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How many marks are required to clear JEE Mains 2025?- Aspirants appearing for BTech admission through JEE Main 2025 must be curious to know the minimum marks required to clear the exam. Every year, the NTA releases a press note stating how many marks are required to clear JEE Mains. According to the previous year trends, candidates should score above 92 marks in the general category in the JEE Main exam to clear the JEE Main 2025 cutoff. The authority conducted the JEE Main exam for session 1 between January 22 to 30, 2025, while session 2 was conducted from April 2 to 9, 2025. Students can check this article for category-wise JEE Main 2025 marks vs percentile and year-wise comparison between the same.
Get latest updates on JEE Main cutoff, percentile
The JEE Main 2026 admit card download link will be available on the official website of the National Testing Agency (NTA) at jeemain.nta.nic.in. Once released, candidates can click the relevant link on the homepage to access and download their admit card by entering the required login credentials.
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The authority will release the mandated JEE Mains marks in the form of an NTA score. It is a percentile score that will indicate the number of candidates equal to or less than the candidate. Aspirants will be able to predict their results based on the passing marks of JEE Main 2025.
Last year the minimum marks required to clear the JEE Main was around 93 for general category candidates. However, due to changes in the syllabus and pattern this year, the expected marks required to clear JEE Main 2025 might go as high as 95 or above. For more details, check the following tables for the previous three years' JEE Main passing marks for various categories below.
Category | NTA Score |
|---|---|
General | 92 - 100 |
General-PwD | 0.0017 - 92 |
EWS | 83 - 92 |
OBC-NCL | 78 - 92 |
SC | 61 - 92 |
ST | 47 - 92 |
Category | NTA Score |
|---|---|
General | 93.2362181 |
General-PwD | 0.0018700 |
EWS | 81.3266412 |
OBC-NCL | 79.6757881 |
SC | 60.0923182 |
ST | 46.6975840 |
Category | NTA Score |
|---|---|
General | 90.78 |
General-PwD | 0.001 |
EWS | 75.62 |
OBC-NCL | 73.61 |
SC | 51.98 |
ST | 37.23 |
Category | NTA Score |
|---|---|
General | 88.41 |
General-PwD | 0.003 |
EWS | 63.11 |
OBC-NCL | 67.01 |
SC | 43.08 |
ST | 26.78 |
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JEE Main result will consist of the NTA score for each subject and overall percentile as well. However, there will be no subject-wise cut off to clear the JEE Mains exam. Students will get to learn about their percentile only after downloading the scorecard of JEE Main.
The exam conducting authority has provided the formula to determine the minimum marks required to clear JEE Mains. The is given below.
Total Percentile (TPI) = 100 X Number of candidates who appeared in the ‘Session’ with a raw score equal to or less than the candidate / The total number of the candidates who appeared in the ‘Session’.
Candidates who score above the NTA marks will be eligible to apply for the JEE Advanced. Aspirants not only have to clear the first phase test, that is, JEE Main, but they have to be among the top 2.5 lakh rank holders as well. This year, IIT Kanpur will be conducting the exam for admission to IIT colleges in India.
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What will be the Expected Percentile for 180 Marks in JEE Main | |
NTA does not provide raw scores. Candidates will be able to check the normalized score, also called the NTA score.
NTA Score is the percentile of JEE Main. For instance, a 93 percentile means, 93% of the total test takers have marks less than or equal to those with that percentile.
The best NTA score out of both JEE Main attempts will be considered while preparing the final merit list.
A specific formula is used to convert the raw scores of Mathematics, Physics and Chemistry and total score into NTA scores.
JEE Main result is comparative in nature. A candidate's final result depends on the performance in the test as well as overall competition.
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Frequently Asked Questions (FAQs)
The expected marks required to clear JEE Main 2025 are approximately 90-95 percentile for the General category, 80-85 percentile for the EWS category, 75-80 percentile for the OBC-NCL category, 55-60 percentile for the SC category, and 45-50 percentile for the ST category.
The overall competition, difficulty level of the paper and candidate’s performance in the test determined whether a particular score is good or bad. As per previous year trends, 150 marks could fetch a rank between 21245 to 16495.
A score of 120 is not a bad score. As per JEE Main marks vs rank vs percentile data, 120 marks will be equal to 95 percentile.
Aspirants can check the above article to figure out the marks to clear JEE Mains.
As per previous year trends and expert analysis, this year, JEE Main 2025 difficulty level is expected to be easy to moderate. However, candidates must thoroughly prepare for the exam.
On Question asked by student community
Hello,
Yes, attendance is compulsory in Class XI and XII.
As per school and board rules, students must maintain minimum attendance, usually around 75%. Schools can stop students from appearing in board exams if attendance is short.
Even if a student is preparing for JEE or any other competitive exam
Hello,
You can find here the direct links to download the JEE Main last 10 years PYQ PDFs from the Official Careers360 website.
Kindly visit this link to access the question papers : Last 10 Years JEE Main Question Papers with Solutions PDF
Hope it helps !
Hello Harika,
Firstly, you cannot prepare for JEE in 8 days if you havent studied before. But still, You can try solving the previous year question papers. Here's a Link for the same
HELLO,
If you are from General category with 57 percent in 12th then to appear for JEE Advanced you need to be in top percentile of your board as the eligibility for JEE advanced you need at least 75 percent in 12th or in the top 20 percentile of your
Hello aspirant,
The JEE Main 2026 admission card will include information about the exam location. On the other hand, students can use the JEE Main 2026 city notification slip, which was made available on January 8, 2026, to check the exam city beforehand. The second week of January 2026 is
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