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    JEE Main 2021 Question Paper PDF with Solutions

    JEE Main 2021 Question Paper PDF with Solutions

    #JEE Main
    Simran KashyapUpdated on 09 Apr 2026, 02:35 PM IST

    JEE Main 2021 Question Paper: Applicants appearing for the JEE Main exam can check the JEE Main 2021 question paper with the solution PDF download link here in this article. The JEE Main question paper PDF 2021 helps students to assess their performance, estimate their scores, and tentatively gauge their ranks. The question paper for JEE Main 2021 is important sources material for preparation for the upcoming JEE Main exam. Candidates can find the JEE Main question papers and solutions for both the sessions and previous year questions with oultions PDF. The authority conducted the JEE Main exam in four sessions in 2021. Due to the COVID pandemic, the JEE Main 2021 paper was conducted in four sessions (i.e. February, March, July, and August).

    This Story also Contains

    1. JEE Main 2021 Question Paper with Solutions PDF
    2. JEE Main Sample Paper PDF
    3. Benefits of Solving JEE Main Question Papers 2021
    4. Few Solved Questions from JEE Main 2021 Paper
    JEE Main 2021 Question Paper PDF with Solutions
    JEE Main 2021 Question Paper PDF with Solutions

    JEE Main 2021 Question Paper with Solutions PDF

    Applicants looking for the JEE Main Question Paper 2021 PDF download for all shift question paper PDFs with solutions PDFs can check the table below:

    The question PDFs has a total of 2340 questions for practice for applicants. This will help candidates to analyse the exam pattern, key focus topics, time-management, and others. This consists questions from all the sections of Physics, Maths, and Chemistry.

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    JEE Main Question Paper 2021

    The IIT JEE question paper 2021 is mentioned here in this article. Candidate ca access the link for the JEE Main 2021 question paper PDF in this article. Students can also check the JEE Main answer key for all the question papers given here. The JEE Main question paper 2021 with solutions will help candidates to cross-check their answers. Aspirants appearing for the upcoming JEE Main exam usually solves JEE Mains 2021 question paper with solutions to get a idea of the level of difficulty exams, question types, and others.

    The JEE Main 2021 question paper solutions is made available in the PDF format for free. Candidates should prepare using the JEE Main syllabus and exam structure for effective preparation for the JEE Main examination .These sources can provide invaluable preparation tips and recommendations on essential reference books. Detailed information about JEE Main 2021 question papers is available in the provided article.

    Previous Year’s JEE Main PYQ with Solutions

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    JEE Main Sample Paper PDF

    Applicants giving the IIT JEE Main exam should also solve and practice sample papers. The sample papers for the JEE Main exam uusally helps candidates to understand the exam pattern, difficulty questions,time-solving, and others. The sample papers are carefully aligned with the JEE Main syllabus. Candidates can download the JEE Main sample paper in PDF format in the link below.

    JEE Main Sample Paper


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    JEE Main Paper 1

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    Benefits of Solving JEE Main Question Papers 2021

    Below are some of the advantages for solving the JEE Main 2021 question papers. Candidates can check some of them from below:

    • Clarity on Question Types: Solving JEE Main 2021 question papers helps candidates to analyse the question types, weighatage, key topics, and difficulty of questions in the exam.

    • Understanding the Exam Pattern: Solving the IIT JEE 2021 question papers makes students familiar with the JEE Main exam pattern and marking scheme.

    • Knowledge Assessment: It serves as a tool to gain their knowledge about weightage and time-management.

    • Skill Enhancement: Practice enhances problem-solving abilities and time management skills.

    • Real-time Experience: provides a real-time feel of the exam environment with management of time within solving questions.

    • Effective Preparation Strategy: Helps in devising an efficient and result-oriented preparation plan.

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    Few Solved Questions from JEE Main 2021 Paper

    1. (Subject - Physics, Chapter - Current Electricity, Shift - 20 July shift 1)

    Question:-

    1719990199500

    The value of current in the 6\; \Omega resistance is :

    1. 4A

    2. 8A

    3. 10A

    4. 6A

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    Answer- 3) 10A

    Solution:-

    1719990199548

    Applying KCL at the junction with voltage x (assigned)

    1719990199447

    By KCL,

    \text{I}_{1}+\text{I}_{2}+\text{I}_{3}= 0

    \left(\frac{x-90}{5}\right)+\left(\frac{x-140}{20}\right)+\left(\frac{x-0}{6}\right)=0

    \begin{aligned} 24 x-24 \times 90+6 x-6 \times 140+20 x=0 \\ \end{aligned}

    \begin{aligned} 50 x &=24 \times 90+6 \times 140 \\ \end{aligned}

    \begin{aligned} &=6[4 \times 90+140] \\ \end{aligned}

    \begin{aligned} 50 x &=3000 \\ \end{aligned}

    \begin{aligned} x &=60 \mathrm{~V} \end{aligned}

    Current through 6\; \Omega resistor is

    I_{3}=\left(\frac{x-0}{6}\right)=\left(\frac{60-0}{6}\right)=10 \mathrm{~A}

    The correct option is (3)

    2. (Subject - Maths, Chapter - Integral Calculus, Shift - 27 August Shift 1)

    Question:- \int_{6}^{16} \frac{\log _{\mathrm{e}} x^{2}}{\log _{\mathrm{e}} x^{2}+\log _{\mathrm{e}}\left(x^{2}-44 x+484\right)} \mathrm{d} x is equal to:

    1. 5

    2. 10

    3. 8

    4. 6

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    Answer- 1) 5

    Solution:-

    Let\, I= \int_{6}^{16}\frac{\log_{e} x^{2} }{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx ---\left ( 1 \right )

    Using properties of Integral

    I= \int_{6}^{16}\frac{\log_{e} \left ( 6+16-x \right )^{2}}{\log_{e}\left ( 6+16-x \right )^{2}+\log_{e}\left ( 22-\left ( 6+16-x \right ) \right )^{2}}dx

    \Rightarrow I= \int_{6}^{16}\frac{\log_{e} \left ( 22-x \right )^{2}}{\log_{e}\left ( 22-x \right )^{2}+\log_{e}x^{2}}dx---\left ( 2 \right )

    Adding (1) and (2)

    2I= \int_{6}^{16}\frac{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx

    \Rightarrow 2I= \int_{6}^{16}dx= 10

    \Rightarrow I= 5

    Hence, the answer is the option 1.

    3. (Subject - Chemistry, Chapter - Equilibrium, Shift - 31 August Shift 1)

    Question:-

    \mathrm{A}_{3} \mathrm{~B}_{2} is a sparingly soluble salt of molar mass \mathrm{M (g\ mol^{-1})} and solubility x \mathrm{~g} \mathrm{}^{-1}. The solubility product satisfies \mathrm{K}_{\mathrm{sp}}=a\left(\frac{x}{\mathrm{M}}\right)^{5}. The value of a is __________. (Integer answer)

    Answer- (108)

    Solution:-

    Given,

    \mathrm{solubility\, of\, A_{3}B_{2}}= x\ \mathrm{gL^{-1}}

    \mathrm{\therefore solubility\, in\,\frac{moles}{lit}= \left ( \frac{x}{M} \right )\, mol\, L^{-1}}

    {\therefore \mathrm{s}= \left ( \frac{x}{\mathrm{M}} \right )}

    Now, \mathrm{ A_{3}B_{2}} dissolves as

    \mathrm{A_{3}B_{2}\rightleftharpoons 3A^{2+}+2B^{3-}}

    \quad - \quad\quad\quad 3s\quad\quad\quad2s

    Expression for solubility product gives us

    \mathrm{\therefore K_{sp}= \left ( 3s \right )^{3}\left ( 2s \right )^{2}} \mathrm{=108 \, s^{5}} \mathrm{=108 \left ( \frac{x}{M} \right )^{5}}

    Hence, the answer is (108).

    JEE Main Syllabus: Subjects & Chapters
    Select your preferred subject to view the chapters

    Frequently Asked Questions (FAQs)

    Q: What is the mode of examination for JEE Main?
    A:

    JEE Main is conducted online as a computer-based test. While Paper-1 is entirely computer-based, Paper-2 includes computer-based Mathematics and Aptitude sections, along with a pen-and-paper-based Drawing exam.

    Q: Could you explain the exam pattern for JEE Main?
    A:

    The exam pattern for JEE Main consists of a total of 75 questions (i.e. 25 questions each in Physics, Maths and Chemistry), with candidates required to attempt all 75 questions. Each subject consists of 2 sections (i.e. Section A with 20 MCQs and Section B with 5 questions whose answers are to be filled in as a numerical value). In Section B candidates have to attempt all 5 questions.

    Q: What types of questions can I anticipate in JEE Main?
    A:

    JEE Main question paper primarily comprises 2 types of questions i.e. 1. Multiple-choice type questions and 2. Questions whose answers are to be filled in as a numerical value covering the subjects of Physics, Chemistry, and Mathematics.

    Q: Has the NTA modified the syllabus for JEE Main?
    A:

    Yes, the syllabus for JEE Main has changed from the previous year.

    Q: In what languages is the JEE Main question paper available?
    A:

    The JEE Main question paper is available in a bilingual medium, encompassing 13 different languages, including Hindi, Urdu, Bengali, Gujarati, and more.

    Q: Do I need to attempt all the questions in each section of the JEE Main?
    A:

    Yes, all the questions are compulsory. For each subject, In Section A candidates can attempt all 20 questions and in Section B candidates also attempt all 5 questions.

    Q: What are the advantages of practising previous years' JEE Main question papers?
    A:

    Solving previous years' question papers can help candidates grasp the exam pattern, identify important topics, assess areas of weakness, and enhance speed and accuracy in answering questions.

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    Hello Dear Student,
    With 190 marks in JEE Advanced, getting a Computer Science and Engineering (CSE) branch in top or older IITs is generally not possible for general category students, but you may get CSE in some newer or lower-generation IITs (like IIT Ropar or similar newer peers) or good

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    Hello Dear Student,

    Yes, NIOS is a valid board for JEE Main, JEE Advanced, and JoSAA. However, in your specific case , you cannot simply improve only 2 subjects in NIOS and combine those marks with your 2026 CG Board marksheet to satisfy the 75% criterion.

    For admission through JoSAA/IITs/NITs:

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    Samyak Jain
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    my WB JEE rank GMR is 36007/SC category rank 3907 I don't allotted any government engineering seats in 2nd round counselling will I get any government engineering college ECE mechanical EE branch in 3rd round because cut off is so high in round 1 and 2

    Hello Dear Student,
    With a GMR of 36,007 and an SC rank of 3,907, your chances of securing a core branch (ECE, EE, or Mechanical) in top-tier government engineering colleges like JU or KGEC are very low, as these fill up much earlier. However, you have moderate to high chances

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    How much suitable chances for NiTs, IITs GFTIs to get admission in core branch CSE / ECE on behalf of my jee mains CRL-92133 2026 under EWS category in csab counseling ?

    Hello Student,

    Based on the details you shared, your JEE Mains 2026 CRL rank is around 92,133 under the EWS category, and you are aiming for CSE/ECE in NITs, IIITs or GFTIS through CSAB counselling.

    With this ranking your chances are:

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    King Singh
    23 Jul'26
    how hectic is life in vit chennai as 1st year ece.is it stressful.should I spend 4 to 5 hrs daily if I am an avg understanding person.Considering a lot of jee people here (myself 95)....my roommates are having a lot...with regards of cgpa am pretty sure I am cooked.pleae guide me.

    Hello Student,

    First of all YOU are not cooked; considering your JEE Main percentile, you have a good foundation and might not need to study 4-5 hours if you pay attention in class and ask and clear your doubts. In the first year, though. There will be continuous assessments, lab

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