How to Attempt IIT JEE Main and Advanced 2025 - Know success mantra from experts

Trigonometric Identities - Practice Questions & MCQ

Edited By admin | Updated on Sep 18, 2023 18:34 AM | #JEE Main

Quick Facts

  • Trigonometric Identities is considered one of the most asked concept.

  • 48 Questions around this concept.

Solve by difficulty

If A=\sin ^{2}x+\cos ^{4}x, then for all real x

The sum of all values of $\theta \epsilon(0, \pi / 2)$ satisfying $\sin ^2 2 \theta+\cos ^4 2 \theta=3 / 4$ is:

For $\alpha, \beta \in(0, \pi / 2)$, let $3 \sin (\alpha+\beta)=2 \sin (\alpha-\beta)$ and a real number $\mathrm{k}$ be such that $\tan \alpha=\mathrm{k} \tan \beta$. Then, the value of $\mathrm{k}$ is equal to

 

 

 

$\sqrt{1-\sin^{2}\theta}$  equals

If $\tan \theta=\frac{4}{5}$, find $\sec \theta$ ( $\theta$ is in 4th quadrant)

$\cos ^{-1} x=\tan ^{-1} x$, then $\cos ^2 \theta=$ ?

$\operatorname{Sec}^2\left(\tan ^{-1} 2\right)+\operatorname{cosec}^2\left(\cot ^{-1} 3\right)$ is equal to

GNA University B.Tech Admissions 2025

100% Placement Assistance | Avail Merit Scholarships | Highest CTC 43 LPA

UPES B.Tech Admissions 2025

Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 15th July

If the perimeter of a sector of a circle, of area $25 \pi$ square cms is 20 cm , then area of a sector is

 

 

If $\sin \theta+\sin ^2 \theta=1$, then the value of $\cos ^{12} \theta+3 \cos ^{10} \theta+3 \cos ^8 \theta+\cos ^6 \theta-1$ is equal to

Best Public Engineering Institutes 2025
Discover the top public engineering colleges in India beyond IITs and NITs for 2025. Get insights on placements, eligibility, application process, and more in this comprehensive ebook.
Check Now

The number of real values of the triplet $(p, q, r)$ for which $p \operatorname{cos}^2 x+q \operatorname{sin}^2 x+r=0$ is satisfied by all real x , is

Concepts Covered - 1

Trigonometric Identities

Trigonometric Identities
These identities are the equations that hold true regardless of the angle being chosen.

$
\begin{aligned}
& \sin ^2 t+\cos ^2 t=1 \\
& 1+\tan ^2 t=\sec ^2 t \\
& 1+\cot ^2 t=\csc ^2 t \\
& \tan t=\frac{\sin t}{\cos t}, \quad \cot t=\frac{\cos t}{\sin t}
\end{aligned}
$
 

Study it with Videos

Trigonometric Identities

"Stay in the loop. Receive exam news, study resources, and expert advice!"

Get Answer to all your questions

Back to top