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Domain and range of Inverse Trigonometric Function (Part 1) is considered one the most difficult concept.
35 Questions around this concept.
The largest interval lying in for which the function,
is defined, is
Let be a function defined by
then is both one-one and onto when is the interval
Domain and range of Inverse Trigonometric Function (Part 1)
y = sin-1(x)
The function y = sin(x) is many one so it is not invertible. Now consider the small portion of the function
Which is strictly increasing, Hence, one-one and inverse is y = sin-1(x)
y = cos-1(x)
y = tan-1(x)
Domain and range of Inverse Trigonometric Function (Part 2)
y = cot-1(x)
y = sec-1(x)
y = cosec-1(x)
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