80 Percentile in JEE Mains 2026 Means How Many Marks?

80 Percentile in JEE Mains 2026 Means How Many Marks?

Chintakuntla Sai GnanUpdated on 20 Dec 2025, 05:35 PM IST

80 Percentile in JEE Mains 2026 Means How Many Marks?: Candidates can check how many marks they will get with an 80 percentile in JEE Mains 2026 in this article. The expected marks are 53 to 54 out of a total of 300 marks to get a percentile of 80 in the JEE Mains exam 2026. The range of JEE Main marks vs percentile changes every year based on various factors like the difficulty level of the exam, competition, category of the students, etc. The 80 percentile in JEE Mains is a good score for general category candidates; however, it will not help them to secure a seat in top NITs or IITs. To get NIT admission, the minimum score required is 95th percentile in JEE Mains exam.

This Story also Contains

  1. 80 Percentile in JEE Mains 2026 Means How many Marks
  2. Previous Year’s JEE Main Marks vs Percentile
  3. What is the JEE Main Percentile Score?
  4. Entrance Exams alternative to the JEE Mains Exam
  5. Factors Affecting JEE Mains Marks vs Percentile
  6. What is JEE Main Normalisation Formula
80 Percentile in JEE Mains 2026 Means How Many Marks?
80 Percentile in JEE Mains 2026 Means How Many Marks?

80 Percentile in JEE Mains 2026 Means How many Marks

Candidates are expected to score 53 to 54 marks if they get 80 percentile in JEE Mains 2026. The marks will change every year based on many factors. The authority uses the normalisation method in allotting percentiles and marks for the students. The table below gives information about how many marks for 80 percentile will get in JEE Mains 2026.

Expected Marks for 80 Percentile in JEE Mains 2026

JEE Main Marks Range


JEE Main Marks Range

45 – 46

72.0 – 73.5

47 – 48

73.5 – 75.0

49 – 50

75.0 – 78.0

51 – 52

78.0 – 79.5

53 – 54

79.5 – 81.0

55 – 56

81.0 – 82.5

57 – 58

82.5 – 84.0

59 – 60

84.0 – 86.0

61 – 62

86.0 – 87.0

63 – 64

87.0 – 88.0

65 – 66

88.0 – 89.0


Previous Year’s JEE Main Marks vs Percentile

Based on the last year's details, aspirants can expect a mark between 41-50 if they get 80 percentile in JEE Mains

MarksPercentile

61-70

87.512225 - 90.702200

51 - 60

82.016062 - 86.907944

41-50

73.287808 - 80.982153

What is the JEE Main Percentile Score?

The authority allots percentile scores for all JEE Main candidates who appeared in the exam. The JEE Mains percentile score will be obtained after the normalisation method. Candidates who get a top score will be given the 100th percentile, while others will be allotted as per their scores. To avoid confusion and ties between the candidates, the percentile will be calculated to 7 decimal places. The JEE Main percentile score means the percentage of marks scored by the candidate in that particular session.

Entrance Exams alternative to the JEE Mains Exam

Here is the list of entrance exams with their cutoff ranks


Exam Name

Conducting Body/College Name

Eligibility Criteria

SRMJEEE

SRM University

Class 12 with 60%

UPSEAT

UPES

Class 12 with 50%

LPUNEST

Lovely Professional University (LPU)

Class 12 with 60%

MHT CET

State Common Entrance Test Cell - Maharashtra State

HSC or an equivalent exam with a minimum of 50% aggregate

WBJEE

West Bengal Joint Entrance Examinations Board

Class 12 with 45%

NMIMS CET

NIMS University, Jaipur

Class 12 with 45%

KITEE

KIIT Bhubaneswar

Class 12 with 60%

CUCET

Chandigarh University

Class 12 with 60%

AEEE

Amrita Vishwa Vidyapeetham

Class 12 with a minimum of 60%

JEE Main Syllabus: Subjects & Chapters
Select your preferred subject to view the chapters

Factors Affecting JEE Mains Marks vs Percentile

Many factors affect the allotment of the percentile and marks to the candidate during the normalisation method. Below are various factors that decide marks vs percentile in JEE Mains every year.

  • Difficulty level of the exam

  • Number of students who appear in that session.

  • Category of the candidates

  • Depends on the normalisation formula that is used for calculation

  • Competition between candidates.

Amity University-Noida B.Tech Admissions 2026

Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026

UPES B.Tech Admissions 2026

Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements

What is JEE Main Normalisation Formula

The authority uses a normalisation formula to allot marks, percentiles and rank to the candidates who appeared for the JEE Mains exam. The percentile score also means about the percentage of candidates with marks less than or equal to the candidate with the highest marks obtained in that particular JEE Main session. The raw score and percentile score are different from each other. The JEE Main percentile score is calculated with the following formulae.

Percentile score = 100 ( Number of candidates with raw score less than or equal to the candidates with higher marks in that session / Total number of students appeared in that session.)

Frequently Asked Questions (FAQs)

Q: What is the raw score in JEE Mains?
A:

The raw score is the sum of all the marks in the JEE Mains exam after removing the negative marks. 

Q: How is the JEE Main percentile score calculated?
A:

The authority uses a formula to obtain the JEE Main percentile score. The percentile score equals to the number of candidates with raw scores less than or equal to the higher marks of the candidate in that session divided by the total number of students appeared in that session multiplied by 100.

Q: Is 80 percentile enough for top NIT admission?
A:

Candidates need to score at least 95 percentile to get admission in top NITs.

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Questions related to JEE Main

On Question asked by student community

Have a question related to JEE Main ?

Hello aspirant,

If your syllabus is completed with theory , use the next 30 days only for smart revision . Make short notes and revise formulas daily for Physics , Chemistry and Maths . Solve previous year JEE Main questions topic-wise and then full mock tests every 3-4 days. Analyse mistakes properly and revise weak areas again . Avoid new topics and focus on accuracy , speed and confidence building during revision.

FOR REFERENCE : https://engineering.careers360.com/articles/jee-main-revision-strategy

Hope the details will help you.

THANK YOU

Preparing for the JEE Main in just 30 days is a challenging but achievable task if you follow a highly disciplined and strategic approach. According to the Careers360 30-day study plan , the key is to shift your focus from learning everything to mastering high-weightage topics and practicing rigorously.

Phase 1: Week 1 & 2 – Focus on High-Weightage Chapters

During the first 15 days, prioritize topics that frequently appear in the exam.

  • Physics: Modern Physics, Heat & Thermodynamics, Optics, and Current Electricity.

  • Chemistry: GOC (General Organic Chemistry), Chemical Bonding, p-Block elements, and Solutions.

  • Maths: Matrices & Determinants, Sequences & Series, Coordinate Geometry, and Vector & 3D Geometry.

  • Study Strategy: Use NCERT for Chemistry and simplified notes for Physics/Maths. Spend 3-4 hours on each subject daily.

Phase 2: Week 3 – Revision and Formula Memorization

  • Short Notes: Go through the short notes you made during the first two weeks.

  • Flashcards: Use flashcards for inorganic chemistry reactions and physics formulas.

  • Mock Tests: Start giving one full-length mock test every alternate day. Analyze your mistakes immediately to avoid repeating them.

Phase 3: Final Week – Full Simulation and Relaxation

  • Previous Year Papers (PYQs): Solve the last 3-5 years of JEE Main papers in the actual exam time slot (9 AM–12 PM or 3 PM–6 PM) to sync your body clock.

  • No New Topics: Stop picking up new chapters. Focus solely on what you already know to build confidence.

  • Accuracy over Speed: Focus on getting the questions right rather than attempting all of them, as negative marking can significantly lower your percentile.

Downloadable Resources:

You can download the comprehensive day-by-day schedule, which includes specific topics to cover each morning and evening, by visiting the link : https://engineering.careers360.com/download/ebooks/jee-main-study-plan-30-days

Hello

I think your question sounds like this: "Can a candidate who passed Class 12 in 2025 and filled JEE Main Session 1 apply for Session 2 as 'Appearing' in 2026 as a fresh board candidate, and will both sessions have the same details? "

So yes, you can fill the JEE Main Session 2 as "Appearing". The information filled in Session 1 will remain exactly as it was and will not change.
Session 1 and Session 2 are treated as separate applications. There is no issue if the qualifying status is different in both sessions. During counselling, the board marks that meet the 75 rule will be considered.

Hello,

If you filled the JEE Main January form with Class 12 passed in 2025 and are planning to appear again for the Class 12 exam through HOS, there is usually no serious issue. You were eligible to apply since you had already passed Class 12. Reappearing through HOS for improvement or requalification is allowed, provided HOS is a recognized board. During counselling, your latest valid Class 12 result will be considered. Make sure you meet the 75% marks or top 20 percentile requirement where applicable. If a correction window opens, update details if needed.

Hope this has solved your query. Thank You.

Good Evening,

Yes, you are eligible for both JEE Mains and Advanced, as you completed your 12th with physics, chemistry and biology. Moreover, you passed mathematics in 2025, which makes you fit the eligibility criteria of both exams.

Aspirant, I would like to inform you that Careers360 recently launched a free mock test series for JEE students. The last date of registration is 8th January, 2026. Enroll and solve chapter wise question papers and improve you concept and assess your learning. The link to the mock test series is attached herewith. https://learn.careers360.com/test-series-jee-main-free-mock-test/

Best regards.