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JEE Main 2021 Question Paper PDF with Solutions

JEE Main 2021 Question Paper PDF with Solutions

#JEE Main
Avinash DongreUpdated on 08 Dec 2025, 05:29 PM IST

JEE Main 2021 Question Paper: Candidates can check the JEE Main 2021 question paper with the solution PDF download link here. The JEE Main question paper PDF 2021 serve as the best material for candidates who have taken the exam, allowing them to assess their performance, estimate their scores, and tentatively gauge their ranks. Further, the JEE Main 2021 question papers also serve as a useful source of material for candidates preparing for the upcoming JEE Main exam. The JEE Main question papers and solutions are available for various sessions, including JEE Main previous question papers covering both shift 1 and shift 2 in this article. The authority conducted the JEE Main exam in four sessions in 2021. Due to the COVID pandemic, the JEE Main 2021 paper was conducted in four sessions (i.e. February, March, July, and August).

This Story also Contains

  1. JEE Main 2021 Question Paper with Solutions PDF
  2. JEE Main Sample Paper PDF
  3. Benefits of Solving JEE Main Question Papers 2021
  4. Few Solved Questions from JEE Main 2021 Paper
JEE Main 2021 Question Paper PDF with Solutions
JEE Main 2021 Question Paper PDF with Solutions

JEE Main 2021 Question Paper with Solutions PDF

Aspirants can find the link for the JEE Mains Question Paper 2021 PDF download for all shift question paper PDFs with solutions PDFs below.

As you can see a total number of 2340 questions are there for practice for candidates which will ultimately be very helpful to understand the JEE main 2025 exam pattern, question types, questions difficulty level etc. Also since the number of questions are very large here so candidates will have access to questions from nearly all the chapters from Physics, Maths and Chemistry subjects.

JEE Main 2021 Question Paper PDF With Solutions July Session

JEE Main 2021 Question Paper PDF by Resonance

JEE Main 2021 Question Paper PDF by Reliable Kota

JEE Main Question Paper 2021

The IIT Question Paper 2021, accessible on this page, is designed for both sessions. Additionally, candidates can access the JEE Main answer key for the question papers provided here. Utilising the JEE Main question paper with solutions, candidates can cross-check their responses following their attempts.

For aspirants gearing up for future exams, the JEE Mains 2021 question paper with solutions PDF offers a valuable window into the exam's format, level of difficulty, and the types of questions typically encountered. Subject matter experts have meticulously provided detailed explanations for each JEE Main 2021 question paper, enhancing their educational value.

The accessibility of JEE Main 2021 Question Paper Solutions in PDF format ensures that these materials are readily available and free to JEE Main 2021 paper download, making them a potent resource for efficient exam readiness. In essence, JEE Main 2021 Question Paper pdf downloads are indispensable assets for both current and future JEE aspirants, providing them with the necessary tools to excel in this fiercely competitive examination.

For effective preparation for the JEE Main examination, it's imperative for aspirants to thoroughly acquaint themselves with the JEE Main syllabus and exam structure. In addition to studying previous years' JEE Main question papers, candidates are encouraged to seek out the wisdom shared by successful JEE Main toppers and experienced educators. These sources can provide invaluable preparation tips and recommendations on essential reference books. Detailed information about JEE Main 2021 question papers is available in the provided article.

JEE Main Sample Paper PDF

Aspirants preparing for the IIT JEE Main examination are encouraged to practise with sample papers. Engaging with JEE Main sample papers enables candidates to gain insights into the question formats commonly featured in the exam. These sample questions are meticulously crafted to align with the official exam syllabus. You can access the JEE Main sample paper in PDF format via the provided link.

JEE Main Sample Paper

JEE Main Paper 1

JEE Main Paper 2

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Benefits of Solving JEE Main Question Papers 2021

There are some significant benefits of solving JEE Main 2021 question papers. Here we have mentioned a few of them.

  • Clarity on Question Types: Solving JEE Main 2021 question papers helps students understand the variety and difficulty of questions in the exam.

  • Exam Pattern Familiarity: Going through JEE 2021 papers makes students acquainted with the JEE Main exam pattern and marking scheme.

  • Knowledge Assessment: It serves as a tool to assess their knowledge and readiness for the exam.

  • Skill Enhancement: Practice enhances problem-solving abilities and time management skills.

  • Real-time Experience: provides a real-time feel of the exam environment.

  • Effective Preparation Strategy: Helps in devising an efficient and result-oriented preparation plan.

Few Solved Questions from JEE Main 2021 Paper

1. (Subject - Physics, Chapter - Current Electricity, Shift - 20 July shift 1)

Question:-

1719990199500

The value of current in the 6\; \Omega resistance is :

  1. 4A

  2. 8A

  3. 10A

  4. 6A

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Answer- 3) 10A

Solution:-

1719990199548

Applying KCL at the junction with voltage x (assigned)

1719990199447

By KCL,

\text{I}_{1}+\text{I}_{2}+\text{I}_{3}= 0

\left(\frac{x-90}{5}\right)+\left(\frac{x-140}{20}\right)+\left(\frac{x-0}{6}\right)=0

\begin{aligned} 24 x-24 \times 90+6 x-6 \times 140+20 x=0 \\ \end{aligned}

\begin{aligned} 50 x &=24 \times 90+6 \times 140 \\ \end{aligned}

\begin{aligned} &=6[4 \times 90+140] \\ \end{aligned}

\begin{aligned} 50 x &=3000 \\ \end{aligned}

\begin{aligned} x &=60 \mathrm{~V} \end{aligned}

Current through 6\; \Omega resistor is

I_{3}=\left(\frac{x-0}{6}\right)=\left(\frac{60-0}{6}\right)=10 \mathrm{~A}

The correct option is (3)

2. (Subject - Maths, Chapter - Integral Calculus, Shift - 27 August Shift 1)

Question:- \int_{6}^{16} \frac{\log _{\mathrm{e}} x^{2}}{\log _{\mathrm{e}} x^{2}+\log _{\mathrm{e}}\left(x^{2}-44 x+484\right)} \mathrm{d} x is equal to:

  1. 5

  2. 10

  3. 8

  4. 6

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Answer- 1) 5

Solution:-

Let\, I= \int_{6}^{16}\frac{\log_{e} x^{2} }{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx ---\left ( 1 \right )

Using properties of Integral

I= \int_{6}^{16}\frac{\log_{e} \left ( 6+16-x \right )^{2}}{\log_{e}\left ( 6+16-x \right )^{2}+\log_{e}\left ( 22-\left ( 6+16-x \right ) \right )^{2}}dx

\Rightarrow I= \int_{6}^{16}\frac{\log_{e} \left ( 22-x \right )^{2}}{\log_{e}\left ( 22-x \right )^{2}+\log_{e}x^{2}}dx---\left ( 2 \right )

Adding (1) and (2)

2I= \int_{6}^{16}\frac{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx

\Rightarrow 2I= \int_{6}^{16}dx= 10

\Rightarrow I= 5

Hence, the answer is the option 1.

3. (Subject - Chemistry, Chapter - Equilibrium, Shift - 31 August Shift 1)

Question:-

\mathrm{A}_{3} \mathrm{~B}_{2} is a sparingly soluble salt of molar mass \mathrm{M (g\ mol^{-1})} and solubility x \mathrm{~g} \mathrm{}^{-1}. The solubility product satisfies \mathrm{K}_{\mathrm{sp}}=a\left(\frac{x}{\mathrm{M}}\right)^{5}. The value of a is __________. (Integer answer)

Answer- (108)

Solution:-

Given,

\mathrm{solubility\, of\, A_{3}B_{2}}= x\ \mathrm{gL^{-1}}

\mathrm{\therefore solubility\, in\,\frac{moles}{lit}= \left ( \frac{x}{M} \right )\, mol\, L^{-1}}

{\therefore \mathrm{s}= \left ( \frac{x}{\mathrm{M}} \right )}

Now, \mathrm{ A_{3}B_{2}} dissolves as

\mathrm{A_{3}B_{2}\rightleftharpoons 3A^{2+}+2B^{3-}}

\quad - \quad\quad\quad 3s\quad\quad\quad2s

Expression for solubility product gives us

\mathrm{\therefore K_{sp}= \left ( 3s \right )^{3}\left ( 2s \right )^{2}} \mathrm{=108 \, s^{5}} \mathrm{=108 \left ( \frac{x}{M} \right )^{5}}

Hence, the answer is (108).

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Frequently Asked Questions (FAQs)

Q: What is the mode of examination for JEE Main?
A:

JEE Main is conducted online as a computer-based test. While Paper-1 is entirely computer-based, Paper-2 includes computer-based Mathematics and Aptitude sections, along with a pen-and-paper-based Drawing exam.

Q: Could you explain the exam pattern for JEE Main?
A:

The exam pattern for JEE Main consists of a total of 75 questions (i.e. 25 questions each in Physics, Maths and Chemistry), with candidates required to attempt all 75 questions. Each subject consists of 2 sections (i.e. Section A with 20 MCQs and Section B with 5 questions whose answers are to be filled in as a numerical value). In Section B candidates have to attempt all 5 questions.

Q: What types of questions can I anticipate in JEE Main?
A:

JEE Main question paper primarily comprises 2 types of questions i.e. 1. Multiple-choice type questions and 2. Questions whose answers are to be filled in as a numerical value covering the subjects of Physics, Chemistry, and Mathematics.

Q: Has the NTA modified the syllabus for JEE Main?
A:

Yes, the syllabus for JEE Main has changed from the previous year.

Q: Do I need to attempt all the questions in each section of the JEE Main?
A:

Yes, all the questions are compulsory. For each subject, In Section A candidates can attempt all 20 questions and in Section B candidates also attempt all 5 questions.

Q: In what languages is the JEE Main question paper available?
A:

The JEE Main question paper is available in a bilingual medium, encompassing 13 different languages, including Hindi, Urdu, Bengali, Gujarati, and more.

Q: What are the advantages of practising previous years' JEE Main question papers?
A:

Solving previous years' question papers can help candidates grasp the exam pattern, identify important topics, assess areas of weakness, and enhance speed and accuracy in answering questions.

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Usha Mittal of Technology has no AI quota officially. please contact the college for any mangement quota seats.

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99.132 percentile in jee mains jan 2026. Any chance to get ECE in NIT SURATKAL general female pool with karnataka homestate

decent chances actually as home state quota seats are 50%. allotments will depend on the JEE rank and not percentile though. in 2025, for female supernumerary it closed at 9286  rank while for open gen it closed at 5573.

So, would advise to use this tool to check the probable

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25 Feb'26
i have paid jee mains fee twice.... 1st time amount was debited but not updated in application form... 2nd time i paid it was updated... so will i get my money back?

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Check out https://engineering.careers360.com/jee-main-rank-predictor to know the probable rank

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24 Feb'26
i got 47 percentile in jee mains which college i can get in pune

Hi Smita Sharma,

With 47 percentile in JEE Mains 2026, you might get rank around 7,00,000 plus which is very high. Check the link below for the Best engineering colleges available for you based on yours percentile.

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Link 2: https://engineering.careers360.com/colleges/list-of-private-engineering-colleges-in-pune-accepting-jee-main

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