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What is Percentile in JEE? - Aspirants of JEE Main who are wondering what percentile means have come to the right place. Careers360 has explained in detail what is percentile in JEE Mains signifies and how it is calculated in this article. Candidates aiming for engineering admissions in India appear for the national-level JEE Mains exam. Admission to NITs, IIITs and GFTIs is based on the candidate’s performance in the JEE Main exam.
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Lakhs of students appear for the exam each year hence the results are announced in terms of "percentiles," which are crucial for determining a candidate's relative performance in comparison to others. Read through the article to understand what exactly is a percentile in JEE Mains and how is it calculated. NTA conducted the JEE Main 2025 exam for session 1 from January 22 to 30, 2025. The JEE Main session 1 result was declared on February 11, 2025.
A percentile is a statistical measure that indicates the relative rank of a candidate in a given population. It helps in comparing the performance of a candidate with that of others in the same group. A percentile score reflects the percentage of candidates who have scored lower than or equal to a particular candidate.
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For example, if a candidate has a percentile of 95 in JEE Main, it means that the candidate has scored better than 95% of all the candidates who appeared for the exam. A higher percentile indicates better performance, while a lower percentile shows a relatively lower ranking as compared to other examinees.
The National Testing Agency (NTA), the conducting body for JEE Main, uses a formula to compute the percentile for each candidate. This ensures that the score reflects the candidate's standing in relation to others. One of the key factors in JEE Main percentile calculation is the normalization process. Since JEE Main is held in multiple shifts and sessions, the difficulty level of the exam may vary. To account for this variation, the NTA uses a normalization method that adjusts the scores based on the relative performance of candidates in each shift. This ensures fairness in the evaluation process and makes sure that candidates are not disadvantaged due to the exam’s difficulty. In the case of JEE Main, percentile calculation is a bit more complex because it is not based on raw marks, but instead on the relative performance of all the candidates. The percentile score in JEE Main is calculated using the following formula
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
NTA calculates the JEE Main 2025 percentile by applying the process of normalization of marks. There is a certain number of marks against which the percentile score is allotted which in turn can be called the JEE Main 2025 marks vs percentile. Aspirants may refer to the table below to know the expected range of marks for which a certain percentile is allotted to the respective candidates.
Marks out of 300 | Percentile |
288- 294 | 99.99826992- 99.99890732 |
280-284 | 99.99617561 - 99.99790569 |
270-279 | 99.99034797 - 99.99417236 |
252- 268 | 99.95228621- 99.99016586 |
231-249 | 99.87388626-99.95028296 |
215-230 | 99.74522293-99.87060821 |
202-214 | 99.57503767- 99.73930423 |
190-200 | 99.39319714- 99.56019541 |
175-189 | 99.02150308 - 99.3487614 |
161-174 | 98.52824811-98.99673561 |
149-159 | 98.07460288-98.49801724 |
132-148 | 97.0109678-97.97507774 |
120-131 | 96.0687115-96.93721175 |
110-119 | 95.05625037-95.983027 |
102-109 | 94.01228357-94.96737888 |
95-101 | 93.05600452 -93.89928202 |
89-94 | 92.05811248 -92.88745828 |
79-88 | 90.0448455 -91.79177119 |
62-87 | 84.56203931-91.59517945 |
41-61 | 70.26839007-84.22540213 |
1-42 | 66.6590786-69.5797271 |
Frequently Asked Questions (FAQs)
Yes, a higher percentile indicates a better performance of the individual as compared to others who took the test.
Yes. It is possible for two students to have the same percentile in JEE Mains. In this situation, the authorities use the JEE Mains tie-breaking rule for the allocation of ranks.
The National Testing Agency uses a set formula for the calculation of percentile in JEE Mains. Candidates must check the JEE Mains percentile calculator for more details on how the percentile is calculated.
In JEE Mains, a percentile score indicates how many students are equal to or less than the said percentile. It shows the performance of the candidate with respect to all other students who took the exam.
On Question asked by student community
With your JEE Main CRL 476199 and OBC rank 173160, admission to Civil Engineering at Indira Gandhi Institute of Technology (IGIT), Sarang under JoSAA counseling is highly unlikely, since even civil branch closing ranks in IGIT usually remain within 50k–80k CRL (general) and much lower for OBC. However, you may try through state counseling (Odisha JEE) where cutoffs are sometimes more flexible, but chances are still very low. You should keep other private/state colleges as backup.
Hey! With a JEE Main rank of around 1 lakh, you still have a good chance to get admission in several engineering colleges that provide quality education at a reasonable fee. For government colleges, you can aim for NITs or GFTIs in branches like Civil, Mechanical, or Chemical Engineering, as these usually have slightly higher closing ranks. For example, colleges like NIT Goa, NIT Puducherry, and NIT Srinagar might have seats available in certain branches.
Apart from NITs, state government engineering colleges are also a good option, especially under home state quota. They often have lower tuition fees and good faculty, so you can get a solid education without spending much.
If you are open to private colleges, there are options like VIT Vellore, KIIT Bhubaneswar, or Amity University that provide decent infrastructure and placements. However, the fees may be higher than government colleges.
My advice is to focus on branches that are less competitive, check all counseling rounds, and make use of state quotas if applicable. With proper planning, a rank of 1 lakh can still help you get a good college and start your engineering career success
fully.
No, you can’t use a previous year’s JEE rank for the current year’s WBJEE counselling. Only the JEE Main rank of the same admission year is valid along with that year’s WBJEE rank.
Hello Aspirant,
Finding specific JEE exam centers for Whitefield is difficult as they vary each year. The list is released on the admit card . However, many centers are usually iON Digital Zones. For coaching, top centers near Whitefield include Aakash Institute , Narayana Institute , and Allen Career Institute . These centers have branches in and around the Whitefield area to help you prepare for the exam.
Its okay if you missed jee this year you can drop year for JEE to get into a government institute like IET Lucknow to get better placement here and fees is also less in comparison with SRMU but it also means delaying a year with no guarantee success.
Joining a private college like SRMU now avoids losing a year,but it comes with higher costs and generally lower placement statistics compared to top government institutions.
ultimately Your decision should be based on your skill whether you can significantly improve your JEE score versus accepting a faster, but potentially more expensive, path to your B.Tech.
Hope it helps..
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