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JEE Main Syllabus with Weightage - JEE Main is one of the most important examinations for every engineering aspirant. It brings a lot of queries and requires ambit of information about various aspects of JEE Main. After the recent changes announced in exam pattern, one of the mostly searched query by candidates for the upcoming examination is detailed JEE Main syllabus with weightage. By using the information about the weightage of JEE Main syllabus, the candidates will be able to know the topics which has to be more focused on and accordingly prepare for the examination. Every year there may be variation in JEE Main syllabus with regards to weightage,however the analysis of past years weightage solves much of a query. Candidates can check the previous year question papers for syllabus weightage of JEE Main to know which topics and units may have a higher number of questions. While the topics with more weightage has to be given importance, the candidates are advised to study all of the topics mentioned in the JEE Main syllabus. Read the full article to know more information about JEE Main Syllabus with Weightage. JEE Main 2020 will be conducted by NTA from January 6 to 11 as a computer based test. The application form of JEE Main 2020 was available from September 2 to October 10.Latest: Download the admit card of JEE Main 2020 now. Use application number, date of birth or password to download it
Latest : JEE Main 2020 College Predictor - Know your admission chances through JEE Main 2020 Percentile. Start Now
The authorities will declare the result of JEE Main 2020 on January 31. The provisional answer key of JEE Main 2020 for January session will also be released by the NTA.
Computer-based test (CBT)
Physics, Chemistry, and Mathematics
Total number of questions
75 (Each subject will have 25 questions)
Type of Questions
Each section will have 20 Objective questions having 4 options each with only 1 correct option and 5 Numerical questions with numerical value as answer
For MCQs - 4 Marks will be awarded for every correct answer and 1 Mark will be deducted for every incorrect answer
For answer with numeric value - 4 Marks will be awarded for every correct answer and 0 Mark will be deducted for every incorrect answer
Medium of paper
English or Hindi (Candidates from Gujarat, Daman & Diu and Dadra and Nagar Haveli can opt for Gujarati as well)
No of Questions
Heat and Thermodynamics
Unit,Dimension and Vector
Laws of motion
Work,Power and Energy
Centre Of Mass, Impulse and Momentum
Simple Harmonic Motion
Solids and Fluids
Electromagnetics Induction ; AC
To check the detailed JEE Main Syllabus for Physics click here
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Transition Elements and Coordination Chemistry
Periodic table and Representative Elements
Thermodynamics And Gaseous State
Chemical And Ionic Equilibrium
Solid State And Surface Chemistry
Nuclear Chemistry And Environment
Solution and Colligative Properties
General Organic Chemistry
Carboxylic Acid and their Derivatives
Carbohydrates,amino acid and Polymers
To check the detailed JEE Main Syllabus for Chemistry click here
Limits, Continuity and Differentiability
Complex numbers and Quadratic Equation
Matrices and Determinants
Statistics and Probability
Three Dimensional Geometry
Sets, Relation and Function
Permutations and Combinations
Binomial Theorem and Its Application
Sequences and Series
Statics and Dynamics
To check the detailed JEE Main Syllabus for Mathematics click here
No! Questions are asked from every topic covered by JEE Main. The formulation of questions in exam depends of authority; but there is no such parity among topics.
Students can find the topic wise distribution of questions from JEE Main syllabus with weightage to understand which topics have been covered in recent years. This will help students to study for the exam accordingly.
JEE Main 2020 will have a total of 75 questions, 25 each from Physics, Chemistry and Mathematics. Further, out of 25 questions, 20 questions will be MCQs and 5 questions will be questions with Numeric answer.
Yes! JEE Main is now conducted only in online mode.
National Testing Agency has declared the syllabus of JEE Main 2020. Go through the link below to check the official syllabus:
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IIEST (Indian Institute of Engineeering Science and Technology), Shibpur takes admission for UG courses through JEE-Mains. Cut-off ranks for CSE of different rounds of previous year are given below :
- 9379 and
- 9967 and
- 11355 and
- 11796 and
*Home State & Other State.
I hope you got the required information.
Final ranks are declared only after the April session is concluded.
It would be more helpful if you have given some decimal values of your percentile.
For 75 percentile, your estimated rank would be less than 2 lakhs 20 thousand considering only the January case.
Note: This is general rank. It is difficult to predict category wise rank as sufficient information about number of students from different categories is not available.
ST candidate would qualify for JEE Advanced with 75 percentile.
Hope this helps.
Since the change in declaring results in the form of Percentile, the raw score obtained by the student has become the second priority.
In my opinion, you should now rather concentrate on getting better percentile.
This can be achieved by:
1. Solving Maths questions over others because it is comparatively easy and gives you upper hand in case of a tie.
2. Practice NCERT textual exercises. Mere good grip in subjects by attending regular classes will give you 70+ percentile.
3. Prepare according to weightage of chapters.
4. Since there is less time available to you and you also have your board exams, I suggest, in this last moment to try to solve previous year papers as they can give you idea of questions.
5. Watch online tutorials to learn concepts.
6. Keep your accuracy high and attempt all Numerical Questions as there is no Negative marking.
These are some simple tactics to better your score.
More details are given in this link:
All The Very Best..!
Well i cannot tell you the no of question to be attempted but i can tell you how much marks you should get to percentile of 97 or 98. I cannot tell you the exact marks but i can give you a range
127 to 118 97.13841571 - 96.41990133
137 to 128 97.69477799 - 97.17648701
147 to 138 98.14939961 - 97.75686494
157 to 148 98.53104347 - 98.20040957
Ill provide you a link where you can find other datas similar to these
HOPE IT HELPS!!
Maximum marks for JEE advanced is not fixed and it keeps on changing every year sometimes it is more than 500 and sometime it is close to 350. Therefore don't go for marks because it even happens that sometimes the question paper comes very difficult and with less marks also you will get very good rank therefore it is totally unpredictable also the pattern of JEE advanced is completely anonymous and will be known only after prepare for JEE advanced.
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