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84 percentile in JEE Mains Means how many marks: Candidates can check the details on JEE Main 2025 84 percentile means how many marks on this page. The National Testing Agency releases the 84 percentile in JEE Mains 2025 means how many marks on the official website, jeemain.nta.nic.in. In the JEE Main 2025 exam, an 84th percentile typically corresponds to a score range of around 60-75 marks out of 300.
NTA allows candidates to appear for the JEE Mains 2026 exam six times. However, candidates can appear for the exam only twice a year. JEE Mains attempts over three consecutive years make it a total of six attempts
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For candidates with a percentile above 84, the score typically ranges between 86.4 and 87.7 marks, with a rank ranging from 1,86,000 to 1,92,000. According to the JEE Main 2025 marks vs percentile vs rank data, candidates must score above 250 marks to achieve a percentile of over 90. For more detailed information, candidates can refer to the 84 percentile in JEE Mains Means how many marks below.
Candidates can check the 80 percentile in JEE Main Expected Marks vs Percentile vs Rank in the table given below.
Marks Out of 300 | Percentile | Overall Rank |
100 - 90 | 95.64338495 - 94.39636137 | 61651 - 79298 |
90 - 80 | 94.39636137 - 92.76234617 | 79298 - 102421 |
80 - 70 | 92.76234617 - 90.4109851 | 102421 - 135695 |
70 - 60 | 90.4109851 - 87.06073037 | 135695 - 183105 |
60 - 50 | 87.06073037 - 81.57582987 | 183105 - 260722 |
50 - 40 | 81.57582987 - 73.08140938 | 260722 - 380928 |
40 - 30 | 73.08140938 - 59.84001311 | 380928 - 568308 |
30 - 20 | 59.84001311 - 40.3469266 | 568308 - 844157 |
20 - 10 | 40.3469266 - 20.95045141 | 844157 - 1118638 |
10 - 0 | 20.95045141 - 6.599800585 | 1118638 - 1321716 |
Therefore, in JEE Main, percentiles are useful while understanding how a student has performed in relation to other students. Consequently, a higher percentile indicates a better performance and a higher rank. To be more precise, 99th percentiles may be approximately more than 175 marks, while 80th percentiles may range between 55 and 76 marks. Nevertheless, the score ranges can change year by year based on the difficulty of the examination and the number of candidates involved.
To calculate the JEE Main percentile for 2025, candidates need to use the following formula: Percentile = (100 x Number of candidates from the session with a raw score equal to or less than T1 score) / Total number of candidates who appeared in the session.
Total Percentile (T1P) | (100 x No. of candidates from the session with a raw score equal to or less than T1 score) / Total No. of candidates who appeared in the session |
Mathematics Percentile (M1P) | (100 x No. of candidates appeared from the session with a raw score equal to or less than than M1 score in Mathematics) / Total No. of candidates who appeared in the session |
Chemistry Percentile (C1P): | (100 x No. of candidates appeared from the session with a raw score equal to or less than C1 score in Chemistry) / Total No. of candidates who appeared in the session |
Physics Percentile (P1P) | (100 x No. of candidates appeared from the session with raw score equal to or less than P1 score in Physics) / Total No. of candidates who appeared in the session |
The percentile range of 80-90 in the JEE Mains 2025 exam means that the candidate has been ranked between 1,50,000 and 3,00,000. Although, one can get a chance to get admissions to some of the renowned institutes of India including NITs and IIITs even if this percentile is achieved.
Number of applicants
Performance in the entrance examination
Difficulty level of the JEE Main 2025
Cutoff trends of the previous years’ examination
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Frequently Asked Questions (FAQs)
An 84+ percentile in JEE Main typically corresponds to an expected marks range of 86.4 - 87.7. This percentile usually translates to an expected rank range of 1,86,000 - 1,92,000.
An 84 percentile in JEE Mains is a good score, providing opportunities for admission to various engineering colleges.
As per the latest trend, with 84 marks in the JEE Mains, you come in the percentile range of 89-90.
On Question asked by student community
Helloaspirant,
The JEE Main 2026 syllabus, which is broken down into Physics, Chemistry, and Mathematics, is based on the NCERT curriculum for Classes 11 and 12. Calculus, Algebra, and Coordinate Geometry in Mathematics; Organic, Inorganic, and Physical Chemistry; and Mechanics, Thermodynamics, and Optics in Physics are important subjects.
To know the syllabus, you can visit our site through following link:
https://engineering.careers360.com/articles/jee-main-syllabus
Thank you
You will get last 10 years JEE Mains papers in hindi below
JEE MAIN 10 YEAR PAPER IN HINDI
Practising these papers will increase your confidence and you will be better prepared for the exam.
Good luck!!
Yes, if you appear for the CBSE improvement exam as a private candidate and score higher marks, then the latest marksheet will be considered as your valid Class 12th result. For IIM A, B, C and other top IIMs, they look at the final updated marksheet that you present at the time of admission.
So, if you improve your percentage from 70% to 90%, then definitely the improved score will be counted in your profile evaluation. Just make sure you give the exam through the official CBSE improvement route and keep the valid documents.
Hey! For JEE Main 2026, focus on Physics: Modern Physics, Electrostatics, Magnetism, Thermodynamics; Chemistry: Coordination Compounds, Thermodynamics, Basic Concepts, Hydrocarbons; Maths: Coordinate Geometry, Calculus, Limits, Sets & Functions, Complex Numbers, 3D Geometry, Probability.
Removed topics: Physics – Semiconductors, Communication Systems; Chemistry – Surface Chemistry, s-block, Polymers, Alcohols/Phenols/Ethers; Maths – Induction, Reasoning, Triangle Inequality.
Hello, You have asked for JEE Mains previous year questions Chapter wise.
I am providing you the link of previous year chapter wise question of JEE Mains, from there you can download chapter wise previous year question of JEE Mains.
Here is your link: CLICK HERE
Click on "CLICK HERE" to download the pyqs.
I hope you found this information helpful.
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