Careers360 Logo
ask-icon
share
    NIT JEE Main Cutoff 2026 - NIT BTech Admission Process

    Equation Of Motions - Practice Questions & MCQ

    Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

    Quick Facts

    • Equation of motions is considered one the most difficult concept.

    • 74 Questions around this concept.

    Solve by difficulty

    A particle has an initial velocity 3\hat{i}+4\hat{j} and an acceleration of 0.4\hat{i}+0.3\hat{j}. Its speed after 10s is

    An engine of the train, moving with uniform acceleration, passes the signal -post with velocity u and the last compartment with velocity v. The velocity with which the middle point of the train passes the signal post is:

    Speeds of two identical cars are u and 4u at a specific instant. If the same deceleration is applied on both cars, the ratio of the respective distances in which the two cars are stopped from that instant is :

    A car moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is :

    An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be :

    A particle is moving with velocity \vec{v}=K(y\hat{i}+x\hat{j}),where\; K is a constant. The general equation for its path is

    A train is standing on a platform, and a man inside a compartment of a train drops a stone. At the same instant train starts to move with constant acceleration. The path of the particle as seen by the person who drops the stone is :

    Amity University Noida-B.Tech Admissions 2026

    Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026

    UPES B.Tech Admissions 2026

    Last Date to Apply: 29th April | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements

    A car travelling at a speed of 60 km/hr can break and stop within a distance of 20 metres. If the car is travelling at twice the speed, i.e.,120 km/hr the stopping distance will be:
     

    Two balls A and B are thrown from a building, A is thrown up and B is thrown down (both vertically). Let v_A and  v_B be their respective speeds when they reach the ground, then:

     

    JEE Main 2026 Rank Predictor
    Use the JEE Main 2026 Rank Predictor to estimate your expected rank based on your scores or percentile and plan your college options smartly.
    Try Now

    Assertion: When the initial velocity is zero; then the final velocity value depends upon the acceleration and time taken by the particle.

    Reason: The kinematical equation of motion relating initial velocity, final velocity,  acceleration and time taken by the particle is v=u+at.

     

    Concepts Covered - 1

    Equation of motions

    There are three equations of motion

    1. The first kinematical equation of motion (velocity-time equation)

    Formula

    $
    v=u+a t
    $

    $v=$ Final velocity
    $\mathrm{u}=$ Initial velocity
    $A=$ acceleration

    $
    \mathrm{T}=\text { time }
    $

    2. The second kinematical equation of motion (Position-time equation)

    Formula
    $s=u t+\frac{1}{2} a t^2$
    $s \rightarrow$ Displacement
    $u \rightarrow$ Initial velocity
    $a \rightarrow$ acceleration
    $t \rightarrow$ time


    3. The third kinematical equation of motion (Velocity-displacement equation)

    Formula

    $
    v^2-u^2=2 a s
    $
     

    $v \rightarrow $ Final Velocity
    $s \rightarrow$ Displacement
    $u \rightarrow$ Initial velocity
    $a \rightarrow$ acceleration

    Displacement in nth second
    Formula: $S_n=u+\frac{a}{2}(2 n-1)$
    Where $u=$ Initial velocity
    $a=$ uniform acceleration

    Study it with Videos

    Equation of motions

    "Stay in the loop. Receive exam news, study resources, and expert advice!"

    Get Answer to all your questions