JEE Main 2021 Feb 24 Question Paper with Solutions by Resonance

To download PDFs of previous years’ question papers (PYQs) for JEE Mains, follow these steps:

1. Visit Official Websites

Go to the official NTA JEE Main website (jeemain.nta.nic.in).

Check the “Previous Year Question Papers” section (if available) for free downloads.

2. Use Educational Platforms

Websites like Careers360, Embibe, BYJU's, and Aakash BYJU's often provide free or paid access to JEE Main PYQs in PDF format.

Search on these platforms for JEE Main PYQs and filter by year or subject.

3. Explore Online Libraries

Websites such as Vedantu, Allen, or FIITJEE offer downloadable study materials, including PYQs, in PDF format.

4. Apps for JEE Aspirants

Download apps like Unacademy, Toppr, or GradeUp for accessing JEE Main question papers. Many of them offer PDFs you can download for offline use.

5. Direct Search on Google

Search terms like “JEE Main PYQs PDF download [Year]” or “JEE Main previous year question papers with solutions PDF free.”

Check the results from trusted educational websites or forums like Resonance, Allen Kota, or Arihant Publications.

6. Ask Your Coaching Center

If you’re enrolled in a coaching institute, they might provide a compiled set of PYQs for practice.

7. Use Telegram Channels

Join JEE-focused Telegram groups or channels. Many of them share direct links to PDFs of PYQs and other study resources.

Tips While Using PYQs:

Focus on solving the last 10 years’ papers for understanding trends.

Solve with a timer to simulate exam conditions.

Analyze mistakes to improve performance.

Let me know if you

need specific links or guidance on where to start!

Hello aspirant, One of the few things that students hoping to join IIT should consider when preparing for the JEE Advanced entrance exam is the eligibility requirements. The 75% grade in the 12th grade is always problematic. There isn't a minimum percentage requirement to take JEE Main at the moment. Candidates must, however, fulfill the 75% requirement in the 12th grade (or 65% for SC/ST) in order to be eligible for JEE Advanced.

Thank you

Hello student,

As per the latest available information, the JEE Main 2025 Mathematics syllabus includes the study of conic sections, specifically parabola, ellipse, and hyperbola , along with their standard forms, foci, directrices, eccentricity, parametric equations, and equations of tangents and normals.

Therefore, the topics of tangents and normals in conic sections are not deleted from the JEE Main 2025 syllabus.

It's important to note that the syllabus for JEE Advanced 2025 may differ from JEE Main. For instance, the JEE Advanced 2025 syllabus includes equations of tangents and normals for conic sections.

To ensure comprehensive preparation, it's advisable to refer to the official JEE Main and JEE Advanced syllabi released by the National Testing Agency (NTA) and the respective conducting bodies. These documents provide the most accurate and up-to-date information regarding the exam syllabus.

I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.

Hello Sachin,

To secure a rank under 200 in the OBC category for JEE Advanced , the required marks can vary depending on the difficulty of the exam, the performance of candidates in that particular year, and the normalization process. However, as a general guideline:

• In previous years, to get a rank under 200 in the OBC category, you would typically need to score around 230-250 marks (out of 360) in JEE Advanced .
  
  

• Keep in mind that the exact cutoff can fluctuate each year, so focusing on consistently improving your preparation and aiming for a high score is essential.

Additionally, the cutoff for JEE Advanced depends on factors like the overall difficulty level of the exam and the number of candidates appearing, so it's always a good idea to refer to the official cutoff trends once the exam is conducted.


For more details about the cutoff of JEE Advanced Click Here .

I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.

Thank you and wishing you all the best for your bright future.

In the JEE Main 2019 examination, the State-wise toppers for Madhya Pradesh were:

• Dhruv Arora
• Prakhar Jagwani

Both candidates achieved a 100 percentile in the examination.

Jagran Josh (https://www.jagranjosh.com/articles/jee-main-2019-result-released-check-cut-off-and-toppers-list-1556541543-1?utm_source=chatgpt.com)

For a comprehensive list of candidates who qualified for JEE Advanced 2019 through JEE Main 2019, you can refer to the official press release by the National Testing Agency (NTA).

National Testing Agency (https://www.nta.ac.in/Download/Notice/20190429155134.pdf?utm_source=chatgpt.com)

Please note that the merit list for Madhya Pradesh in the JEE Main 2019 examination is not publicly available. However, the state-wise toppers have been highlighted.

For detailed information on the merit list and cut-off scores for Madhya Pradesh , you may refer to the official website of the Directorate of Technical Education (DTE), Madhya Pradesh .

DME MPOnline (https://dme.mponline.gov.in/Quick%20Links/DMECounselling_Public/DMEUG/2020/DMEUG_2020_Merit_List_FR_Round.pdf?utm_source=chatgpt.com)

If you are seeking specific information regarding the merit list or cut-off scores for Madhya Pradesh , I recommend contacting the Directorate of Technical Education (DTE), Madhya Pradesh directly for accurate and up-to-date information.

Hi Heera,

• Year of Passing Class 12:

  • If a candidate passed their Class 12th board exams in 2023-24 (after failing in 2022-23) , their year of passing is considered as 2024 .
  • For JEE Advanced, candidates can only attempt the exam in the year they pass Class 12 and the year immediately after.

• JEE Advanced Attempts:
  • The maximum number of attempts allowed is two consecutive years after passing Class 12.
  • Since the candidate officially passed Class 12 in 2024, they will be eligible for:
    • JEE Advanced 2024 (the year of passing).
    • JEE Advanced 2025 (the year immediately after).

• JEE 2023 Attempt:

If the candidate attempted JEE Advanced 2023 while technically failing Class 12 in 2022-23, that attempt will not count because they were not eligible to appear at that time. Only valid attempts made after officially passing Class 12 count toward the two attempts. The candidate will be eligible for JEE Advanced 2024 and 2025, provided they meet other eligibility criteria. Their participation in JEE Advanced 2023 (if any) will not be considered a valid attempt. For more information regarding this, you can check out the given link.

Best Wishes!

https://engineering.careers360.com/articles/jee-advanced-eligibility-criteria

According to the JEE Advanced eligibility criteria, the number of attempts is counted based on the first appearance in the Class 12th examination. Here’s how it works:

1. Attempt Count Based on First Appearance in Class 12:

   • If a student fails in Class 12 in the year 2022-23 and then appears and passes in 2023-24, the JEE Advanced eligibility rules will consider the 2023 appearance (when they first attempted the exam) as the first attempt.
   • The JEE Advanced attempt count is based on the first appearance, even if the student fails and appears again in the following year. This is because the first appearance in the Class 12th examination is what counts.

2. Eligibility for JEE Advanced 2024 and 2025:

   • For JEE Advanced 2024, the student would be eligible as they have passed their Class 12th exam in 2023-24. This would be considered their first attempt .
   • For JEE Advanced 2025, the student can attempt it as well, as they would still be within the 2-attempt limit, which is valid for two consecutive years after passing the Class 12 exam.

In conclusion, if a student fails in 2022-23 and passes in 2023-24, their first attempt will be considered the 2023 appearance, and they will be eligible for JEE Advanced in both 2024 and 2025, provided they meet all other eligibility requirements.

Hello Shanvi,

Based on the current rules and your situation:

1. JEE Attempt Count: The JEE Advanced attempt count is based on the year in which you first appeared for the Class 12 exams. Since you were absent in 2023-24 and didn't appear for any exams, this year will not be counted as an attempt.

2. 2024-25 as First Attempt: Since you are appearing in 2024-25 as a regular candidate, this will be considered your first attempt for JEE Advanced eligibility.

3. Eligibility for JEE Advanced 2025 & 2026:

   • Your first JEE Advanced attempt will be in 2025 (for the 2024-25 session).
   • You are eligible for two attempts (2025 and 2026), as the attempt count is reset with the first valid appearance in the board exams.

Hence, you will be eligible for JEE Advanced 2025 and 2026, with 2024-25 considered as your first attempt year.

Hope it helps !

Hello

Here’s a concise guide for JEE Mains preparation :

1. Understand the Exam : Know the syllabus and pattern thoroughly .

2. Make a Plan : Study daily with a balanced timetable .

3. Focus on NCERT : Build a strong foundation , specially in Chemistry.

4. Practice Questions : Solve previous year papers and mock tests regularly .

5. Revise Formulas : Keep a formula sheet for quick revisions .

6. Test Yourself : Take timed mock tests and analyze mistakes .

7. Stay Consistent : Study consistently , revise regularly and avoid burnout .

Stay focused and manage your time effectively for success .

https://engineering.careers360.com/articles/jee-main-preparation-tips

Hope this helps you .

Thank you .

Hello Greetings

To find the PDF you downloaded in the JEE app, check the app's built-in file manager or download section. If you can't find it there, look for the PDF in your device's default download location, usually the "Downloads" folder. You can also use your device's file manager app to search for the PDF by name or browse through the folders to locate it.

Have a great day