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84 percentile in JEE Mains Means how many marks: Candidates can check the details on JEE Main 2025 84 percentile means how many marks on this page. The National Testing Agency releases the 84 percentile in JEE Mains 2025 means how many marks on the official website, jeemain.nta.nic.in. In the JEE Main 2025 exam, an 84th percentile typically corresponds to a score range of around 60-75 marks out of 300.
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For candidates with a percentile above 84, the score typically ranges between 86.4 and 87.7 marks, with a rank ranging from 1,86,000 to 1,92,000. According to the JEE Main 2025 marks vs percentile vs rank data, candidates must score above 250 marks to achieve a percentile of over 90. For more detailed information, candidates can refer to the 84 percentile in JEE Mains Means how many marks below.
Candidates can check the 80 percentile in JEE Main Expected Marks vs Percentile vs Rank in the table given below.
Marks Out of 300 | Percentile | Overall Rank |
100 - 90 | 95.64338495 - 94.39636137 | 61651 - 79298 |
90 - 80 | 94.39636137 - 92.76234617 | 79298 - 102421 |
80 - 70 | 92.76234617 - 90.4109851 | 102421 - 135695 |
70 - 60 | 90.4109851 - 87.06073037 | 135695 - 183105 |
60 - 50 | 87.06073037 - 81.57582987 | 183105 - 260722 |
50 - 40 | 81.57582987 - 73.08140938 | 260722 - 380928 |
40 - 30 | 73.08140938 - 59.84001311 | 380928 - 568308 |
30 - 20 | 59.84001311 - 40.3469266 | 568308 - 844157 |
20 - 10 | 40.3469266 - 20.95045141 | 844157 - 1118638 |
10 - 0 | 20.95045141 - 6.599800585 | 1118638 - 1321716 |
Therefore, in JEE Main, percentiles are useful while understanding how a student has performed in relation to other students. Consequently, a higher percentile indicates a better performance and a higher rank. To be more precise, 99th percentiles may be approximately more than 175 marks, while 80th percentiles may range between 55 and 76 marks. Nevertheless, the score ranges can change year by year based on the difficulty of the examination and the number of candidates involved.
To calculate the JEE Main percentile for 2025, candidates need to use the following formula: Percentile = (100 x Number of candidates from the session with a raw score equal to or less than T1 score) / Total number of candidates who appeared in the session.
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
The percentile range of 80-90 in the JEE Mains 2025 exam means that the candidate has been ranked between 1,50,000 and 3,00,000. Although, one can get a chance to get admissions to some of the renowned institutes of India including NITs and IIITs even if this percentile is achieved.
Number of applicants
Performance in the entrance examination
Difficulty level of the JEE Main 2025
Cutoff trends of the previous years’ examination
Frequently Asked Questions (FAQs)
An 84+ percentile in JEE Main typically corresponds to an expected marks range of 86.4 - 87.7. This percentile usually translates to an expected rank range of 1,86,000 - 1,92,000.
An 84 percentile in JEE Mains is a good score, providing opportunities for admission to various engineering colleges.
As per the latest trend, with 84 marks in the JEE Mains, you come in the percentile range of 89-90.
On Question asked by student community
You can download the last 10 years of JEE Main question papers from below link
It is available in PDF format with solutions.you can easily download it..
Prepare well..
Good luck!!
Hello,
you can appear for the TALLENTEX or StarNxt test while in class 10.The offline exams for TALLENTEX 2026 are scheduled for October 5 and October 12 in 2025.you can register online at tallentex.com.
You can also take the ALLEN Scholarship Admission Test (ASAT) and if you score 85% and above in it, you will definitely get a scholarship. Also you get one of the best batches too.
If you're a NTSE scholar, good at National and state Olympiads. You can enlist yourself for Allen Champ.
Basically it is based on academic achievements you have, the more you bag award you are more likely to get a scholarship.
Good luck!!
Hello,
JEE Main 2026 will be held in two sessions. Session 1 is expected in the last week of January 2026 and Session 2 in the first week of April 2026 .
JEE Advanced 2026 is expected to be conducted in May 2026 (likely in mid or last week of May) after JEE Main results.
The exact dates will be announced by NTA and IIT in their official notifications.
Hope it helps !
Hi aspirant,
If you are willing to give jee and you are in 12 th then it is best to focus from now on as u have to give your boards this year as well . And according to the exam pattern you can prepare for your jee prelims with you boards at the same time it is hardly differ from each other . But if you have 0 preparation and even your basics are not clear then i suggest u to take a drop and prepare to the fullest for next year thankyou .
Hello Hari
You can find JEE Mains last 10 year Previous Year Questions (PYQs) with detailed solution at CAREERS360 website . CAREERS360 provide JEE Mains as well as JEE Advance questions with solutions in many languages like English and Hindi.
Here's the link: JEE Mains Last 10 Years PYQs by CAREERS360
Hope this link helps! Thank You!!!
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