How to revise for JEE Main 2026 in 15 Days? – Smart Tips & Tricks

How to revise for JEE Main 2026 in 15 Days? – Smart Tips & Tricks

Team Careers360Updated on 21 Oct 2025, 04:27 PM IST

How to revise JEE Main 2026 in 15 days? - The last 15 days before the JEE Main entrance exam are crucial for aspirants. To crack the JEE Main exam, students should have a proper exam strategy. We have presented the strategy on how to revise for JEE Main 2026 in 15 days in this article. This 15-day revision plan will help the candidates to revise everything for JEE Main 2026 in the last 15 days. JEE Main 2026 aspirants can refer to the page for the revision plan. Since candidates have a lot of time for the exam now, they can use the resources below to prepare for JEE Main in a planned and strategic manner so the chances of you getting good marks increase.

LiveJEE Mains 2026 Jan 29 LIVE: BArch, BPlanning exam in single shift; memory-based questions with solutions soonJan 29, 2026 | 7:33 AM IST

The JEE Main 2026 28 Jan shift 2 paper analysis and difficulty are shown in the table below.

Subjects

Major Topics Asked

Difficulty Level

Physics

Modern Physics, Ray Optics, Formula-based numerical questions

Easy

Chemistry

Chemical Kinetics, Ionic Equilibrium (Buffer), Coordination Compounds, Amines, Inorganic-focused theory

Moderate

Mathematics

Vector & 3D Geometry, Integral Calculus, Differential Equations, Probability, Conic Sections, Trigonometry, Sequences & Series, Statistics

Moderate (Lengthy)

Overall

Statement-based questions across subjects; Maths lengthy; Physics formula-driven

Easy


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How to revise for JEE Main 2026 in 15 Days? – Smart Tips & Tricks
How to revise for JEE Main 2026 in 15 days

How to revise for JEE Mains in 15 days?

Candidates appearing for JEE Main 2026 must give proper time for revision as it is the key to crack any exam. Candidates can refer to the following tips to prepare a perfect strategy on how to revise for JEE Main 2026:

Make a timetable for revision- Candidates should first prepare a new timetable of 15 days for revision. Candidates may divide 5 days for each subject. It must be kept in mind that the timetable for the JEE Main 15-day revision plan has to be religiously followed otherwise it won't be possible to revise everything. Now, it also depends on the candidates what they want to revise. It means whether they want to revise everything or the entire syllabus. This will entirely depend on the candidates if they wish they can take up important topics from each subject and revise them thoroughly based on their JEE Main 15-day revision plan.

Refer to the handy notes- Candidates can refer to the handy notes prepared during the preparation of the exam. The handy notes will help the candidates in quick revision of the syllabus. Candidates can also add topics if they have learned something new.

Other than these things candidates must remember the following tips to ace JEE Main 2026 -

Practice Mock tests and sample papers- Candidates must practice more and more JEE Main sample papers and mock tests. These mock tests and sample papers will open the candidates to different types of questions daily and will help them analyze their performance. JEE Main mock tests and sample papers are based on the actual pattern of the exam, it is beneficial for the candidates to practice one mock test or sample paper daily to have a real feel of the examination.

Do not panic- Lastly, candidates should not panic at this time as they have enough time to prepare for now. They should keep themselves stress-free and stay healthy. They must take proper care of their health as any health issues at this time will directly affect their preparations.

JEE Mains High-weightage Subjects

Candidates preparing for JEE Mains should focus on High weightage topics of different chapters of Physics, chemistry, and biology.

High-weightage JEE Main Physics Topics

  • Laws of Motion- Under this unit, important topics to keep in mind are Force and Inertia, Newton’s First Law of Motion; Momentum, Newton’s Second Law of Motion; and Impulse, Newton’s Third Law of Motion. The weightage of these topics is 4%.

  • Gravitation- The universal law of gravitation. Acceleration due to gravity and its variation with altitude and depth. The topic has a weightage of 2%.

  • Properties of Solids and Liquids- Elastic behavior, Stress-strain relationship, Hooke’s Law, Young’s Modulus, Modulus of rigidity.

  • JEE Main 2026 Physics syllabus is vast, here we are providing important topics for a few chapters like Physics and Measurement, Laws of Motion, Kinematics, etc. For important topics from other remaining chapters of physics candidates can go through the Most-scoring topics in JEE Main Physics.

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High-weightage JEE Main Chemistry Topics

  • Atomic Structure- Thomson and Rutherford atomic models and their limitations; Nature of electromagnetic radiation, Photoelectric effect; Spectrum of the hydrogen atom.

  • Equilibrium- Equilibrium involving chemical processes, Ionic equilibrium, Equilibria involving physical processes.

  • Here is the list of important topics from the chapter Atomic Structure. For complete topics from all chapters of chemistry go through the article Most important chapters of JEE main Chemistry

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High-weightage JEE Main Mathematics Topics

  • Sets, Relations, and Functions- Sets and their representation: Union, intersection, and complement of sets and their algebraic properties; Power set; Relation, Type of relations, equivalence relations, functions; one-one, into and onto functions, the composition of functions.

  • Matrices and Determinants- Matrices, algebra of matrices, type of matrices, determinants and matrices of order two and three, properties of determinants, evaluation of determinants.

  • Here we are providing the important topics of chapter trigonometry. For the remaining chapters important topics candidate can go through the Highest scoring topics in JEE Main Maths .

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Frequently Asked Questions (FAQs)

Q: How do I prepare for JEE Main 2026 in 15 days?
A:

Students can start their preparation by drafting a proper 15-day plan with each subject divided on an average scale or based on your comfortable duration of days as required. But since there is enough time, you can plan and ace your exam with strategic preparation.

Q: What is the type of subject-wise number of questions asked in JEE mains exam?
A:

Physics- 20 MCQ and 5 Numerical Value Type  Questions, Chemistry- 20 MCQ and  5 Numerical Value Type Questions, and Mathematics -20 MCQ 5 Numerical Value Type Questions.

Q: What are the things i can carry to JEE main exam hall?
A:

You can carry your JEE main admit card and ID.

Q: What do i do if i don't have any materials before exam?
A:

Students can prepare for their exams by sourcing materials online.

Q: How do i keep myself fit and healthy before the day of exam?
A:

Students should make sure they eat nutritious food, maintain a proper sleeping routine and have their supplements as required. 

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JEE Main 28 Jan shift 2 exam will end at 6 PM. The complete analysis and memory-based questions will solution will be updated in the below article. Keep checking the page-

https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-2-question-paper-with-solutions-pdf

Math and Chemistry was difficult and Physics was moderate. The complete analysis is available here- https://engineering.careers360.com/articles/jee-main-2026-january-28-shift-1-question-paper-with-solutions-pdf

You can also check the memory-based questions and detailed solutions for JEE Main Jan 28 shift 1 paper.

HI Manisha Maharana

You can download the JEE Mains 10 Free Mock Test with Detailed solutions. Its a feely downloadable pdf.
https://engineering.careers360.com/download/sample-papers/jee-main-10-full-mock-test-and-explanations-pdf

Also, you can check ad attemp the online mock test on our platform.
https://learn.careers360.com/test-series-jee-main-free-mock-test/



A general equation of a circle is

$
x^2+y^2+2 g x+2 f y+c=0
$

Since it passes through $(0,0)$,

$
c=0
$

So the equation becomes

$
x^2+y^2+2 g x+2 f y=0
$

It cuts the x -axis at ( $a, 0$ ).

Substituting:

$
a^2+2 g a=0
$

g=-a/2