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What is a good score in JEE Main 2024?

What is a good score in JEE Main 2024?

Edited By Team Careers360 | Updated on Apr 25, 2024 04:46 PM IST | #JEE Main

What is a good score in JEE Main 2024: While preparing for the JEE Main exam the foremost question that arises in the candidate’s mind is what is a good score in JEE Main. The knowledge of good scores in JEE Main 2024 will help the candidates plan their preparation for the exam accordingly. A JEE Main mark above 250+ is considered to be a good mark.
Also Read: JEE Main rank predictor | JEE Mains college predictor | JEE Main accepting colleges

NTA JEE Main percentile between 85 to 95 is ideal for gaining admission to IITs and NITs. Now, the question arises: how to achieve such good marks in JEE Main? So to help candidates with this confusion Careers360 has given a detailed analysis of good marks in JEE Main and the preparation strategy for how to get good marks in JEE Main.

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What is a Good Score in JEE Main 2024?

Aspirants appearing for the upcoming exam can check the good rank in JEE Mains from the table given below. The rank of JEE Main is based on the scores of students in the entrance exam. A good rank in JEE Main depends on the number of students who appeared for the exam, difficulty level of the exam, cutoff marks, etc.

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Category

JEE Ranks

Excellent

1-15,000

Good

15,000-30,000

Average

30,000-50,000

Low

Above 50,000

JEE Main Marks vs Percentile vs Rank

Based on the scores secured by the candidates in the IIT JEE exam can check the JEE Main marks vs percentile vs rank from the table given below. Knowing the marks vs percentile vs rank of JEE Main will help the candidates plan how to score good marks in JEE Mains. NTA adopts a unique normalization formula to arrive at JEE Main Marks Vs Percentile Vs Rank. Here we have given the expected marks vs percentile of JEE Main.

Expected JEE Main marks vs percentile vs Rank

Marks out of 300

Rank

Percentile

286- 292

19-12

99.99826992- 99.99890732

280-284

42-23

99.99617561 - 99.99790569

268- 279

106-64

99.99034797 - 99.99417236

250- 267

524-108

99.95228621- 99.99016586

231-249

1385-546

99.87388626-99.95028296

215-230

2798-1421

99.74522293-99.87060821

200-214

4667-2863

99.57503767- 99.73930423

189-199

6664- 4830

99.39319714- 99.56019541

175-188

10746-7152

99.02150308 - 99.3487614

160-174

16163-11018

98.52824811-98.99673561

149-159

21145-16495

98.07460288-98.49801724

132-148

32826-22238

97.0109678-97.97507774

120-131

43174-33636

96.0687115-96.93721175

110-119

54293-44115

95.05625037-95.983027

102-109

65758-55269

94.01228357-94.96737888

95-101

76260-66999

93.05600452 -93.89928202

89-94

87219-78111

92.05811248 -92.88745828

79-88

109329-90144

90.0448455 -91.79177119

62-87

169542-92303

84.56203931-91.59517945

41-61

326517-173239

70.26839007-84.22540213

1-40

1025009-334080

6.66590786-69.5797271

JEE Main 2024 Cut off Trend Analysis

The minimum rank required by the candidates to get admission in their desired institute is JEE Main cutoff 2024. While this year’s cutoff has been released after the exam, candidates can check the previous year’s cutoff trends to understand what is a good score in JEE Mains. Generally, a higher the rank higher the chances of admission.

JEE Main Cutoff 2024

Category

Cutoff

General

93.2362181

EWS

81.3266412

OBC

79.6757881

SC

60.0923182

ST

46.6975840

PwD

0.0018700

JEE Main Qualifying Cut Off

Category

2023

2022

2021

2020

2019

2018

General

90.7788642

88.4121383

87.8992241

90.3765335

89.7548849

111275

Gen-PwD

0.0013527

0.0031029

0.0096375

0.0618524

0.11371730

2755

EWS

75.6229025

63.1114141

66.2214845

70.2435518

78.2174869

-

OBC-NCL

73.6114227

67.0090297

68.0234447

72.8887969

74.3166557

65313

SC

51.9776027

43.0820954

46.8825338

50.1760245

54.0128155

34425

ST

37.2348772

26.7771328

34.6728999

39.0696101

44.3345172

17256

JEE Main Normalization Process

National Testing Agency, NTA uses the normalization process of JEE Main to calculate the score of JEE Mains. The JEE Main percentile score ranges from 0-100. Below is the formula to calculate the percentile score using the JEE Main normalization process.

JEE Main Normalized score formula: (100 x number of candidates who appeared in the session with a raw score equal to or less than the candidate) / total number of candidates who appeared in that session

JEE Main formula

Preparation Tips for good scores in JEE Main

After knowing what is a good score in JEE Main, now candidates should know what preparation strategy to opt for scoring good marks. To score good marks in JEE Mains candidates need to follow a full proof preparation strategy. So here we have provided the preparation tips for scoring good marks in JEE Main.

  • Go through the JEE Main syllabus and exam pattern which is provided at JEE official website.
  • Get your relevant books, previous year question papers, sample papers, and mock tests.
  • Make a proper study timetable.
  • Solve as many mock test of JEE Main as possible.
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Frequently Asked Question (FAQs)

1. What can be considered as a good score in JEE Main?

As per the previous year trends, 250+ is considered a good score for JEE Main exam.

2. How many marks should I score in JEE Main to get the 92 percentile?

Candidates having marks above 89 but less than 94 will obtain the 92  percentile.

3. How to score 150 in JEE Mains?

In order to score 150 marks in JEE Main exam candidates need to follow proper preparation strategy. Solve as many mock tests as possible and check the exam pattern to get the vibe of actual exam.

4. What would be my percentile if I score 60 marks in JEE Main?

The percentile score will be 70 if the candidate secures 60 marks in JEE Main.

5. What would be my percentile if I score 50 marks in JEE Main?

The percentile score will be 70 if the candidate secures 50 marks in JEE Main.

6. What would be my percentile if I score 70 marks in JEE Main?

The percentile score will range from 84 to 91 if the candidate secures 70 marks in JEE Main.

7. Is 120 a good score in Mains?

120 marks in JEE Mains is considered an average score even as your expected percentile may range between 95-96%. A good score should have a 98-99%.

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Questions related to JEE Main

Have a question related to JEE Main ?

Hello aspirant,

Based on past year's trends, I think you need to be at least in the 93 percentile to get into ECE, ME, or EE, or maybe Mining or Metallurgical, to get admission in BIT Sindri. You roughly need ranking under 80,000 in JEE Mains for admission in this college.

Thank you

Hope this information helps you.

Jee mains sc category 83.7 percentile rank 13161 hai konsi nit milega


You can do two things either wait for few hours or till tomorrow or you can do payment again because in that case previous money will be refunded shortly

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 5 g of Na2SO4 was dissolved in x g of H2O. The change in freezing point was found to be 3.820C.  If Na2SO4 is 81.5% ionised, the value of x (Kf for water=1.860C kg mol−1) is approximately : (molar mass of S=32 g mol−1 and that of Na=23 g mol−1)
Option: 1  15 g
Option: 2  25 g
Option: 3  45 g
Option: 4  65 g  
 

 50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl.  If pKb of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75
Option: 3 8.25
Option: 4 9.25
 

CH_3-CH=CH-CH_3+Br_2\overset{CCl_4}{\rightarrow}A

What is A?

Option: 1

CH_3-CH(Br)-CH_2-CH_3


Option: 2

CH_3-CH(Br)-CH(Br)-CH_3


Option: 3

CH_3-CH_2-CH_2-CH_2Br


Option: 4

None


\mathrm{NaNO_{3}} when heated gives a white solid A and two gases B and C. B and C are two important atmospheric gases. What is A, B and C ?

Option: 1

\mathrm{A}: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 2

A: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{N}_2


Option: 3

A: \mathrm{NaNO}_2 \mathrm{~B}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


Option: 4

\mathrm{A}: \mathrm{Na}_2 \mathrm{OB}: \mathrm{O}_2 \mathrm{C}: \mathrm{Cl}_2


C_1+2 C_2+3 C_3+\ldots .n C_n=

Option: 1

2^n


Option: 2

\text { n. } 2^n


Option: 3

\text { n. } 2^{n-1}


Option: 4

n \cdot 2^{n+1}


 

A capacitor is made of two square plates each of side 'a' making a very small angle \alpha between them, as shown in the figure. The capacitance will be close to : 
Option: 1 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{4 d } \right )

Option: 2 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 + \frac{\alpha a }{4 d } \right )

Option: 3 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{\alpha a }{2 d } \right )

Option: 4 \frac{\epsilon _{0}a^{2}}{d}\left ( 1 - \frac{3 \alpha a }{2 d } \right )
 

 Among the following compounds, the increasing order of their basic strength is
Option: 1  (I) < (II) < (IV) < (III)
Option: 2  (I) < (II) < (III) < (IV)
Option: 3  (II) < (I) < (IV) < (III)
Option: 4  (II) < (I) < (III) < (IV)
 

 An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant.  If during  this process the relation of pressure P and volume V is given by PVn=constant,  then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively)
Option: 1  n=\frac{C_{p}}{C_{v}}


Option: 2  n=\frac{C-C_{p}}{C-C_{v}}


Option: 3 n=\frac{C_{p}-C}{C-C_{v}}

Option: 4  n=\frac{C-C_{v}}{C-C_{p}}
 

As shown in the figure, a battery of emf \epsilon is connected to an inductor L and resistance R in series. The switch is closed at t = 0. The total charge that flows from the battery, between t = 0 and t = tc (tc is the time constant of the circuit ) is : 


Option: 1 \frac{\epsilon L }{R^{2}} \left ( 1 - \frac{1}{e} \right )
Option: 2 \frac{\epsilon L }{R^{2}}


Option: 3 \frac{\epsilon R }{eL^{2}}

Option: 4 \frac{\epsilon L }{eR^{2}}
 

As shown in the figure, a particle of mass 10 kg is placed at a point A. When the particle is slightly displaced to its right, it starts moving and reaches the point B. The speed  of the particle at B is x m/s. (Take g = 10 m/s2 ) The value of 'x' to the nearest is ___________.
Option: 1 10
Option: 2 20
Option: 3 40
Option: 4 15

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