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What is a Percentile in JEE? - NTA releases the JEE Main result in the form of percentile. Eve the cutoff is based on JEE percentile. Hence, aspirants should know what a percentile is in JEE 2026. Careers360 has explained in detail what the percentile in JEE Mains signifies and how it is calculated in this article. Candidates aiming for engineering admissions in India appear for the national-level JEE Mains exam every year. Admission to NITs, IIITs and GFTIs is based on the candidate’s performance in the JEE Main examination. The National Testing Agency will conduct the JEE Main 2026 exam for session 1 from January 21 to 29, 2026, while session 2 is scheduled from April 2 to 9, 2026.
Also Check: JEE Main 2026 Registration I JEE Main 2026 Exam Date
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Lakhs of students appear for the exam each year hence the results are announced in terms of "percentiles," which are crucial for determining a candidate's relative performance in comparison to others Read through the article to understand what exactly is a percentile in JEE Mains and how is it calculated.
A percentile is a statistical measure that indicates the relative rank of a candidate in a given population. It helps in comparing the performance of a candidate with that of others in the same group. A percentile score reflects the percentage of candidates who have scored lower than or equal to a particular candidate.
For example, if a candidate has a percentile of 95 in JEE Main, it means that the candidate has scored better than 95% of all the candidates who appeared for the exam. A higher percentile indicates better performance, while a lower percentile shows a relatively lower ranking as compared to other examinees.
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The National Testing Agency (NTA), the conducting body for JEE Main, uses a formula to compute the percentile for each candidate. This ensures that the score reflects the candidate's standing in relation to others. One of the key factors in JEE Main percentile calculation is the normalisation process. Since JEE Main is held in multiple shifts and sessions, the difficulty level of the exam may vary. To account for this variation, the NTA uses a normalisation method that adjusts the scores based on the relative performance of candidates in each shift. This ensures fairness in the evaluation process and makes sure that candidates are not disadvantaged due to the exam’s difficulty. In the case of JEE Main, percentile calculation is a bit more complex because it is not based on raw marks, but instead on the relative performance of all the candidates. The percentile score in JEE Main is calculated using the following formula
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
NTA calculates the JEE Main 2026 percentile by applying the process of normalisation of marks. There is a certain number of marks against which the percentile score is allotted which in turn can be called the JEE Main 2026 marks vs percentile. Aspirants may refer to the table below to know the expected range of marks for which a certain percentile is allotted to the respective candidates.
Marks out of 300 | Percentile |
288- 294 | 99.99826992- 99.99890732 |
280-284 | 99.99617561 - 99.99790569 |
270-279 | 99.99034797 - 99.99417236 |
252- 268 | 99.95228621- 99.99016586 |
231-249 | 99.87388626-99.95028296 |
215-230 | 99.74522293-99.87060821 |
202-214 | 99.57503767- 99.73930423 |
190-200 | 99.39319714- 99.56019541 |
175-189 | 99.02150308 - 99.3487614 |
161-174 | 98.52824811-98.99673561 |
149-159 | 98.07460288-98.49801724 |
132-148 | 97.0109678-97.97507774 |
120-131 | 96.0687115-96.93721175 |
110-119 | 95.05625037-95.983027 |
102-109 | 94.01228357-94.96737888 |
95-101 | 93.05600452 -93.89928202 |
89-94 | 92.05811248 -92.88745828 |
79-88 | 90.0448455 -91.79177119 |
62-87 | 84.56203931-91.59517945 |
41-61 | 70.26839007-84.22540213 |
1-42 | 66.6590786-69.5797271 |
Frequently Asked Questions (FAQs)
In JEE Mains, a percentile score indicates how many students are equal to or less than the said percentile. It shows the performance of the candidate with respect to all other students who took the exam.
The National Testing Agency uses a set formula for the calculation of percentile in JEE Mains. Candidates must check the JEE Mains percentile calculator for more details on how the percentile is calculated.
Yes, a higher percentile indicates a better performance of the individual as compared to others who took the test.
Yes. It is possible for two students to have the same percentile in JEE Mains. In this situation, the authorities use the JEE Mains tie-breaking rule for the allocation of ranks.
On Question asked by student community
Hello Dear Student,
With a JEE rank of 71,251 (approx. 95.5 percentile), you are unlikely to secure a mainstream Computer Science and Engineering (CSE) seat through the general counselling quotas at VNR Vignana Jyothi Institute of Engineering and Technology (VNR VJIET), Hyderabad.
You can check, find and access more information
Hello,
With a JEE Main score of around 100 marks, your admission chances depend on your percentile, category, state quota, and counselling process.
You can consider B.Tech through your state counselling (such as GUJCET), private engineering colleges, or branches like Civil, Mechanical, Electrical, Electronics, or emerging fields depending on your
Hello Student,
If you are looking for the best online JEE coaching with excellent faculty, high quality lectures, doubt supporting and regular mock test. Some of the most trusted options are Allen digital, Competishun, unacademy, Physics Wala (PW) and Vedantu.
The right choice depend on your preparation level and budget
Hello Dear Student,
With a 91.48 percentile (OBC-NCL rank 44,480; CRL 132,000) and Bihar home state quota, your strong female supernumerary quota makes you highly competitive for core branches (Mechanical, Civil, and Electrical) at NIT Patna and NIT Jamshedpur.
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Hello Dear Student,
With a 60 percentile in both JEE Main and MHT CET, securing B.Tech CSE or IT in top-tier government colleges is highly unlikely. However, you have excellent options available at reputable private engineering universities and can explore state-affiliated private colleges through decentralized counselling.
You can check, find
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