Equation Of Motions - Practice Questions & MCQ

A particle has an initial velocity and an acceleration of Its speed after 10s is

Speeds of two identical cars are  and  at a specific instant. If the same deceleration is applied on both cars, the ratio of the respective distances in which the two cars are stopped from that instant is :

A car moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is :

An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, 120 km/h, the stopping distance will be :

A particle is moving with velocity is a constant. The general equation for its path is

A train is standing on a platform, and a man inside a compartment of a train drops a stone. At the same instant train starts to move with constant acceleration. The path of the particle as seen by the person who drops the stone is :

A car travelling at a speed of 60 km/hr can break and stop within a distance of 20 metres. If the car is travelling at twice the speed, i.e.,120 km/hr the stopping distance will be:
 

Two balls A and B are thrown from a building, A is thrown up and B is thrown down (both vertically). Let  and   be their respective speeds when they reach the ground, then:

The acceleration of a particle increases with time “t” as   From the initial position with a velocity u; the distance travelled by the particle in time “t” is : 

A car is moving with there is a bus stop driver needs to apply a break of 400 m before that to rest the car at the bus stop; now suppose the driver applied the break at half distance so the car will cross the bus stop with   velocity; the value of  :