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Equation Of Motions - Practice Questions & MCQ
Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main
Quick Facts
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Equation of motions is considered one the most difficult concept.
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51 Questions around this concept.
Solve by difficulty
A particle has an initial velocity and an acceleration of
Its speed after 10s is
Speeds of two identical cars are and
at a specific instant. If the same deceleration is applied on both cars, the ratio of the respective distances in which the two cars are stopped from that instant is :
A car moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is :
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An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, 120 km/h, the stopping distance will be :
A particle is moving with velocity is a constant. The general equation for its path is
A train is standing on a platform, and a man inside a compartment of a train drops a stone. At the same instant train starts to move with constant acceleration. The path of the particle as seen by the person who drops the stone is :
A car travelling at a speed of 60 km/hr can break and stop within a distance of 20 metres. If the car is travelling at twice the speed, i.e.,120 km/hr the stopping distance will be:
Two balls A and B are thrown from a building, A is thrown up and B is thrown down (both vertically). Let and
be their respective speeds when they reach the ground, then:
The acceleration of a particle increases with time “t” as From the initial position with a velocity u; the distance travelled by the particle in time “t” is :
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Download EBookA car is moving with there is a bus stop driver needs to apply a break of 400 m before that to rest the car at the bus stop; now suppose the driver applied the break at half distance so the car will cross the bus stop with
velocity; the value of
:
Concepts Covered - 1
Equation of motions
There are three equations of motion
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The first kinematical equation of motion (velocity-time equation)
Formula
$
v=u+a t
$
$v=$ Final velocity
$\mathrm{u}=$ Initial velocity
$A=$ acceleration
$
\mathrm{T}=\text { time }
$
2. The second kinematical equation of motion (Position-time equation)
Formula
$s=u t+\frac{1}{2} a t^2$
$s \rightarrow$ Displacement
$u \rightarrow$ Initial velocity
$a \rightarrow$ acceleration
$t \rightarrow$ time
3. The third kinematical equation of motion (Velocity-displacement equation)
Formula
$
v^2-u^2=2 a s
$
$v \rightarrow \mid$ Final Velocity
$s \rightarrow$ Displacement
$u \rightarrow$ Initial velocity
$a \rightarrow$ acceleration
Displacement in nth second
Formula: $S_n=u+\frac{a}{2}(2 n-1)$
Where $u=$ Initial velocity
$a=$ uniform acceleration
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