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84 percentile in JEE Mains Means how many marks: Candidates can check the details on JEE Main 2025 84 percentile means how many marks on this page. The National Testing Agency releases the 84 percentile in JEE Mains 2025 means how many marks on the official website, jeemain.nta.nic.in. In the JEE Main 2025 exam, an 84th percentile typically corresponds to a score range of around 60-75 marks out of 300.
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For candidates with a percentile above 84, the score typically ranges between 86.4 and 87.7 marks, with a rank ranging from 1,86,000 to 1,92,000. According to the JEE Main 2025 marks vs percentile vs rank data, candidates must score above 250 marks to achieve a percentile of over 90. For more detailed information, candidates can refer to the 84 percentile in JEE Mains Means how many marks below.
Candidates can check the 80 percentile in JEE Main Expected Marks vs Percentile vs Rank in the table given below.
Marks Out of 300 | Percentile | Overall Rank |
100 - 90 | 95.64338495 - 94.39636137 | 61651 - 79298 |
90 - 80 | 94.39636137 - 92.76234617 | 79298 - 102421 |
80 - 70 | 92.76234617 - 90.4109851 | 102421 - 135695 |
70 - 60 | 90.4109851 - 87.06073037 | 135695 - 183105 |
60 - 50 | 87.06073037 - 81.57582987 | 183105 - 260722 |
50 - 40 | 81.57582987 - 73.08140938 | 260722 - 380928 |
40 - 30 | 73.08140938 - 59.84001311 | 380928 - 568308 |
30 - 20 | 59.84001311 - 40.3469266 | 568308 - 844157 |
20 - 10 | 40.3469266 - 20.95045141 | 844157 - 1118638 |
10 - 0 | 20.95045141 - 6.599800585 | 1118638 - 1321716 |
Therefore, in JEE Main, percentiles are useful while understanding how a student has performed in relation to other students. Consequently, a higher percentile indicates a better performance and a higher rank. To be more precise, 99th percentiles may be approximately more than 175 marks, while 80th percentiles may range between 55 and 76 marks. Nevertheless, the score ranges can change year by year based on the difficulty of the examination and the number of candidates involved.
To calculate the JEE Main percentile for 2025, candidates need to use the following formula: Percentile = (100 x Number of candidates from the session with a raw score equal to or less than T1 score) / Total number of candidates who appeared in the session.
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
The percentile range of 80-90 in the JEE Mains 2025 exam means that the candidate has been ranked between 1,50,000 and 3,00,000. Although, one can get a chance to get admissions to some of the renowned institutes of India including NITs and IIITs even if this percentile is achieved.
Number of applicants
Performance in the entrance examination
Difficulty level of the JEE Main 2025
Cutoff trends of the previous years’ examination
Frequently Asked Questions (FAQs)
An 84+ percentile in JEE Main typically corresponds to an expected marks range of 86.4 - 87.7. This percentile usually translates to an expected rank range of 1,86,000 - 1,92,000.
An 84 percentile in JEE Mains is a good score, providing opportunities for admission to various engineering colleges.
As per the latest trend, with 84 marks in the JEE Mains, you come in the percentile range of 89-90.
On Question asked by student community
Preparing for the JEE Main in just 30 days is a challenging but achievable task if you follow a highly disciplined and strategic approach. According to the Careers360 30-day study plan , the key is to shift your focus from learning everything to mastering high-weightage topics and practicing rigorously.
During the first 15 days, prioritize topics that frequently appear in the exam.
Physics: Modern Physics, Heat & Thermodynamics, Optics, and Current Electricity.
Chemistry: GOC (General Organic Chemistry), Chemical Bonding, p-Block elements, and Solutions.
Maths: Matrices & Determinants, Sequences & Series, Coordinate Geometry, and Vector & 3D Geometry.
Study Strategy: Use NCERT for Chemistry and simplified notes for Physics/Maths. Spend 3-4 hours on each subject daily.
Short Notes: Go through the short notes you made during the first two weeks.
Flashcards: Use flashcards for inorganic chemistry reactions and physics formulas.
Mock Tests: Start giving one full-length mock test every alternate day. Analyze your mistakes immediately to avoid repeating them.
Previous Year Papers (PYQs): Solve the last 3-5 years of JEE Main papers in the actual exam time slot (9 AM–12 PM or 3 PM–6 PM) to sync your body clock.
No New Topics: Stop picking up new chapters. Focus solely on what you already know to build confidence.
Accuracy over Speed: Focus on getting the questions right rather than attempting all of them, as negative marking can significantly lower your percentile.
You can download the comprehensive day-by-day schedule, which includes specific topics to cover each morning and evening, by visiting the link : https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days
Good Evening,
Yes, you are eligible for both JEE Mains and Advanced, as you completed your 12th with physics, chemistry and biology. Moreover, you passed mathematics in 2025, which makes you fit the eligibility criteria of both exams.
Aspirant, I would like to inform you that Careers360 recently launched a free mock test series for JEE students. The last date of registration is 8th January, 2026. Enroll and solve chapter wise question papers and improve you concept and assess your learning. The link to the mock test series is attached herewith. https://learn.careers360.com/test-series-jee-main-free-mock-test/
Best regards.
Hello,
Since the NTA conducts exams in Tamil, these official papers will have a Tamil language option. Kindly check the following link to get the question papers.
https://engineering.careers360.com/articles/jee-main-question-papers
I hope this helps you.
Hello there,
Understanding and solving different question papers is one of the best practice for the preparation specially when it comes to JEE mains. It gives you proper understanding of the exam pattern, important topics to cover and marking scheme.
Here is the link attached from the official website of Careers360 which will provide you with the link of previous year question papers on chemistry in PDF format. Hope it helps!
https://engineering.careers360.com/articles/jee-mains-chemistry-questions-in-last-year-exam-premium
thank you!
Good Morning, Candidate,
The 30-day study plan for JEE is now available on the website of Careers360. The link is attached herewith.
https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days
There is an option for free download, which will help to proceed further.
Careers360 would like to inform you that you can have an opportunity to analyse your in-depth performance. Careers360 is conducting a free all-India online JEE mock test series on 11th January. It will provide you with a proper question pattern with chapter-wise questions and answers.
Registration is closed on 8th January. Registered and assessed your learning.
Thank You
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