Top 10 Most Repeated Topics in Physics for JEE Mains - Boost Your Score in JEE 2027 Exam

Top 10 Most Repeated Physics Topics for JEE Main 2027

Here in this segment, we will discuss the top 10 most frequent topics for the physics section of JEE Main. This data has been obtained by our experts by carefully reviewing the last 10 years' JEE Main examination question papers and syllabus for JEE Main 2027. Along with the topic name, the total number of questions asked in the span of 5 years is also given in the table below. This data about the most repeated physics topics for JEE Main is going to help students strategise for their exam. Students must avoid skipping the following topics as they are the top 10 most repeated topics in physics for JEE Main from 2016 to 2026.

Most Important Chapters For JEE Main Physics 2027

Acing the exam is all about studying smart these days due to the huge competition. Smart study requires strategy and in-depth research. The good thing is we have already researched for you. Again, like the topics, we have curated a list of the top 10 most important chapters for JEE Main Physics 2027. This data is also researched and curated by experts from 2016 to 2026, including all JEE Main physics question papers.

The table given below provides the names of the most important chapters for JEE Main physics 2027 and the total number of questions asked from that particular chapter over the past 5 years.

JEE Main Previous Year Questions from Frequently Repeated Physics Topics

In this section, we shall look at some of the topics and questions asked in previous years to help you get an idea of what kind of questions are asked. We shall go topic-wise from the above table of topics:

Q1. The truth table for the above logic circuit is the same as that of:

(A) NOR

(B) OR

(C) AND

(D) NAND

Solution:

As we learn

NOR Gate -

NOT + OR Gate

- wherein

$Y=\overline{A+B}$

A and B are input

Y is output

The output (y) of two input (A, B) NOR gates is :

$Y=\overline{A+B}$

Hence, the answer is the option (1).

Q2. The de Broglie weave length for an electron accelerated through the potential difference $\mathrm{V}_1$ volt is $\lambda_1$. When the potential difference is changed to $\mathrm{V}_2$ volt, the associated de Broglie wavelength is increased by $50 \%$. If $\left(\mathrm{V}_1 / \mathrm{V}_2\right)=(9 / \alpha)$, then the value of $\alpha$ is $\_\_\_\_$

(A) 4

(B) 2

(C) 1

(D) 3

Solution:

$\begin{aligned} & \lambda_1=\frac{\mathrm{h}}{\mathrm{m} \nu}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{meV}_1}}=\lambda \\ & \lambda_2=\frac{\mathrm{h}}{\sqrt{2 \mathrm{meV}_2}}=\frac{3 \lambda}{2}=\frac{3}{2} \frac{\mathrm{~h}}{\sqrt{2 \mathrm{meV}_1}} \\ & \mathrm{~V}_2=\frac{4}{9} \cdot \mathrm{~V}_1 \\ & \frac{\mathrm{~V}_1}{\mathrm{~V}_2}=\frac{9}{4} \Rightarrow \alpha=4\end{aligned}$

Q3. A projectile is thrown with a velocity $u_0$ at an angle $\theta$ with the horizontal. The ratio of the rate of change of speed with respect to time at the highest point to that at the point of projection is
(A) $g \sin \theta$
(B) $-g \sin \theta$
(C) Zero
(D) $g$

Solution:

$$
\left(\frac{d v}{d t}\right)_{\text {top }}=0
$$

As tangential acceleration at the top

$$
\begin{gathered}
=0 \\
\left(\frac{d v}{d t}\right)_{\text {starting point }}=-g \sin \theta
\end{gathered}
$$

So, the required ratio

$$
=\frac{\left(\frac{d v}{d t}\right)_{\text {top }}}{\left(\frac{d v}{d t}\right)_{\text {starting point }}}=\frac{0}{-g \sin \theta}=0
$$

Hence, the answer is zero. Option (C)

Q4. In an electromagnetic wave, the electric and magnetising fields are 100 v/m and 0.135 A/m. The maximum energy flow is

(A) $13.5 \mathrm{w} / \mathrm{m}^2$

(B) $26.5 \mathrm{w} / \mathrm{m}^2$

(C) $27.0 \mathrm{w} / \mathrm{m}^2$

(D) None of these

Solution:

As we learned

Poynting Vector -

$
\vec{S}=\frac{\vec{E} \times \vec{B}}{\mu_o}
$

- wherein

It is total energy flowing perpendicularly per second per unit area into the surface in free space.

The maximum rate of energy flow

$
\theta=\frac{\epsilon_o \times \beta_o}{\mu}=100 \times 0.135=13.5 \mathrm{w} / \mathrm{m}^2
$

Hence, the correct answer is option (a).

Q5. In which case, the wire has maximum expansion if the same force is applied to each wire?
(A) $L=500 \mathrm{~cm}, d=0.05 \mathrm{~mm}$
(B) $L=200 \mathrm{~cm}, d=0.02 \mathrm{~mm}$
(C) $L=300 \mathrm{~cm}, d=0.03 \mathrm{~mm}$
(D) $L=400 \mathrm{~cm}, d=0.01 \mathrm{~mm}$

Solution:

$$
\Delta l=\frac{F L}{\pi r^2 Y}
$$

where $F$ and $Y$ are constant.

$$
\Delta l \propto \frac{L}{r^2}
$$

The maximum expansion occurs in the wire for which

$$
\frac{L}{r^2}
$$

is maximum.
For option (D),

$$
L=400 \mathrm{~cm}, \quad d=0.01 \mathrm{~mm}
$$

Hence, expansion is maximum.

Q6. At what temperature does the average translational kinetic energy of a molecule in a gas equal the kinetic energy of an electron accelerated from rest through a potential difference of 5 volts?

(A) $386.5 \times 10^3 \mathrm{~K}$
(B) $3.865 \times 10^3 \mathrm{~K}$
(C) $0.38 \times 10^3 \mathrm{~K}$
(D) $38.65 \times 10^3 \mathrm{~K}$

Solution:

K.E. of electron

$$
\begin{gathered}
=5 \mathrm{eV} \\
=5 \times 1.6 \times 10^{-19} \mathrm{~J}
\end{gathered}
$$

But,

$$
K . E .=\frac{3}{2} k T
$$

Therefore,

$$
\begin{gathered}
5 \times 1.6 \times 10^{-19}=\frac{3}{2}\left(1.38 \times 10^{-23}\right) T \\
T=\frac{5 \times 1.6 \times 10^{-19} \times 2}{3 \times 1.38 \times 10^{-23}} \\
T=3.865 \times 10^4 K \\
T=38.65 \times 10^3 K
\end{gathered}
$$

Q7. In the figure shown below, a resistance of $150.4 \Omega$ is connected in series to an ammeter A of resistance $240 \Omega$. A shunt resistance of $10 \Omega$ is connected in parallel with the ammeter. The reading of the ammeter is $\_\_\_\_$ mA .

Solution:

$$
\begin{aligned}
& \mathrm{R}_{\mathrm{eq}}=\mathrm{R}_1+\mathrm{R}_2 \\
& \mathrm{R}_{\mathrm{eq}}=150.4+\frac{240 \times 10}{250} \\
& =150.4+9.6=160 \Omega \\
& \mathrm{I}_1=\frac{\mathrm{IR}_2}{240} \\
& \mathrm{I}_1=\frac{\mathrm{I} \times 9.6}{240} \\
& =\frac{20}{160} \times \frac{9.6}{2400}=\frac{1}{200}=5 \times 10^{-3} \mathrm{~A}=5 \mathrm{~mA}
\end{aligned}
$$

Hence, the answer is 5.

Q8. An adiabatic change is represented by the equation
(A) $V P^\gamma=$ constant
(B) $P T^{-\gamma}=$ constant
(C) $T V^\gamma=$ constant
(D) $P V^\gamma=$ constant

Solution:

The process equation for an adiabatic change is

$$
P V^\gamma=\mathrm{constant}
$$

Hence, the correct option is (D)

Q9. The position vector of a particle related to time $t$ is given by

$$
\overrightarrow{\mathrm{r}}=\left(10 \mathrm{t} \hat{\mathrm{i}}+15 \mathrm{t}^2 \hat{\mathrm{j}}+7 \hat{\mathrm{k}}\right) \mathrm{m}
$$

The direction of net force experienced by the particle is :

areers360.com

(A) Positive z-axis
(B) In x -y plane
(C) Positive y - axis
(D) Positive $x$-axis

Solution:

Given, $\overrightarrow{\mathrm{r}}=10 \hat{t} \hat{i}+15 \mathrm{t}^2 \hat{\mathrm{j}}+7 \hat{\mathrm{k}}$

$$
\begin{aligned}
& \overrightarrow{\mathrm{v}}=\frac{\mathrm{dr}}{\mathrm{dt}}=10 \hat{\mathrm{j}}+30 \mathrm{t} \hat{\mathrm{j}} \\
& \overrightarrow{\mathrm{a}}=\frac{\mathrm{d} \overrightarrow{\mathrm{v}}}{\mathrm{dt}}=30 \hat{\mathrm{j}} \\
& \overrightarrow{\mathrm{~F}}=\mathrm{ma} \rightarrow \text { along }(+) y \text {-axis }
\end{aligned}
$$
Hence, the answer is the option (C).

Q10. A double slit interference experiment performed with a light of wavelength 600 nm forms an interference fringe pattern on a screen with $10^{\text {th }}$ bright fringe having its center at a distance of 10 mm from the central maximum. Distance of the centre of the same $10^{\text {th }}$ bright fringe from the central maximum when the rays of light are replaced by another source of wavelength 660 nm would be $\_\_\_\_$ mm.

Solution:

In case of YDSE the distance of $\mathrm{n}^{\text {th }}$ maxima from central maxima is given by,

$$
y=\frac{D}{d} n \lambda
$$

Here $\mathrm{n}, \mathrm{D}$ \& d are same
So, $\mathrm{y} \propto \lambda$

$$
\begin{aligned}
& \Rightarrow \frac{\mathrm{y}_2}{\mathrm{y}_1}=\frac{\lambda_2}{\lambda_1} \Rightarrow \frac{\mathrm{y}_2}{10 \mathrm{~mm}}=\frac{660 \mathrm{~nm}}{600 \mathrm{~nm}} \\
& \Rightarrow \mathrm{y}_2=11 \mathrm{~mm}
\end{aligned}
$$
Hence, the answer is 11.

Physics Study Plan for JEE Main 2027

It is very important to approach Physics with a proper strategy. Given below complete preparation strategy for JEE Main that will help you prepare effectively:

• Physics is one of the most challenging subjects. In order to prepare this subject well, students must focus on conceptual clarity.

• First, start preparing with the NCERT books. After that, students can follow reference books and JEE Main mock tests.

• It is very important to solve previous year questions to understand the pattern and difficulty level.

• According to this subject-wise study plan for JEE Main 2027, Candidates should regularly practice numerical problems.

How to prepare for repeated topics of Physics for JEE Main 2027.

1. Memorise formulas before solving numericals: Students have to first memorise all the important formulas of a chapter before solving numericals. They should also memorise and learn the logic behind when and at what time to solve a particular formula. A separate notebook of formulas can be maintained for better problem-solving and accuracy in solving problems.

2. Solve the PYQs topic-wise from the last 10 years: One of the best preparation tools for the JEE Main exam is PYQs. Students are required to solve topic-wise PYQs of the last 10 years to gain familiarity with the exam pattern of the physics subject in JEE Main and identify repeated topics that appear in the examination quite frequently. It helps improve both the accuracy and speed of solving.

3. Emphasise conceptual rather than procedural understanding: Physics is a subject that tests concept more than memory. Candidates should not only memorise formulas but should also be able to derive the important concepts. This allows candidates to score better in questions testing logic and application of concepts.

4. Practice the moderate and difficult questions: After getting a grip of the easy problems, students should move on to the moderate and difficult questions related to a topic. Answering a variety of questions, ranging from easy to difficult, helps candidates in developing strong problem-solving and logical ability to face different levels of problems in the JEE Main 2027 examination.

5. Revise the short notes weekly: To remember formulas and important observations related to a concept, candidates should revise the subject from the notes they prepared. Regular revision can prevent you from forgetting important formulas, concepts, and observations to be applied for solving specific problems. Weekly revision is crucial to boost retention in the long term.

6. Take the chapter-wise mock tests: This will allow you to evaluate your current level of preparation for a topic and to pinpoint your weaker areas in the examination. In these mock tests, students are subjected to real-time exam conditions, which help improve their time management skills. Students need to analyse the results of the post-test and focus more on improving the errors in the test to avoid recurrence in the real exam.

7. An additional point: The best thing to do for preparing repeated Physics topics is being consistent; students should work regularly on these recurring topics, combined with regular revisions and mock tests.

Best Books for Repeated Physics Topics in JEE Main

Recommended Books

The significance of repeated topics in JEE Main Physics:

Focusing on the topics that repeat the most in JEE Main Physics allows students to prepare with a strategy in order to obtain high marks. Some of the reasons behind repeated topics are:

1. A good clue to the Exam Pattern: If the question has been coming in every year for years, that shows the exam pattern of JEE Main is constant. If you can examine past papers and find out the recurring subjects, then we can estimate what type of questions will come in the real exam.

2. Maximum scores possible: It is obvious that if there is more possibility for the questions being asked from some topics, then there is more possibility of getting marks by practising these topics in the JEE Main Physics paper, which increases the marks in the final result.

3. Direction for prioritising topics for studies: The syllabus is very long in physics, so it is not possible to give each chapter the same amount of time. But if the repeating topics in the exam are known, you will know where you should pay more attention during preparation and where to waste less time by studying less important topics.

4. Improve your solving speed of numericals: When the same kind of numerical problems come regularly, then by solving the most frequent topics, you will improve the speed of solving numericals. Speed is very important in the JEE Main exam.

5. More competitive preparation: There are lakhs of students giving the JEE Main. So, you should use smart preparation techniques to get a higher rank by scoring more marks in the Physics paper.