s \right )^{3}\left ( 2s \right )^{2}} \mathrm{=108 \, s^{5}} \mathrm{=108 \left ( \frac{x}{M} \right )^{5}}

Hence, the answer is (108).

Frequently Asked Questions (FAQs)

Q: What is the mode of examination for JEE Main 2025?
A:

JEE Main 2025 is conducted online as a computer-based test. While Paper-1 is entirely computer-based, Paper-2 includes computer-based Mathematics and Aptitude sections, along with a pen-and-paper-based Drawing exam.

Q: Could you explain the exam pattern for JEE Main 2025?
A:

The exam pattern for JEE Main 2025 consists of a total of 75 questions (i.e. 25 questions each in Physics, Maths and Chemistry), with candidates required to attempt all 75 questions. Each subject consists of 2 sections (i.e. Section A with 20 MCQs and Section B with 5 questions whose answers are to be filled in as a numerical value). In Section B candidates have to attempt all 5 questions.

Q: What types of questions can I anticipate in JEE Main 2025?
A:

JEE Main 2025 question paper primarily comprises 2 types of questions i.e. 1. Multiple-choice type questions and 2. Questions whose answers are to be filled in as a numerical value covering the subjects of Physics, Chemistry, and Mathematics.

Q: Has the NTA modified the syllabus for JEE Main 2025?
A:

Yes, the syllabus for JEE Main 2025 has changed from the previous year.

Q: In what languages is the JEE Main question paper available?
A:

The JEE Main question paper is available in a bilingual medium, encompassing 13 different languages, including Hindi, Urdu, Bengali, Gujarati, and more.

Q: Do I need to attempt all the questions in each section of the JEE Main?
A:

Yes, all the questions in 2025 are compulsory. For each subject, In Section A candidates can attempt all 20 questions and in Section B candidates also attempt all 5 questions.

Q: What are the advantages of practising previous years' JEE Main question papers?
A:

Solving previous years' question papers can help candidates grasp the exam pattern, identify important topics, assess areas of weakness, and enhance speed and accuracy in answering questions.

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OBC RANK 173160 on JEE MAIN ON YEAR NTA SCORE 68.4122869. CRL 476199. ADMISSION POSSIBLE CIVIL BRANCH INDIRA GANDHI INSTITUTE SARANG, ODISHA POSSIBLE OR NOT.

With your JEE Main CRL 476199 and OBC rank 173160, admission to Civil Engineering at Indira Gandhi Institute of Technology (IGIT), Sarang under JoSAA counseling is highly unlikely, since even civil branch closing ranks in IGIT usually remain within 50k–80k CRL (general) and much lower for OBC. However, you may try through state counseling (Odisha JEE) where cutoffs are sometimes more flexible, but chances are still very low. You should keep other private/state colleges as backup.

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Rithwik Kumar Sahu
29 Aug'25
1L rank in jee main which college is admission in less fee and good education please reply

Hey! With a JEE Main rank of around 1 lakh, you still have a good chance to get admission in several engineering colleges that provide quality education at a reasonable fee. For government colleges, you can aim for NITs or GFTIs in branches like Civil, Mechanical, or Chemical Engineering, as these usually have slightly higher closing ranks. For example, colleges like NIT Goa, NIT Puducherry, and NIT Srinagar might have seats available in certain branches.


Apart from NITs, state government engineering colleges are also a good option, especially under home state quota. They often have lower tuition fees and good faculty, so you can get a solid education without spending much.


If you are open to private colleges, there are options like VIT Vellore, KIIT Bhubaneswar, or Amity University that provide decent infrastructure and placements. However, the fees may be higher than government colleges.


My advice is to focus on branches that are less competitive, check all counseling rounds, and make use of state quotas if applicable. With proper planning, a rank of 1 lakh can still help you get a good college and start your engineering career success

fully.

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Ankur Mehta
29 Aug'25
can you use previous year jee rank in current year wbjee counselling?

No, you can’t use a previous year’s JEE rank for the current year’s WBJEE counselling. Only the JEE Main rank of the same admission year is valid along with that year’s WBJEE rank.

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Rithwik Kumar Sahu
29 Aug'25
Jee exam centres and coaching centres in bangalore near whitefield

Hello Aspirant,

Finding specific JEE exam centers for Whitefield is difficult as they vary each year. The list is released on the admit card . However, many centers are usually iON Digital Zones. For coaching, top centers near Whitefield include Aakash Institute , Narayana Institute , and Allen Career Institute . These centers have branches in and around the Whitefield area to help you prepare for the exam.

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SHUBHRADIP ROY
28 Aug'25
I got 60 percent in class 12 I wanted to do btech, I am now confused that should I take admission in private college (Shri ram Swaroop college) or take drop and give JEE for admission in IET Lucknow . I missed both the JEE attempts of 2025?

Its okay if you missed jee this year you can drop year for JEE to get into a government institute like IET Lucknow to get better placement here and fees is also less in comparison with SRMU but it also means delaying a year with no guarantee success.

Joining a private college like SRMU now avoids losing a year,but it comes with higher costs and generally lower placement statistics compared to top government institutions.

ultimately Your decision should be based on your skill whether you can significantly improve your JEE score versus accepting a faster, but potentially more expensive, path to your B.Tech.

Hope it helps..

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sadafreen356
28 Aug'25
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