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What is a Percentile in JEE? - NTA releases the JEE Main result in the form of percentile. Eve the cutoff is based on JEE percentile. Hence, aspirants should know what a percentile is in JEE 2026. Careers360 has explained in detail what the percentile in JEE Mains signifies and how it is calculated in this article. Candidates aiming for engineering admissions in India appear for the national-level JEE Mains exam every year. Admission to NITs, IIITs and GFTIs is based on the candidate’s performance in the JEE Main examination. The National Testing Agency will conduct the JEE Main 2026 exam for session 1 from January 21 to 29, 2026, while session 2 is scheduled from April 2 to 9, 2026.
Also Check: JEE Main 2026 Registration I JEE Main 2026 Exam Date
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Lakhs of students appear for the exam each year hence the results are announced in terms of "percentiles," which are crucial for determining a candidate's relative performance in comparison to others Read through the article to understand what exactly is a percentile in JEE Mains and how is it calculated.
A percentile is a statistical measure that indicates the relative rank of a candidate in a given population. It helps in comparing the performance of a candidate with that of others in the same group. A percentile score reflects the percentage of candidates who have scored lower than or equal to a particular candidate.
For example, if a candidate has a percentile of 95 in JEE Main, it means that the candidate has scored better than 95% of all the candidates who appeared for the exam. A higher percentile indicates better performance, while a lower percentile shows a relatively lower ranking as compared to other examinees.
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The National Testing Agency (NTA), the conducting body for JEE Main, uses a formula to compute the percentile for each candidate. This ensures that the score reflects the candidate's standing in relation to others. One of the key factors in JEE Main percentile calculation is the normalisation process. Since JEE Main is held in multiple shifts and sessions, the difficulty level of the exam may vary. To account for this variation, the NTA uses a normalisation method that adjusts the scores based on the relative performance of candidates in each shift. This ensures fairness in the evaluation process and makes sure that candidates are not disadvantaged due to the exam’s difficulty. In the case of JEE Main, percentile calculation is a bit more complex because it is not based on raw marks, but instead on the relative performance of all the candidates. The percentile score in JEE Main is calculated using the following formula
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
NTA calculates the JEE Main 2026 percentile by applying the process of normalisation of marks. There is a certain number of marks against which the percentile score is allotted which in turn can be called the JEE Main 2026 marks vs percentile. Aspirants may refer to the table below to know the expected range of marks for which a certain percentile is allotted to the respective candidates.
Marks out of 300 | Percentile |
288- 294 | 99.99826992- 99.99890732 |
280-284 | 99.99617561 - 99.99790569 |
270-279 | 99.99034797 - 99.99417236 |
252- 268 | 99.95228621- 99.99016586 |
231-249 | 99.87388626-99.95028296 |
215-230 | 99.74522293-99.87060821 |
202-214 | 99.57503767- 99.73930423 |
190-200 | 99.39319714- 99.56019541 |
175-189 | 99.02150308 - 99.3487614 |
161-174 | 98.52824811-98.99673561 |
149-159 | 98.07460288-98.49801724 |
132-148 | 97.0109678-97.97507774 |
120-131 | 96.0687115-96.93721175 |
110-119 | 95.05625037-95.983027 |
102-109 | 94.01228357-94.96737888 |
95-101 | 93.05600452 -93.89928202 |
89-94 | 92.05811248 -92.88745828 |
79-88 | 90.0448455 -91.79177119 |
62-87 | 84.56203931-91.59517945 |
41-61 | 70.26839007-84.22540213 |
1-42 | 66.6590786-69.5797271 |
Frequently Asked Questions (FAQs)
In JEE Mains, a percentile score indicates how many students are equal to or less than the said percentile. It shows the performance of the candidate with respect to all other students who took the exam.
The National Testing Agency uses a set formula for the calculation of percentile in JEE Mains. Candidates must check the JEE Mains percentile calculator for more details on how the percentile is calculated.
Yes, a higher percentile indicates a better performance of the individual as compared to others who took the test.
Yes. It is possible for two students to have the same percentile in JEE Mains. In this situation, the authorities use the JEE Mains tie-breaking rule for the allocation of ranks.
On Question asked by student community
Hello Dear Student,
Yes, with an SC category rank of 31,370, you have a very strong chance of getting admission to IIITDM Kancheepuram. While highly demanding branches like Computer Science and Engineering may close earlier (around 3,400 - 92,000 depending on the round), your rank is highly competitive for other
Hello Dear Student,
With a JEE Main CRL of 1,22,306 and an OBC rank of 40,694, securing a seat in top-tier NITs or IIITs for core branches will be highly challenging. However, using your Gujarat Home State Quota, your best options include GFTIs, newer IIITs, state-funded universities, and reputable private
Hello,
With 982/1000 in IPE (98.2%) and 89 percentile in JEE Main , you have a good chance of getting a seat at SASTRA University , especially through the admission process that considers both Class 12 marks and JEE Main scores. Your excellent board marks will work strongly in your
Hello,
With a CRL rank of 1.57 lakh , OBC rank of 54,000 , and Haryana domicile , getting CSE at YMCA Faridabad is unlikely based on previous cutoff trends.
However, you may still have a chance in:
Electronics & Computer Engineering (depending on cutoff movement)
Hello Dear Student,
With an OBC-NCL category rank of 25,995 in JEE Main , your chances at the most sought-after branches in top IIITs are limited, but you still have several realistic options through JoSAA and especially CSAB Special Rounds .
You may have chances in:
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