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    JEE Main 2021 Question Paper PDF with Solutions

    JEE Main 2021 Question Paper PDF with Solutions

    #JEE Main
    Simran KashyapUpdated on 09 Apr 2026, 02:35 PM IST

    JEE Main 2021 Question Paper: Applicants appearing for the JEE Main exam can check the JEE Main 2021 question paper with the solution PDF download link here in this article. The JEE Main question paper PDF 2021 helps students to assess their performance, estimate their scores, and tentatively gauge their ranks. The question paper for JEE Main 2021 is important sources material for preparation for the upcoming JEE Main exam. Candidates can find the JEE Main question papers and solutions for both the sessions and previous year questions with oultions PDF. The authority conducted the JEE Main exam in four sessions in 2021. Due to the COVID pandemic, the JEE Main 2021 paper was conducted in four sessions (i.e. February, March, July, and August).

    This Story also Contains

    1. JEE Main 2021 Question Paper with Solutions PDF
    2. JEE Main Sample Paper PDF
    3. Benefits of Solving JEE Main Question Papers 2021
    4. Few Solved Questions from JEE Main 2021 Paper
    JEE Main 2021 Question Paper PDF with Solutions
    JEE Main 2021 Question Paper PDF with Solutions

    JEE Main 2021 Question Paper with Solutions PDF

    Applicants looking for the JEE Main Question Paper 2021 PDF download for all shift question paper PDFs with solutions PDFs can check the table below:

    The question PDFs has a total of 2340 questions for practice for applicants. This will help candidates to analyse the exam pattern, key focus topics, time-management, and others. This consists questions from all the sections of Physics, Maths, and Chemistry.

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    JEE Main Question Paper 2021

    The IIT JEE question paper 2021 is mentioned here in this article. Candidate ca access the link for the JEE Main 2021 question paper PDF in this article. Students can also check the JEE Main answer key for all the question papers given here. The JEE Main question paper 2021 with solutions will help candidates to cross-check their answers. Aspirants appearing for the upcoming JEE Main exam usually solves JEE Mains 2021 question paper with solutions to get a idea of the level of difficulty exams, question types, and others.

    The JEE Main 2021 question paper solutions is made available in the PDF format for free. Candidates should prepare using the JEE Main syllabus and exam structure for effective preparation for the JEE Main examination .These sources can provide invaluable preparation tips and recommendations on essential reference books. Detailed information about JEE Main 2021 question papers is available in the provided article.

    Previous Year’s JEE Main PYQ with Solutions

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    JEE Main Sample Paper PDF

    Applicants giving the IIT JEE Main exam should also solve and practice sample papers. The sample papers for the JEE Main exam uusally helps candidates to understand the exam pattern, difficulty questions,time-solving, and others. The sample papers are carefully aligned with the JEE Main syllabus. Candidates can download the JEE Main sample paper in PDF format in the link below.

    JEE Main Sample Paper


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    JEE Main Paper 1

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    Benefits of Solving JEE Main Question Papers 2021

    Below are some of the advantages for solving the JEE Main 2021 question papers. Candidates can check some of them from below:

    • Clarity on Question Types: Solving JEE Main 2021 question papers helps candidates to analyse the question types, weighatage, key topics, and difficulty of questions in the exam.

    • Understanding the Exam Pattern: Solving the IIT JEE 2021 question papers makes students familiar with the JEE Main exam pattern and marking scheme.

    • Knowledge Assessment: It serves as a tool to gain their knowledge about weightage and time-management.

    • Skill Enhancement: Practice enhances problem-solving abilities and time management skills.

    • Real-time Experience: provides a real-time feel of the exam environment with management of time within solving questions.

    • Effective Preparation Strategy: Helps in devising an efficient and result-oriented preparation plan.

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    Few Solved Questions from JEE Main 2021 Paper

    1. (Subject - Physics, Chapter - Current Electricity, Shift - 20 July shift 1)

    Question:-

    1719990199500

    The value of current in the 6\; \Omega resistance is :

    1. 4A

    2. 8A

    3. 10A

    4. 6A

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    Answer- 3) 10A

    Solution:-

    1719990199548

    Applying KCL at the junction with voltage x (assigned)

    1719990199447

    By KCL,

    \text{I}_{1}+\text{I}_{2}+\text{I}_{3}= 0

    \left(\frac{x-90}{5}\right)+\left(\frac{x-140}{20}\right)+\left(\frac{x-0}{6}\right)=0

    \begin{aligned} 24 x-24 \times 90+6 x-6 \times 140+20 x=0 \\ \end{aligned}

    \begin{aligned} 50 x &=24 \times 90+6 \times 140 \\ \end{aligned}

    \begin{aligned} &=6[4 \times 90+140] \\ \end{aligned}

    \begin{aligned} 50 x &=3000 \\ \end{aligned}

    \begin{aligned} x &=60 \mathrm{~V} \end{aligned}

    Current through 6\; \Omega resistor is

    I_{3}=\left(\frac{x-0}{6}\right)=\left(\frac{60-0}{6}\right)=10 \mathrm{~A}

    The correct option is (3)

    2. (Subject - Maths, Chapter - Integral Calculus, Shift - 27 August Shift 1)

    Question:- \int_{6}^{16} \frac{\log _{\mathrm{e}} x^{2}}{\log _{\mathrm{e}} x^{2}+\log _{\mathrm{e}}\left(x^{2}-44 x+484\right)} \mathrm{d} x is equal to:

    1. 5

    2. 10

    3. 8

    4. 6

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    Answer- 1) 5

    Solution:-

    Let\, I= \int_{6}^{16}\frac{\log_{e} x^{2} }{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx ---\left ( 1 \right )

    Using properties of Integral

    I= \int_{6}^{16}\frac{\log_{e} \left ( 6+16-x \right )^{2}}{\log_{e}\left ( 6+16-x \right )^{2}+\log_{e}\left ( 22-\left ( 6+16-x \right ) \right )^{2}}dx

    \Rightarrow I= \int_{6}^{16}\frac{\log_{e} \left ( 22-x \right )^{2}}{\log_{e}\left ( 22-x \right )^{2}+\log_{e}x^{2}}dx---\left ( 2 \right )

    Adding (1) and (2)

    2I= \int_{6}^{16}\frac{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}{\log_{e}x^{2}+\log_{e}\left ( 22-x \right )^{2}}dx

    \Rightarrow 2I= \int_{6}^{16}dx= 10

    \Rightarrow I= 5

    Hence, the answer is the option 1.

    3. (Subject - Chemistry, Chapter - Equilibrium, Shift - 31 August Shift 1)

    Question:-

    \mathrm{A}_{3} \mathrm{~B}_{2} is a sparingly soluble salt of molar mass \mathrm{M (g\ mol^{-1})} and solubility x \mathrm{~g} \mathrm{}^{-1}. The solubility product satisfies \mathrm{K}_{\mathrm{sp}}=a\left(\frac{x}{\mathrm{M}}\right)^{5}. The value of a is __________. (Integer answer)

    Answer- (108)

    Solution:-

    Given,

    \mathrm{solubility\, of\, A_{3}B_{2}}= x\ \mathrm{gL^{-1}}

    \mathrm{\therefore solubility\, in\,\frac{moles}{lit}= \left ( \frac{x}{M} \right )\, mol\, L^{-1}}

    {\therefore \mathrm{s}= \left ( \frac{x}{\mathrm{M}} \right )}

    Now, \mathrm{ A_{3}B_{2}} dissolves as

    \mathrm{A_{3}B_{2}\rightleftharpoons 3A^{2+}+2B^{3-}}

    \quad - \quad\quad\quad 3s\quad\quad\quad2s

    Expression for solubility product gives us

    \mathrm{\therefore K_{sp}= \left ( 3s \right )^{3}\left ( 2s \right )^{2}} \mathrm{=108 \, s^{5}} \mathrm{=108 \left ( \frac{x}{M} \right )^{5}}

    Hence, the answer is (108).

    JEE Main Syllabus: Subjects & Chapters
    Select your preferred subject to view the chapters

    Frequently Asked Questions (FAQs)

    Q: What is the mode of examination for JEE Main?
    A:

    JEE Main is conducted online as a computer-based test. While Paper-1 is entirely computer-based, Paper-2 includes computer-based Mathematics and Aptitude sections, along with a pen-and-paper-based Drawing exam.

    Q: Could you explain the exam pattern for JEE Main?
    A:

    The exam pattern for JEE Main consists of a total of 75 questions (i.e. 25 questions each in Physics, Maths and Chemistry), with candidates required to attempt all 75 questions. Each subject consists of 2 sections (i.e. Section A with 20 MCQs and Section B with 5 questions whose answers are to be filled in as a numerical value). In Section B candidates have to attempt all 5 questions.

    Q: What types of questions can I anticipate in JEE Main?
    A:

    JEE Main question paper primarily comprises 2 types of questions i.e. 1. Multiple-choice type questions and 2. Questions whose answers are to be filled in as a numerical value covering the subjects of Physics, Chemistry, and Mathematics.

    Q: Has the NTA modified the syllabus for JEE Main?
    A:

    Yes, the syllabus for JEE Main has changed from the previous year.

    Q: In what languages is the JEE Main question paper available?
    A:

    The JEE Main question paper is available in a bilingual medium, encompassing 13 different languages, including Hindi, Urdu, Bengali, Gujarati, and more.

    Q: Do I need to attempt all the questions in each section of the JEE Main?
    A:

    Yes, all the questions are compulsory. For each subject, In Section A candidates can attempt all 20 questions and in Section B candidates also attempt all 5 questions.

    Q: What are the advantages of practising previous years' JEE Main question papers?
    A:

    Solving previous years' question papers can help candidates grasp the exam pattern, identify important topics, assess areas of weakness, and enhance speed and accuracy in answering questions.

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    Have a question related to JEE Main ?
    i have got 91% in pcm and overall i got 85% in 12th board but my jee rank is not good its 54% so is it possible to take admission in dseu ?

    Yes, it is possible , but it depends on which course at DSEU you're applying for .

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    can I get cse in vnr i have 71251 jee rank with 95.46 percentile

    Hello Dear Student,
    With a JEE rank of 71,251 (approx. 95.5 percentile), you are unlikely to secure a mainstream Computer Science and Engineering (CSE) seat through the general counselling quotas at VNR Vignana Jyothi Institute of Engineering and Technology (VNR VJIET), Hyderabad.

    You can check, find and access more information

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    Samyak Jain
    3 Jul'26
    What course or field to take after jee or gujcet, I have an average score of 100 in jee

    Hello,

    With a JEE Main score of around 100 marks, your admission chances depend on your percentile, category, state quota, and counselling process.

    You can consider B.Tech through your state counselling (such as GUJCET), private engineering colleges, or branches like Civil, Mechanical, Electrical, Electronics, or emerging fields depending on your

    Read Complete Answer
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    Moturi Gana Amrutha Varshini
    3 Jul'26
    want to join online jee coaching with best features and lecture quality. suggest me a institute

    Hello Student,

    If you are looking for the best online JEE coaching with excellent faculty, high quality lectures, doubt supporting and regular mock test. Some of the most trusted options are Allen digital, Competishun, unacademy, Physics Wala (PW) and Vedantu.

    The right choice depend on your preparation level and budget

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    King Singh
    3 Jul'26
    JEE mains: 91.48 percentile obc ncl rank : 44480 , Female CRL: 132000 home state: Bihar Which NITs can I get for Core branch?

    Hello Dear Student,

    With a 91.48 percentile (OBC-NCL rank 44,480; CRL 132,000) and Bihar home state quota, your strong female supernumerary quota makes you highly competitive for core branches (Mechanical, Civil, and Electrical) at NIT Patna and NIT Jamshedpur.

    You can get directly find, check, get more information here:

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